{"id":31166,"date":"2019-07-05T18:34:49","date_gmt":"2019-07-05T13:04:49","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=31166"},"modified":"2019-07-05T18:34:49","modified_gmt":"2019-07-05T13:04:49","slug":"clocks-calendars-questions-for-rrb-group-d-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/clocks-calendars-questions-for-rrb-group-d-pdf\/","title":{"rendered":"Clocks & Calendars Questions for RRB Group-D PDF"},"content":{"rendered":"

Clocks & Calendars Questions for RRB Group-D PDF<\/strong><\/span><\/h2>\n

Download Top-15 RRB Group-D Clocks & Calendars\u00a0 Questions PDF.\u00a0RRB GROUP-D Clocks & Calendars questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download Clocks & Calendars Questions for RRB Group-D PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>Find the mirror image of the clock when the time is 03:00<\/p>\n

a)\u00a008:57<\/p>\n

b)\u00a009:00<\/p>\n

c)\u00a009:03<\/p>\n

d)\u00a009:01<\/p>\n

Question 2:\u00a0<\/b>If 15-06-1994 is wednesday, then what day is 19-07-1995 ?<\/p>\n

a)\u00a0Tuesday<\/p>\n

b)\u00a0Wednesday<\/p>\n

c)\u00a0Thursday<\/p>\n

d)\u00a0Friday<\/p>\n

Question 3:\u00a0<\/b>What day is it after 178 days if it is a Monday tomorrow?<\/p>\n

a)\u00a0Tuesday<\/p>\n

b)\u00a0Saturday<\/p>\n

c)\u00a0Friday<\/p>\n

d)\u00a0Wednesday<\/p>\n

Question 4:\u00a0<\/b>Which day is it on 1st January, 2000.<\/p>\n

a)\u00a0Monday<\/p>\n

b)\u00a0Wednesday<\/p>\n

c)\u00a0Saturday<\/p>\n

d)\u00a0Sunday<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

770 Mocks (cracku Pass) Just Rs.199<\/a><\/p>\n\n

Question 5:\u00a0<\/b>At what time the hands of the clock show a mirror image of 4:10 ?<\/p>\n

a)\u00a07:10<\/p>\n

b)\u00a07:40<\/p>\n

c)\u00a07:50<\/p>\n

d)\u00a08:10<\/p>\n

Question 6:\u00a0<\/b>At what time between 2 O\u2019Clock and 3 O\u2019Clock, will the minute hand and hour hand of the clock be exactly opposite to each other?<\/p>\n

a)\u00a0$02:46$<\/p>\n

b)\u00a0$02:47\\dfrac{6}{11}$<\/p>\n

c)\u00a0$02:43\\dfrac{7}{11}$<\/p>\n

d)\u00a0$02:47$<\/p>\n

Question 7:\u00a0<\/b>Find the number of days in p weeks and p days.<\/p>\n

a)\u00a08p<\/p>\n

b)\u00a0$7p^2$<\/p>\n

c)\u00a0$8p^2$<\/p>\n

d)\u00a07p<\/p>\n

Question 8:\u00a0<\/b>Find the total number of days present in the first century.<\/p>\n

a)\u00a036500<\/p>\n

b)\u00a036512<\/p>\n

c)\u00a036524<\/p>\n

d)\u00a036525<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

Daily Free RRB Online Test<\/a><\/p>\n

Question 9:\u00a0<\/b>Which of the following is not a leap year?<\/p>\n

a)\u00a01800<\/p>\n

b)\u00a01864<\/p>\n

c)\u00a01600<\/p>\n

d)\u00a01624<\/p>\n

Question 10:\u00a0<\/b>Find the angle between the hands of the clock when the time is 10:30<\/p>\n

a)\u00a0$160^\\circ$<\/p>\n

b)\u00a0$120^\\circ$<\/p>\n

c)\u00a0$180^\\circ$<\/p>\n

d)\u00a0$135^\\circ$<\/p>\n

Question 11:\u00a0<\/b>What day is it on 26th January, 1950?<\/p>\n

a)\u00a0Wednesday<\/p>\n

b)\u00a0Thursday<\/p>\n

c)\u00a0Friday<\/p>\n

d)\u00a0Saturday<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 12:\u00a0<\/b>Which of the following years has the same calendar as that of the year 1963?<\/p>\n

a)\u00a01971<\/p>\n

b)\u00a01972<\/p>\n

c)\u00a01973<\/p>\n

d)\u00a01974<\/p>\n

Question 13:\u00a0<\/b>A clock shows 7 O’clock in the morning. By how much angle will the hours hand rotate when the clock shows 9 O\u2019clock in the morning.<\/p>\n

a)\u00a0$40^\\circ$<\/p>\n

b)\u00a0$60^\\circ$<\/p>\n

c)\u00a0$45^\\circ$<\/p>\n

d)\u00a0$90^\\circ$<\/p>\n

Question 14:\u00a0<\/b>Which of the following days cannot be the last day of the century?<\/p>\n

a)\u00a0Friday<\/p>\n

b)\u00a0Wednesday<\/p>\n

c)\u00a0Sunday<\/p>\n

d)\u00a0Saturday<\/p>\n

Question 15:\u00a0<\/b>What will be the day of the week on 13th April, 2006?<\/p>\n

a)\u00a0Thursday<\/p>\n

b)\u00a0Saturday<\/p>\n

c)\u00a0Sunday<\/p>\n

d)\u00a0Tuesday<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

We need to subtract from 12:00 or 11:60 to get mirror image time
\nMirror image of 03:00 = 12:00 – 03:00 = 09:00<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

a non leap year has 365 days (52 weeks+1 day).
\n1995 is not a leap year, And 15-06-1994 is wednesday, So 15-06-1995 would be thursday.
\nAnd 19-07-1995 is 34th day after 15-06-1995 (thursday), \u21d2 34 = 7(4)+6 days, So 6th day after thursday is Wednesday.<\/p>\n

So the answer is option B.<\/p>\n

3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

If tomorrow is a Monday, then today is a Sunday.
\n178 = (7 * 25) + 3
\n178 days is equal to 25 weeks and 3 odd days.
\n3 days after a Sunday is a Wednesday.
\nHence, it is a Wednesday after 178 days.<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The number of odd days in every 400 years = 0
\n=> 31st December 2000 is a Sunday.
\n=> 1st January 2001 is a Monday.
\n2000 is a leap year => It has 2 odd days.
\nSo, the day on 1st January 2000 will be two days prior to a Monday.
\nHence, 1st January 2000 is a Saturday.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

<\/figure>\n

It should be 7:50<\/p>\n

So the answer is option C.<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Angle between two hands $= \\dfrac{11}{2}M – 30H$ where H is hours and M is Minutes
\nHere, H = 2 and Angle = $180^\\circ$
\n$180^\\circ = \\dfrac{11}{2}M – 30\\times2$
\n\u21d2 $\\dfrac{11}{2}M = 240$
\n\u21d2 $M = \\dfrac{480}{11} = 43\\dfrac{7}{11}$
\nHence, the required time = $02:43\\dfrac{7}{11}$<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Each week has 7 days.
\np weeks => 7p days.
\nSo, the total number of days in p weeks and p days = 7p + p = 8p days<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

There are 76 ordinary years and 24 leap years in the first century.
\n=> Number of days = (76 * 365) + (24 * 366)
\n= (100 * 365) + 24
\n= 36524<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

We know that all the years that are a multiple of 4 but are not centuries are leap years.
\nHence, 1864 and 1624 are leap years.
\nAlso, all the years that are multiple of 400 are leap years.
\nHence, 2000 is a leap year.
\n=> 1800 is not a leap year.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Required angle $= 30H – \\dfrac{11}{2}M$ where H is hours and M is Minutes
\nHere, H = 10 and M = 30
\nHence, Required angle $= 30\\times10 – \\dfrac{11}{2}\\times30$
\n$= 300 – 165 = 135^\\circ$<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

1949 = 1600 + 349
\nWe know that after every 400 years, the number of odd days is 0.
\nHence, after 1600 years, the number of odd days is 0.
\n350 = 300 + 50.
\nWe know that after every 300 years, there is exactly 1 odd day.
\nIn next 49 years, there are 12 leap years and 37 ordinary years.
\n=> Number of odd days until 31st December 1949 = (12 * 2) + (37 * 1) + 1 = 24 + 37 + 1 = 62
\nTotal number of odd days until 26th January, 1950 = 26 + 62 = 88
\n88 = (7 * 12) + 4
\n=> 4 odd days
\n=> It is a Thursday.<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

On counting the number of odd days from 1963 to the year that has the same calendar as that of 1963, we must get 0 odd number of days.
\nLet’s calculate the number of number of odd days up to 1970.
\n1963 has 1 odd day.
\n1964 has 2 odd days.
\n1965 has 1 odd day.
\n1966 has 1 odd day.
\n1967 has 1 odd day.
\n1968 has 2 odd days.
\n1969 has 1 odd day.
\n1970 has 1 odd day.
\nSum of the odd days until 1970 is 10.
\n10 = (1 * 7) + 3 => Number of odd days is not 0 => 1971 does not have the same calendar as 1963.
\n1971 has 1 odd day.
\nSum of the odd days until 1971 is 11.
\n11 = (1 * 7) + 4 => Number of odd days is not 0 => 1972 does not have the same calendar as 1963.
\n1972 has 2 odd days.
\nSum of the odd days until 1972 is 13.
\n13 = (1 * 7) + 6 => Number of odd days is not 0 => 1973 does not have the same calendar as 1963.
\n1973 has 1 odd day.
\nSum of the odd days until 1973 is 14.
\n14 = (2 * 7) + 0 => Number of odd days is 0 => 1974 has the same calendar as 1963.<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

In 12 hours, the hand turns $360^\\circ$.
\nHere, the difference between time = 2 hours
\nThen, Required angle $= \\dfrac{360}{12}\\times2 = 60^\\circ$<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let’s calculate the number of odd days is 100 years.
\nIn 100 years, there are 76 ordinary years and 24 leap years.
\nSo, in 100 years, there are (76*1) + (24*2) odd days, which is equal to 124 odd days.
\n124 = (7 * 17) + 5
\nSo, 124 days is equal to 17 weeks and 5 odd days. Hence, 100 years have 5 odd days => Friday
\nIn 200 years, there are 2*5 odd days, which is equal to 10 days.
\n10 = (7 * 1) + 3
\nSo, 10 days is equal to 1 week and 3 odd days. Hence, 200 years have 3 odd days.
\nIn 300 years, there are 3*5 odd days, which is equal to 15 days.
\n15 = (7 * 2) + 1
\nSo, 15 days is equal to 2 weeks and 1 odd day. Hence, 300 years have 1 odd day.
\nIn 400 years, there are (4 * 5 + 1) odd days. 1 is added because every 4th century is a leap year. So, there are 21 odd days in every 400 years.
\n21 = (7 * 3) + 0
\nHence, there are 0 odd days in every 400 years => Sunday
\nSo, only Sunday, Monday, Wednesday and Friday can be the last day of the century.
\nAmong the given options, only Saturday cannot be the last day of the century.<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

We know that the number of odd days in every 400 years is 0.
\nHence, the number of odd days in 2000 years is 0.
\nIn the remaining 5 years, there are 4 ordinary years and 1 leap year.
\n=> There are (4 * 1) + (1 * 2) = 6 odd days until December 31st, 2005.
\nThe number of days in 2006 until 13th April is 31 + 28 + 31 + 13 = 103.
\n6 + 103 = 109
\n109 = (7 * 15) + 4.
\n4 odd days => It is a Thursday on 13th April 2006.<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Clocks & Calendars Questions PDF for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Clocks & Calendars Questions for RRB Group-D PDF Download Top-15 RRB Group-D Clocks & Calendars\u00a0 Questions PDF.\u00a0RRB GROUP-D Clocks & Calendars questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0Find the mirror image […]<\/p>\n","protected":false},"author":41,"featured_media":31178,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679,1601],"tags":[489,491,1637,492,1647],"class_list":{"0":"post-31166","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"category-rrb-ntpc-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-exam","15":"tag-rrb-group-d","16":"tag-rrb-mocks"},"better_featured_image":{"id":31178,"alt_text":"Clocks & Calendars Questions for RRB Group-D PDF","caption":"Clocks & Calendars Questions for RRB Group-D PDF","description":"Clocks & Calendars Questions for RRB 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