Download Top-20 SSC MTS Number Series Questions PDF. Numerical Series questions based on asked questions in previous year exam papers very important for the SSC MTS exam.<\/p>\n
Download Number Series Questions For SSC MTS<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n SSC MTS Previous Papers<\/a> (Download PDF)<\/p>\n Instructions<\/b><\/p>\n In the following question, select the missing number from the given series.<\/p>\n Question 1:\u00a0<\/b>4,4,8,12,16,36,32,?<\/p>\n a)\u00a096<\/p>\n b)\u00a0108<\/p>\n c)\u00a0114<\/p>\n d)\u00a0128<\/p>\n Question 2:\u00a0<\/b>2,6,12,20,30,?<\/p>\n a)\u00a040<\/p>\n b)\u00a036<\/p>\n c)\u00a028<\/p>\n d)\u00a042<\/p>\n Question 3:\u00a0<\/b>-1,3,15,35,63,?<\/p>\n a)\u00a087<\/p>\n b)\u00a099<\/p>\n c)\u00a092<\/p>\n d)\u00a077<\/p>\n Question 4:\u00a0<\/b>3,6,24,192,3072,?<\/p>\n a)\u00a099212<\/p>\n b)\u00a098208<\/p>\n c)\u00a098304<\/p>\n d)\u00a096484<\/p>\n Question 5:\u00a0<\/b>0,1,5,14,30,55,?<\/p>\n a)\u00a084<\/p>\n b)\u00a091<\/p>\n c)\u00a0104<\/p>\n d)\u00a074<\/p>\n SSC MTS Previous Papers PDF<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n Question 6:\u00a0<\/b>0,3,8,15,24,?<\/p>\n a)\u00a026<\/p>\n b)\u00a048<\/p>\n c)\u00a035<\/p>\n d)\u00a029<\/p>\n Question 7:\u00a0<\/b>0,7,26,63,124,?<\/p>\n a)\u00a0342<\/p>\n b)\u00a0215<\/p>\n c)\u00a0224<\/p>\n d)\u00a0142<\/p>\n Question 8:\u00a0<\/b>3,4,12,39,103,?<\/p>\n a)\u00a0244<\/p>\n b)\u00a0256<\/p>\n c)\u00a0228<\/p>\n d)\u00a0262<\/p>\n Question 9:\u00a0<\/b>4,4,6,12,30,?<\/p>\n a)\u00a065.8<\/p>\n b)\u00a075<\/p>\n c)\u00a066.67<\/p>\n d)\u00a090<\/p>\n Question 10:\u00a0<\/b>2,2,4,16,128,?<\/p>\n a)\u00a02048<\/p>\n b)\u00a02196<\/p>\n c)\u00a01248<\/p>\n d)\u00a01684<\/p>\n SSC Study Material (18000 Solved Questions)<\/a><\/p>\n General Science Notes for SSC Exams<\/a><\/p>\n Question 11:\u00a0<\/b>11,39,525,749,981,?<\/p>\n a)\u00a01024<\/p>\n b)\u00a0729<\/p>\n c)\u00a08476<\/p>\n d)\u00a011121<\/p>\n Question 12:\u00a0<\/b>A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series. a)\u00a072<\/p>\n b)\u00a0144<\/p>\n c)\u00a048<\/p>\n d)\u00a075<\/p>\n Question 13:\u00a0<\/b>A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series. a)\u00a072<\/p>\n b)\u00a0180<\/p>\n c)\u00a048<\/p>\n d)\u00a075<\/p>\n Question 14:\u00a0<\/b>A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series. a)\u00a0-72<\/p>\n b)\u00a0-60<\/p>\n c)\u00a0-48<\/p>\n d)\u00a0-75<\/p>\n Instructions<\/b><\/p>\n A series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series.<\/p>\n Question 15:\u00a0<\/b>91,97,107,121,?<\/p>\n a)\u00a0137<\/p>\n b)\u00a0139<\/p>\n c)\u00a0135<\/p>\n d)\u00a0133<\/p>\n Question 16:\u00a0<\/b>21,23,31,63,?<\/p>\n a)\u00a0127<\/p>\n b)\u00a0191<\/p>\n c)\u00a095<\/p>\n d)\u00a0193<\/p>\n Question 17:\u00a0<\/b>3,7,12,18,?<\/p>\n a)\u00a025<\/p>\n b)\u00a024<\/p>\n c)\u00a026<\/p>\n d)\u00a027<\/p>\n Question 18:\u00a0<\/b>12,12,6,2,?<\/p>\n a)\u00a01<\/p>\n b)\u00a00.5<\/p>\n c)\u00a00.25<\/p>\n d)\u00a00.66<\/p>\n Question 19:\u00a0<\/b>2,10,30,68,?<\/p>\n a)\u00a0120<\/p>\n b)\u00a0130<\/p>\n c)\u00a0110<\/p>\n d)\u00a0140<\/p>\n Question 20:\u00a0<\/b>-1,0,7,26,?<\/p>\n a)\u00a057<\/p>\n b)\u00a060<\/p>\n c)\u00a063<\/p>\n d)\u00a066<\/p>\n 200+ SSC Important Practice Sets<\/a><\/p>\n General Knowledge Q&A for Competitive Exams (Download PDF)<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given series is a double series. 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 1*2 = 2 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $0^2 -1 = 0-1 = -1$ 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 3*2 = 6 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $0+1^2 = 0+1 = 1$ 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $1^2-1 = 1-1 = 0$ 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $1^3-1 = 1-1 = 0$ 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $3+1^3 = 3+1 = 4$ 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 4*1 = 4 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 2*1 = 2 11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The given series is in the form of $[x][x^2]$ 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The pattern is that each number is divided by -2 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The pattern is that each number is divided by -2 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The pattern is that each number is divided by -2<\/p>\n $480\\div-2 = -240$<\/p>\n $-240\\div-2 = 120$<\/p>\n $120\\div\u22122 = -60$<\/p>\n $-60\\div\u22122 = 30$<\/p>\n $30\\div-2 = -15$<\/p>\n => ans B<\/p>\n 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In this series next term is obtained by adding 6,10,14,18…respectively i.e 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In this series next term is obtained by adding odd powers of 2 to the previous term i.e 21+2=23 17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n In this series next term is obtained by adding natural number starting from 4 i.e 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In this series next term is obtained by dividing with natural numbers starting from 1 i.e 12\/1=12 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In this series each term is n^{3}+n starting from n=1 i.e for n=1 we have 2 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In this each term follows the trend of $n^{3}-1$ starting from n=0 i.e
\n3888, -1296, 432, ? , 48, -16<\/p>\n
\n1440, -720, 360, ? , 90, -45<\/p>\n
\n480, -240, 120, ? , 30, -15<\/p>\n
\n4,8,16,32,…. and 4,12,36,….
\nIn the first series,
\n4*2 = 8
\n8*2 = 16
\n16*2 = 32
\nIn the second series,
\n4*3 = 12
\n12*3 = 36
\nSimilarly next number should be
\n36*3 = 108.<\/p>\n
\n2*3 = 6
\n3*4 = 12
\n4*5 = 20
\n5*6 = 30
\nSimilarly next number should be
\n6*7 = 42<\/p>\n
\n$2^2 -1 = 4-1 = 3$
\n$4^2 – 1 = 16-1 = 15$
\n$8^2-1 = 64-1 = 63$
\nSimilarly Next number should be
\n$10^2-1 = 100-1 = 99$<\/p>\n
\n6*4 = 24
\n24*8 = 192
\n192*16 = 3072
\nSimilarly Next number should be
\n3072*32 = 98304<\/p>\n
\n$1+2^2 = 1+4 = 5$
\n$5+3^2 = 5+9 = 14$
\n$14+4^2 = 14+16 = 30$
\n$30+5^2 = 30+25 = 55$
\nSimilarly Next number should be
\n$55+6^2 = 55+36 = 91$<\/p>\n
\n$2^2-1 = 4-1 = 3$
\n$3^2-1 = 9-1 =8$
\n$4^2-1 =16-1 = 15$
\n$5^2-1 = 25-1 = 24$
\nSimilarly Next number should be
\n$6^2-1 = 36-1 = 35$<\/p>\n
\n$2^3-1 = 8-1 = 7$
\n$3^3-1 = 27-1 = 26$
\n$4^3-1 = 64-1 = 63$
\n$5^3-1 = 125-1 = 124$
\nSimilarly, Next number should be
\n$6^3-1 = 216-1 = 215$<\/p>\n
\n$4+2^3 = 4+8 = 12$
\n$12+3^3 = 12+27 = 39$
\n$39+4^3 = 39+64 = 103$
\nSimilarly, Next number should be
\n$103+5^3 = 103+125 = 228$<\/p>\n
\n4*1.5 = 6
\n6*2 = 12
\n12*2.5 = 30
\nHence, Next number should be
\n30*3 = 90.<\/p>\n
\n2*2 = 4
\n4*4 = 16
\n16*8 = 128
\nHence, Next number should be
\n128*16 = 2048<\/p>\n
\n$11 \u2192 [1][1^2]$
\n1+2 = 3
\n$39 \u2192 [3][3^2]$
\n3+2 = 5
\n$525 \u2192 [5][5^2]$
\nSimilarly, Next number should be
\n9+2 = 11
\n$[11][11^2] = [11][121] = 11121$<\/p>\n
\n$3888\\div-3 = -1296$
\n$-1296\\div-3 = 432$
\n$432\\div\u22123 = -144$
\n$-144\\div\u22123 = 48$
\n$48\\div-3 = -16$
\n=> Ans – (B)<\/p>\n
\n$1440\\div-2 = -720$
\n$-720\\div-2 = 360$
\n$360\\div\u22122 = -180$
\n$-180\\div\u22122 = 90$
\n$90\\div-2 = -45$
\n=> Ans – (B)<\/p>\n
\n91+6=97
\n97+10=107
\n107+14=121
\n121+18=139<\/p>\n
\n23+8=31
\n31+32=63
\n63+128=191<\/p>\n
\n3+4=7
\n7+5=12
\n12+6=18
\n18+7=25<\/p>\n
\n12\/2=6
\n6\/3=2
\n2\/4=0.5<\/p>\n
\nFor n=2 we have 10
\nFor n=3 we have 30
\nFor n=4 we have 68
\nFor n=5 we have 130<\/p>\n
\n0-1=-1
\n1-1=0
\n8-1=7
\n27-1=26
\n64-1=63<\/p>\n