Download Top-20 IBPS RRB PO Approximation Questions PDF. Approximation questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam.<\/p>\n
Download Approximation Questions For IBPS RRB PO PDF<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n 70 IBPS RRB (PO + Clerk) Mocks @ Rs. 199<\/a><\/p>\n Take a free mock test for IBPS RRB PO<\/a><\/p>\n Download IBPS RRB PO Previous Papers PDF<\/a><\/p>\n <\/p>\n Question 2:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following questions? a)\u00a049<\/p>\n b)\u00a058<\/p>\n c)\u00a022<\/p>\n d)\u00a066<\/p>\n e)\u00a034<\/p>\n Question 3:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value) a)\u00a03800<\/p>\n b)\u00a04500<\/p>\n c)\u00a02600<\/p>\n d)\u00a03000<\/p>\n e)\u00a04080<\/p>\n Question 4:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following equation ? a)\u00a014<\/p>\n b)\u00a017<\/p>\n c)\u00a012<\/p>\n d)\u00a016<\/p>\n e)\u00a015<\/p>\n Question 5:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following equation ? a)\u00a010<\/p>\n b)\u00a013<\/p>\n c)\u00a014.5<\/p>\n d)\u00a01.35<\/p>\n e)\u00a012<\/p>\n Question 6:\u00a0<\/b>What approximate value should come in place of question mark(?) in the following equation ? a)\u00a0395<\/p>\n b)\u00a0295<\/p>\n c)\u00a0300<\/p>\n d)\u00a0315<\/p>\n e)\u00a0310<\/p>\n Free Mock Test for IBPS RRB PO<\/a><\/p>\n IBPS RRB Clerk Previous Papers<\/a><\/p>\n Question 7:\u00a0<\/b>What approximate value should come in place of the question mark(?) in the following question? (Note: You are not expected to find the exact value). a)\u00a07500<\/p>\n b)\u00a010500<\/p>\n c)\u00a09000<\/p>\n d)\u00a013500<\/p>\n e)\u00a012000<\/p>\n Question 8:\u00a0<\/b>What approximate value should come in place of the question mark(?) in the following question? (Note: You are not expected to find the exact value). a)\u00a071<\/p>\n b)\u00a076<\/p>\n c)\u00a081<\/p>\n d)\u00a086<\/p>\n e)\u00a091<\/p>\n Question 9:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question\u2019?$ 754 \\div \\sqrt{4076} \\times 24 $ = ?<\/p>\n a)\u00a0294<\/p>\n b)\u00a0256<\/p>\n c)\u00a0265<\/p>\n d)\u00a0300<\/p>\n e)\u00a0288<\/p>\n Question 10:\u00a0<\/b>What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value) a)\u00a03750<\/p>\n b)\u00a03900<\/p>\n c)\u00a04000<\/p>\n d)\u00a03950<\/p>\n e)\u00a04050<\/p>\n Question 11:\u00a0<\/b>What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value) a)\u00a0145<\/p>\n b)\u00a0140<\/p>\n c)\u00a0135<\/p>\n d)\u00a0130<\/p>\n e)\u00a0125<\/p>\n Question 12:\u00a0<\/b>What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value) a)\u00a01400<\/p>\n b)\u00a01000<\/p>\n c)\u00a01250<\/p>\n d)\u00a01500<\/p>\n e)\u00a0None of the above<\/p>\n Question 13:\u00a0<\/b>What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value) a)\u00a090<\/p>\n b)\u00a095<\/p>\n c)\u00a0110<\/p>\n d)\u00a0105<\/p>\n e)\u00a0115<\/p>\n Question 14:\u00a0<\/b>What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value) a)\u00a05400<\/p>\n b)\u00a05120<\/p>\n c)\u00a05200<\/p>\n d)\u00a05000<\/p>\n e)\u00a0None of the above<\/p>\n Quantitative Aptitude formulas PDF<\/a><\/p>\n 520 Banking Mocks – Just Rs. 499<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Expression\u00a0:\u00a0$59.786 \\div 14.444 \\times 8.321 = ?$<\/p>\n = $\\frac{60}{15} \\times 8$<\/p>\n = $4 \\times 8$<\/p>\n = $32 \\approx 34$<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Since an approximate answer is sufficient, you can rewrite the question as $10000 \\div 50 \\times 5^{2} – 1130$<\/p>\n Following BDMAS rule the result is 3870.<\/p>\n The nearest value is 3800.<\/p>\n Hence Option A is the correct answer.<\/p>\n 4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the number to replace the question mark be equal to $X$<\/p>\n Hence, $695.95\\div 29.07 \\times X + 40.25 = 399.99$<\/p>\n $399.99 \\approx 400$ and $695.95 \\approx 696$ and $29.07 \\approx 29$<\/p>\n So, the expression looks like $696 \\div 29 \\times X + 40 = 400$ 5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the number to come in place of the question mark be equal to $X$<\/p>\n So, $29.38 \\times 37.05 \\div X + 7.45 = 100.5$ 18000 Free Solved Questions – Banking Study Material<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let x be the value of the unknown number.<\/p>\n x= $\\frac{9876}{24.96}$ + 215.005 – 309.99<\/p>\n = 395.67 – 94.985 $ = \\approx$ 300<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The question can be modified to 30*50*7 to get the approximate answer. 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n We know that $80^2$ is equal to 6400 and $90^2$ = 8100. 9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n In order to find the approximate value of $ 754 \\div \\sqrt{4076} \\times 24 $, we need to find the approximate value of $\\sqrt{4076}$<\/p>\n We know that $64^2 = 4096$ and $63^2 = 3969$ So, a rough approximation of the expression needed becomes $754 \\div 63.8 \\times 24 $<\/p>\n We note that 63.8 * 12 = 765 Hence, the required approximation is $24 \\times 12 = 288$<\/p>\n Hence, the correct answer is option (e)<\/p>\n 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The approximate calculation is as follows:<\/p>\n 3000 + 35 * 30<\/p>\n 35*30 = 1050<\/p>\n 3000 + 1050 = 4050<\/p>\n 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 23 * 145 = 3335 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 0.33 = 1\/3<\/p>\n The approximate calculation is as follows:<\/p>\n 50 * 75 * (1\/3) = 50 * 25 = 1250<\/p>\n 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $105^2$ = 11025<\/p>\n From the options, the closest number to the square root of 11023 is 105.<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The approximate calculation is as follows:<\/p>\n 8*16*40 = 8*8*2*8*5 = $8^3$ * 10 = 5120<\/p>\n
\n$59.786 \\div 14.444 \\times 8.321 = ?$<\/p>\n
\n$9980 \\div 49 \\times (4.9)^{2} – 1130 = ?$<\/p>\n
\n$695.95\\div 29.07 \\times ? + 40.25 = 399.99$<\/p>\n
\n$29.38 \\times 37.05 \\div ? + 7.45 = 100.5$<\/p>\n
\n$9876\\div 24.96+215.005-?=309.99$<\/p>\n
\n30.003 * 49.991 * 6.984 = ?<\/p>\n
\n$\\sqrt{7394} = ? $<\/p>\n
\n3001.45 + 34.990 * 29.923 = ?<\/p>\n
\n$\\frac{3330}{23}$ = ?<\/p>\n
\n49.99 * 74.910 * 0.33 = ?<\/p>\n
\n$\\sqrt{11023}$ = ?<\/p>\n
\n7.997 * 16.005 * 40.055 = ?<\/p>\n
\nHence, $24 \\times X = 360$ or $X = 15$<\/p>\n
\nOr, $29.38 \\times 37.05 \\div X = 93.05$
\nSo, $X = \\frac{29.38 \\times 37.05}{93.05} = 11.69 \\approx 12$<\/p>\n
\n30 * 50 * 7
\n= 1500 * 7
\n= 10500<\/p>\n
\nSince 7394 is between 6400 and 8100, its square root must lie between 80 and 90.
\nSo, it is either 81 or 86.
\nLets find the square of 81 => 81*81 = 6561
\n=> $\\sqrt{7394}$ = 86 approximately<\/p>\n
\nSo, a rough approximation of $\\sqrt{4076} = 63.8$<\/p>\n
\nSo, $754 \\div 63.8 \\approx 12$<\/p>\n
\nFrom the options, we can see that 145 is the number that is closest to the answer.<\/p>\n