Take a free mock test for SSC MTS<\/a><\/p>\n SSC MTS Previous Papers<\/a> (Download PDF)<\/p>\n Question 1:\u00a0<\/b>If 6 # 8 = 10 and 5 # 12 = 13, then 9 # 40 = ?<\/p>\n a)\u00a047<\/p>\n b)\u00a063<\/p>\n c)\u00a041<\/p>\n d)\u00a053<\/p>\n Question 2:\u00a0<\/b>If \u201cA\u201d denotes \u201cadded to\u201d, \u201cB\u201d denotes \u201csubtracted from\u201d, \u201cC\u201d denotes \u201cmultiplied by\u201d and \u201cD\u201d denotes \u201cdivided by\u201d then which of the following equation is true ?<\/p>\n a)\u00a012 A 6 B 3 C 4 D 3 = 14<\/p>\n b)\u00a013 B 6 D 3 C 2 A 5 = 12<\/p>\n c)\u00a072 D 18 C 14 B 68 A 10 = – 4<\/p>\n d)\u00a068 D 4 A 6 B 3 C 8 = 0<\/p>\n Question 3:\u00a0<\/b>If ” @”denotes “added to”, “#” denotes “multiplied by”, $”\\circledR”$ denotes “divided by” and “%” denotes “subtracted from”, then which of the following equation is true?<\/p>\n a)\u00a0$8@8\\circledR$8#8%8=9<\/p>\n b)\u00a042%26$\\circledR$13#2@8=46<\/p>\n c)\u00a019%84$\\circledR$4@3#4=12<\/p>\n d)\u00a031%4$\\circledR$2#19@3=4<\/p>\n Question 4:\u00a0<\/b>In a certain code language, \u201cCONGO\u201d is written as \u201cRZPRD\u201d and \u201cTREAT\u201d is written as \u201c UQGWX\u201d. How is \u201cPHONE\u201d written in that code language ?<\/p>\n a)\u00a0JNQIJ<\/p>\n b)\u00a0KMQHK<\/p>\n c)\u00a0MKQKH<\/p>\n d)\u00a0LLPIL<\/p>\n Question 5:\u00a0<\/b>In a certain code language, \u201cRESTED\u201d is written as \u201cSDTSFC\u201d. How is \u201cBANNED\u201d written in that code language ?<\/p>\n a)\u00a0CZOMFC<\/p>\n b)\u00a0ABMODE<\/p>\n c)\u00a0CZOODE<\/p>\n d)\u00a0ABMMFC<\/p>\n SSC MTS Previous Papers PDF<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n Question 6:\u00a0<\/b>In the following question, select the word which connot be formed using the letters of the given word. a)\u00a0GRAIN<\/p>\n b)\u00a0RAGING<\/p>\n c)\u00a0GAUGE<\/p>\n d)\u00a0ENCOURAGE<\/p>\n Question 7:\u00a0<\/b>If \u2018P 3 Q\u2019 means \u2018Q is daughter of P\u2019, \u2018P 5 Q\u2019 means \u2018Q is son of P\u2019, \u2018P 7 Q\u2019 means \u2018P is sister Q\u2019, \u2018P 9 Q\u2019 means \u2018P is brother of Q\u2019. Which of the following Expression indicates A is nephew of D ?<\/p>\n a)\u00a0B 9 D 5 C 5 A<\/p>\n b)\u00a0B 7 D 9 C 5 A<\/p>\n c)\u00a0B 7 D 7 C 3 A<\/p>\n d)\u00a0 Question 8:\u00a0<\/b>In a row of people, there are 12 people before Q. There are 4 people between P and Q. There are 15 people between Q and S. If there are 8 people between S and R, then how many minimum people are there in the row ?<\/p>\n a)\u00a029<\/p>\n b)\u00a032<\/p>\n c)\u00a036<\/p>\n d)\u00a037<\/p>\n Question 9:\u00a0<\/b>In a row of cars, red car is 14th from left and 23rd from right. How many cars are there in the row ?<\/p>\n a)\u00a036<\/p>\n b)\u00a037<\/p>\n c)\u00a035<\/p>\n d)\u00a034<\/p>\n Question 10:\u00a0<\/b>A series is given with one term missing. Select the correct alternative from the given ones that will complete the series: a)\u00a0W<\/p>\n b)\u00a0X<\/p>\n c)\u00a0U<\/p>\n d)\u00a0V<\/p>\n SSC Study Material (18000 Solved Questions)<\/a><\/p>\n General Science Notes for SSC Exams<\/a><\/p>\n Question 11:\u00a0<\/b>A series is given with one term missing. Select the correct alternative from the given ones that will complete the series. a)\u00a0I<\/p>\n b)\u00a0G<\/p>\n c)\u00a0J<\/p>\n d)\u00a0H<\/p>\n Question 12:\u00a0<\/b>Arrange the given words in the sequence in which they occur in the dictionary: a)\u00a021453<\/p>\n b)\u00a012435<\/p>\n c)\u00a021435<\/p>\n d)\u00a014253<\/p>\n Question 13:\u00a0<\/b>Arrange the given words in the sequence in which they occur in the dictionary: a)\u00a042531<\/p>\n b)\u00a043251<\/p>\n c)\u00a045312<\/p>\n d)\u00a045231<\/p>\n Question 14:\u00a0<\/b>In the following question, select the odd number-pair from the alternatives:<\/p>\n a)\u00a08-72<\/p>\n b)\u00a06-42<\/p>\n c)\u00a012-156<\/p>\n d)\u00a04-12<\/p>\n Question 15:\u00a0<\/b>In the following question, select the odd number-pair from the given alternatives:<\/p>\n a)\u00a015-45<\/p>\n b)\u00a09-29<\/p>\n c)\u00a031-93<\/p>\n d)\u00a041-123<\/p>\n Question 16:\u00a0<\/b>In the following question, select the odd letters from the given alternatives<\/p>\n a)\u00a0AEI<\/p>\n b)\u00a0IMQ<\/p>\n c)\u00a0EIL<\/p>\n d)\u00a0MQU<\/p>\n Question 17:\u00a0<\/b>In the following question, select the odd letters from the given alternatives:<\/p>\n a)\u00a0GEF<\/p>\n b)\u00a0MLK<\/p>\n c)\u00a0IKJ<\/p>\n d)\u00a0VWY<\/p>\n Question 18:\u00a0<\/b>In the following question, select the odd word pari from the given alternatives:<\/p>\n a)\u00a0Wheat – Rabi<\/p>\n b)\u00a0Rice – Rabi<\/p>\n c)\u00a0Maize – Kharif<\/p>\n d)\u00a0Barley – Rabi<\/p>\n Question 19:\u00a0<\/b>In the following question, select the odd word pair from the given alternatives:<\/p>\n a)\u00a0Speaker – Sound<\/p>\n b)\u00a0Bulb – Light<\/p>\n c)\u00a0Fire – Heat<\/p>\n d)\u00a0Earth – Land<\/p>\n Question 20:\u00a0<\/b>In the following question, select the related number from the given alternatives: a)\u00a0257<\/p>\n b)\u00a089<\/p>\n c)\u00a0173<\/p>\n d)\u00a0343<\/p>\n 200+ SSC Important Practice Sets<\/a><\/p>\n General Knowledge Q&A for Competitive Exams (Download PDF)<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The pattern followed is : $a$ # $b=c$ $\\equiv a^2+b^2=c^2$<\/p>\n Eg\u00a0:- $(6)^2+(8)^2=36+64=100=(10)^2$<\/p>\n and\u00a0$(5)^2+(12)^2=25+144=169=(13)^2$<\/p>\n Similarly,\u00a0$(9)^2+(40)^2=81+1600=1681=(41)^2$<\/p>\n => Ans – (C)<\/p>\n 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n (A) :\u00a012 A 6 B 3 C 4 D 3 = 14<\/p>\n $\\equiv12+6-3\\times4\\div3=14$<\/p>\n L.H.S. = $12+6-(\\frac{3\\times4}{3})$<\/p>\n = $18-4=14=$ R.H.S.<\/p>\n => Ans – (A)<\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n (A) :\u00a0$8@8\\circledR$8#8%8=9<\/p>\n $\\equiv8+8\\div8\\times8-8$<\/p>\n L.H.S. = $8+8-8=8\\neq$ R.H.S.<\/p>\n (B) :\u00a042%26$\\circledR$13#2@8=46<\/p>\n $\\equiv42-26\\div13\\times2+8$<\/p>\n L.H.S. = $42-4+8=46=$ R.H.S.<\/p>\n => Ans – (B)<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n \u201cCONGO\u201d is written as \u201cRZPRD\u201d and \u201cTREAT\u201d is written as \u201c UQGWX\u201d<\/p>\n The pattern followed is\u00a0:<\/p>\n Similarly, for PHONE\u00a0:\u00a0KMQHK<\/strong><\/p>\n => Ans – (B)<\/p>\n 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Expression :\u00a0\u201cRESTED\u201d is written as \u201cSDTSFC\u201d<\/p>\n The pattern followed is\u00a0:<\/p>\n Similarly, for\u00a0BANNED\u00a0:\u00a0CZOMFC<\/strong><\/p>\n => Ans – (A)<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The word ENCOURAGING does not contain any ‘E’, thus the term\u00a0Encourage<\/b>\u00a0cannot be formed.<\/p>\n => Ans – (D)<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n (A) :\u00a0B 9 D 5 C 5 A<\/p>\n B is brother of D and D is son of C.<\/p>\n Also, C\u00a0is son of A, => A is either grandfather or grandmother of D.<\/p>\n (B) : B 7 D 9 C 5 A<\/p>\n B is sister of D and D is brother of C.<\/p>\n Also, A is son of C, => A is nephew of D.<\/p>\n => Ans – (B)<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n There are 12 people before Q, => Let us assume Q is at 13th position from left end.<\/p>\n There are 15 people between Q and S, => S is at 29th position.<\/p>\n There are 4 people between P and Q, => P can be either at 8th or 18th position from left.<\/p>\n There are 8 people between S and R, => R is at 20th position.<\/p>\n Thus, there are minimum of\u00a029 people<\/span><\/strong> in the row.<\/p>\n => Ans – (A)<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Red car is 14th from left and 23rd from right<\/p>\n => Total number of cars = $(14+23)-1=36$<\/p>\n => Ans – (A)<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The letters corresponding to the above series are\u00a0: B(2), E(5), I(9), S(19), K(11 or 37<\/em>)<\/p>\n 2 $\\times2+1=5$<\/p>\n 5\u00a0$\\times2-1=9$<\/p>\n 9\u00a0$\\times2+1=19$<\/p>\n 19\u00a0$\\times2-1=37$ (or 11)<\/p>\n 11\u00a0$\\times2+1=23\\equiv W$<\/p>\n => Ans – (A)<\/p>\n 11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Consecutive odd numbers are added.<\/p>\n B (+5) = G (+7) = N\u00a0(+9) = W (+11) =\u00a0H<\/strong><\/p>\n =>\u00a0Ans – (D)<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n As per the order of dictionary,<\/p>\n =\u00a0Habit ->\u00a0Habitat ->\u00a0Hammer ->\u00a0Handle ->\u00a0Harvest<\/p>\n $\\equiv$\u00a012435<\/p>\n => Ans – (B)<\/p>\n 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n As per the order of dictionary,<\/p>\n =\u00a0Replicate ->\u00a0Repository ->\u00a0Reptile ->\u00a0Republic ->\u00a0Reputation<\/p>\n $\\equiv$\u00a045231<\/p>\n => Ans – (D)<\/p>\n 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The numbers are of the form : $n^2+n$<\/p>\n (A) : $(8)^2+8=72$<\/p>\n (B) :\u00a0$(6)^2+6=42$<\/p>\n (C) :\u00a0$(12)^2+12=156$<\/p>\n (D) :\u00a0$(4)^2+4=20\\neq12$<\/p>\n => Ans – (D)<\/p>\n 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n If we divide the second number by first number, quotient is 3.<\/p>\n (A) : $\\frac{45}{15}=3$<\/p>\n (B) :\u00a0$\\frac{29}{9}=3.22$<\/p>\n (C) :\u00a0$\\frac{93}{31}=3$<\/p>\n (D) :\u00a0$\\frac{123}{41}=3$<\/p>\n => Ans – (B)<\/p>\n 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n (A) : A (+4) = E\u00a0(+4) =\u00a0I<\/p>\n (B) : I\u00a0(+4) =\u00a0M\u00a0(+4) =\u00a0Q<\/p>\n (C) : E\u00a0(+4) =\u00a0I\u00a0(+3<\/strong>) =\u00a0L<\/p>\n (D) : M\u00a0(+4) =\u00a0Q\u00a0(+4) =\u00a0U<\/p>\n => Ans – (C)<\/p>\n 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In the first three options, the given combinations are groups of consecutive letters from English alphabetical series, i.e. (EFG), (KLM), (IJK), hence VWY<\/span><\/strong> is the odd one.<\/p>\n => Ans – (D)<\/p>\n 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n First is the type of second, Wheat and barley are rabi crops, while rice and maize are kharif crops, hence\u00a0Rice – Rabi\u00a0<\/span><\/strong>is the odd one.<\/p>\n => Ans – (B)<\/p>\n 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n First is the source of second, sound comes from speaker, light from a bulb and fire provides heat, hence\u00a0Earth – Land<\/span><\/strong> is the odd one.<\/p>\n => Ans – (D)<\/p>\n 20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Expression =\u00a036 : 27 :: 196 : ?<\/p>\n The pattern followed is = $(n)^2:(\\frac{n}{2})^3$<\/p>\n Eg\u00a0:- $(6)^2:(\\frac{6}{2})^3=36:27$<\/p>\n Similarly, $(14)^2=196$<\/p>\n => $(\\frac{14}{2})^3=(7)^3=343$<\/p>\n => Ans – (D)<\/p>\n
\nENCOURAGING<\/p>\n<\/del>B 7 D 9 C 3 A<\/p>\n
\nB, E, I, S, K, ?<\/p>\n
\nB, G, N, W, ?<\/p>\n
\n1. Habit
\n2. Habitat
\n3. Handle
\n4. Hammer
\n5. Harvest<\/p>\n
\n1. Reputation
\n2. Reptile
\n3. Republic
\n4. Replicate
\n5. Repository<\/p>\n
\n36 : 27 :: 196 : ?<\/p>\n<\/figure>\n
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