{"id":30410,"date":"2019-06-14T17:42:01","date_gmt":"2019-06-14T12:12:01","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=30410"},"modified":"2019-06-14T17:42:01","modified_gmt":"2019-06-14T12:12:01","slug":"maths-questions-for-rrb-group-d-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/maths-questions-for-rrb-group-d-set-2-pdf\/","title":{"rendered":"Maths Questions for RRB Group-D Set 2 PDF"},"content":{"rendered":"

Maths Questions for RRB Group-D Set 2 PDF<\/strong><\/span><\/h2>\n

Download Top-15 RRB Group-D Maths Questions set-2 PDF.\u00a0RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download Maths Questions for RRB Group-D Set 2 PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>Find the approximate value of\u00a0 $\\sqrt[3]{10645}\\div\\sqrt{249}\\times\\sqrt{4084}\\div\\sqrt[3]{1328}\\div\\sqrt[6]{26}$<\/p>\n

a)\u00a06<\/p>\n

b)\u00a02<\/p>\n

c)\u00a012<\/p>\n

d)\u00a04<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

Find the approximate value of?<\/p>\n

Question 2:\u00a0<\/b>$\\sqrt{2024.99}\\times 80.03-65.038$% of $1199.989+ \\dfrac{15}{11}\\times 770.03 = ?$<\/p>\n

a)\u00a03870<\/p>\n

b)\u00a03260<\/p>\n

c)\u00a03100<\/p>\n

d)\u00a03640<\/p>\n

e)\u00a03780<\/p>\n

Instructions<\/b><\/p>\n

Find the approximate value of ?<\/p>\n

Question 3:\u00a0<\/b>$\\sqrt{\\dfrac{67.03*\\sqrt{36.008}+\\sqrt{168.998}*\\sqrt[4]{80.998}}{2.004^3*5.013+\\sqrt[3]{27.005}}} = ?$<\/p>\n

a)\u00a03<\/p>\n

b)\u00a014<\/p>\n

c)\u00a025<\/p>\n

d)\u00a010<\/p>\n

e)\u00a07<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

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Instructions<\/b><\/p>\n

Find the missing number (?) in the given series from the options provided.<\/p>\n

Question 4:\u00a0<\/b>$2, 5, 13, 35, 97, ?$<\/p>\n

a)\u00a0253<\/p>\n

b)\u00a0245<\/p>\n

c)\u00a0113<\/p>\n

d)\u00a0259<\/p>\n

e)\u00a0275<\/p>\n

Question 5:\u00a0<\/b>By what percent Ramesh should mark up the price of an article so that he makes 20% profit even after offering a discount of 20%?<\/p>\n

a)\u00a050 %<\/p>\n

b)\u00a070\u00a0%<\/p>\n

c)\u00a075\u00a0%<\/p>\n

d)\u00a080\u00a0%<\/p>\n

e)\u00a040\u00a0%<\/p>\n

Question 6:\u00a0<\/b>When a student of weight 39 kg is added to a class, the average weight increases by 1 Kg. If the number of students was numerically equal to the average weight initially, then the number of students in the class initially was<\/p>\n

a)\u00a020<\/p>\n

b)\u00a021<\/p>\n

c)\u00a019<\/p>\n

d)\u00a018<\/p>\n

e)\u00a017<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

Daily Free RRB Online Test<\/a><\/p>\n

Question 7:\u00a0<\/b>Average of 13 consecutive natural numbers is A. By how much will the average increase if next 5 consecutive numbers are also considered.<\/p>\n

a)\u00a02.5<\/p>\n

b)\u00a01.5<\/p>\n

c)\u00a02<\/p>\n

d)\u00a02.25<\/p>\n

e)\u00a02.75<\/p>\n

Instructions<\/b><\/p>\n

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/strong><\/p>\n

Question 8:\u00a0<\/b>Quantity 1: Volume of a sphere of 20 cm radius.
\nQuantity 2: Volume of a right circular cone whose height is 60cm and radius of the circular base is 25 cm.<\/p>\n

a)\u00a0Quantity 1 > Quantity 2<\/p>\n

b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 < Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 = Quantity 2<\/p>\n

Question 9:\u00a0<\/b>Quantity 1: Area of an equilateral triangle with side equals to 32 cm.
\nQuantity 2: Area of a square with side equals to 20 cm.<\/p>\n

a)\u00a0Quantity 1 > Quantity 2<\/p>\n

b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 < Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 = Quantity 2<\/p>\n

Question 10:\u00a0<\/b>Ratan cuts a cube into 4 equal parts by making 2 perpendicular cuts to each other on the top surface. If the side of the original cube is 20 cm and the cost of painting 1 sq cm is Rs. 3, then, the total cost incurred in painting 4 cuboids?<\/p>\n

a)\u00a012000<\/p>\n

b)\u00a09000<\/p>\n

c)\u00a015000<\/p>\n

d)\u00a018000<\/p>\n

e)\u00a07500<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 11:\u00a0<\/b>Quantity 1: LCM of 18 and 32
\nQuantity 2: HCF of 1800 and 720<\/p>\n

a)\u00a0Quantity 1 > Quantity 2 > 400<\/p>\n

b)\u00a0Quantity 1 < Quantity 2 < 390<\/p>\n

c)\u00a0Quantity 1 $\\geq 380 > $ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq 200 $ < Quantity 2<\/p>\n

e)\u00a0Quantity 1 = Quantity 2 = 400<\/p>\n

Question 12:\u00a0<\/b>There three lights on a board, red, blue, and green. Red light blinks in 45 seconds, blue in 1.25 minutes, and green in 2.25 minutes. If they blinked together at 8:00 am, at what time will they blink again together? (Ignore the duration of the blink)<\/p>\n

a)\u00a08:05:00 am<\/p>\n

b)\u00a08:05:35 am<\/p>\n

c)\u00a08:11:15 am<\/p>\n

d)\u00a08:15:30 am<\/p>\n

e)\u00a0None of these<\/p>\n

Question 13:\u00a0<\/b>The least natural number which when divided by 23, 34 and 41 leaves a remainder of 14, 25 and 32 respectively is?<\/p>\n

a)\u00a01823<\/p>\n

b)\u00a01536<\/p>\n

c)\u00a011008<\/p>\n

d)\u00a01376<\/p>\n

e)\u00a0None of these<\/p>\n

Question 14:\u00a0<\/b>There are some coins on the table out of which one-third are heads. If I turn 2 coins then half of them show heads. How many coins are there on the table?<\/p>\n

a)\u00a020<\/p>\n

b)\u00a018<\/p>\n

c)\u00a016<\/p>\n

d)\u00a08<\/p>\n

e)\u00a012<\/p>\n

Question 15:\u00a0<\/b>The cost of 10 pens, 12 pencils and 14 erasers is Rs 76. The cost of 2 pens, 3 pencils and 4 erasers is Rs 20 and the cost of 5 pens, 3 pencils and 3 erasers is Rs 20. What is the cost of one pen?<\/p>\n

a)\u00a0Rs 1<\/p>\n

b)\u00a0Rs 2<\/p>\n

c)\u00a0Rs 1.5<\/p>\n

d)\u00a0Rs 2.5<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$\\large\\sqrt[3]{10645}\\div\\sqrt{249}\\times\\sqrt{4084}\\div\\sqrt[3]{1328}\\div\\sqrt[6]{26} \\simeq \\sqrt[3]{10648}\\div\\sqrt{256}\\times\\sqrt{4096}\\div\\sqrt[3]{1331}\\div\\large\\sqrt[6]{27}$<\/p>\n

$\\large\\sqrt[6]{27}$ $=$ $(27)^{\\large\\frac{1}{6}}$ $=$ $(27^{\\large\\frac{1}{3}})^{\\large\\frac{1}{2}}$ $=$ $(3)^{\\large\\frac{1}{2}}$ $\\simeq$ $(4)^{\\large\\frac{1}{2}}$ $= 2$<\/p>\n

$\\Large\\frac{22\\times64}{16\\times11\\times2} =$ $4$<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The given expression is:-
\n$\\sqrt{2024.99}\\times 80.03-65.038$% of $1199.989+ \\dfrac{15}{11}\\times 770.03 = ?$
\nIt can be approximated as:-
\n$\\sqrt{2025}\\times 80 -65$% of $1200+ \\dfrac{15}{11}\\times 770 = ?$
\n$3600 – 780+1050 = ?$
\nThus, ? =3870.
\nHence, option A is the correct answer.<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The given expression is:-
\n$\\sqrt{\\dfrac{67.03*\\sqrt{36.008}+\\sqrt{168.998}*\\sqrt[4]{80.998}}{2.004^3*5.013+\\sqrt[3]{27.005}}} = ?$
\nIt can be approximated as:-
\n$\\sqrt{\\dfrac{67*\\sqrt{36}+\\sqrt{169}*\\sqrt[4]{81}}{2^3*5+\\sqrt[3]{27}}} = ?$
\n= $\\sqrt{\\dfrac{402+39}{40+9}} = ?$
\n= $\\sqrt{\\dfrac{441}{49}} = 3 = ?$
\nHence, option A is the correct answer<\/p>\n

4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The given expression is:
\n$\\Rightarrow$ $T_{1} = 2 = 2^0 + 3^0$
\n$\\Rightarrow$ $T_{2} = 5 = 2^1 + 3^1$
\n$\\Rightarrow$ $T_{3} = 13 = 2^2 + 3^2$
\n$\\Rightarrow$ $T_{4} = 35 = 2^3 + 3^3$
\n$\\Rightarrow$ $T_{5} = 97 = 2^4 + 3^4$
\nHence, we can say that $\\Rightarrow$ $T_{n} = 2^{n-1} + 3^{n-1}$
\n$\\Rightarrow$ $T_{6} = 2^{5} + 3^{5} = 275$
\nHence, option E is the correct answer.<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let us the cost price of the product is Rs. X.
\nThe selling price of the article = 1.20 X
\nHence, marked price of the article = $\\frac{100}{100-20}\\times 1.20 X$ = 1.5 X
\nTherefore, we can say that the Ramesh should mark-up the price by 50%.
\nHence, option A is the correct answer.<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the number of students initially be \u2018n\u2019 and the average weight initially be \u2018x\u2019.
\nIt has been given that (nx + 39)\/(n+1) = (x+1)
\nnx + 39 = (n+1)(x+1)
\nnx + 39 = nx + n + x + 1
\n=> n + x = 38 ————–(1)<\/p>\n

It has been given that n = x
\n=> n = x = 19
\nTherefore, option C is the right answer.<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the first number of the 13 consecutive numbers be x.
\nSo sum of the 13 consecutive numbers = 13x + (1+2+3+\u2026+12) = 13x + 78
\nAverage of these 13 numbers, A = $\\frac{13x+78}{13} = x+6$
\nSum of the 13+5 = 18 consecutive numbers starting from x = 18x + (1+2+3+\u2026+17) = 18x + 153
\nAverage of these 18 numbers = $\\frac{18x+153}{18} = x+8.5$
\nIncrease in the average x + 8. 5 – x – 6 = 2.5
\nHence, A is the right choice.<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Volume of the sphere of 20 cm radius = $\\dfrac{4\\pi}{3}\\times 20^3$ = $\\dfrac{32000\\pi}{3}$
\nVolume of right-circular cone whose height is 20cm and radius of circular base is 15 cm.= $\\dfrac{\\pi}{3}\\times 25^2*60$ = $12500\\pi$
\nHence, we can say that Quantity 1 < Quantity 2. Option C is the correct answer.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Area of equilateral triangle with side equals to 30cm = $\\dfrac{\\sqrt{3}}{4}\\times 32^2$ = 443.40 sq.cm
\nArea of square with side equals to 20cm = 20^2 = 400 sq. cm
\nHence, we can say that Quantity 1 > Quantity 2. Option A is the correct answer.<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The cuboids formed by 2 perpendicular cuts will be of side 10cm, 10cm, 20cm.
\nSurface area of 1 cuboid = 2*(10 * 10 + 20 *10 + 10 * 20) = 1000 sq cm
\nTotal surface are that is to be painted = 4 * 1000 = 4000 sq cm
\nTotal cost incurred for painting these 4 cuboids = 4000 * 3 = 12000<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

18 = $2*3^2$
\n32 = $2^5$
\nHence LCM = $2^5*3^2 = 288$<\/p>\n

1800 = $2^3*3^2*5^2$
\n720 = $2^4*3^2*5$
\nHence the HCF is 8*9*5 = 360
\nThus Quantity 2 > Quantity 1.
\nHence the correct answer is option B.<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Red light-> 45 seconds
\nBlue light -> 1.25 minutes = 75 seconds.
\nGreen light -> 2.25 minutes = 135 seconds.
\nNow, they will blink together after LCM (45, 75, 135) seconds = 675 seconds = 11 minutes 15 seconds. So, C is the correct answer.<\/p>\n

13)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Here, the difference between any of the divisors and their remainders is the same i.e., 9.
\nTherefore the required number = (LCM of 23, 34, 41)-9 = 32053.
\nSince there is no such option, the correct answer to choose is E.<\/p>\n

14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let \u2018x\u2019 be the total number of coins on the table.
\nSince after turning 2 coins the ratio of coins showing heads increases, both the coins previously must be tails.
\nWe have,
\n$\\frac{x}{3} + 2 = \\frac{x}{2}$
\nx = 12
\nHence, option E is the right choice.<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the cost of a pen be x, cost of a pencil be y and the cost of an eraser be z.
\n10x + 12y + 14z = 76 -> (1)
\n2x + 3y + 4z = 20 -> (2)
\n5x + 3y + 3z = 20 -> (3)<\/p>\n

(1) – 4*(2) gives 10x + 12y + 14z – 8x – 12y – 16z = 76 – 80
\n=> 2x – 2z = -4 => x – z = -2<\/p>\n

(2) – (3) gives -3x + z = 0 => z = 3x
\nSo, x – 3x = -2 => x = 1<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Maths\u00a0 Questions Set-2 for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Maths Questions for RRB Group-D Set 2 PDF Download Top-15 RRB Group-D Maths Questions set-2 PDF.\u00a0RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0Find the approximate value of\u00a0 $\\sqrt[3]{10645}\\div\\sqrt{249}\\times\\sqrt{4084}\\div\\sqrt[3]{1328}\\div\\sqrt[6]{26}$ a)\u00a06 […]<\/p>\n","protected":false},"author":41,"featured_media":30432,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679,1601],"tags":[489,491,1819,2052,1647],"class_list":{"0":"post-30410","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"category-rrb-ntpc-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-group-d-exam","15":"tag-rrb-maths","16":"tag-rrb-mocks"},"better_featured_image":{"id":30432,"alt_text":"Maths Questions for RRB Group-D Set 2 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