{"id":30324,"date":"2019-06-13T12:43:46","date_gmt":"2019-06-13T07:13:46","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=30324"},"modified":"2019-06-13T12:43:46","modified_gmt":"2019-06-13T07:13:46","slug":"rrb-ntpc-expected-maths-questions-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-ntpc-expected-maths-questions-set-2-pdf\/","title":{"rendered":"RRB NTPC Expected Maths Questions Set-2 PDF"},"content":{"rendered":"<h2><span style=\"text-decoration: underline;\"><strong>RRB NTPC Expected Maths Questions 2019 Set-2 PDF<\/strong><\/span><\/h2>\n<p>Download RRB NTPC Expected Maths Questions and Answers 2019 Set-2 PDF. Top 15 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/4859\" target=\"_blank\" class=\"btn btn-danger  download\">Download RRB NTPC EXpected Maths Questions Set-2 PDF<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p>Take a <a href=\"https:\/\/cracku.in\/rrb-ntpc-mock-test\" target=\"_blank\" rel=\"noopener\">free mock test for RRB NTPC<\/a><\/p>\n<p>Download <a href=\"https:\/\/cracku.in\/railways-ntpc-previous-papers\" target=\"_blank\" rel=\"noopener\">RRB NTPC Previous Papers PDF<\/a><\/p>\n<p><b>Question 1:\u00a0<\/b>If tan(\u03b8\/2) = 5\/12, then find sin\u03b8 = ?<\/p>\n<p>a)\u00a05\/13<\/p>\n<p>b)\u00a0119\/120<\/p>\n<p>c)\u00a0120\/169<\/p>\n<p>d)\u00a012\/13<\/p>\n<p><b>Question 2:\u00a0<\/b>$1\/sinA &#8211; SinA\/Cos^2A$ = ?<\/p>\n<p>a)\u00a0$2Cot2A.secA$<\/p>\n<p>b)\u00a0$2Cos2A.cosecA$<\/p>\n<p>c)\u00a0$2Cos2A.secA$<\/p>\n<p>d)\u00a0$2Cot2A.cosecA$<\/p>\n<p><b>Question 3:\u00a0<\/b>$a^{2}-10a+16$=0 and $b^{2}-14b+48$=0, compare the values of a and b.<\/p>\n<p>a)\u00a0$ a&gt;b $<\/p>\n<p>b)\u00a0$ a&lt;b $<\/p>\n<p>c)\u00a0$a \\leq b$<\/p>\n<p>d)\u00a0$a \\geq b$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/railways-ntpc-previous-papers\" target=\"_blank\" class=\"btn btn-primary \">RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/www.youtube.com\/channel\/UCMDJPaiDdRPv2mrEJoLfklA?sub_confirmation=1\" target=\"_blank\" class=\"btn btn-warning \">FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n<p><b>Question 4:\u00a0<\/b>A two digit number when reverse decreases its value by 27 and the sum of the digits of the number is 7.Fin the value of the number.<\/p>\n<p>a)\u00a034<\/p>\n<p>b)\u00a016<\/p>\n<p>c)\u00a052<\/p>\n<p>d)\u00a043<\/p>\n<p><b>Question 5:\u00a0<\/b>M is as much younger than N as he is older than O. If the sum of the ages of N and O is 48 years, then find the age of M.<\/p>\n<p>a)\u00a020 years<\/p>\n<p>b)\u00a012 years<\/p>\n<p>c)\u00a024 years<\/p>\n<p>d)\u00a016 years<\/p>\n<p><b>Question 6:\u00a0<\/b>Two containers of equal volume contain milk and water in the ratio 3 : 2 and 5 : 3 respectively. If they are mixed together, find the new ratio.<\/p>\n<p>a)\u00a05 : 2<\/p>\n<p>b)\u00a025 : 4<\/p>\n<p>c)\u00a016 : 9<\/p>\n<p>d)\u00a049 : 31<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-ntpc-mock-test\" target=\"_blank\" class=\"btn btn-danger \">RRB NTPC Free Mock Test<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 7:\u00a0<\/b>$\\sqrt{\\sqrt{\\sqrt{\\sqrt{65536}}}}$<\/p>\n<p>a)\u00a02<\/p>\n<p>b)\u00a03<\/p>\n<p>c)\u00a04<\/p>\n<p>d)\u00a05<\/p>\n<p><b>Question 8:\u00a0<\/b>$2\\sqrt{48}-4\\sqrt{12}+3\\sqrt{3} = ?$<\/p>\n<p>a)\u00a00<\/p>\n<p>b)\u00a0$\\sqrt{3}$<\/p>\n<p>c)\u00a0$3\\sqrt{3}$<\/p>\n<p>d)\u00a0$2\\sqrt{3}$<\/p>\n<p><b>Question 9:\u00a0<\/b>20% of 30% of 400% of 50% of 60 = ?<\/p>\n<p>a)\u00a08.4<\/p>\n<p>b)\u00a07.2<\/p>\n<p>c)\u00a06.8<\/p>\n<p>d)\u00a08.2<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/blog\/general-science-questions-answers-competitive-exams-pdf-mcq-quiz\/\" target=\"_blank\" class=\"btn btn-info \">Download General Science Notes PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-je-mock-test\" target=\"_blank\" class=\"btn btn-primary \">RRB JE Free Mock Test<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 10:\u00a0<\/b>If circumference of a circle is increased by 10%, the area of the circle will increase by<\/p>\n<p>a)\u00a05%<\/p>\n<p>b)\u00a010%<\/p>\n<p>c)\u00a020%<\/p>\n<p>d)\u00a021%<\/p>\n<p><b>Question 11:\u00a0<\/b>In an examination, a student gets 20% of total marks and fails by 30 marks. Another student gets 32% of total marks which is more than the minimum pass marks by 42 marks. The pass percentage is<\/p>\n<p>a)\u00a024%<\/p>\n<p>b)\u00a025%<\/p>\n<p>c)\u00a026%<\/p>\n<p>d)\u00a028%<\/p>\n<p><b>Question 12:\u00a0<\/b>The ratio of present ages of Ratna and Shantanu is 5:4. After 19 years the ratio of their ages will be 10:9. What is Ratna&#8217;s present age?<\/p>\n<p>a)\u00a019<\/p>\n<p>b)\u00a015<\/p>\n<p>c)\u00a09<\/p>\n<p>d)\u00a072<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-online-test\" target=\"_blank\" class=\"btn btn-danger \"> Daily Free RRB Online Tests for RRB Exams<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-ntpc-mock-test\" target=\"_blank\" class=\"btn btn-primary \">RRB NTPC Free Mock Test<\/a><\/p>\n<p><b>Question 13:\u00a0<\/b>If 42 persons consume 144 kg, of wheat in 15 days, then in how many days will 30 persons consume 48 kg of wheat ?<\/p>\n<p>a)\u00a08 days<\/p>\n<p>b)\u00a07 days<\/p>\n<p>c)\u00a012 days<\/p>\n<p>d)\u00a06 days<\/p>\n<p><b>Question 14:\u00a0<\/b>Instead of dividing 391 cookies among 3 children A, B, C in the ratio\u00a0$\\frac{1}{5}:\\frac{1}{4}:\\frac{1}{8}$, it was divided in to the ratio 5: 4: 8. Who gains the most and how many ?<\/p>\n<p>a)\u00a0A, 21 cookies<\/p>\n<p>b)\u00a0B, 78 cookies<\/p>\n<p>c)\u00a0C, 99 cookies<\/p>\n<p>d)\u00a0C, 78 cookies<\/p>\n<p><b>Question 15:\u00a0<\/b>In a circle of radius 30 cm, two parallel chords were drawn which are separated by a distance of 42 cm and length of one of the chord is 48 cm. What is the length of other chord ?<\/p>\n<p>a)\u00a036 cm<\/p>\n<p>b)\u00a048 cm<\/p>\n<p>c)\u00a032 cm<\/p>\n<p>d)\u00a040 cm<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-je-previous-papers\" target=\"_blank\" class=\"btn btn-warning \">Download Current Affairs Questions &amp; Answers PDF<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$Sin\u03b8$ = $\\frac{2tan(\u03b8\/2)}{1+tan^2(\u03b8\/2)}$ = $\\frac{2(5\/12)}{1+(5\/12)^2}$ = $120\/169$<\/p>\n<p>So the answer is option C.<\/p>\n<p><strong>2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$1\/sinA &#8211; SinA\/Cos^2A$<br \/>\n= $(cos^2A-sin^2A)\/(sinA.cos^2A)$<br \/>\n= $2(Cos2A)\/(sin2A.CosA)$<br \/>\n= $2Cot2A.secA$<br \/>\nSo the answer is option A.<\/p>\n<p><strong>3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>$a^{2}-10a+25$=0<br \/>\n$a^{2}-5a-5a+25$=0<br \/>\n$a(a-5)-5(a-5)$=0<br \/>\n$(a-5)(a-5)$=0<br \/>\n$a$=5 and $a$=5<br \/>\n$b^{2}-14b+48$=0<br \/>\n$b^{2}-8b-6b+48$=0<br \/>\n$b(b-8)-6(b-8)$=0<br \/>\n$(b-8)(b-6)$=0<br \/>\n$b$=8 and $b$=6<br \/>\nTherefore\u00a0$ a&lt;b $<br \/>\nHence, option B is the correct answer.<\/p>\n<p><strong>4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>let the number be yx<br \/>\nGiven x+y=7<br \/>\n10y+x-(10x+y)=27<br \/>\n9(y-x)=27<br \/>\ny-x=3<br \/>\n2y=10<br \/>\ny=5<br \/>\nx=2<br \/>\nRequired number is 52<br \/>\nHence, option C is the correct answer.<\/p>\n<p><strong>5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Given that difference between the ages of M and N is equal to the difference between the ages of N and O.<br \/>\nN &#8211; M = M &#8211; O<br \/>\n\u21d2 2M = N+O<br \/>\nGiven, N+O = 48 years<br \/>\nThen, 2M = 48 \u21d2 M = 24 years<br \/>\nTherefore, The age of M = 24 years.<\/p>\n<p><strong>6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Let the total quantity of the mixture be x litres.<br \/>\nGiven that both the containers have same volume.<br \/>\nHence, Volume of container 1 = Volume of container 2 = x litres.<br \/>\nQuantity of milk in container 1 = $\\dfrac{3}{5}x$ litres<br \/>\nQuantity of water in container 1 = $\\dfrac{2}{4}x$ litres<\/p>\n<p>Quantity of milk in container 2 = $\\dfrac{5}{8}x$ litres<br \/>\nQuantity of water in container 2 = $\\dfrac{3}{8}x$ litres<\/p>\n<p>Quantity of milk in new container = $\\dfrac{3}{5}x + \\dfrac{5}{8}x = \\dfrac{49x}{40}$ litres<br \/>\nQuantity of water in new container = $\\dfrac{2}{5}x + \\dfrac{3}{8}x = \\dfrac{31x}{40}$ litres<\/p>\n<p>Required ratio = $\\dfrac{49x}{40} : \\dfrac{31x}{40} = 49 : 31$<\/p>\n<p><strong>7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$\\sqrt{\\sqrt{\\sqrt{\\sqrt{65536}}}}$ = $\\sqrt{\\sqrt{\\sqrt{256}}}$ = $\\sqrt{\\sqrt{16}}$ = $\\sqrt{4} = 2$<\/p>\n<p>So the answer is option A.<\/p>\n<p><strong>8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$2\\sqrt{48}-4\\sqrt{12}+3\\sqrt{3}$ = $2(4\\sqrt3)-4(2\\sqrt3)+3\\sqrt3 = 8\\sqrt3-8\\sqrt3+3\\sqrt3 = 3\\sqrt3$<\/p>\n<p>So the answer is option C.<\/p>\n<p><strong>9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>$(0.2)(0.3)(4)(0.5)(60) = (0.2)(0.3)(120) = (0.06)(120) = 7.2$<\/p>\n<p>So the answer is option B.<\/p>\n<p><strong>10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Circumference of a circle is 2$ \\pi$ r<\/p>\n<p>So, if the circumference increases by 10%, the radius also increases by 10%<\/p>\n<p>area of the circle = $ \\pi r ^ {2}$<\/p>\n<p>If radius becomes 1.1r, area increases by $1.1 ^ {2}$ = 1.21<\/p>\n<p><strong>11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Let the total marks be x<\/p>\n<p>and pass marks be z<\/p>\n<p>So, x * 20% = z &#8211; 30<\/p>\n<p>x * 32% = z + 42<\/p>\n<p>Implies, x * 12% = 72 or x = 600<\/p>\n<p>z = 150<\/p>\n<p>The required ratio = 150\/600 = 25%<\/p>\n<p><strong>12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>Let Ratna&#8217;s present age = $5x$ years and Shantanu&#8217;s present age = $4x$ years<\/p>\n<p>According to ques, =&gt; $\\frac{5x + 19}{4x + 19} = \\frac{10}{9}$<\/p>\n<p>=&gt; $45x + 171 = 40x + 190$<\/p>\n<p>=&gt; $45x &#8211; 40x = 190 &#8211; 171$<\/p>\n<p>=&gt; $5x = 19$<\/p>\n<p>=&gt; $x = \\frac{19}{5}$<\/p>\n<p>$\\therefore$ Ratna&#8217;s age = $5 \\times \\frac{19}{5} = 19$ years<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Using, $\\frac{M_1D_1}{W_1}$\u00a0$=\\frac{M_2D_2}{W_2}$, where $M$ is number of men, $D$ is number of days and $W$ is work done.<\/p>\n<p>Let in $x$ days,\u00a030 persons will consume 48 kg of wheat.<\/p>\n<p>According to ques,<\/p>\n<p>=&gt; $\\frac{42\\times15}{144}=\\frac{30\\times x}{48}$<\/p>\n<p>=&gt; $\\frac{7\\times5}{8}=\\frac{5x}{8}$<\/p>\n<p>=&gt; $x=7$<\/p>\n<p>$\\therefore$\u00a030 persons will consume 48 kg of wheat in <strong>7 days<\/strong>.<\/p>\n<p>=&gt; Ans &#8211; (B)<\/p>\n<p><strong>14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Case\u00a0I = A : B : C =\u00a0$\\frac{1}{5}:\\frac{1}{4}:\\frac{1}{8}$<\/p>\n<p>L.C.M. (5,4,8) = 40<\/p>\n<p>=\u00a0$\\frac{40}{5}:\\frac{40}{4}:\\frac{40}{8}=8:10:5$<\/p>\n<p>Sum of terms of ratio = $8+10+5=23$<\/p>\n<p>Case II = A : B : C = $5:4:8$<\/p>\n<p>Sum of term of ratio = $5+4+8=17$<\/p>\n<p>Clearly, only C gains by = $(\\frac{8}{17}-\\frac{5}{23})\\times391$<\/p>\n<p>= $\\frac{184-85}{391}\\times391=99$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/209608.png\" data-image=\"209608.png\" \/><\/figure>\n<p>let the two chords be AB and CD<br \/>\nMidpoints of AB and CD be X and Y<br \/>\nFrom the figure we have $OC^{2}$=$OY^{2}+YC^{2}$<br \/>\n$30^{2}$=$OY^{2}+24^{2}$<br \/>\n$OY^{2}$=54*6<br \/>\nOY=18 cm<br \/>\nGiven XY=42<br \/>\nXO+OY=42<br \/>\nXO=42-18<br \/>\nXO=24<br \/>\nFrom the figure we have $OA^{2}$=$OX^{2}+XA^{2}$<br \/>\n900=576+$XA^{2}$<br \/>\n$XA^{2}$=324<br \/>\nXA=18 cm<br \/>\nAB=2 AX<br \/>\nAB=36 cm<\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_US\" target=\"_blank\" class=\"btn btn-danger \">DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n<p>We hope this Expected Maths Set-2 Questions for RRB NTPC Exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>RRB NTPC Expected Maths Questions 2019 Set-2 PDF Download RRB NTPC Expected Maths Questions and Answers 2019 Set-2 PDF. Top 15 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Take a free mock test for RRB NTPC Download RRB NTPC Previous Papers PDF Question [&hellip;]<\/p>\n","protected":false},"author":41,"featured_media":30327,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603,1601],"tags":[491,1637,1647,1619],"class_list":{"0":"post-30324","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"category-rrb-ntpc-je","12":"tag-rrb","13":"tag-rrb-exam","14":"tag-rrb-mocks","15":"tag-rrb-ntpc-2019"},"better_featured_image":{"id":30327,"alt_text":"Mathematics Questions for RRB NTPC SET-3 PDF","caption":"Mathematics Questions for RRB  NTPC SET-3 PDF","description":"Mathematics Questions for RRB  NTPC SET-3 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