790+ Mocks – Just Rs. 194. Use coupon: SBIDREAM70<\/a><\/p>\n Question 1:\u00a0<\/b>In 8 years, Ramesh will be twice as old as Farheen was 8 years ago. If Ramesh is now 16 years older than Farheen, the present age of Farheen is :<\/p>\n a)\u00a032<\/p>\n b)\u00a040<\/p>\n c)\u00a036<\/p>\n d)\u00a044<\/p>\n e)\u00a024<\/p>\n Question 2:\u00a0<\/b>Find the approximate value of $\\Large\\frac{169.87^{2}-13.94^{2}}{183.87}$ $\\large+$ $\\Large\\frac{3211.96}{44.002}$<\/p>\n a)\u00a0224<\/p>\n b)\u00a0236<\/p>\n c)\u00a0239<\/p>\n d)\u00a0229<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>The average marks of a class increased by $\\large\\frac{1}{3}$ when a student\u2019s marks were wrongly entered as 64 instead of 46. The number of students in the class are<\/p>\n a)\u00a054<\/p>\n b)\u00a058<\/p>\n c)\u00a063<\/p>\n d)\u00a057<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n Select the correct option.<\/p>\n Question 4:\u00a0<\/b>Quantity 1:A number is increased by 85% and then it is decreased by 15% and result is approximately 357 a)\u00a0Quantity 1 $\\leq$Quantity 2<\/p>\n b)\u00a0Quantity 1 $\\geq$Quantity 2<\/p>\n c)\u00a0Quantity 1 < Quantity 2<\/p>\n d)\u00a0Quantity 1 > Quantity 2<\/p>\n e)\u00a0Quantity 1 = Quantity 2<\/p>\n Instructions<\/b><\/p>\n The following table shows the breakup of the marks scored by students of Class X of Sharda Mandir in Maths for 5 years from 2001-2005.<\/p>\n Note: A student can score a maximum of 100 marks.<\/p>\n Question 5:\u00a0<\/b>The students scoring below 40 are said to have failed the exam whereas the students scoring in between are 60-90 said to have passed the exam with distinction. a)\u00a0420:313<\/p>\n b)\u00a0417:305<\/p>\n c)\u00a0323:251<\/p>\n d)\u00a04:3<\/p>\n e)\u00a05:4<\/p>\n Take a Free Mock test for SBI PO<\/a><\/p>\n SBI PO Solved Previous Papers PDF<\/a><\/p>\n Instructions<\/b><\/p>\n Each of the question given below is followed by three statements. You have to study the questions and all the three statements given to decide whether any information provided in the statement\/s is\/are redundant and can be dispensed with while answering the given questions.<\/p>\n Question 6:\u00a0<\/b>What is the maximum marks that can be obtained in the examination?<\/p>\n I: Ravi secured 35% of the maximum marks and failed by 7 marks. III: Soham secured 82 marks which was 5 marks more than the passing marks.<\/p>\n a)\u00a0Only I<\/p>\n b)\u00a0Both II and III<\/p>\n c)\u00a0Both I and II<\/p>\n d)\u00a0Only II<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/strong><\/p>\n Question 7:\u00a0<\/b>Quantity 1: Volume of a sphere of 20 cm radius. a)\u00a0Quantity 1 > Quantity 2<\/p>\n b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n c)\u00a0Quantity 1 < Quantity 2<\/p>\n d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n e)\u00a0Quantity 1 = Quantity 2<\/p>\n Question 8:\u00a0<\/b>A shopkeeper wants to buy a rod of certain length such that he can measure 140 cm, 420 cm and 280 cm precisely. What is the maximum possible length of the rod that the shopkeeper can buy?<\/p>\n a)\u00a070 cm<\/p>\n b)\u00a0140 cm<\/p>\n c)\u00a035 cm<\/p>\n d)\u00a07 cm<\/p>\n e)\u00a020 cm<\/p>\n Instructions<\/b><\/p>\n Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/strong><\/p>\n Question 9:\u00a0<\/b>Quantity 1: Simple interest charged by a bank on a sum of Rs. 1000 at the rate of 22% annum for 2 years. a)\u00a0Quantity 1 > Quantity 2<\/p>\n b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n c)\u00a0Quantity 1 < Quantity 2<\/p>\n d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n e)\u00a0Quantity 1 = Quantity 2<\/p>\n Question 10:\u00a0<\/b>Three friends, A, B and C invested Rs. 10000 each to start a company. A withdrew his whole invested amount after 4 months. B withdrew half of the invested amount after 6 months. If C got Rs. 1200 as his share of profit after one year, what was A’s share in the profit?<\/p>\n a)\u00a0Rs. 600<\/p>\n b)\u00a0Rs. 400<\/p>\n c)\u00a0Rs. 1000<\/p>\n d)\u00a0Rs. 500<\/p>\n e)\u00a0Rs. 800<\/p>\n Banking Study Material – 18000 Questions<\/a><\/p>\n Daily Free SBI Online Tests<\/a><\/p>\n Question 11:\u00a0<\/b>5 bottles of apple juice and 9 bottles of mango juice together fill 71 glasses. Also, 7 bottles of apple juice and 11 bottles of mango juice together fill 93 glasses. How many glasses can be filled with 3 bottles of apple juice and 4 bottles of mango juice if each bottle of either of the juices fills an integer number of glasses?<\/p>\n a)\u00a037<\/p>\n b)\u00a041<\/p>\n c)\u00a034<\/p>\n d)\u00a045<\/p>\n e)\u00a032<\/p>\n Question 12:\u00a0<\/b>A, B and C can do a piece of work in 20, 25 and 40 days. They started the work together but B left 4 days before completion. In how many days the work is completed?<\/p>\n a)\u00a013$\\large\\frac{4}{23}$ days<\/p>\n b)\u00a010$\\large\\frac{2}{23}$\u00a0days<\/p>\n c)\u00a012$\\large\\frac{3}{17}$\u00a0days<\/p>\n d)\u00a014$\\large\\frac{5}{17}$\u00a0days<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n One of the numbers in the given series is incorrect. Find the incorrect number in the series<\/p>\n Question 13:\u00a0<\/b>7, 33, 137, 553, 2217, 8871<\/p>\n a)\u00a033<\/p>\n b)\u00a0137<\/p>\n c)\u00a0553<\/p>\n d)\u00a08871<\/p>\n e)\u00a02217<\/p>\n Question 14:\u00a0<\/b>Ravi rolled a dice twice. What is the probability that sum of both the outcome is less than 5?<\/p>\n a)\u00a01\/6<\/p>\n b)\u00a01\/4<\/p>\n c)\u00a01\/3<\/p>\n d)\u00a01\/2<\/p>\n e)\u00a0None of the above.<\/p>\n Question 15:\u00a0<\/b>To meet the demand during summer, a milkman mixed water with pure milk in 2:5. Then he sold the same mixture at 20% more than normal price. By what percent his revenue will increase during summers? (Water is available without any cost)<\/p>\n a)\u00a060 percent<\/p>\n b)\u00a050 percent<\/p>\n c)\u00a040 percent<\/p>\n d)\u00a068 percent<\/p>\n e)\u00a063 percent<\/p>\n Instructions<\/b><\/p>\n In the following questions 2 quantities X and Y are given. Select the option which best captures the relations between X and Y.<\/p>\n Question 16:\u00a0<\/b>3 dices are thrown. a)\u00a0X>Y<\/p>\n b)\u00a0X<Y<\/p>\n c)\u00a0X$\\geq$Y<\/p>\n d)\u00a0X$\\leq$Y<\/p>\n e)\u00a0X=Y or Cannot be determined<\/p>\n Question 17:\u00a0<\/b>Ram purchased three variety of barley at Rs. 100 per kg, Rs. 140 per kg and Rs. 180 per kg respectively. In what ratio he should mix these three varieties in that order so that the average cost of the mixture is Rs. 150 per kg?<\/p>\n a)\u00a02 : 4 : 7<\/p>\n b)\u00a01 : 5 : 10<\/p>\n c)\u00a01 : 2 : 3<\/p>\n d)\u00a02 : 5 : 5<\/p>\n e)\u00a0None of the above<\/p>\n Question 18:\u00a0<\/b>Ram takes 30 minutes to reach office from home by car. One day, due to heavy traffic he drove his car at (4\/5)th of original speed for (1\/3)rd of total distance and remaining distance at (2\/5)th of the original speed. Find out the time taken by Ram on that day?<\/p>\n a)\u00a060 minutes<\/p>\n b)\u00a075 minutes<\/p>\n c)\u00a065 minutes<\/p>\n d)\u00a067.5 minutes<\/p>\n e)\u00a062.5 minutes<\/p>\n Instructions<\/b><\/p>\n In each of the following questions a question is asked followed by three statements.You have to study the questions and all the given three statements and all the statements and decide whether any information provided in the statement are redundant and can be dispensed with while answering the questions ?<\/p>\n Question 19:\u00a0<\/b>What will be the cost of the painting the four walls of a room with length ,width and height is 5,3,8 meters respectively. The room has one window and one door. a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III only<\/p>\n d)\u00a0II or III only<\/p>\n e)\u00a0All are required to answer the question<\/p>\n Instructions<\/b><\/p>\n There are 450 students in a college. Each student has to choose one or more elective out of management, history and physics. Further following information is also known – Question 20:\u00a0<\/b>How many students selected both management and physics as elective?<\/p>\n a)\u00a084<\/p>\n b)\u00a0107<\/p>\n c)\u00a075<\/p>\n d)\u00a089<\/p>\n e)\u00a098<\/p>\n 200+ Free GK Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us assume the present age of Farheen = x years Ramesh\u2019s age after 8 years will be = x+16+8 = x+24 years $\\Rightarrow$ x+24 = 2*(x-8) So the present age of Farheen will be 40 years.<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $\\Large\\frac{169.87^{2}-13.94^{2}}{183.87}$ $\\large+$ $\\Large\\frac{3211.96}{44.002}\\simeq \\frac{170^{2}-14^{2}}{184}$ $\\large+$ $\\Large\\frac{3212}{44}$<\/p>\n $= \\Large\\frac{(170+14)(170-14)}{184}$ $+$ $73$<\/p>\n $= \\Large\\frac{184\\times156}{184}$ $+$ $73$<\/p>\n $= 156+73 = 229$<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the number of students be ‘x’<\/p>\n Given that the average is increased by $\\Large\\frac{1}{3}$ due to the increase of $18$ marks ( $64$ $-$ $46$ $=$ $18$ marks )<\/p>\n Actual increase in marks $=$ $\\Large\\frac{1}{3}$ $\\times$ x<\/p>\n $\\Rightarrow$ $\\Large\\frac{1}{3}$ $\\times$ x $=$ $18$<\/p>\n $\\therefore$ Number of students(x) $=$ $54$<\/p>\n 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In Q1 we have x*1.85*0.85=357 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20 Thus, the required ratio = 2085:1525 = 417:305 General Knowledge Questions & Answers PDF<\/a><\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n let the maximum marks be \u2018x\u2019.<\/p>\n Ravi = 0.35x<\/p>\n passing marks = 0.35x + 7<\/p>\n Passing marks is also equal to 82 – 5 = 77 marks<\/p>\n Thus, 0.35x + 7 = 77<\/p>\n x = 200<\/p>\n Thus statements I and III both are required to answer the question.<\/p>\n Using statement II alone or with any other statement we cannot find the answer.<\/p>\n Hence, option D is right answer.<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Volume of the sphere of 20 cm radius = $\\dfrac{4\\pi}{3}\\times 20^3$ = $\\dfrac{32000\\pi}{3}$ 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The lengths 140 cm, 280 cm and 420 cm should be the multiples of the length of the rod. The maximum possible length of the rod will be equal to the HCF of these 3 numbers.<\/p>\n 140 = 2*70 As we can see, the HCF is 2*70 = 140 cm. 9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Simple interest paid to bank = 1000*.22*2 = Rs. 440 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Monthly average of A = $\\dfrac{10000 * 4}{12}$ = Rs. $\\dfrac{10000}{3}$<\/p>\n Monthly average of C = $\\dfrac{10000 * 12}{12}$ Rs. 10000<\/p>\n So, monthly average of A is $\\frac{1}{3}$ of the monthly average of C<\/p>\n So, A’s profit = $\\frac{1}{3}$ of C’s profit = Rs. 400<\/p>\n Hence, option B is the correct answer.<\/p>\n 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let 1 bottle of apple juice fill \u2018a\u2019 glasses and 1 bottle of mango juice fill \u2018m\u2019 glasses. 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n A can do the work in 20 days<\/p>\n B can do the work in 25 days<\/p>\n C can do the work in 40 days<\/p>\n Total work = LCM of 20,25,40 $=$ 200 units<\/p>\n Efficiency of A $=$ $\\Large\\frac{200}{20}$ $=$ 10 units\/day<\/p>\n Efficiency of B $=$ $\\Large\\frac{200}{25}$ $=$ 8 units\/day<\/p>\n Efficiency of C $=$ $\\Large\\frac{200}{40}$ $=$ 5 units\/day<\/p>\n Let the number of days required to complete the work be \u2018X\u2019 days<\/p>\n Total work done by A in X days $=$ 10 $\\times$ X $=$ 10X units<\/p>\n Total work done by C in X days $=$ 5 \\times X $=$ 5X days<\/p>\n B left 4 days before completion<\/p>\n Total work done by B in (X – 4) days $=$ 8(X – 4) $=$ (8X – 32) units<\/p>\n $\\therefore$ 10X + 5X + 8X – 32 $=$ 200<\/p>\n 23X – 32 $=$ 200<\/p>\n $\\therefore$ X $=$ $\\Large\\frac{232}{23}$ $=$ 10$\\Large\\frac{2}{23}$ days<\/p>\n 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 7*4+5 = 28+5 = 33 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n When a dice is rolled we get outcome from (1,2,3,4,5,6) so favourable cases (Sum = 2,3,4) 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let us assume that on a normal day he sells milk at x rupee per litre and he sells y litre of milk He mixed water with milk in ratio of 2:5 so net quantity = $\\frac{2+5}{5} * y$ = 1.4y So revenue generated in summers = 1.4y * 1.2x = 1.68xy 16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n 7 = 1 + 1 + 5 = 2 + 2 + 3 = 3 + 3 + 1 = 1 + 2 + 4 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let us check the options. 18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the distance between Ram\u2019s office and home = 150d Distance that Ram covered at (1\/3)rd of original distance = $\\frac{150d}{3}$ = 50d Remaining distance = 150d – 50d = 100d Hence total time taken by Ram = 12.5 + 50 = 62.5 minutes<\/p>\n 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Length = 5 m , Breadth = 3 m and Height = 8 m<\/p>\n To find the cost of painting the walls of the room, we should know the cost of painting and the area of door and window.<\/p>\n Area of 4 walls (Curved Surface Area of cuboid) = $2h(l+b)$<\/p>\n = $(2 \\times 8)(5+3) = 16 \\times 8 = 128$ $m^2$<\/p>\n From I & II : Cost = Rs 25 per square meter<\/p>\n Area of window = $2.25$ $m^2$<\/p>\n and Area of door = $2 \\times 2.25 = 4.5$ $m^2$<\/p>\n Thus, area to be painted = $128 – 2.25 – 4.5 = 121.25$ $m^2$<\/p>\n $\\therefore$ Cost of painting 4 walls = $25 \\times 121.25 = Rs$ $3031.25$<\/p>\n Thus, statement III is redundant.<\/p>\n => Ans – (C)<\/p>\n 20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let \u2018x\u2019 be the number of students who took all the three electives and \u2018y\u2019 be the number of students who took only management as an elective. Considering students who took management as an elective we have,<\/p>\n y + x + 84 + 75 = 238<\/p>\n x + y = 79<\/p>\n Considering students who took history as an elective we have,<\/p>\n 137 – y + x + 84 + 52 = 240<\/p>\n y – x = 33<\/p>\n Adding both the equation we get,<\/p>\n 2y = 112<\/p>\n y = 56<\/p>\n So, x = 23<\/p>\n So, number of students who took all the three electives = 23<\/p>\n Number of students who took only management = 56<\/p>\n Number of students who took only history = 137 – 56 = 81<\/p>\n So, the number of students who took only physics = 450 – 240 – 56 – 75 = 79<\/p>\n Thus, we get following venn diagram –<\/p>\n Number of students who selected both management and physics as elective = 75 + 23 = 98 Banking 1 Year Plan – 350 Mocks for just Rs. 499<\/a><\/p>\n
\nQuantity 2:A number is increased by 82% and then it is decreased by 12% and the result is approximately 355.5<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/di-2409-1-1.PNG\")
<\/figure>\n
\nWhat is the ratio of the number of students that failed and the number of students that got distinction during the given period?<\/p>\n
\nII: The difference between marks scored by Ravi and Soham is 12 marks.<\/p>\n
\nQuantity 2: Volume of a right circular cone whose height is 60cm and radius of the circular base is 25 cm.<\/p>\n
\nQuantity 2: Compound interest charged by another bank on a sum of Rs. 1000 at the rate of 20% annum for 2 years compounded annually.<\/p>\n
\nX is the probability that sum of the number on the faces of the dice is 7.
\nY is the probability that sum of the number on the faces of the dice is 14.<\/p>\n
\nI.Cost of painting per square meter is Rs 25
\nII.Area of window is 2.25 sq m which is half of the area of the door
\nIII.Area of the room is 15 sq meter<\/p>\n
\n1) 75 students selected only management and physics.
\n2) 84 students selected only management and history.
\n3) 52 students selected only physics and history.
\n4) The number of students who selected only history is 137 less the number of students who selected only management.
\n5) In total 238 students selected management as an elective.
\n6) In total 240 students selected history as an elective.<\/p>\n
\nSo present age of Ramesh will be = x + 16 years<\/p>\n
\nFarheen\u2019s age 8 years ago = x – 8 years<\/p>\n
\n$\\Rightarrow$ x= 40 years<\/p>\n
\nx=357\/(1.85*0.85)
\nx=227
\nIn Q2 we have x*1.82*0.88=355.5
\nx=355.5\/(1.82*0.88)
\nx=220
\nTherefore Q1>Q2<\/p>\n
\nNumber of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
\nNumber of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
\nNumber of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
\nNumber of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
\nNumber of students scoring in between 90-100 = Number of students scoring above 90<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/di-2409-1-2.PNG\")
<\/figure>\n
\nHence, option B is the correct answer.<\/p>\n
\nVolume of right-circular cone whose height is 20cm and radius of circular base is 15 cm.= $\\dfrac{\\pi}{3}\\times 25^2*60$ = $12500\\pi$
\nHence, we can say that Quantity 1 < Quantity 2. Option C is the correct answer.<\/p>\n
\n280 = 4*70
\n420 = 6*70<\/p>\n
\nTherefore, option B is the right answer.<\/p>\n
\nCompound interest paid to bank = $1000(1 + \\dfrac{20}{100})^2 – 1000$ = Rs. 440
\nHence, we can say that Quantity 1 = Quantity 2. Option E is the correct answer.<\/p>\n
\nWe have 5a + 9m = 71 and 7a + 11m = 93.
\nSolving we get a = 7 and m = 4.
\nSo 3 bottles of apple juice and 4 bottles of mango juice will fill = 7*3 + 4*4 = 37 glasses
\nHence, option A is the right choice.<\/p>\n
\n33*4+5 = 132+5 = 137
\n137*4+5 = 548+5 = 553
\n553*4+5 = 2212+5 = 2217
\n2217*4+5 = 8868+5 = 8873
\nHence, 8871 must be replaced by 8873<\/p>\n
\nFavourable cases = (1,1) (1,2) (2,1) (1,3) (3,1) (2,2)
\nTotal cases = 6*6 = 36
\nSo probability $= \\frac{ \\text{Favourable cases}}{\\text{Total cases}}$
\n$= \\frac{6}{36} =\\frac{1}{6}$<\/p>\n
\nSo revenue generated on normal day = x*y = xy<\/p>\n
\nNew selling price during summer = 1.2x rupees per litre<\/p>\n
\nHence we can say that revenue will go up by 68 percent.<\/p>\n
\nThus, the probability that sum of the number on the faces of the dice is 7 = (3C1+3C1+3C1+3!)\/216 = 15\/216 = X
\n10 = 6 + 3 + 1 = 6 + 2 + 2 = 5 + 3 + 2 = 4 + 4 + 2 = 4 + 3 + 3 = 1 + 4 + 5
\nThus, the probability that sum of the number on the faces of the dice is 14 = (3C1+3C1+3C1+3!)\/216 = 15\/216 = Y
\nHence, X=Y
\nHence, option E is the correct answer.<\/p>\n
\nOption (A): Average cost price of the mixture = $\\dfrac{200+560+1260}{2+4+7}$ = Rs. 155.38
\nOption (B): Average cost price of the mixture = $\\dfrac{100+700+1800}{1+5+10}$ = Rs. 162.50
\nOption (C): Average cost price of the mixture = $\\dfrac{100+280+540}{1+2+3}$ = Rs. 153.33
\nOption (D): Average cost price of the mixture = $\\dfrac{200+700+900}{2+5+5}$ = Rs. 150
\nTherefore, option D is the correct answer.<\/p>\n
\nThen his original speed = $\\frac{150d}{30}$ = 5d<\/p>\n
\n(4\/5)th of original speed = $\\frac{4}{5} * 5d$ = 4d
\nTime taken by Ram to cover this distance = $\\frac{50d}{4d} = 12.5$minutes<\/p>\n
\n(2\/5)th of original speed = $\\frac{2}{5}*5d$ = 2d
\nTime taken by Ram to cover the remaining distance = $\\frac{100d}{2d}$ = 50 minutes<\/p>\n
\nWe get following venn diagram –<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/venn_1.PNG\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/venn_2.PNG\")
<\/figure>\n
\nHence, option E is the correct choice.<\/p>\n