Download SBI Clerk Quantitative Apptitude Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Quantitative Aptitude questions with solutions.<\/p>\n
Download Quantitative Aptitude Questions For SBI Clerk<\/a><\/p>\n 790+ Mocks – Just Rs. 194. Use coupon: SBIDREAM70<\/a><\/p>\n Download SBI Clerk Puzzles Set-1 PDF<\/a><\/p>\n Question 1:\u00a0<\/b>The ratio of 3rd and 6th term of a GP is 27. If the first term of the GP is 10, then find out the sum of infinite terms of this convergent GP.<\/p>\n a)\u00a030<\/p>\n b)\u00a040<\/p>\n c)\u00a015<\/p>\n d)\u00a020<\/p>\n e)\u00a025<\/p>\n Question 2:\u00a0<\/b>Sum of the first 3 terms of an AP is 2\/9 times the sum of first 6 terms of the same AP. Find out the ratio of first term to the common difference of the same AP.<\/p>\n a)\u00a03 : 8<\/p>\n b)\u00a01 : 4<\/p>\n c)\u00a02 : 7<\/p>\n d)\u00a01 : 3<\/p>\n e)\u00a01 : 5<\/p>\n Question 3:\u00a0<\/b>N is a number that leaves the same remainder on dividing 2527, 2419, 2383, and 2599. The largest value of N that satisfies the condition is<\/p>\n a)\u00a054<\/p>\n b)\u00a018<\/p>\n c)\u00a072<\/p>\n d)\u00a036<\/p>\n e)\u00a090<\/p>\n Download SBI Clerk Previous Papers PDF<\/a><\/p>\n Take a free mock test for SBI Clerk<\/a><\/p>\n Instructions<\/b><\/p>\n In each of the following questions a question is asked followed by three statements.You have to study the questions and all the given three statements and all the statements and decide whether any information provided in the statement are redundant and can be dispensed with while answering the questions ?<\/p>\n Question 4:\u00a0<\/b>What will be the cost of the painting the four walls of a room with length ,width and height is 5,3,8 meters respectively. The room has one window and one door. a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III only<\/p>\n d)\u00a0II or III only<\/p>\n e)\u00a0All are required to answer the question<\/p>\n Question 5:\u00a0<\/b>How much time will the train X take to cross another train Y running in the opposite direction ? a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III only<\/p>\n d)\u00a0I or II only<\/p>\n e)\u00a0Data inadequate<\/p>\n Question 6:\u00a0<\/b>Three friends X,Y,Z started a partnership business investing money in the ratio of the 5 :4:2 respectively for a period of 3 years.What is the amount received by X as share in the total profit ? a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III Only<\/p>\n d)\u00a0I and II only<\/p>\n e)\u00a0I or II or III<\/p>\n Question 7:\u00a0<\/b>Ram purchased three variety of barley at Rs. 100 per kg, Rs. 140 per kg and Rs. 180 per kg respectively. In what ratio he should mix these three varieties in that order so that the average cost of the mixture is Rs. 150 per kg?<\/p>\n a)\u00a02 : 4 : 7<\/p>\n b)\u00a01 : 5 : 10<\/p>\n c)\u00a01 : 2 : 3<\/p>\n d)\u00a02 : 5 : 5<\/p>\n e)\u00a0None of the above<\/p>\n Banking Study Material – 18000 Questions<\/a><\/p>\n Daily Free SBI Online Tests<\/a><\/p>\n Question 8:\u00a0<\/b>Ram mixes acid and water in 3:5 to get solution X whereas he mixes water and acid in 2:3 to get solution Y. In what ratio he should mix solution X and Y to make another solution which contains 50% acid?<\/p>\n a)\u00a03 : 5<\/p>\n b)\u00a04 : 5<\/p>\n c)\u00a05 : 4<\/p>\n d)\u00a05 : 3<\/p>\n e)\u00a01 : 1<\/p>\n Question 9:\u00a0<\/b>Jar A contains 70% milk and the rest is water whereas Jar B contains 60% water and the rest is milk. How many liters of solution A should be mixed with 100 liters of solution B to make 50% water-milk solution?<\/p>\n a)\u00a020<\/p>\n b)\u00a0100<\/p>\n c)\u00a080<\/p>\n d)\u00a040<\/p>\n e)\u00a050<\/p>\n Instructions<\/b><\/p>\n In the following questions 2 quantities X and Y are given. Select the option which best captures the relations between X and Y.<\/p>\n Question 10:\u00a0<\/b>3 dices are thrown. a)\u00a0X>Y<\/p>\n b)\u00a0X<Y<\/p>\n c)\u00a0X$\\geq$Y<\/p>\n d)\u00a0X$\\leq$Y<\/p>\n e)\u00a0X=Y or Cannot be determined<\/p>\n 200+ Free GK Tests<\/a><\/p>\n Question 11:\u00a0<\/b>Solution A has p and q in the ratio 1:2. Solution B has p and q in the ratio 5:4. Solution A and Solution B are mixed in the ratio 3:4 to form the solution C. Solution A and Solution B are mixed in the ratio 5:3 to form the solution D. a)\u00a0X>Y<\/p>\n b)\u00a0X<\/p>\n c)\u00a0X$\\geq$Y<\/p>\n d)\u00a0X$\\leq$Y<\/p>\n e)\u00a0X=Y or Cannot be determined<\/p>\n Question 12:\u00a0<\/b>Cost price of 6 articles is equal to the Selling price of 4 articles. The shopkeeper Marked up the price by 100%. X is the % discount offered. a)\u00a0X>Y<\/p>\n b)\u00a0X<Y<\/p>\n c)\u00a0X$\\geq$Y<\/p>\n d)\u00a0X$\\leq$Y<\/p>\n e)\u00a0X=Y or Cannot be determined<\/p>\n Question 13:\u00a0<\/b>To meet the demand during summer, a milkman mixed water with pure milk in 2:5. Then he sold the same mixture at 20% more than normal price. By what percent his revenue will increase during summers? (Water is available without any cost)<\/p>\n a)\u00a060 percent<\/p>\n b)\u00a050 percent<\/p>\n c)\u00a040 percent<\/p>\n d)\u00a068 percent<\/p>\n e)\u00a063 percent<\/p>\n Question 14:\u00a0<\/b>A retailer bought 5 dozen notebooks. He got these notebooks at 30% less than printed price. To clear his stock soon he offered 1 notebook free on buying 4 notebooks. If the retailer sold all notebooks on printed price, what\u2019s is retailer\u2019s profit percentage in this transaction?<\/p>\n a)\u00a028.57%<\/p>\n b)\u00a021.35%<\/p>\n c)\u00a012.48%<\/p>\n d)\u00a042.89%<\/p>\n e)\u00a014.28%<\/p>\n Question 15:\u00a0<\/b>Krishna purchased a new laptop. After 2 years, he sold it to Pradeep at a discount of 30% when compared to the actual cost price. Pradeep spent 680 for repairing the laptop after purchase. After using it for 2 years, he sold it to Ravi at a discount of 30% when compared to the total amount he invested in the laptop. If Ravi paid exactly half the amount which Krishna paid, find the amount that Krishna paid when he purchased the laptop?<\/p>\n a)\u00a047600<\/p>\n b)\u00a036600<\/p>\n c)\u00a068000<\/p>\n d)\u00a072000<\/p>\n e)\u00a0None of the above.<\/p>\n Instructions<\/b><\/p>\n One of the numbers in the given series is incorrect. Find the incorrect number in the series<\/p>\n Question 16:\u00a0<\/b>7, 33, 137, 553, 2217, 8871<\/p>\n a)\u00a033<\/p>\n b)\u00a0137<\/p>\n c)\u00a0553<\/p>\n d)\u00a08871<\/p>\n e)\u00a02217<\/p>\n Question 17:\u00a0<\/b>6, 12, 15, 30, 42, 56<\/p>\n a)\u00a012<\/p>\n b)\u00a030<\/p>\n c)\u00a06<\/p>\n d)\u00a056<\/p>\n e)\u00a015<\/p>\n Question 18:\u00a0<\/b>6, 19, 58, 172, 526<\/p>\n a)\u00a0172<\/p>\n b)\u00a058<\/p>\n c)\u00a019<\/p>\n d)\u00a0526<\/p>\n e)\u00a06<\/p>\n Question 19:\u00a0<\/b>5 bottles of apple juice and 9 bottles of mango juice together fill 71 glasses. Also, 7 bottles of apple juice and 11 bottles of mango juice together fill 93 glasses. How many glasses can be filled with 3 bottles of apple juice and 4 bottles of mango juice if each bottle of either of the juices fills an integer number of glasses?<\/p>\n a)\u00a037<\/p>\n b)\u00a041<\/p>\n c)\u00a034<\/p>\n d)\u00a045<\/p>\n e)\u00a032<\/p>\n Question 20:\u00a0<\/b>An ATM machine contains 100 notes. The notes are of Rs. 5, Rs. 10 and Rs. 20 denominations. The total value of the notes in the machine is Rs.1500. If the number of Rs.10 and Rs. 20 notes is exchanged, the net value goes down by Rs. 400. The number of 20 rupee notes in the machine is<\/p>\n a)\u00a010<\/p>\n b)\u00a020<\/p>\n c)\u00a040<\/p>\n d)\u00a060<\/p>\n e)\u00a080<\/p>\n General Knowledge Questions & Answers PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let \u2018r\u2019 be the common ratio of the given GP. 2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let \u2018a\u2019 and \u2018d\u2019 be the first term and common difference of the given AP. 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n N leaves the same remainder on dividing 2527, 2419, 2383, and 2599, the difference between any pair of these numbers should be divisible by the number. The smallest difference will be the limiting factor. 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Length = 5 m , Breadth = 3 m and Height = 8 m<\/p>\n To find the cost of painting the walls of the room, we should know the cost of painting and the area of door and window.<\/p>\n Area of 4 walls (Curved Surface Area of cuboid) = $2h(l+b)$<\/p>\n = $(2 \\times 8)(5+3) = 16 \\times 8 = 128$ $m^2$<\/p>\n From I & II : Cost = Rs 25 per square meter<\/p>\n Area of window = $2.25$ $m^2$<\/p>\n and Area of door = $2 \\times 2.25 = 4.5$ $m^2$<\/p>\n Thus, area to be painted = $128 – 2.25 – 4.5 = 121.25$ $m^2$<\/p>\n $\\therefore$ Cost of painting 4 walls = $25 \\times 121.25 = Rs$ $3031.25$<\/p>\n Thus, statement III is redundant.<\/p>\n => Ans – (C)<\/p>\n 5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n To find the time taken by train X to cross train Y, we should know the sum of speed of the trains\u00a0(as they are moving in opposite directions) and the sum of lengths of the train<\/p>\n In statement II, ratio of speed of train\u00a0X : Y = 3\u00a0: 2<\/p>\n Thus, we cannot find the speeds of the two trains.<\/p>\n $\\therefore$ Data is inadequate<\/p>\n => Ans – (E)<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Ratio of investment of\u00a0X : Y : Z = 5\u00a0: 4\u00a0: 2<\/p>\n To find the share of profit earned by X (or anyone), we need to find the total profit earned.<\/p>\n From statement III : Average profit for 3 years = Rs. 2750<\/p>\n => Total profit = $2750 \\times 3$ = Rs. 8250<\/p>\n Amount received by X = $\\frac{5}{(5+4+2)} \\times 8250$ = Rs. 3750<\/p>\n Thus, statements I and II are redundant.<\/p>\n => Ans – (D)<\/p>\n 7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let us check the options. 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let \u2018a\u2019 and \u2018b\u2019 be the quantity of solution X and Y mixed by Ram. It is given that the solution contains 50% acid hence, $\\Rightarrow$ $\\dfrac{15a+24b}{40(a+b)} = \\dfrac{1}{2}$<\/p>\n $\\Rightarrow$ $30a+48b = 40a+40b$<\/p>\n $\\Rightarrow$ $\\dfrac{a}{b} = \\dfrac{4}{5}$<\/p>\n Hence, option B is the correct answer.<\/p>\n 9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let \u2018X\u2019 liters of solution A is mixed with 100 liters of solution B. 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n 7 = 1 + 1 + 5 = 2 + 2 + 3 = 3 + 3 + 1 = 1 + 2 + 4 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the quantity of A and B be 9L. 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the CP be 10 Rs. 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let us assume that on a normal day he sells milk at x rupee per litre and he sells y litre of milk He mixed water with milk in ratio of 2:5 so net quantity = $\\frac{2+5}{5} * y$ = 1.4y So revenue generated in summers = 1.4y * 1.2x = 1.68xy 14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Number of notebooks that retailer bought = 5 * 12 = 60<\/p>\n Let us assume that printed price on each notebook = 100<\/p>\n The retailer bought these notebooks at 30% less = 70 Rupees\/notebook<\/p>\n Sum invested by the retailer = 60*70 = 4200<\/p>\n By selling 60 notebooks he will get money for = $\\frac{4}{5}*60$ = 48 notebooks<\/p>\n Money collected by the retailer by selling these notebooks = 48*100 = 4800<\/p>\n Hence, retailer\u2019s profit percentage = $\\frac{4800-4200}{4200}*100$ = 14.28%<\/p>\n 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let assume Krishna paid 100x when he purchased the laptop. 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 7*4+5 = 28+5 = 33 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n 2*3 = 6 18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The pattern being followed here is *3+1 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let 1 bottle of apple juice fill \u2018a\u2019 glasses and 1 bottle of mango juice fill \u2018m\u2019 glasses. 20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the number of 5 rupee notes be x, 10 rupee notes be y and 20 rupee notes be z. Multiplying equation (1) by 5 and substituting it in equations (2) and (3), we get, (4)*3 – (5) => 40z = 2400
\nI.Cost of painting per square meter is Rs 25
\nII.Area of window is 2.25 sq m which is half of the area of the door
\nIII.Area of the room is 15 sq meter<\/p>\n
\nI.Train X crosses a signal pole in 6 secs
\nII.Ratio of the speeds of trains X and Y is 3:2
\nIII.Length of the two trains together is 500 meters<\/p>\n
\nI.Total amount invested in the business is Rs.22,000
\nII.Profit was distributed after a period of 2 years
\nIII.The average amount of profit earned per year is Rs 2,750<\/p>\n
\nX is the probability that sum of the number on the faces of the dice is 7.
\nY is the probability that sum of the number on the faces of the dice is 14.<\/p>\n
\nX = the ratio of p and q in Solution C
\nY = the ratio of p and q in Solution D.<\/p>\n
\nY is the % profit obtained.<\/p>\n
\nThe ratio of 3rd and 6th term of a GP is 27.
\n$\\dfrac{ar^2}{ar^5}$ = 27
\n$\\Rightarrow$ $\\dfrac{1}{r^3}$ = 27
\n$\\Rightarrow$ $r = \\dfrac{1}{3}$
\nSum of infinite GP = $\\dfrac{a}{1-r}$ = $\\dfrac{10}{1-1\/3}$ = 15
\nHence, option C is the correct answer.<\/p>\n
\n$\\Rightarrow$ $\\dfrac{3}{2}(2a + 2d) = \\dfrac{2}{9}[\\dfrac{6}{2}(2a + 5d)]$
\n$\\Rightarrow$ $3a+3d = \\dfrac{2}{3}(2a + 5d)$
\n$\\Rightarrow$ $9a+9d = 4a + 10d$
\n$\\Rightarrow$ $5a = d$
\n$\\Rightarrow$ $\\dfrac{a}{d} = \\dfrac{1}{5}$
\nTherefore, option E is the correct answer.<\/p>\n
\n2599 – 2527 = 72
\n2599- 2419= 180
\n2599-2383= 216
\n2527- 2419= 108
\n2527- 2383= 144
\n2419- 2383= 36
\nAs we can see, 36 is the smallest difference and hence, the largest number that satisfies the given condition is 36.
\nTherefore, option D is the right answer.<\/p>\n
\nOption (A): Average cost price of the mixture = $\\dfrac{200+560+1260}{2+4+7}$ = Rs. 155.38
\nOption (B): Average cost price of the mixture = $\\dfrac{100+700+1800}{1+5+10}$ = Rs. 162.50
\nOption (C): Average cost price of the mixture = $\\dfrac{100+280+540}{1+2+3}$ = Rs. 153.33
\nOption (D): Average cost price of the mixture = $\\dfrac{200+700+900}{2+5+5}$ = Rs. 150
\nTherefore, option D is the correct answer.<\/p>\n
\n$\\Rightarrow$ $\\dfrac{\\dfrac{3a}{8}+\\dfrac{3b}{5}}{a+b} = \\dfrac{50}{100}$<\/p>\n
\nConcentration of milk in solution B = 100 – 60 = 40%.
\nThe resultant solution is a 50% water-milk solution.
\nHence,
\n$\\dfrac{0.70*X + 0.40*100}{X+100} = \\dfrac{50}{100}$
\n$70*X + 4000 = 50*X + 5000$
\n$20X= 1000$
\n$X= 50$liters.
\nHence, option E is the correct answer.<\/p>\n
\nThus, the probability that sum of the number on the faces of the dice is 7 = (3C1+3C1+3C1+3!)\/216 = 15\/216 = X
\n10 = 6 + 3 + 1 = 6 + 2 + 2 = 5 + 3 + 2 = 4 + 4 + 2 = 4 + 3 + 3 = 1 + 4 + 5
\nThus, the probability that sum of the number on the faces of the dice is 14 = (3C1+3C1+3C1+3!)\/216 = 15\/216 = Y
\nHence, X=Y
\nHence, option E is the correct answer.<\/p>\n
\nThus, the amount of p and q in A is 3L and 6L respectively.
\nAlso, the amount of p and q in B is 5L and 4L respectively.
\nA and B are mixed in the ratio 3:4 to form solution C.
\nThus, the amount of p and q in solution C = (3*3+5*4):(6*3+4*4) = 29:34=X
\nSolution A and Solution B are mixed in the ratio 5:3 to form the solution D.
\nThus, the amount of p and q in solution D = (5*3+5*3):(6*5+4*3) = 30:42=Y
\nHence, X>Y
\nHence, option A is the correct answer.<\/p>\n
\nThus, 6*10 = 4*SP. Thus, SP = 15 Rs
\nMP = 2*10 = 20 Rs
\n% discount = $\\frac{20-15}{20}$ = 25% = X
\n% profit = $\\frac{15-10}{10}$ = 50% = Y
\nHence, option B is the correct answer.<\/p>\n
\nSo revenue generated on normal day = x*y = xy<\/p>\n
\nNew selling price during summer = 1.2x rupees per litre<\/p>\n
\nHence we can say that revenue will go up by 68 percent.<\/p>\n
\nSo Krishna sold it to Pradeep for = $\\frac{100-30}{100}*100x$ = 70x
\nAnd Pradeep also spent 680 rupees for repairing
\nSo total amount invested by Pradeep = 70x+680
\nSo the amount Ravi paid to Pradeep = $\\frac{100-30}{100}*(70x+680)$ = 49x+476
\nWe also know that Ravi paid exactly half of what Krishna paid
\ni.e. 0.5*(100x) = 49x+476
\n$\\Rightarrow$ x = 476
\nSo the amount for which Krishna purchased the laptop = 100*476 = 47600<\/p>\n
\n33*4+5 = 132+5 = 137
\n137*4+5 = 548+5 = 553
\n553*4+5 = 2212+5 = 2217
\n2217*4+5 = 8868+5 = 8873
\nHence, 8871 must be replaced by 8873<\/p>\n
\n3*4 = 12
\nNext term would be 4*5 = 20
\n5*6 = 30
\n6*7 = 42
\n7*8 = 56
\nHence, 15 must be replaced by 20.<\/p>\n
\n6*3+1 = 19,
\n19*3+1=58,
\nso next term would be 58*3+1= 175
\n175*3+1 = 526.
\nHence, 172 must be replaced by 175.<\/p>\n
\nWe have 5a + 9m = 71 and 7a + 11m = 93.
\nSolving we get a = 7 and m = 4.
\nSo 3 bottles of apple juice and 4 bottles of mango juice will fill = 7*3 + 4*4 = 37 glasses
\nHence, option A is the right choice.<\/p>\n
\nWe know that,
\nx + y + z = 100 ———————–(1)
\n5x + 10y + 20z = 1500————–(2)
\n5x + 20y + 10z = 1100————-(3)<\/p>\n
\n5y + 15z = 1000——-(4)
\n15y + 5z = 600 —-(5)<\/p>\n
\nz = 60
\nTherefore, the number of 20 rupee notes is 60.
\nTherefore, option D is the right answer.<\/p>\n