{"id":29719,"date":"2019-05-31T13:17:30","date_gmt":"2019-05-31T07:47:30","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=29719"},"modified":"2019-05-31T13:17:30","modified_gmt":"2019-05-31T07:47:30","slug":"square-root-questions-for-rrb-group-d-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/square-root-questions-for-rrb-group-d-pdf\/","title":{"rendered":"Square Root Questions for RRB Group-D PDF"},"content":{"rendered":"

Square Root Questions for RRB Group-D PDF<\/strong><\/span><\/h1>\n

Download Top-15 RRB Group-D Square root\u00a0 Questions PDF.\u00a0RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download Square Root Questions for RRB Group-D PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>The square root of $27-4\\sqrt{35}$ is :<\/p>\n

a)\u00a0$\\pm(\\sqrt{5}+2\\sqrt{7})$<\/p>\n

b)\u00a0$\\pm(\\sqrt{5}-2\\sqrt{7})$<\/p>\n

c)\u00a0$\\pm(\\sqrt{7}-2\\sqrt{5})$<\/p>\n

d)\u00a0$\\pm(\\sqrt{7}+2\\sqrt{5})$<\/p>\n

Question 2:\u00a0<\/b>What is the square root of $214 – 78\\sqrt{5}$<\/p>\n

a)\u00a0$13-3\\sqrt{5}$<\/p>\n

b)\u00a0$17-4\\sqrt{5}$<\/p>\n

c)\u00a0$13-6\\sqrt{5}$<\/p>\n

d)\u00a0$17-3\\sqrt{5}$<\/p>\n

Question 3:\u00a0<\/b>What is the square root of 97-16$\\sqrt{3}$<\/p>\n

a)\u00a09-4$\\sqrt{3}$<\/p>\n

b)\u00a09+4$\\sqrt{3}$<\/p>\n

c)\u00a07-4$\\sqrt{3}$<\/p>\n

d)\u00a07+4$\\sqrt{3}$<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

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Question 4:\u00a0<\/b>Find the square root of discriminant of $2x^2-3x-7 = 0$ ?<\/p>\n

a)\u00a065<\/p>\n

b)\u00a0$\\sqrt{65}$<\/p>\n

c)\u00a056<\/p>\n

d)\u00a0$\\sqrt{56}$<\/p>\n

Question 5:\u00a0<\/b>What can be said about the roots of the following equation $3x^2 – 5x + 4 = 0$<\/p>\n

a)\u00a0They are real and distinct, but one root is not square of the other<\/p>\n

b)\u00a0They are real and distinct, and one root is a perfect square of the other<\/p>\n

c)\u00a0They are real and equal<\/p>\n

d)\u00a0They are complex<\/p>\n

Question 6:\u00a0<\/b>Sum of the squares of the roots of a quadratic equation is 25 and the product of the roots of the equation is -12. Which of the below four equations can be the quadratic equation –<\/p>\n

a)\u00a0$z^2+3z-12=0$<\/p>\n

b)\u00a0$z^2-z-12=0$<\/p>\n

c)\u00a0$z^2-3z-12=0$<\/p>\n

d)\u00a0$z^2+4z-12=0$<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

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Question 7:\u00a0<\/b>If one of the roots of the equation $ x^2 + kx – 27 = 0$ is a square of another. What is the value of k?<\/p>\n

a)\u00a0-2<\/p>\n

b)\u00a0-4<\/p>\n

c)\u00a0-6<\/p>\n

d)\u00a02<\/p>\n

Question 8:\u00a0<\/b>The square root of $33-4\\sqrt{35}$ is :<\/p>\n

a)\u00a0$\\pm(2\\sqrt{7}+\\sqrt{5})$<\/p>\n

b)\u00a0$\\pm(\\sqrt{7}+2\\sqrt{5})$<\/p>\n

c)\u00a0$\\pm(\\sqrt{7}-2\\sqrt{5})$<\/p>\n

d)\u00a0$\\pm(2\\sqrt{7}-\\sqrt{5})$<\/p>\n

Question 9:\u00a0<\/b>The greatest 4 digit Number which is a perfect square, is<\/p>\n

a)\u00a09999<\/p>\n

b)\u00a09909<\/p>\n

c)\u00a09801<\/p>\n

d)\u00a09081<\/p>\n

Question 10:\u00a0<\/b>What is the positive square root of $[19+4\\sqrt21]?$<\/p>\n

a)\u00a0$\\sqrt{7}+2\\sqrt{3}$<\/p>\n

b)\u00a0$\\sqrt{3}+2\\sqrt{7}$<\/p>\n

c)\u00a0$\\sqrt{2}+3\\sqrt{7}$<\/p>\n

d)\u00a0$\\sqrt{7}+3\\sqrt{3}$<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 11:\u00a0<\/b>What is the square root of $\\frac{(3-2\\sqrt2)}{(3+2\\sqrt2)}$ ?<\/p>\n

a)\u00a0$3-2\\sqrt2$<\/p>\n

b)\u00a0$3+2\\sqrt2$<\/p>\n

c)\u00a0$1$<\/p>\n

d)\u00a0$17$<\/p>\n

Question 12:\u00a0<\/b>What is the square root of $\\frac{(3-2\\sqrt2)}{(3+2\\sqrt2)}?$<\/p>\n

a)\u00a0$3-2\\sqrt2$<\/p>\n

b)\u00a0$3+2\\sqrt2$<\/p>\n

c)\u00a0$1$<\/p>\n

d)\u00a0$$17$<\/p>\n

Question 13:\u00a0<\/b>What is the positive square root of $[25+4\\sqrt{39}]$ ?<\/p>\n

a)\u00a0$\\sqrt{13}+2\\sqrt3$<\/p>\n

b)\u00a0$\\sqrt{13}+3\\sqrt2$<\/p>\n

c)\u00a0$\\sqrt{11}+2\\sqrt3$<\/p>\n

d)\u00a0$11+3\\sqrt2$<\/p>\n

Question 14:\u00a0<\/b>What is the square root of 156.25<\/p>\n

a)\u00a013.5<\/p>\n

b)\u00a015.25<\/p>\n

c)\u00a010.5<\/p>\n

d)\u00a012.5<\/p>\n

Question 15:\u00a0<\/b>The smallest positive integer to be added to 5467 to make it a perfect square is?<\/p>\n

a)\u00a09<\/p>\n

b)\u00a011<\/p>\n

c)\u00a017<\/p>\n

d)\u00a025<\/p>\n\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We have to find $27-4\\sqrt{35}$<\/p>\n

We can write it as :<\/p>\n

= $\\sqrt{{27} – 2\u00a0\\times 2\\times \\sqrt{5}\u00a0\\times \\sqrt{7}}$<\/p>\n

Since, $(a^2 + b^2 – 2ab) = (a-b)^2$<\/p>\n

= $\\sqrt{(2\\sqrt{5})^2 + (\\sqrt{7})^2 – 2\\times2\\sqrt{5}\\times\\sqrt{7}}$<\/p>\n

= $\\sqrt{(\\sqrt{7} – 2\\sqrt{5})^2}$<\/p>\n

= $\\pm(\\sqrt{7} – 2\\sqrt{5})$<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

we have $(a-b)^{2}$=$a^{2}+b^{2}-2ab$<\/p>\n

Comparing this with $214-78\\sqrt{5}$ = $a^{2}+b^{2}-2ab$<\/p>\n

We have 214=$a^{2}+b^{2}$<\/p>\n

& $ab = 39\\sqrt{5}$<\/p>\n

For a=13 and b=3$\\sqrt{5}$; 2ab=2*13*3$\\sqrt{5}$<\/p>\n

And so required answer is 13-3$\\sqrt{5}$<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

we have $(a-b)^{2}$=$a^{2}+b^{2}-2ab$
\nComparing this with 97-56$\\sqrt{3}$=$a^{2}+b^{2}-2ab$
\nWe have 97=$a^{2}+b^{2}$
\nFor a=7 and b=4$\\sqrt{3}$ it gets satisfied and also 2ab=2*7*4$\\sqrt{3}$
\nSo the $(7-4\\sqrt{3})^{2}$=$7^{2}+(4\\sqrt{3})^{2}-2*7*4*\\sqrt{3}$
\nAnd so required answer is 7-4$\\sqrt{3}$<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Discriminant of $ax^2+bx+c=0$ is $b^2-4ac$.<\/p>\n

Discriminant of\u00a0$2x^2-3x-7 = 0$ is $(-3)^2-4(2)(-7) = 9+56 = 65$<\/p>\n

Square root of discriminant = $\\sqrt{65}$<\/p>\n

So the answer is option B.<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$3x^2 – 5x + 4 = 0$
\nFinding discriminant of the given equation we have
\n$(-5)^2 – 4 *3*4$ = 25-48 = -23
\nSince discriminant<0
\nThe roots are complex.
\nHence, option D is the right answer.<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the roots of the equation be z and y.
\n$ z^2 + y^2 = (z+y)^2 – 2zy$
\n25 = (z+y)^2 +24
\nz+y = +1 or = -1
\nSo, quadratic equation can be either $z^2+z-12=0$ or $z^2-z-12=0$
\nHence, option B is the right answer.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given equation, $ x^2 + kx – 27 = 0$
\nLet a and $ a^2$ be the roots of the equation.
\nWe have,
\na * $a^2$ = -27
\na = -3
\nAlso, a + $a^2$ = -k
\nk = -6
\nHence, option C is the right answer.<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

To find : $\\sqrt{33-4\\sqrt{35}}$<\/p>\n

We can write it as :<\/p>\n

= $\\sqrt{33 – 2 * 2 * \\sqrt{7} * \\sqrt{5}}$<\/p>\n

Since, $(a^2 + b^2 – 2ab) = (a-b)^2$<\/p>\n

= $\\sqrt{(2\\sqrt{7})^2 + (5)^2 – 2*2\\sqrt{7}*\\sqrt{5}}$<\/p>\n

= $\\sqrt{(2\\sqrt{7} – \\sqrt{5})^2}$<\/p>\n

= $\\pm(2\\sqrt{7}-\\sqrt{5})$<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Since the number has 4 digits, its square root will always have 2 digits.<\/p>\n

=> Greatest 2 digit no. = 99<\/p>\n

Greatest 4 digit no. which is perfect square = $99^2$ = 9801<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0$[19+4\\sqrt21]?$<\/p>\n

= $[19+2\\sqrt{4\\times21}]=[19+2\\sqrt{84}]$<\/p>\n

= $7+12+2\\sqrt{7\\times12}$<\/p>\n

= $(7)^2+(12)^2+2\\sqrt{7\\times12}$<\/p>\n

Now, we know that $a^2+b^2+2ab=(a+b)^2$<\/p>\n

= $(\\sqrt{7}+\\sqrt{12})^2$<\/p>\n

Thus, square root is = $\\sqrt{7}+\\sqrt{12}$<\/p>\n

=\u00a0$\\sqrt7+2\\sqrt3$<\/p>\n

=> Ans – (A)<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given\u00a0:\u00a0$x=\\frac{(3-2\\sqrt2)}{(3+2\\sqrt2)}$<\/p>\n

To find\u00a0: $\\sqrt{x}$<\/p>\n

Solution\u00a0: rationalizing the denominator, we get<\/p>\n

=>\u00a0$\\frac{(3-2\\sqrt2)}{(3+2\\sqrt2)}\\times\\frac{(3-2\\sqrt2)}{(3-2\\sqrt2)}$<\/p>\n

=\u00a0$\\frac{(3-2\\sqrt2)^2}{(3)^2-(2\\sqrt2)^2}$<\/p>\n

=\u00a0$\\frac{(3-2\\sqrt2)^2}{9-8}$<\/p>\n

=> $x=(3-2\\sqrt2)^2$<\/p>\n

Taking square root on both sides,<\/p>\n

=> $\\sqrt{x}=3-2\\sqrt2$<\/p>\n

=> Ans – (A)<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\frac{(3-2\\sqrt2)}{(3+2\\sqrt2)}$<\/p>\n

Rationalizing the denominator,<\/p>\n

=\u00a0$\\frac{(3-2\\sqrt2)}{(3+2\\sqrt2)}\\times\\frac{(3-2\\sqrt2)}{(3-2\\sqrt2)}$<\/p>\n

= $\\frac{(3-2\\sqrt2)^2}{(3+2\\sqrt2)(3-2\\sqrt2)}$<\/p>\n

= $\\frac{(3-2\\sqrt2)^2}{9-8}=(3-2\\sqrt2)^2$<\/p>\n

Thus, square root is =\u00a0$3-2\\sqrt2$<\/p>\n

=> Ans – (A)<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0$[25+4\\sqrt{39}]$<\/p>\n

= $[25+2\\sqrt{4\\times39}]=[25+2\\sqrt{156}]$<\/p>\n

= $13+12+2\\sqrt{13\\times12}$<\/p>\n

= $(13)^2+(12)^2+2\\sqrt{13\\times12}$<\/p>\n

Now, we know that $a^2+b^2+2ab=(a+b)^2$<\/p>\n

= $(\\sqrt{13}+\\sqrt{12})^2$<\/p>\n

Thus, square root is = $\\sqrt{13}+\\sqrt{12}$<\/p>\n

=\u00a0$\\sqrt13+2\\sqrt3$<\/p>\n

=> Ans – (A)<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$15625 = 5*3125 = 25*625 = 25^3 = 5^6$
\nHence, $\\sqrt{15625} = 5^3 = 125$
\nTherefore, $\\sqrt{156.25} = 12.5$<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Lets try to find the rough vicinity of the square root of 5467. $70^2 = 4900$ and $80^2 = 6400$. Hence, the number is between 70-80. $75^2 = 5625$. Hence, the number is between 70-75 and is likely to be close to 75. We see that $74^2$ = 5476. Hence, we need to add 9 to make 5467 into a perfect square.<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Square root Questions for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Square Root Questions for RRB Group-D PDF Download Top-15 RRB Group-D Square root\u00a0 Questions PDF.\u00a0RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0The square root of $27-4\\sqrt{35}$ is : a)\u00a0$\\pm(\\sqrt{5}+2\\sqrt{7})$ […]<\/p>\n","protected":false},"author":41,"featured_media":29721,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679,1605],"tags":[489,491,1637,492,1647],"class_list":{"0":"post-29719","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"category-rrb-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-exam","15":"tag-rrb-group-d","16":"tag-rrb-mocks"},"better_featured_image":{"id":29721,"alt_text":"Square root Questions for RRB Group-D PDF","caption":"Square root Questions for RRB Group-D PDF","description":"Square root Questions for RRB Group-D 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