Download SSC CGL Time and Work Problems questions with answers PDF based on previous papers very useful for SSC CGL exams. 20 Very important Time and Work Problems on objective questions (MCQ’s) for SSC exams.<\/p>\n
Download Time And Work Problems For SSC CGL<\/a><\/p>\n Get 125 SSC CGL Mocks for Rs. 199<\/a><\/p>\n Question 1:\u00a0<\/b>A person travelled from his home to his office at 48 km\/hr and returned from his office to his home at 32 km\/hr. Find his average speed.<\/p>\n a)\u00a040 km\/hr<\/p>\n b)\u00a037.5 km\/hr<\/p>\n c)\u00a036 km\/hr<\/p>\n d)\u00a038.4 km\/hr<\/p>\n Question 2:\u00a0<\/b>A train travelled from A to B at a speed of 60 km\/hr and returned from B to A at a speed of 40 km\/hr. Find the average speed of the train.<\/p>\n a)\u00a050 km\/hr<\/p>\n b)\u00a048 km\/hr<\/p>\n c)\u00a042 km\/hr<\/p>\n d)\u00a056 km\/hr<\/p>\n Question 3:\u00a0<\/b>The average speed of a bus is 72km\/hr without stoppages and 60 km\/hr with stoppages. How many minutes per hour does the bus stop.<\/p>\n a)\u00a012 minutes<\/p>\n b)\u00a010 minutes<\/p>\n c)\u00a015 minutes<\/p>\n d)\u00a016 minutes<\/p>\n Question 4:\u00a0<\/b>A train travels a certain distance in a certain time. If it covers triple the distance in double the time, then find the ratio between original speed and current speed.<\/p>\n a)\u00a01:3<\/p>\n b)\u00a02:3<\/p>\n c)\u00a03:5<\/p>\n d)\u00a02:5<\/p>\n Question 5:\u00a0<\/b>The average speed of a bus is 25 km\/hr without stoppages and 20 km\/hr with stoppages. How many minutes per hour does the bus stop?<\/p>\n a)\u00a05 minutes<\/p>\n b)\u00a020 minutes<\/p>\n c)\u00a012 minutes<\/p>\n d)\u00a015 minutes<\/p>\n SSC CGL Previous Papers Download PDF<\/a><\/p>\n SSC CHSL PREVIOUS PAPERS DOWNLOAD<\/a><\/p>\n Question 6:\u00a0<\/b>A train travels from Delhi to Mumbai at a speed of 60 km\/hr and returns at a speed of 75 km\/hr. Find its average speed.<\/p>\n a)\u00a066.67 km\/hr<\/p>\n b)\u00a045 km\/hr<\/p>\n c)\u00a060 km\/hr<\/p>\n d)\u00a067.5 km\/hr<\/p>\n Question 7:\u00a0<\/b>A bus can travel at 150 km\/hr without stoppages and at 120 km\/hr with stoppages. How many minutes per hour does the bus stop?<\/p>\n a)\u00a015 minutes<\/p>\n b)\u00a012 minutes<\/p>\n c)\u00a016 minutes<\/p>\n d)\u00a020 minutes<\/p>\n Question 8:\u00a0<\/b>A train travels a distance of 480 km at uniform speed. Due to breakdown, its speed is reduced by 20 km\/hr and hence it travels the destination 4 hours late. Find the initial speed of the train.<\/p>\n a)\u00a060 km\/hr<\/p>\n b)\u00a040 km\/hr<\/p>\n c)\u00a025 km\/hr<\/p>\n d)\u00a035 km\/hr<\/p>\n Question 9:\u00a0<\/b>A train travels at a speed of 125 km\/hr without stoppages and at 100 km\/hr with stoppages. How many minutes per hour does the train stop?<\/p>\n a)\u00a025 min<\/p>\n b)\u00a020 min<\/p>\n c)\u00a015 min<\/p>\n d)\u00a012 min<\/p>\n Question 10:\u00a0<\/b>A bus travels at a speed of 75 km\/hr without stoppages and at 50 km\/hr with stoppages. How many minutes per hour does the bus stop?<\/p>\n a)\u00a025 min<\/p>\n b)\u00a020 min<\/p>\n c)\u00a015 min<\/p>\n d)\u00a010 min<\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n Question 11:\u00a0<\/b>A, B and C can do a piece of work individually in 8, 12 and 4 days respectively. A started the work and is assisted by B and C on every third day. Then, in how many days will the work be completed?<\/p>\n a)\u00a0$4\\dfrac{1}{2}$ days<\/p>\n b)\u00a0$5\\dfrac{3}{4}$ days<\/p>\n c)\u00a0$5\\dfrac{1}{11}$ days<\/p>\n d)\u00a0$4\\dfrac{2}{3}$ days<\/p>\n Question 12:\u00a0<\/b>A, B and C can do a piece of work individually in 12, 16 and 24 days respectively. A started the work and is assisted by B and C on every third day. Then in how many days will the total work be completed?<\/p>\n a)\u00a0$10\\dfrac{1}{3}$ days<\/p>\n b)\u00a0$8\\dfrac{2}{3}$ days<\/p>\n c)\u00a0$14$ days<\/p>\n d)\u00a0$12$ days<\/p>\n Question 13:\u00a0<\/b>20 men can complete a piece of work in 36 days. In how many days will 48 men with same efficiency be able to complete the work?<\/p>\n a)\u00a012 days<\/p>\n b)\u00a018 days<\/p>\n c)\u00a015 days<\/p>\n d)\u00a024 days<\/p>\n Question 14:\u00a0<\/b>A can do half of a piece of work in 12 days. B can do 1\/4th of the same work in 12 days. In how many days will the total work be completed if they work together?<\/p>\n a)\u00a014 days<\/p>\n b)\u00a018 days<\/p>\n c)\u00a012 days<\/p>\n d)\u00a016 days<\/p>\n Question 15:\u00a0<\/b>A can do 1\/3rd of the work in 10 days. B can do half of the same work in 15 days. In how many days will the work be completed if they both work together?<\/p>\n a)\u00a012 days<\/p>\n b)\u00a010 days<\/p>\n c)\u00a015 days<\/p>\n d)\u00a09 days<\/p>\n SSC CGL Free Mock Test<\/a><\/p>\n SSC CHSL Free Mock Test<\/a><\/p>\n Question 16:\u00a0<\/b>By working 8 hours a day, a man completed his work in 12 days. If the work needs to be completed in 8 days, then he needs to work for how many hours per day?<\/p>\n a)\u00a010 hours<\/p>\n b)\u00a012 hours<\/p>\n c)\u00a014 hours<\/p>\n d)\u00a016 hours<\/p>\n Question 17:\u00a0<\/b>A and B can do a piece of work individually in 24 days and 36 days respectively. A alone worked on it for 18 days and left. B can complete the remaining work in?<\/p>\n a)\u00a012 days<\/p>\n b)\u00a09 days<\/p>\n c)\u00a06 days<\/p>\n d)\u00a04 days<\/p>\n Question 18:\u00a0<\/b>A and B can do a piece of work individually in 20 days and 25 days respectively. A alone worked on it for 12 days and left. B can finish the remaining work in?<\/p>\n a)\u00a09 days<\/p>\n b)\u00a08 days<\/p>\n c)\u00a010 days<\/p>\n d)\u00a012 days<\/p>\n Question 19:\u00a0<\/b>A, B and C are employed to work for Rs.2100. A and B are supposed to finish $\\dfrac{37}{42}th$ of work. Then, amount paid to C is?<\/p>\n a)\u00a0Rs.225<\/p>\n b)\u00a0Rs.300<\/p>\n c)\u00a0Rs.325<\/p>\n d)\u00a0Rs.250<\/p>\n Question 20:\u00a0<\/b>A, B and C are employed to do a work for Rs.1440. A and C are supposed to complete $\\dfrac{29}{36}th$ of work. Then, Salary of B will be?<\/p>\n a)\u00a0Rs.400<\/p>\n b)\u00a0Rs.250<\/p>\n c)\u00a0Rs.280<\/p>\n d)\u00a0Rs.350<\/p>\n 1500+ Free SSC Questions & Answers<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the distance between his home and his office be 96 km. (LCM of 48 and 32) 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the distance between A and B be 120 km each (LCM of 60 and 40). 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Due to stoppages, bus travelled 12 km less in an hour. 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the distance travelled by the train be D km. 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Due to stoppages, bus travelled 5 km less in an hour. 100+ Free GK Tests for SSC Exams<\/a><\/p>\n Download Free GK PDF<\/a><\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the total distance be 300 km (LCM of 60 and 75). 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Due to stoppages, bus travelled 30 km less in an hour. 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Given that the distance $= 480$ km 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Due to stoppages, train travelled 25 km less in an hour. 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Due to stoppages, bus travelled 25 km less in an hour. 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the total work be 24 units. 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the total work be 48 units. First day: 4 units 15000 Questions – Free SSC Study Material<\/a><\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $\\text{No. of Men}_1 \\times \\text{No. of days}_1 = \\text{No. of Men}_2 \\times \\text{No. of days}_2$ 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Given, A can do half of the work in 12 days 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given, A can do 1\/3rd of work in 10 days 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $\\text{No. of hours}_1\\times\\text{No. of days}_1 = \\text{No. of hours}_2\\times\\text{No. of days}_2$ 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the total work be 72 units (LCM of 24 and 36). 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the total work be 100 units (LCM of 20 and 25) 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the total work be 42 units. 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let total work be 36 units.
\nTotal distance = 96+96 = 192 km
\nTime required to travel 96 km at 48 km\/hr = 2 hours
\nTime required to travel 96 km at 32 km\/hr = 3 hours
\nTotal time = 2+3 = 5 hours
\nAverage speed $= \\dfrac{\\text{Total Distance}}{\\text{Total Time}} = \\dfrac{192}{5} = 38.4 km\/hr$<\/p>\n
\nTime taken by the train to travel 120 km at 60 km\/hr = 2 hours
\nTime taken by the train to travel 120 km at 40 km\/hr = 3 hours
\nTotal distance = 120+120 = 240 km
\nTotal time = 2+3 = 5 hours
\nAverage speed $= \\dfrac{\\text{Total Distance}}{\\text{Total Time}} = \\dfrac{240}{5} = 48 km\/hr$<\/p>\n
\n12 km can be travelled without stoppages in $\\dfrac{12}{72} \\times 60 = 10$ minutes<\/p>\n
\nLet the time taken by the train to travel D km be T hours.
\nOriginal speed = $\\dfrac{D}{T}$ km\/hr
\nNew Distance = 3D km
\nNew time = 2T hours
\nNew speed = $\\dfrac{3D}{2T}$ km\/hr
\nRatio between original speed and new speed = $\\dfrac{D}{T} : \\dfrac{3D}{2T} = 1 : \\dfrac{3}{2} = 2:3$<\/p>\n
\nTime required to travel 5 km without stoppages = $\\dfrac{5}{25} \\times 60 = 12$ minutes<\/p>\n
\nTime required to travel 300 km at 60 km\/hr = 300\/60 = 5 hours
\nTime required to travel 300 km at 75 km\/hr = 300\/75 = 4 hours
\nTotal time to travel 600 km = 9 hours
\nTotal distance = 600 km
\nAverage speed = 600\/9 = 200\/3 = 66.67 km\/hr<\/p>\n
\nTime taken to travel 30 km $= \\dfrac{30}{150}\\times60 = 12$ minutes<\/p>\n
\nLet the speed of the train $= x$ km\/hr
\nThen, time in which it can travel $480$ km $= \\dfrac{480}{x}$ hr
\nNow, Speed is reduced by $20$ km\/hr
\nReduced speed $= (x-20)$ km\/hr
\nTime in which it can travel $480$ km at reduced speed $= \\dfrac{480}{(x-20)}$
\nDifference in time = 4 hours
\n\u21d2 $\\dfrac{480}{(x-20)} – \\dfrac{480}{x} = 4$
\n\u21d2 $\\dfrac{480(x-x+20)}{x^2-20x} = 4$
\n\u21d2 $9600 = 4(x^2-20x)$
\n\u21d2 $x^2-20x-2400 = 0$
\n\u21d2 $x^2-60x+40x-2400 = 0$
\n\u21d2 $x(x-60)+40(x-60) = 0$
\n\u21d2 $(x+40)(x-60) = 0$
\nx+40 = 0 | x-60 = 0
\nx = -40 | x = 60
\nSpeeds cannot be negative.
\nHence, Initial speed = 60 km\/hr<\/p>\n
\nTime required to travel 25 km in an hour $ = \\dfrac{25}{125}\\times 60 = 12$ minutes.<\/p>\n
\nTime required to travel 25 km in an hour $ = \\dfrac{25}{75}\\times 60 = 20$ minutes.<\/p>\n
\nEfficiency of A = 24\/8 = 3 units\/day
\nEfficiency of B = 24\/12 = 2 units\/day
\nEfficiency of C = 24\/4 = 6 units\/day
\nGiven that A started the work and is assisted by B and C on every third day.
\nFirst day: 3 units
\nSecond day: 3 units
\nThird day: 3+2+6 = 11 units
\n\u21d2 17 units of work will be completed in 3 days.
\nRemaining work = 24-17 = 7 units
\nIn 7 units, 6 units will be completed by A in 2 days.
\nRemaining 1 unit will be completed by A+B+C in $\\dfrac{1}{6}$ days.
\nHence, Total work will be completed in $3+2+\\dfrac{1}{6} days = 5\\dfrac{1}{6}$ days<\/p>\n
\nEfficiency of A = 48\/12 = 4 units\/day
\nEfficiency of B = 48\/16 = 3 units\/day
\nEfficiency of C = 48\/24 = 2 units\/day
\nA started the work and is assisted by B and C on every third day.<\/p>\n
\nSecond day: 4 units
\nThird day: 4+3+2 = 9 units
\n\u21d2 17 units of work will be completed in 3 days.
\n\u21d2 34 units of work will be completed in 6 days.
\nRemaining work = 48-34 = 14 units
\n8 units of work will be done by A in the next two days.
\nRemaining work = 14-8 = 6 units
\n6 units of work will be completed by A,B and C together in $\\dfrac{6}{9} = \\dfrac{2}{3}$ days
\nHence, Total work will be completed in $6+2+\\dfrac{2}{3} days = 8\\dfrac{2}{3}$ days<\/p>\n
\nLet the number of days required be \u2018x\u2019
\n\u21d2 $20\\times36 = 48\\times x$
\n\u21d2 x = 15
\nTherefore, Number of days required for 48 men to complete the work = 15 days.<\/p>\n
\n\u21d2 A can do complete work in 24 days.
\nB can do 1\/4th of the work in 12 days.
\n\u21d2 B can do complete work in 48 days.
\nLet the total work be 48 units (LCM of 24 and 48)
\nEfficiency of A = 48\/24 = 2 units\/day
\nEfficiency of B = 48\/48 = 1 unit\/day
\nThen, the total work will be completed in 48\/3 = 16 days<\/p>\n
\n\u21d2 A can do complete work alone in 30 days
\nB can do half of work in 15 days
\n\u21d2 B can do complete work in 30 days
\nLet total work be 30 units (LCM of 30,30)
\nEfficiency of A = 30\/30 = 1 unit\/day
\nEfficiency of B = 30\/30 = 1 units\/day
\nThen, Total work will be completed in 30\/2 = 15 days<\/p>\n
\nLet the number of hours per day required to work to finish the work in 8 days = x hours
\n\u21d2 $8\\times12 = 8\\times x$
\n\u21d2 $x = 12$<\/p>\n
\nEfficiency of A = 72\/24 = 3 units\/day
\nEfficiency of B = 72\/36 = 2 units\/day
\nA worked alone for 18 days.
\nA can do 3 units of work in a day.
\n\u21d2 In 18 days, he can complete 54 units of work.
\nRemaining work = 72-54 = 18 units
\nB can do 2 units of work in 1 day.
\nThen, 18 units will be completed by B in 18\/2 = 9 days.<\/p>\n
\nEfficiency of A = 100\/20 = 5 units\/day
\nEfficiency of B = 100\/25 = 4 units\/day
\nA worked alone for 12 days.
\n5 units of work will be completed by A in 1 day.
\nThen, 60 units of work will be completed by A in 12 days.
\nRemaining work = 100-60 = 40 units.
\n4 units of work will be completed by B in 1 day.
\nHence, 40 units of work will be completed by B in 10 days.<\/p>\n
\nA and B will complete 37 units.
\nRemaining work = 42-37 = 55 units.
\n42 units \u2192 Rs.2100
\n1 unit \u2192 Rs.50
\nThen, Salary of C = 50*5 = Rs.250<\/p>\n
\nA and C will complete 29 units.
\nRemaining work = 36-29 = 7 units.
\n36 units \u2192 Rs.1440
\n1 unit \u2192 Rs.40
\nThen, Salary of B will be 7*40 = Rs.280<\/p>\n