790+ Mocks – Just Rs. 194. Use coupon: SBIDREAM70<\/a><\/p>\n Instructions<\/b>Instructions: In each of these questions, a number series is given. In each series, only one number is wrong. Find out the wrong number.<\/p>\n Question 1:\u00a0<\/b>4 \u00a0 \u00a012 \u00a0 \u00a042 \u00a0 \u00a0196 \u00a0 \u00a01005 \u00a0 \u00a06066 \u00a0 \u00a042511<\/p>\n a)\u00a012<\/p>\n b)\u00a042<\/p>\n c)\u00a01005<\/p>\n d)\u00a0196<\/p>\n e)\u00a06066<\/p>\n Question 2:\u00a0<\/b>2 \u00a0 \u00a08 \u00a0 \u00a012 \u00a0 \u00a020 \u00a0 \u00a030 \u00a0 \u00a042 \u00a0 \u00a056<\/p>\n a)\u00a08<\/p>\n b)\u00a042<\/p>\n c)\u00a030<\/p>\n d)\u00a020<\/p>\n e)\u00a012<\/p>\n Instructions<\/b><\/p>\n Study the following information carefully to answer the questions.<\/p>\n The teacher\u2019s colony has 2800 members, out of which 650 members read only English newspaper. 550 members read only Hindi newspaper and 450 members read only Marathi newspaper. The number of members reading all the 3 newspaper is 100. Members reading Hindi as well as English newspaper are 200. 400 members read Hindi as well as Marathi newspaper and 300 members read English as well as Marathi newspaper.<\/p>\n Question 3:\u00a0<\/b>Find the difference between number of members reading English as well as Marathi newspaper and the number of members reading English as well as Hindi newspaper?<\/p>\n a)\u00a0300<\/p>\n b)\u00a0200<\/p>\n c)\u00a0100<\/p>\n d)\u00a050<\/p>\n e)\u00a0None of these<\/p>\n Download SBI Clerk Previous Papers PDF<\/a><\/p>\n Take a free mock test for SBI Clerk<\/a><\/p>\n Question 4:\u00a0<\/b>How many members read atleast 2 newspapers?<\/p>\n a)\u00a0600<\/p>\n b)\u00a0800<\/p>\n c)\u00a0500<\/p>\n d)\u00a01000<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n In each of the following questions a question is asked followed by three statements.You have to study the questions and all the given three statements and all the statements and decide whether any information provided in the statement are redundant and can be dispensed with while answering the questions ?<\/p>\n Question 5:\u00a0<\/b>What will be the cost of the painting the four walls of a room with length ,width and height is 5,3,8 meters respectively. The room has one window and one door. a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III only<\/p>\n d)\u00a0II or III only<\/p>\n e)\u00a0All are required to answer the question<\/p>\n Question 6:\u00a0<\/b>The time taken by a boat to travel \u2018x\u2019 km upstream is twice the time taken by the same boat to travel \u2018x\u2019 km downstream. If speed of the boat in still water is 12 km\/h, what is the speed of current ? (in km\/h)<\/p>\n a)\u00a03<\/p>\n b)\u00a04<\/p>\n c)\u00a03.5<\/p>\n d)\u00a04.5<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>A tap can empty a tank in one hour. A second tap can empty it in 30 min If both the taps operate simultaneously, how much time is needed to empty the tank ?<\/p>\n a)\u00a020 min<\/p>\n b)\u00a030 min<\/p>\n c)\u00a040 min<\/p>\n d)\u00a045 min<\/p>\n e)\u00a0None of these<\/p>\n Banking Study Material – 18000 Questions<\/a><\/p>\n Daily Free SBI Online Tests<\/a><\/p>\n Question 8:\u00a0<\/b>A sum of money is divided among three employees A, B and C. A\u2019s share is 10 times that of B, whose share is 6 times the share of C. If the sum of money that was divided was Rs 32,294 what is the share of B?<\/p>\n a)\u00a0Rs 2892<\/p>\n b)\u00a0Rs 17892<\/p>\n c)\u00a0Rs 29820<\/p>\n d)\u00a0Rs 482<\/p>\n Question 9:\u00a0<\/b>Three numbers are in such a way that the ratio of the first two numbers is 3 : 5 and the ratio of the second and third numbers is 4 : 1. If the sum of the three numbers is 259, then what is the second number?<\/p>\n a)\u00a0140<\/p>\n b)\u00a0120<\/p>\n c)\u00a035<\/p>\n d)\u00a0135<\/p>\n Instructions<\/b><\/p>\n In the following question, two equations are given. You have to solve both the equations & find out the relationship between the variables:<\/p>\n Question 10:\u00a0<\/b>$10x^2-27x-28=0$ a)\u00a0$x > y$<\/p>\n b)\u00a0$x \\geq y$<\/p>\n c)\u00a0$x < y$<\/p>\n d)\u00a0$x \\leq y$<\/p>\n e)\u00a0x = y or No relationship can be established<\/p>\n 100+ Free GK Tests<\/a><\/p>\n Question 11:\u00a0<\/b>$6x^2-5x+1=0$ a)\u00a0$x > y$<\/p>\n b)\u00a0$x \\geq y$<\/p>\n c)\u00a0$x < y$<\/p>\n d)\u00a0$x \\leq y$<\/p>\n e)\u00a0x = y or No relationship can be established<\/p>\n Question 12:\u00a0<\/b>Mehul sold an item for Rs. 5.025 and incurred a loss of 25% At what price should he have sold the item to have gained a profit of 25% ?<\/p>\n a)\u00a0Rs. 8.375<\/p>\n b)\u00a0Rs. 10,500<\/p>\n c)\u00a0Rs. 8,250<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 13:\u00a0<\/b>The cost price of an item is two-third of its selling price. What is the gain\/loss percent on that item?<\/p>\n a)\u00a045<\/p>\n b)\u00a050<\/p>\n c)\u00a035<\/p>\n d)\u00a054<\/p>\n e)\u00a0None of these<\/p>\n Question 14:\u00a0<\/b>A bag contains 16 eggs out of which 5 are rotten. The remaining eggs are in good condition. If two eggs are drawn randomly, what is the probability that exactly one of the eggs drawn is rotten ?<\/p>\n a)\u00a0$\\frac{11}{24}$<\/p>\n b)\u00a0$\\frac{13}{24}$<\/p>\n c)\u00a0$\\frac{65}{12}$<\/p>\n d)\u00a0$\\frac{17}{24}$<\/p>\n e)\u00a0$\\frac{7}{12}$<\/p>\n Question 15:\u00a0<\/b>In how many different ways can the letters of the word \u2018MARKERS\u2019 be arranged ?<\/p>\n a)\u00a0840<\/p>\n b)\u00a05040<\/p>\n c)\u00a02520<\/p>\n d)\u00a01680<\/p>\n e)\u00a0None of these<\/p>\n Question 16:\u00a0<\/b>What should come in the place of ? in the following series? a)\u00a01270<\/p>\n b)\u00a01260<\/p>\n c)\u00a01290<\/p>\n d)\u00a01296<\/p>\n e)\u00a01236<\/p>\n Instructions<\/b><\/p>\n What should come in the place of ? in the following series?<\/p>\n Question 17:\u00a0<\/b>641, 643, 647, 653, 659, 661, ?<\/p>\n a)\u00a0663<\/p>\n b)\u00a0667<\/p>\n c)\u00a0671<\/p>\n d)\u00a0673<\/p>\n e)\u00a0669<\/p>\n Question 18:\u00a0<\/b>For the following set of equations, determine the value of x + y + z ? a)\u00a08<\/p>\n b)\u00a012<\/p>\n c)\u00a06<\/p>\n d)\u00a05<\/p>\n e)\u00a0cannot be determined<\/p>\n Question 19:\u00a0<\/b>The cost of 4 pens, 5 pencils and 6 sharpener is 80 and the cost of 7 pens, 9 pencils and 11 sharpener is 143. Find the cost of 1 pen, 1 pencil and 1 sharpener?<\/p>\n a)\u00a013<\/p>\n b)\u00a015<\/p>\n c)\u00a016<\/p>\n d)\u00a017<\/p>\n e)\u00a0cannot be determined<\/p>\n Instructions<\/b><\/p>\n The table shows the number of students who appeared in the prelims exams. Both the prelims and mains exams take place every year. Those who clear prelims exams appear in mains exam and those who clear mains exam appear in PI round.<\/p>\n For example, in the year 2016, a total of 90000 students appeared in the prelims exam, 40% of these students cleared prelims examinations and hence, appeared in mains examination. 38% of the students who appeared in mains exams cleared the exam and hence are eligible for PI round.<\/p>\n <\/p>\n Question 20:\u00a0<\/b>What is the number of students who were eligible for PI round in the year 2014?<\/p>\n a)\u00a012000<\/p>\n b)\u00a020000<\/p>\n c)\u00a015000<\/p>\n d)\u00a025000<\/p>\n e)\u00a030000<\/p>\n General Knowledge Questions & Answers PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n (4 x 2) + 22<\/sup>\u00a0= 12 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 2 + 4 = 6\u00a0\u2260 8 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n According to the question, 4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n According to the question, 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Length = 5 m , Breadth = 3 m and Height = 8 m<\/p>\n To find the cost of painting the walls of the room, we should know the cost of painting and the area of door and window.<\/p>\n Area of 4 walls (Curved Surface Area of cuboid) = $2h(l+b)$<\/p>\n = $(2 \\times 8)(5+3) = 16 \\times 8 = 128$ $m^2$<\/p>\n From I & II : Cost = Rs 25 per square meter<\/p>\n Area of window = $2.25$ $m^2$<\/p>\n and Area of door = $2 \\times 2.25 = 4.5$ $m^2$<\/p>\n Thus, area to be painted = $128 – 2.25 – 4.5 = 121.25$ $m^2$<\/p>\n $\\therefore$ Cost of painting 4 walls = $25 \\times 121.25 = Rs$ $3031.25$<\/p>\n Thus, statement III is redundant.<\/p>\n => Ans – (C)<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n REASONING<\/p>\n 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 1 minute work of tap A = $\\frac{1}{60}$<\/p>\n 1 minute work of tap B = $\\frac{1}{30}$<\/p>\n => (A + B)’s 1 minute work = $\\frac{1}{60} + \\frac{1}{30}$<\/p>\n = $\\frac{1 + 2}{60} = \\frac{3}{60}$<\/p>\n = $\\frac{1}{20}$<\/p>\n $\\therefore$ Time taken by (A + B) to empty the tank = 20 min<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the share of B be x. 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Multiply the first ratio by 4 and the second ratio by 5. 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n $10x^2-27x-28=0$ can be written as, 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $6x^2-5x+1=0$ can be written as, 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Mehul Selling Price = Rs.5.025 Now again, Option A is the right answer.<\/p>\n 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given that ,<\/p>\n Cost price (cp) = $\\frac{2}{3}$ selling price(sp)<\/p>\n 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Out of the 16 eggs, 5 eggs are rotten and 11 eggs are in good condition.<\/p>\n According to the question, out of the two eggs drawn one is rotten and the other is in good condition.<\/p>\n Hence, required probability = $ \\frac{^5C_{1} * ^{11}C_{1}}{^{16}C_{2}} = \\frac{5*11}{16*15\/2} = \\frac{11}{24}$<\/p>\n Hence, option A is the right choice.<\/p>\n 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The word MARKERS has 7 letters in which ‘R’ comes twice.<\/p>\n \u2234 Required number of arrangements = $\\frac{7!}{2!}$<\/p>\n = 7*6*5*4*3 = 2520<\/p>\n 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $2^4-2^2 = 16 – 4 = 12$ 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The given series consists of prime numbers from 641. 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n x + 3y + 4z = 16 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the cost of 1 pen be p, 1 pencil be q and 1 sharpener be r 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In the year 2013, we are given that 33000 students appeared in mains round whereas 60000 students appeared in prelims round.<\/p>\n Hence, percentage of appeared candidates who qualified for mains round = $\\dfrac{33000}{60000}\\times 100$ = 55%<\/p>\n Also, number of candidates eligible for PI round = $\\dfrac{20}{100}\\times 33000$ = 6600. In similar way we can calculate missing data for each year. Tabulating the same<\/p>\n From the table, we can see that the number of students who were eligible for PI round in the year 2014 = 15000. Therefore, option C is the correct answer.<\/p>\n
\nI.Cost of painting per square meter is Rs 25
\nII.Area of window is 2.25 sq m which is half of the area of the door
\nIII.Area of the room is 15 sq meter<\/p>\n
\n$6y^2-17y-14=0$<\/p>\n
\n$y^2-7y+12=0$<\/p>\n
\n12, 72, 240, 600, ?<\/p>\n
\nx + 3y + 4z = 16
\n2x + 4y + 5z = 22<\/p>\n<\/figure>\n
\n(12 x 3) + 32<\/sup>\u00a0= 45 \u2260\u00a042
\n(45 x 4) + 42 <\/sup>=\u00a0196
\n(196 x 5) + 52 <\/sup>=\u00a01005
\n(1005 x 6) + 62<\/sup>\u00a0= 6066
\n(6066 x 7) + 72 <\/sup>=\u00a042511<\/p>\n
\n6 + 6 = 12
\n12 + 8 = 20
\n20 + 10 = 30
\n30 + 12 = 42
\n42 + 14 = 56<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2015\/05\/02\/6704.png\")
<\/p>\n
\na=650; f=550;
\ng=450; c=100;
\nb+c=200; c+e = 400;
\nc+d = 300
\nb=100, e=300 and d=200
\nRequired difference = 300-200 = 100<\/p>\n<\/p>\n
\na=650; f=550;
\ng=450; c=100;
\nb+c=200; c+e = 400;
\nc+d = 300
\nb=100, e=300 and d=200
\nNumber of member who read at least two newspapers
\n= b + c + d + e = 100 + 100 + 200 + 300 = 700<\/p>\n
\nSo, share of A = ten times of x = 10x
\nShare of C = one-sixth the share of b = x\/6
\nSo, total amount = 10x + x + x\/6 = 67x\/6 = 32294
\n=> x = Rs 2892<\/p>\n
\nSo, the first ratio becomes 12 : 20 and the second ratio becomes 20 : 5
\nSo, the ratio of the three numbers is 12 : 20 : 5
\nLet the three numbers be 12k, 20k and 5k
\nSum of the numbers = 37k
\n=> 37k = 259
\n=> k = 7
\nSo, the second number is 20k = 20*7 = 140<\/p>\n
\n$(x-\\frac{7}{2})(x+\\frac{4}{5})=0$
\nSo $x = \\frac{7}{2}$ or $x = -\\frac{4}{5}$
\n$6y^2-17y-14=0$ can be written as,
\n$(y+\\frac{2}{3})(y-\\frac{7}{2})=0$
\nSo $y = -\\frac{2}{3}$ or $y = \\frac{7}{2}$
\nx = y or No relationship can be established
\nHence, option E is the correct choice.<\/p>\n
\n$(x-\\frac{1}{2})(x-\\frac{1}{3})=0$
\nSo $x = \\frac{1}{2}$ or $x = \\frac{1}{3}$
\n$y^2-7y+12=0$ can be written as,
\n$(y-3)(y-4)=0$
\nSo $y = 3$ or $y = 4$
\nc: $x < y$
\nHence, option C is the correct choice.<\/p>\n
\nLoss = 25%
\nUsing S.P=C.P(1-(loss\/100)) ,
\nWe get S.P = 0.75C.P
\n=> C.P = Rs.6.7<\/p>\n
\nS.P=C.P(1+(profit\/100))
\nProfit=25 % and C.P.=6.7
\nWe get S.P = 1.25*6.7
\nS.P=Rs. 8.375<\/p>\n\n
\n$3^4-3^2 = 81-9 = 72$
\n$4^4 – 4^2 = 256-16 = 240$
\n$5^4-5^2 = 625-25=600$
\n$6^4 – 6^2 = 1296-36= 1260$
\nTherefore, option B is the right answer.<\/p>\n
\n663 is divisible by 3.
\n665 is divisible by 5.
\n667 is divisible by 23.
\n669 is divisible by 3.
\n671 is divisible by 11.
\n673 is the next prime number after 661. Therefore, option\u00a0D is the right answer.<\/p>\n
\n2x + 4y + 5z = 22
\nSubtracting both equations give
\nx + y + z = 6<\/p>\n
\nThen
\n4p + 5q + 6r = 80
\n7p + 9q + 11 r = 143
\nSubtracting both we get
\n3p + 4q + 5r = 63
\nSubtracting this from equation 1 gives
\np + q + r = 17<\/p>\n<\/figure>\n