{"id":29539,"date":"2019-05-27T15:00:03","date_gmt":"2019-05-27T09:30:03","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=29539"},"modified":"2019-05-27T16:28:17","modified_gmt":"2019-05-27T10:58:17","slug":"rrb-ntpc-previous-year-maths-question-answers-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-ntpc-previous-year-maths-question-answers-pdf\/","title":{"rendered":"RRB NTPC Previous Year Maths Question &#038; Answers PDF Set-2"},"content":{"rendered":"<h2><span style=\"text-decoration: underline; font-size: 20pt;\"><strong>RRB NTPC Previous Year Maths Question &amp; Answers PDF\u00a0Set-2<\/strong><\/span><\/h2>\n<p>Download RRB NTPC\u00a0 Previous Year Maths Questions and Answers PDF. Top 15 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/4627\" target=\"_blank\" class=\"btn btn-danger  download\">Download RRB NTPC Previous Year Maths Questions PDF<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p>Take a <a href=\"https:\/\/cracku.in\/rrb-ntpc-mock-test\" target=\"_blank\" rel=\"noopener\">free mock test for RRB NTPC<\/a><\/p>\n<p>Download <a href=\"https:\/\/cracku.in\/railways-ntpc-previous-papers\" target=\"_blank\" rel=\"noopener\">RRB NTPC Previous Papers PDF<\/a><\/p>\n<p><b>Question 1:\u00a0<\/b>Find the ratio in which a dealer should mix sugar of 12\/- per kg with another sugar of 18\/- per kg so that he can sell the mixture at 20\/- to earn 25% profit ?<\/p>\n<p>a)\u00a02 : 1<\/p>\n<p>b)\u00a01 : 2<\/p>\n<p>c)\u00a02 : 3<\/p>\n<p>d)\u00a03 : 2<\/p>\n<p><b>Question 2:\u00a0<\/b>Pipe A can fill a tank in 2 hrs and pipe B can empty the tank in 2.5 hrs, then find the time in which the tank would be filled if both pipes are opened at the same time ?<\/p>\n<p>a)\u00a010 hrs<\/p>\n<p>b)\u00a012 hrs<\/p>\n<p>c)\u00a08 hrs<\/p>\n<p>d)\u00a06 hrs<\/p>\n<p><b>Question 3:\u00a0<\/b>Find the value of $\\dfrac{1}{sin A} &#8211; \\dfrac{sin A}{cos^2 A}$.<\/p>\n<p>a)\u00a00<\/p>\n<p>b)\u00a01<\/p>\n<p>c)\u00a02cot 2A sec A<\/p>\n<p>d)\u00a02 tan 2A sec A<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/railways-ntpc-previous-papers\" target=\"_blank\" class=\"btn btn-primary \">RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/www.youtube.com\/channel\/UCMDJPaiDdRPv2mrEJoLfklA?sub_confirmation=1\" target=\"_blank\" class=\"btn btn-warning \">FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n<p><b>Question 4:\u00a0<\/b>If cos x + sec x = 3, find the value of $cos^3 x + sec^3 x$.<\/p>\n<p>a)\u00a012<\/p>\n<p>b)\u00a018<\/p>\n<p>c)\u00a015<\/p>\n<p>d)\u00a021<\/p>\n<p><b>Question 5:\u00a0<\/b>If sec x = cosec 5x ( 0 &lt; x &lt; $90^\\circ$), then find the value of x.<\/p>\n<p>a)\u00a012<\/p>\n<p>b)\u00a014<\/p>\n<p>c)\u00a016<\/p>\n<p>d)\u00a015<\/p>\n<p><b>Question 6:\u00a0<\/b>If a = 6, b = 2 and c = -8, then what is the value of $a^3 + b^3 + c^3$?<\/p>\n<p>a)\u00a00<\/p>\n<p>b)\u00a0-2146<\/p>\n<p>c)\u00a0-286<\/p>\n<p>d)\u00a0-288<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-ntpc-mock-test\" target=\"_blank\" class=\"btn btn-danger \">RRB NTPC Free Mock Test<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 7:\u00a0<\/b>If $x + \\dfrac{1}{x} = 3$, find the value of $x^3 + \\dfrac{1}{x^3}$.<\/p>\n<p>a)\u00a015<\/p>\n<p>b)\u00a018<\/p>\n<p>c)\u00a012<\/p>\n<p>d)\u00a09<\/p>\n<p><b>Question 8:\u00a0<\/b>Find $(a+b)(a^2-ab+b^2+3ab)$ = ?<\/p>\n<p>a)\u00a0$(a-b)^3$<\/p>\n<p>b)\u00a0$(b+a)^3$<\/p>\n<p>c)\u00a0$(a+b)^2$<\/p>\n<p>d)\u00a0$(b-a)^3$<\/p>\n<p><b>Question 9:\u00a0<\/b>Find the value of $x$ (from the given options), if $5x^2-13x-6 = 0$ ?<\/p>\n<p>a)\u00a0-2<\/p>\n<p>b)\u00a03\/5<\/p>\n<p>c)\u00a0-3<\/p>\n<p>d)\u00a0-2\/5<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/blog\/general-science-questions-answers-competitive-exams-pdf-mcq-quiz\/\" target=\"_blank\" class=\"btn btn-info \">Download General Science Notes PDF<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 10:\u00a0<\/b>If p, q are the sum and product of the roots of $3x^3-4x^2+5x-6=0$, then find p\/q ?<\/p>\n<p>a)\u00a03<\/p>\n<p>b)\u00a01\/3<\/p>\n<p>c)\u00a02\/3<\/p>\n<p>d)\u00a03\/2<\/p>\n<p><b>Question 11:\u00a0<\/b>Two numbers A and B are in the ratio 2:5. If the sum of squares of numbers is 2349, then find the smallest number.<\/p>\n<p>a)\u00a014<\/p>\n<p>b)\u00a018<\/p>\n<p>c)\u00a020<\/p>\n<p>d)\u00a012<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/blog\/general-science-questions-answers-competitive-exams-pdf-mcq-quiz\/\" target=\"_blank\" class=\"btn btn-info \">Download General Science Notes PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-je-mock-test\" target=\"_blank\" class=\"btn btn-primary \">RRB JE Free Mock Test<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 12:\u00a0<\/b>The ratio of two numbers is 2:5. If the difference between the squares of the numbers is 1029, then find the sum of the two numbers.<\/p>\n<p>a)\u00a035<\/p>\n<p>b)\u00a056<\/p>\n<p>c)\u00a049<\/p>\n<p>d)\u00a028<\/p>\n<p><b>Question 13:\u00a0<\/b>The average weight of 6 employees increases by 3.5 kg when a new employee comes in place of one of them weighing 57 kg. What might be the weight of the new employee?<\/p>\n<p>a)\u00a082 kg<\/p>\n<p>b)\u00a072 kg<\/p>\n<p>c)\u00a088 kg<\/p>\n<p>d)\u00a078 kg<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-online-test\" target=\"_blank\" class=\"btn btn-danger \"> Daily Free RRB Online Tests for RRB Exams<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-ntpc-mock-test\" target=\"_blank\" class=\"btn btn-primary \">RRB NTPC Free Mock Test<\/a><\/p>\n<p><b>Question 14:\u00a0<\/b>What is the value of (361.223-34.567$\\times$2+123.345)<\/p>\n<p>a)\u00a0413.137<\/p>\n<p>b)\u00a0412.267<\/p>\n<p>c)\u00a0415.434<\/p>\n<p>d)\u00a0414.367<\/p>\n<p><b>Question 15:\u00a0<\/b>Find the HCF of two numbers if LCM and product of those two numbers are 45 and 675 respectively ?<\/p>\n<p>a)\u00a025<\/p>\n<p>b)\u00a020<\/p>\n<p>c)\u00a015<\/p>\n<p>d)\u00a035<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/rrb-je-previous-papers\" target=\"_blank\" class=\"btn btn-warning \">Download Current Affairs Questions &amp; Answers PDF<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Selling price of the mixture = 20\/-<\/p>\n<p>Profit % = 25%<\/p>\n<p>1.25(CP) = 20<\/p>\n<p>CP = 16\/-<\/p>\n<p>Let the ratio = m:n<\/p>\n<p>12(m)+18(n) = 16(m+n)<\/p>\n<p>12m + 18n = 16m + 16n<\/p>\n<p>4m = 2n<\/p>\n<p>m\/n = 2\/4 = 1\/2<\/p>\n<p>So the answer is option B.<\/p>\n<p><strong>2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>Let the capacity of tank = LCM of 2 and 2.5 = 10 units<\/p>\n<p>Filling efficiency of pipe A = 10\/2 = 5 units\/hr<\/p>\n<p>Emptying efficiency of pipe B = 10\/2.5 = 4 units\/hr<\/p>\n<p>If both pipes are opened,<\/p>\n<p>The tank will be filled in 10\/(5-4) = 10\/(1) = 10 hrs<\/p>\n<p>So the answer is option A.<\/p>\n<p><strong>3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$1\/sinA &#8211; SinA\/Cos^2A$<br \/>\n= $(cos^2A-sin^2A)\/(sinA.cos^2A)$<br \/>\n= $2(Cos2A)\/(sin2A.CosA)$<br \/>\n= $2Cot2A.secA$<br \/>\nSo the answer is option A<\/p>\n<p><strong>4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Given, cos x + sec x = 3<br \/>\nCubing on both sides,<br \/>\n$(cos x + sec x)^3 = 27$<\/p>\n<p>\u21d2 $cos^3 x + sec^3 x + 3 \\times cos x \\times sec x \\times (cos x + sec x) = 27$<br \/>\n\u21d2 $cos^3 x + sec^3 x + 3 \\times 3 = 27$<br \/>\nTherefore, $cos^3 x + sec^3 x = 27 &#8211; 9 = 18$<\/p>\n<p><strong>5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>sec x = cosec 5x<br \/>\n\u21d2 sec x = sec (90 &#8211; 5x)<br \/>\n\u21d2 x = 90 &#8211; 5x<br \/>\n\u21d2 6x = 90<br \/>\n\u21d2 x = 15<\/p>\n<p><strong>6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Given, a = 6, b = 2, c = -8<br \/>\nHere, a+b+c = 0.<br \/>\nWe know that if a+b+c = 0, then $a^3+b^3+c^3 = 3abc$<br \/>\nTherefore, $a^3 + b^3 + c^3 = 3 \\times 6 \\times 2 \\times (-8) = -288$<\/p>\n<p><strong>7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Given, $x + \\dfrac{1}{x} = 3$<br \/>\nCubing on both sides,<br \/>\n$(x + \\dfrac{1}{x})^3 = 27$<br \/>\n$x^3 + \\dfrac{1}{x^3} + 3 \\times x \\times \\dfrac{1}{x} (x + \\dfrac{1}{x}) = 27$<br \/>\n$x^3 + \\dfrac{1}{x^3} + 3 \\times 3 = 27$<br \/>\nTherefore, $x^3 + \\dfrac{1}{x^3} = 27-9 = 18$<\/p>\n<p><strong>8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>$(a+b)(a^2-ab+b^2+3ab)$ = $(a+b)(a^2+b^2+2ab)$ = $(a+b)(a+b)^2$ = $(a+b)^3$<\/p>\n<p>So the answer is option B.<\/p>\n<p><strong>9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$5x^2-13x-6 = 0$<\/p>\n<p>$5x^2-15x+2x-6 = 0$<\/p>\n<p>$5x(x-3)+2(x-3) = 0$<\/p>\n<p>$(x-3)(5x+2) = 0$<\/p>\n<p>$ x = 3 (or) x = -2\/5$<\/p>\n<p>So the answer is option D.<\/p>\n<p><strong>10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Sum of roots = p = -b\/a = 4\/3<\/p>\n<p>Product of roots = -d\/a = 6\/3\u00a0 = 2<\/p>\n<p>p\/q = (4\/3)\/2 = 2\/3<\/p>\n<p>So the answer is option C.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Let the numbers be 2x and 5x<br \/>\nGiven, $(2x)^2 + (5x)^2 = 2349$<br \/>\n\u21d2 $29x^2 = 2349$<br \/>\n\u21d2 $x^2 = 81$<br \/>\n\u21d2 $x = 9$<br \/>\nHence, Smallest number = 2x = 2*9 = 18<\/p>\n<p><strong>12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Let the two numbers be 2x and 5x.<br \/>\nGiven, $(5x)^2 &#8211; (2x)^2 = 1029<br \/>\n\u21d2 $25x^2 &#8211; 4x^2 = 1029<br \/>\n\u21d2 $21x^2 = 1029<br \/>\n\u21d2 x^2 = 49<br \/>\n\u21d2 x = 7.<br \/>\nThen, the two numbers will be,<br \/>\n2x = 2*7 = 14<br \/>\n5x = 5*7 = 35<br \/>\nThen, Sum of two numbers = 14+35 = 49.<\/p>\n<p><strong>13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Given that the average weight increased by 3.5 Kg when a new employee replaced an older one<br \/>\nSo the total increase in average weight = (6 x 3.5) kg = 21 kg.<br \/>\nAs, the new employee is replacing an older employee, the Weight of new employee = (57 + 21) kg = 78 kg.<\/p>\n<p><strong>14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>By simplifying we get<br \/>\n(292.089+123.345)=415.434<\/p>\n<p><strong>15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>LCM*HCF = 675<\/p>\n<p>(45)*HCF = 675<\/p>\n<p>HCF = 675\/45 = 15<\/p>\n<p>So the answer is option C.<\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_US\" target=\"_blank\" class=\"btn btn-danger \">DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n<p>We hope this Previous Year Maths Questions for RRB NTPC Exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>RRB NTPC Previous Year Maths Question &amp; Answers PDF\u00a0Set-2 Download RRB NTPC\u00a0 Previous Year Maths Questions and Answers PDF. Top 15 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Take a free mock test for RRB NTPC Download RRB NTPC Previous Papers PDF Question [&hellip;]<\/p>\n","protected":false},"author":41,"featured_media":29542,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603,1601],"tags":[489,491,1647,1619],"class_list":{"0":"post-29539","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"category-rrb-ntpc-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-mocks","15":"tag-rrb-ntpc-2019"},"better_featured_image":{"id":29542,"alt_text":"RRB NTPC Previous Year Maths Question & Answers PDF","caption":"RRB NTPC Previous Year  Maths Question & Answers PDF","description":"RRB NTPC Previous Year  Maths Question & Answers 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