{"id":29515,"date":"2019-05-24T18:10:59","date_gmt":"2019-05-24T12:40:59","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=29515"},"modified":"2019-05-24T18:10:59","modified_gmt":"2019-05-24T12:40:59","slug":"sbi-clerk-previous-year-number-series-questions","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/sbi-clerk-previous-year-number-series-questions\/","title":{"rendered":"SBI Clerk Previous Year Number Series Questions"},"content":{"rendered":"

SBI Clerk Previous Year Number Series Questions<\/h1>\n

Download SBI Clerk Number Series Previous Year Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Number Series Previous Year questions on with solutions.<\/p>\n

Download SBI Clerk Previous Year Number Series Questions<\/a><\/p>\n

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Instructions<\/b><\/p>\n

Select the option which replaces (?)<\/p>\n

Question 1:\u00a0<\/b>7, 11, 23, 51, 103, ?<\/p>\n

a)\u00a0187<\/p>\n

b)\u00a0193<\/p>\n

c)\u00a0195<\/p>\n

d)\u00a0185<\/p>\n

e)\u00a0173<\/p>\n

Question 2:\u00a0<\/b>16, 23, 28, 38, ?, 62<\/p>\n

a)\u00a051<\/p>\n

b)\u00a047<\/p>\n

c)\u00a053<\/p>\n

d)\u00a045<\/p>\n

e)\u00a049<\/p>\n

Question 3:\u00a0<\/b>2, 6, 30, 60, 130, ?<\/p>\n

a)\u00a0220<\/p>\n

b)\u00a0210<\/p>\n

c)\u00a0200<\/p>\n

d)\u00a0190<\/p>\n

e)\u00a0180<\/p>\n

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Question 4:\u00a0<\/b>23, 39, 71, 119, ?<\/p>\n

a)\u00a0192<\/p>\n

b)\u00a0181<\/p>\n

c)\u00a0174<\/p>\n

d)\u00a0183<\/p>\n

e)\u00a0185<\/p>\n

Instructions<\/b><\/p>\n

Find the next term in the series.<\/p>\n

Question 5:\u00a0<\/b>11, 26, 51, 76, 115, 174, ?<\/p>\n

a)\u00a0245<\/p>\n

b)\u00a0243<\/p>\n

c)\u00a0217<\/p>\n

d)\u00a0219<\/p>\n

e)\u00a0231<\/p>\n

Question 6:\u00a0<\/b>221, 222, 223, 225, 228, 233, 241, 254, ?<\/p>\n

a)\u00a0263<\/p>\n

b)\u00a0296<\/p>\n

c)\u00a0308<\/p>\n

d)\u00a0275<\/p>\n

e)\u00a0302<\/p>\n

Question 7:\u00a0<\/b>462, 506, 552, 600, 650, ?<\/p>\n

a)\u00a0806<\/p>\n

b)\u00a0718<\/p>\n

c)\u00a0750<\/p>\n

d)\u00a0812<\/p>\n

e)\u00a0702<\/p>\n

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Question 8:\u00a0<\/b>972, 648, 432, 288, ?<\/p>\n

a)\u00a0186<\/p>\n

b)\u00a0192<\/p>\n

c)\u00a0212<\/p>\n

d)\u00a0188<\/p>\n

e)\u00a0200<\/p>\n

Question 9:\u00a0<\/b>17, 34, 31, 124, 119, 714, ?<\/p>\n

a)\u00a04284<\/p>\n

b)\u00a0743<\/p>\n

c)\u00a0707<\/p>\n

d)\u00a0711<\/p>\n

e)\u00a0728<\/p>\n

Instructions<\/b><\/p>\n

Identify the number which will replace the question mark (?).<\/p>\n

Question 10:\u00a0<\/b>11, 13, 16, 21, 28, 39, 52, ?<\/p>\n

a)\u00a089<\/p>\n

b)\u00a083<\/p>\n

c)\u00a069<\/p>\n

d)\u00a067<\/p>\n

e)\u00a072<\/p>\n

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Question 11:\u00a0<\/b>23, 31, 29, 35, 35, 39?<\/p>\n

a)\u00a039<\/p>\n

b)\u00a044<\/p>\n

c)\u00a047<\/p>\n

d)\u00a041<\/p>\n

e)\u00a037<\/p>\n

Question 12:\u00a0<\/b>123, 124, 120, 129, 113, 138, ?<\/p>\n

a)\u00a0102<\/p>\n

b)\u00a0152<\/p>\n

c)\u00a0172<\/p>\n

d)\u00a0113<\/p>\n

e)\u00a0165<\/p>\n

Question 13:\u00a0<\/b>67, 68, 76, ?, 167<\/p>\n

a)\u00a0112<\/p>\n

b)\u00a0103<\/p>\n

c)\u00a097<\/p>\n

d)\u00a0107<\/p>\n

e)\u00a0113<\/p>\n

Question 14:\u00a0<\/b>17, 25, 32, 37, ?, 58<\/p>\n

a)\u00a051<\/p>\n

b)\u00a047<\/p>\n

c)\u00a043<\/p>\n

d)\u00a049<\/p>\n

e)\u00a045<\/p>\n

Instructions<\/b><\/p>\n

Find the missing number in the series.<\/p>\n

Question 15:\u00a0<\/b>14, 30, 63, 130, 265, ?<\/p>\n

a)\u00a0428<\/p>\n

b)\u00a0447<\/p>\n

c)\u00a0489<\/p>\n

d)\u00a0536<\/p>\n

e)\u00a0545<\/p>\n

Question 16:\u00a0<\/b>31, 44, 88, 176, 847, 1595, ?<\/p>\n

a)\u00a05586<\/p>\n

b)\u00a02534<\/p>\n

c)\u00a06537<\/p>\n

d)\u00a01892<\/p>\n

e)\u00a07546<\/p>\n

Question 17:\u00a0<\/b>2, 12, 36, 80, 150, ?<\/p>\n

a)\u00a0212<\/p>\n

b)\u00a0272<\/p>\n

c)\u00a0252<\/p>\n

d)\u00a0220<\/p>\n

e)\u00a0290<\/p>\n

Question 18:\u00a0<\/b>13, 18, 25, 34, 45, ?<\/p>\n

a)\u00a058<\/p>\n

b)\u00a054<\/p>\n

c)\u00a067<\/p>\n

d)\u00a059<\/p>\n

e)\u00a065<\/p>\n

Question 19:\u00a0<\/b>113, 118, 128, 139, 152, ?<\/p>\n

a)\u00a0172<\/p>\n

b)\u00a0159<\/p>\n

c)\u00a0166<\/p>\n

d)\u00a0160<\/p>\n

e)\u00a0162<\/p>\n

Question 20:\u00a0<\/b>Select the option that logically continues the series:<\/p>\n

-2, -3, 8, 95, ?<\/p>\n

a)\u00a0673<\/p>\n

b)\u00a0684<\/p>\n

c)\u00a0691<\/p>\n

d)\u00a0672<\/p>\n

e)\u00a0671<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Taking the difference of consecutive numbers, we have,
\n11 – 7 = 4
\n23 – 11 = 12
\n51 – 23 = 28
\n103-51 = 52
\nTakin difference of the difference of numbers, we have,
\n12- 4 =8
\n23-12 = 16
\n52-28 = 24
\nAccordingly, 52 + 32 = 84
\nSo, the next number must be
\n103 + 84 = 187
\nHence, option A is the right choice.<\/p>\n

2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

16 + 1 +6 = 23
\n23 + 2 + 3 = 28
\n28 + 2 + 8 = 38
\n38 + 3 + 8 = 49
\n49 + 4+ 9 = 62
\nHence, option E is the correct option.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$1^3$ + 1 = 2
\n$2^3$ – 2 = 6
\n$3^3$ + 3 = 30
\n$4^3$ – 4 = 60
\n$5^3$ + 5 = 130
\n$6^3$ – 6 = 210
\nHence, option B is the correct option.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

23+16 = 39
\n39 + 16*2 = 71
\n71 + 16*3 = 119
\n119 + 16*4 = 183
\nHence, option D is the correct option.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The continuous prime numbers are multiplied by 1, 2, 3 and so on<\/p>\n

11
\n13 * 2 = 26
\n17 * 3 = 51
\n19 * 4 = 76
\n23 * 5 = 115
\n29 * 6 = 174
\n31 * 7 = 217<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The difference forms a Fibonacci series
\n1, 1, 2, 3, 5, 8, 13, 21
\nThe series is:
\n221
\n221 + 1 = 222
\n222 + 1 = 223
\n223 + 2 = 225
\n225 + 3 = 228
\n228 + 5 = 233
\n233 + 8 = 241
\n241 + 13 = 254
\n254 + 21 = 275<\/p>\n

Hence, 254 + 21 = 275 is the answer.<\/p>\n

7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The series follows the following pattern:
\n21 * 22 = 462
\n22* 23 = 506
\n23 * 24 = 552
\n24*25 = 600
\n25*26 = 650
\n26*27 = 702<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The series follows the following pattern:
\n972 * (2\/3) = 648
\n648 * (2\/3) = 432
\n432 * (2\/3) = 288
\n288 * (2\/3) = 192<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The series follows the following pattern:
\n17 * 2 = 34
\n34 – 3 = 31
\n31 * 4 = 124
\n124 – 5 = 119
\n119 * 6 = 714
\n714 – 7 = 707<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Consecutive prime numbers are being added in successive terms.
\n11 + 2 =13
\n13 + 3 = 16
\n16 + 5 = 21
\n21 + 7 = 28
\n28 + 11 = 39
\n39 + 13 = 52
\nHence, the next term will be
\n52 + 17 = 69<\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

There are two series in the given set of numbers.
\nThe numbers at odd places form 1 series which is given by
\n23, 29, 35
\nThe numbers at the even places form the second sequence which is given by
\n31, 35, 39
\nHence the next term would be 35+6 = 41<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The pattern being followed is
\n$ 123 + 1^{2} = 124$
\n$ 124 – 2^{2} = 120$
\n$ 120 + 3^{2} = 129$
\n$ 129 – 4^{2} = 113$
\n$ 113 + 5^{2} = 138$
\n$ 138 + 5^{2} = 138$
\nSo the next term would be
\n$ 138 – 6^{2} = 102$<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The difference between the two consecutive terms is the cubes of natural numbers. For example
\n67+1 = 68
\n68+8 = 76
\n76 + 27 = 103
\n103 + 64 = 167
\nHence, the missing term is 103
\nThus, option B is the correct answer.<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The sum of the digits of the previous number is being added to the number to get the new number.
\nFor example:
\n17 + 1 + 7 = 25
\n25 + 2 + 5 = 32
\n32 + 3 + 2 = 37
\n37 + 3 + 7 = 47
\n47 + 4 + 7 = 58
\nHence, the missing number is 47.<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The series follows the following pattern:
\n14
\n14*2 + 2 = 30
\n30 * 2 + 3 = 63
\n63 * 2 + 4 = 130
\n130*2 + 5 = 265
\n265*2 + 6 = 536<\/p>\n

16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The series follows the following pattern:
\n31 + (13) = 44 (reverse of the number is added)
\n44 + 44 = 88
\n88 + 88 = 176
\n176 + 671 = 847
\n847 + 748 = 1595
\n1595 + 5951 = 7546<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The series follows the following pattern:
\n$1^2 + 1^3 = 2$
\n$ 2^2 + 2^3 = 12$
\n$ 3^2 + 3^3 = 36$
\n$4^2 + 4^3 = 80$
\n$5^2 + 5^3 = 150$
\n$6^2 + 6^3 = 252$<\/p>\n

18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The series follows the following pattern:
\n13 + 5 = 18
\n18 + 7 = 25
\n25 + 9 = 34
\n34 + 11 = 45
\n45 + 13 = 58<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The series follows the following pattern:
\n113
\n113 + (1 + 1 + 3) = 118
\n118 + (1 + 1 + 8) = 128
\n128 + (1 + 2 + 8) = 139
\n139 + (1 + 3 + 9) = 152
\n152 + ( 1 + 5 + 2) = 160<\/p>\n

20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The given numbers are of the form $n! – n^2$.
\n$2!-2^2$ = $2-4$=$-2$
\n$3!-3^2$ = $6-9$=$-3$
\n$4!-4^2$ = $24-16$=$8$
\n$5!-5^2$ = $120-25$=$95$
\n$6!-6^2$ = $720-36$=$684$
\nTherefore, option B is the right answer.<\/p>\n

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SBI Clerk Previous Year Number Series Questions Download SBI Clerk Number Series Previous Year Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Number Series Previous Year questions on with solutions. Instructions Select the option which replaces (?) Question 1:\u00a07, 11, 23, 51, 103, ? a)\u00a0187 b)\u00a0193 c)\u00a0195 d)\u00a0185 […]<\/p>\n","protected":false},"author":32,"featured_media":29519,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[232],"tags":[49],"class_list":{"0":"post-29515","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-sbiclerk","8":"tag-sbi-clerk"},"better_featured_image":{"id":29519,"alt_text":"sbi clerk previous year number series questions","caption":"sbi clerk previous year number series questions","description":"sbi clerk previous year number series 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