Download SBI Clerk Simplification Previous Year Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Simplification Previous Year questions on with solutions.<\/p>\n
Download SBI Clerk Previous Year Simplification Questions<\/a><\/p>\n 790+ Mocks – Just Rs. 194. Use coupon: SBIDREAM70<\/a><\/p>\n Instructions<\/b><\/p>\n What should come in place of the question mark (?) in the following question ?<\/p>\n Question 1:\u00a0<\/b>?% of 5600\u00ac28% of 3500=1988<\/p>\n a)\u00a058<\/p>\n b)\u00a055<\/p>\n c)\u00a051<\/p>\n d)\u00a053<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>$\\frac{5}{8}+\\frac{1}{4}+\\frac{7}{12}=?$<\/p>\n a)\u00a0$1\\frac{11}{24}$<\/p>\n b)\u00a0$1\\frac{13}{24}$<\/p>\n c)\u00a0$1\\frac{9}{26}$<\/p>\n d)\u00a0$1\\frac{7}{24}$<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>Simplify: $\\sqrt{19+4\\sqrt{21}}$<\/p>\n a)\u00a0$2+\\sqrt{26} $<\/p>\n b)\u00a0$3-\\sqrt{15} $<\/p>\n c)\u00a0$\\sqrt{5}+\\sqrt{26} $<\/p>\n d)\u00a0$\\sqrt{12}+\\sqrt{7}$<\/p>\n Download SBI Clerk Previous Papers PDF<\/a><\/p>\n Take a free mock test for SBI Clerk<\/a><\/p>\n Instructions<\/b><\/p>\n What should come in place of the question mark (?) in the following question ?<\/p>\n Question 4:\u00a0<\/b>$\\frac{57}{67}\\times\\frac{32}{171}\\times\\frac{45}{128}=?$<\/p>\n a)\u00a0$\\frac{15}{262}$<\/p>\n b)\u00a0$\\frac{15}{268}$<\/p>\n c)\u00a0$\\frac{15}{266}$<\/p>\n d)\u00a0$\\frac{17}{268}$<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>What will come in the place of question mark (?) in the following equation ? a)\u00a0$8^{4}$<\/p>\n b)\u00a0$16^{4}$<\/p>\n c)\u00a0$2^{15}$<\/p>\n d)\u00a0$2^{27}$<\/p>\n e)\u00a0None of these<\/p>\n Question 6:\u00a0<\/b>Simplify: $\\frac{0.0347 \\times 0.0347 \\times 0.0347 + (0.9653)^3}{(0.0347)^2 – (0.347)(0.9653) + (0.9653)^2}$<\/p>\n a)\u00a00.9306<\/p>\n b)\u00a01.0009<\/p>\n c)\u00a01.0050<\/p>\n d)\u00a01<\/p>\n Question 7:\u00a0<\/b>Simplify the surd $ \\frac{7 \\sqrt{7} – 3 \\sqrt{3}}{\\sqrt{7} – \\sqrt{3}}$<\/p>\n a)\u00a0$ 10 + \\sqrt{21}$<\/p>\n b)\u00a0$ 10 – \\sqrt{21}$<\/p>\n c)\u00a0$ \\sqrt{21} – 10 $<\/p>\n d)\u00a0$ 7\\sqrt{3} + 3\\sqrt{7}$<\/p>\n Banking Study Material – 18000 Questions<\/a><\/p>\n Daily Free SBI Online Tests<\/a><\/p>\n Instructions<\/b><\/p>\n Instructions: What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)<\/p>\n Question 8:\u00a0<\/b>$4\\frac{1}{5} + 5\\frac{5}{6} \\times \\frac{24}{7} \\times 2\\frac{4}{5}$ = ?<\/p>\n a)\u00a060<\/p>\n b)\u00a0$60\\frac{1}{5}$<\/p>\n c)\u00a044.8<\/p>\n d)\u00a072.6<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n In the following questions, what will come in the place of the question mark (?)<\/p>\n Question 9:\u00a0<\/b>$ \\dfrac{ \\sqrt{4225} * \\sqrt{?} }{ \\sqrt{6400} }$ = 13<\/p>\n a)\u00a0225<\/p>\n b)\u00a0250<\/p>\n c)\u00a0256<\/p>\n d)\u00a0275<\/p>\n e)\u00a0Can’t be determined<\/p>\n Instructions<\/b><\/p>\n Find the approximate value of the number which should replace (?) in the following questions.<\/p>\n Question 10:\u00a0<\/b>$18.02*21.98 +\\sqrt[3]{4923}*2.969 = ?$<\/p>\n a)\u00a0487<\/p>\n b)\u00a0397<\/p>\n c)\u00a0429<\/p>\n d)\u00a0447<\/p>\n e)\u00a0477<\/p>\n 100+ Free GK Tests<\/a><\/p>\n Question 11:\u00a0<\/b>What is the value of $1.75^3 – 1.25^3$?<\/p>\n a)\u00a03<\/p>\n b)\u00a03.2<\/p>\n c)\u00a03.4<\/p>\n d)\u00a03.6<\/p>\n Question 12:\u00a0<\/b>Simplify the equation: $\\frac{31^3 + 22^3}{31^2 + 22^2 – 682}$<\/p>\n a)\u00a09<\/p>\n b)\u00a053<\/p>\n c)\u00a069<\/p>\n d)\u00a093<\/p>\n Instructions<\/b><\/p>\n What will come in place of question mark \u2018?\u2019 in the following questions?<\/p>\n Question 13:\u00a0<\/b>$\\frac{4}{9} * \\frac{18}{7} * (\\frac{14}{3} * 1.5)$ = ?<\/p>\n a)\u00a08<\/p>\n b)\u00a09<\/p>\n c)\u00a012<\/p>\n d)\u00a016<\/p>\n e)\u00a021<\/p>\n Question 14:\u00a0<\/b>$6\\times 13+6+11-36\\div 12$ =?<\/p>\n a)\u00a029<\/p>\n b)\u00a036<\/p>\n c)\u00a064<\/p>\n d)\u00a078<\/p>\n e)\u00a092<\/p>\n Instructions<\/b><\/p>\n What value should come in place of the question mark (?) in the following questions?<\/p>\n Question 15:\u00a0<\/b>102-(91-(83-(76-17-61))) is equal to?<\/p>\n a)\u00a069<\/p>\n b)\u00a076<\/p>\n c)\u00a083<\/p>\n d)\u00a096<\/p>\n e)\u00a0104<\/p>\n General Knowledge Questions & Answers PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Reframing the question to simplify,<\/p>\n 1988+28% of 3500 = 1988+(28*35)<\/p>\n Which reduces to,<\/p>\n 1988+980=2968<\/p>\n 2968=(x\/100)*5600<\/p>\n x=2968\/56<\/p>\n x=53<\/p>\n 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n $\\frac{5}{8}+\\frac{1}{4}+\\frac{7}{12}=?$<\/p>\n Simplifying,<\/p>\n $\\frac{7}{8}+\\frac{7}{12}=?$<\/p>\n The equation reduces to,<\/p>\n 7*{(1\/8)+(1\/12)}=(35\/24)<\/p>\n Now converting $\\frac{35}{24}$ to mixed fration, we get<\/p>\n $1\\frac{11}{24}$<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let $\\sqrt{19+4\\sqrt{21}} = \\sqrt{a}+\\sqrt{b}$ 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The expression, on reframing gives, $\\frac{57}{171}\\times\\frac{32}{128}\\times\\frac{45}{67}$<\/p>\n which on simplifying gives,<\/p>\n (1\/4)*(1\/3)*(45\/67) = (15\/268)<\/p>\n 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n As $16,8,2$ are all exponents of $2$, let us simplify the expression to the powers of 2.<\/p>\n $16^{7.5} = (2^4)^{7.5} = 2^{30}$ Hence, the given expression looks like this $2^{30} \\div 2^{10.5} \\div 2^{7.5} = 2^{30-10.5-7.5} = 2^{12} = 8^4$<\/p>\n Hence, the correct answer is option (a)<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Numerator is of the form of $a^{3} + b^{3}$ and denominator is of the form of\u00a0\u00a0$a^{2} + b^{2} – ab$ 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let $X = \\frac{7 \\sqrt{7} – 3 \\sqrt{3}}{\\sqrt{7} – \\sqrt{3}}$ $ X = (49 – 3 \\sqrt{21} + 7 \\sqrt{21} – 9)\/4 = 10 + \\sqrt{21}$<\/p>\n 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n We use BEDMAS rule to simplify the expression. We perform multiplication first. 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Sqrt of 4225 = 65 and sqrt of 6400 = 80. Simplifying, ? = 256<\/p>\n 10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n We can approximate $18.02 \\approx 18$ and $21.98 \\approx 22$ 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n To simplify the expression , we use the formula: So, $1.75^3 – 1.25^3$ = (1.75-1.25) * (1.75 ^ 2 + 1.25 ^2 + 1.75 * 1.25) = 0.5 * (3.06 + 1.56 + 2.19) = 3.4<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n We can solve the equation using the formula $a^3 + b^3$ = (a+b) * ($a^2+b^2$-ab) 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n We have to simplify: $\\frac{4}{9} * \\frac{18}{7} * \\frac{14}{3} * 1.5$ 14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n $6\\times 13+6+11-36\\div 12$ =? 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n When we solve questions involving multiple brackets, we solve the inside brackets first and gradually simplify the outer brackets. So,102-(91-(83-(76-17-61))) = 102-(91-(83-(-2)))<\/p>\n Minus of a negative number = positive value of the same number. Hence, 102-(91-(83-(-2))) = 102-(91-(85)) = 102 – 6 = 96<\/p>\n
\n$16^{7.5}\\div8^{3.5}\\div2^{7.5}$=?<\/p>\n
\n$\\rightarrow a+b+2\\sqrt{ab} = 19+4\\sqrt{21}$.
\nHence, a+b=19 and ab=84. Hence a=12, b=7.<\/p>\n
\n$8^{3.5} = (2^3)^{3.5} = 2^{10.5}$<\/p>\n
\nwhere a = .0347 and b= .9653
\nit will get reduce to a+b = 1<\/p>\n
\nMultiplying numerator and denominator by $(\\sqrt{7} + \\sqrt{3})$,<\/p>\n
\nHence, expression = $4\\frac{1}{5} + 5\\frac{5}{6} \\times \\frac{24}{7} \\times 2\\frac{4}{5}$ = $4\\frac{1}{5} + \\frac{35*24*14}{6*7*5}$ = $4\\frac{1}{5} + 4*14$ = $4\\frac{1}{5} + 56$ = $60\\frac{1}{5}$ .<\/p>\n
\nSimilarly, note that $17^3 = 4913$. Hence, $\\sqrt[3]{4923}\\approx 17$
\nAnd, $2.969 \\approx 3$
\nUsing the above approximations, we can simplify the expression to the below value.
\n$18*22 + 17*3 = 396 + 51= 447$<\/p>\n
\n$a^3 – b^3$ = $(a-b)(a^2+b^2+ab)$<\/p>\n
\nSo, the answer is 31 + 22 = 53<\/p>\n
\nSo, we start with dividing 1.5 by 3 getting 0.5
\nSo, the simplified value is $\\frac{4}{9} * \\frac{18}{7}$ * 14 * 0.5 = $\\frac{4}{9} * \\frac{18}{7}$ * 7
\nCancelling out the 7, we get $\\frac{4}{9}$ * 18
\nSo, the simplified value is 4 * 2 = 8<\/p>\n
\nBy B.O.D.M.A.S rule, we have to follow Brackets first, followed by \u201cOf\u201d, followed by division, followed by multiplication, followed by multiplication, followed by addition and finally subtraction.
\nSo, $6\\times 13+6+11-36\\div 12$ becomes $6\\times 13+6+11-3$(We simplify division first as there are no brackets or \u201cof\u201d)
\n$6\\times 13+6+11-3$ then becomes 78 + 6 + 11 – 3 after we simplify multiplication
\nThen we simplify addition to get 95 – 3 = 92<\/p>\n
\n(76-17-61) = 59 – 61 = -2<\/p>\n
\nSo, -(-2) = +2<\/p>\n