Download RRB JE Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>Find the value of $\\dfrac{1}{sin A} – \\dfrac{sin A}{cos^2 A}$.<\/p>\n a)\u00a00<\/p>\n b)\u00a01<\/p>\n c)\u00a02cot 2A sec A<\/p>\n d)\u00a02 tan 2A sec A<\/p>\n Question 2:\u00a0<\/b>If a = 6, b = 2 and c = -8, then what is the value of $a^3 + b^3 + c^3$?<\/p>\n a)\u00a00<\/p>\n b)\u00a0-2146<\/p>\n c)\u00a0-286<\/p>\n d)\u00a0-288<\/p>\n Question 3:\u00a0<\/b>The present ages of Amit and Balu are in the ratio of 4 : 3. After 10 years, their ages will be in the ratio 6 : 5. Find the present age of Balu.<\/p>\n a)\u00a018 years<\/p>\n b)\u00a015 years<\/p>\n c)\u00a021 years<\/p>\n d)\u00a024 years<\/p>\n Question 4:\u00a0<\/b>2.1221-3.1331+4.1441 = ?<\/p>\n a)\u00a09.3993<\/p>\n b)\u00a03.1331<\/p>\n c)\u00a06.2662<\/p>\n d)\u00a0none of these<\/p>\n Question 5:\u00a0<\/b>Study the following information and answer the question below: Which company has consistent increase in loss from years 2017 to 2019 ?<\/p>\n a)\u00a0B<\/p>\n b)\u00a0A<\/p>\n c)\u00a0D<\/p>\n d)\u00a0C<\/p>\n FREE RRB JE YOUTUBE VIDEOS<\/a><\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n\n Question 6:\u00a0<\/b>What is the HCF of 1\/15,4\/3 and 7\/6 ?<\/p>\n a)\u00a01\/30<\/p>\n b)\u00a04\/30<\/p>\n c)\u00a07\/30<\/p>\n d)\u00a028\/30<\/p>\n Question 7:\u00a0<\/b>There are 83 people standing in the queue to buy movie tickets. Alok is 37th from the start while Sachin is 68th from the start. How many people are standing between Alok and Sachin?<\/p>\n a)\u00a028<\/p>\n b)\u00a030<\/p>\n c)\u00a029<\/p>\n d)\u00a031<\/p>\n Question 8:\u00a0<\/b>Find the sum of the following series upto 10 terms: a)\u00a0505<\/p>\n b)\u00a0495<\/p>\n c)\u00a0515<\/p>\n d)\u00a0485<\/p>\n Question 9:\u00a0<\/b>There are 83 people standing in the queue to buy movie tickets. Alok is 37th from the start while Sachin is 68th from the start. How many people are standing between Alok and Sachin?<\/p>\n a)\u00a028<\/p>\n b)\u00a030<\/p>\n c)\u00a029<\/p>\n d)\u00a031<\/p>\n Question 10:\u00a0<\/b>22 boys are standing in front of Kunal in a Queue 12 boys are standing to the back of Rohit in the same queue. If total number of boys is 30 then the number of boys standing in between Kunal and Rohit is<\/p>\n a)\u00a03<\/p>\n b)\u00a04<\/p>\n c)\u00a06<\/p>\n d)\u00a05<\/p>\n RRB JE Free Mock Test<\/a><\/p>\n RRB JE Free Mock Test (latest pattern)<\/a><\/p>\n\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $1\/sinA – SinA\/Cos^2A$ 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Given, a = 6, b = 2, c = -8 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the present ages of Amit and Balu be 4x years and 3x years respectively. 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 2.1221-3.1331+4.1441 = -1.0110+4.1441 = 3.1331<\/p>\n So the answer is option B.<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n From the line chart we can say that D is the only company in which loss has increased each year from 2017 to 2019 i.e 1,3 and 4 in each years respectively<\/p>\n Daily Free Online Tests for RRB Exams<\/a><\/p>\n Download RRB GK Material PDF<\/a><\/p>\n\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n HCF of fractions=HCF of numerators\/LCM of denominators 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Alok is 37th from the start while Sachin is 68th from start 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given terms can be generalized as $(n-1)(n+1)$ starting from $n=2$. Therefore, sum of the series = $(1^2+2^2 + 3^2 + 4^2 +\u2026..11^2)-1 – (1+1+\u202610 \\text{terms})$.
\nLoss in millions for companies A,B,C and D in the years 2017,2018 and 2019 is given in the line chart.<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/d7.png\")
<\/figure>\n
\n1*3 + 2*4 + 3*5 + 4*6 + \u2026..<\/p>\n
\n= $(cos^2A-sin^2A)\/(sinA.cos^2A)$
\n= $2(Cos2A)\/(sin2A.CosA)$
\n= $2Cot2A.secA$
\nSo the answer is option A<\/p>\n
\nHere, a+b+c = 0.
\nWe know that if a+b+c = 0, then $a^3+b^3+c^3 = 3abc$
\nTherefore, $a^3 + b^3 + c^3 = 3 \\times 6 \\times 2 \\times (-8) = -288$<\/p>\n
\nAfter 10 years, their ages will be 4x+10 years and 3x+10 years respectively.
\nGiven, $\\dfrac{4x+10}{3x+10} = \\dfrac{6}{5}$
\n\u21d2 20x+50 = 18x+60
\n\u21d2 2x = 10
\n\u21d2 x = 5.
\nHence, The present age of Balu is 3x = 3*5 = 15 years.<\/p>\n
\nHCF of 1,4,7=1
\nLCM of 15,3,6 is 30
\nRequired answer is 1\/30.<\/p>\n
\nHence the number of people between Sachin and Alok will be 68 – 37 – 1 = 30
\nHence, option B is the right choice.<\/p>\n
\n$(n+1)(n-1) = n^2 -1$
\n$n$ will vary from $2$ to $11$.<\/p>\n
\n= $\\frac{n(n+1)(2n+1)}{6} -10$
\n=$\\frac{11*12*23}{6} – 11$
\n=$506 -11$
\n=$495$.<\/p>\n