Download SSC CGL Time and Work questions with answers PDF based on previous papers very useful for SSC CGL exams. 20 Very important Time and Work objective questions (MCQ’s) for SSC exams.<\/p>\n
Download SSC CGL Time And Work Previous Year Questions PDF<\/a><\/p>\n 25 SSC CGL Mocks – Just Rs. 149<\/a><\/p>\n FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n Question 1:\u00a0<\/b>\u2018L\u2019 can complete a work in 20 days and after working for 5 days, \u2018L\u2019 left the work and the remaining work was completed by \u2018N\u2019 in 12 days. In how many days can they complete the work if they both work together ?<\/p>\n a)\u00a09 days<\/p>\n b)\u00a080\/9 days<\/p>\n c)\u00a079\/9 days<\/p>\n d)\u00a082\/9 days<\/p>\n Question 2:\u00a0<\/b>E is twice as efficient as F. If they both complete a work in 10 days by working together then how many days that E alone takes to complete the same work ?<\/p>\n a)\u00a015 days<\/p>\n b)\u00a07.5 days<\/p>\n c)\u00a030 days<\/p>\n d)\u00a010 days<\/p>\n Question 3:\u00a0<\/b>\u2018I\u2019 can do a piece of work in 7 days and \u2018J\u2019 can do the same piece of work in 35 days and if I,J and K together completes the work in 5 days then time taken for \u2018K\u2019 alone to complete the work is ?<\/p>\n a)\u00a025 days<\/p>\n b)\u00a020 days<\/p>\n c)\u00a035 days<\/p>\n d)\u00a030 days<\/p>\n Question 4:\u00a0<\/b>Kelly is thrice as efficient as Bella and Bella is twice as efficient as Steph. If they take 7 days to complete the work by working together then how many days does Kelly take to complete the whole work alone ?<\/p>\n a)\u00a010 days<\/p>\n b)\u00a012 days<\/p>\n c)\u00a011 days<\/p>\n d)\u00a010.5 days<\/p>\n Question 5:\u00a0<\/b>M can do a piece of work in 6 days and N can do the same work in 18 days and if M and N begin the work together and M left the work after 3 days. How many days N has to work after M has left in order to complete the work ?<\/p>\n a)\u00a08 days<\/p>\n b)\u00a07 days<\/p>\n c)\u00a06 days<\/p>\n d)\u00a05 days<\/p>\n SSC CGL Previous Papers Download PDF<\/a><\/p>\n SSC CHSL PREVIOUS PAPERS DOWNLOAD<\/a><\/p>\n Question 6:\u00a0<\/b>U takes 12 days to complete a work and V takes 48 days to complete the same work. What is the time taken to complete 75% of the work if they both start the work together ?<\/p>\n a)\u00a07.2 days<\/p>\n b)\u00a07.4 days<\/p>\n c)\u00a07.6 days<\/p>\n d)\u00a07 days<\/p>\n Question 7:\u00a0<\/b>A can do a work in 5 days. B can do the same work in 15 days.If the work on alternative days starting with B then in how many days will they complete\u00a0thrice the work?<\/p>\n a)\u00a020 days<\/p>\n b)\u00a021 days<\/p>\n c)\u00a022 days<\/p>\n d)\u00a023 days<\/p>\n Question 8:\u00a0<\/b>16 Girls take 5 days to complete a work. 15 Women take 4 days to complete the same work. If 10 Girls and 9 Women work \u2018x\u2019 days to complete the same work. What is the value of x ?<\/p>\n a)\u00a039\/11 days<\/p>\n b)\u00a040\/11 days<\/p>\n c)\u00a041\/11 days<\/p>\n d)\u00a042\/11 days<\/p>\n Question 9:\u00a0<\/b>14 Men and 16 Women take 5 days to complete a work and 12 Men and 6 Women take 10 days to complete the same work. In how many days will 20 Men and 10 Women complete the work ?<\/p>\n a)\u00a06 days<\/p>\n b)\u00a05 days<\/p>\n c)\u00a04 days<\/p>\n d)\u00a07 days<\/p>\n Question 10:\u00a0<\/b>W takes 9 days to complete a work and X takes 27 days to complete the same work if they work on alternate days starting with X . How many days does it take to complete the work ?<\/p>\n a)\u00a013(2\/3) days<\/p>\n b)\u00a013(1\/3)days<\/p>\n c)\u00a013 days<\/p>\n d)\u00a014 days<\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n Question 11:\u00a0<\/b>\u2018L\u2019 can complete a work in 24 days and after working for 12 days, \u2018L\u2019 left the work and the remaining work was completed by \u2018N\u2019 in 6 days. In how many days can they complete the work if they both work together ?<\/p>\n a)\u00a09 days<\/p>\n b)\u00a08 days<\/p>\n c)\u00a07 days<\/p>\n d)\u00a06 days<\/p>\n Question 12:\u00a0<\/b>A is four times as efficient as B. If they both complete a work in 7 days by working together then how many days that A alone takes to complete the same work ?<\/p>\n a)\u00a035 days<\/p>\n b)\u00a08.5 days<\/p>\n c)\u00a08.75 days<\/p>\n d)\u00a08.25 days<\/p>\n Question 13:\u00a0<\/b>\u2018X\u2019 can do a piece of work in 6 days and \u2018Y\u2019 can do the same piece of work in 30 days and if X,Y and Z together completes the work in 4 days then time taken for \u2018Z\u2019 alone to complete the work is ?<\/p>\n a)\u00a025 days<\/p>\n b)\u00a020 days<\/p>\n c)\u00a035 days<\/p>\n d)\u00a030 days<\/p>\n Question 14:\u00a0<\/b>Kim is four times as efficient as Kong and Kong is twice as efficient as King. If they take 4 days to complete the work by working together then how many days does Kim take to complete the whole work alone ?<\/p>\n a)\u00a06.5 days<\/p>\n b)\u00a06 days<\/p>\n c)\u00a05 days<\/p>\n d)\u00a05.5 days<\/p>\n Question 15:\u00a0<\/b>A can do a piece of work in 10 days and B can do the same work in 40 days and if A and B begin the work together and A left the work after 2 days. How many days B has to work after A has left in order to complete the work ?<\/p>\n a)\u00a028 days<\/p>\n b)\u00a037 days<\/p>\n c)\u00a036 days<\/p>\n d)\u00a035 days<\/p>\n SSC CGL Free Mock Test<\/a><\/p>\n SSC CHSL Free Mock Test<\/a><\/p>\n Question 16:\u00a0<\/b>C takes 17 days to complete a work and V takes 51 days to complete the same work. What is the time taken to complete 50% of the work if they both start the work together ?<\/p>\n a)\u00a051\/8 days<\/p>\n b)\u00a051\/4 days<\/p>\n c)\u00a049\/4 days<\/p>\n d)\u00a049\/8 days<\/p>\n Question 17:\u00a0<\/b>A and B can do a work in 19 days and B and C can do the same work in 95 days and if C can alone do the same work in 76 days, then how many days will A and C take to complete the same work together ?<\/p>\n a)\u00a0190\/7 days<\/p>\n b)\u00a0192\/7 days<\/p>\n c)\u00a0193\/7 days<\/p>\n d)\u00a0191\/7 days<\/p>\n Question 18:\u00a0<\/b>5 Boys take 6 days to complete a work. 6 Men take 4 days to complete the same work. If 2 Boys and 2 Men work \u2018x\u2019 days to complete the same work. What is the value of x ?<\/p>\n a)\u00a017\/3 days<\/p>\n b)\u00a07 days<\/p>\n c)\u00a020\/3 days<\/p>\n d)\u00a019\/3 days<\/p>\n Question 19:\u00a0<\/b>3 Men and 5 Women take 5 days to complete a work and 2 Men and 4 Women take 7 days to complete the same work. In how many days will 2 Men and 2 Women complete the work ?<\/p>\n a)\u00a068\/8 days<\/p>\n b)\u00a09 days<\/p>\n c)\u00a08 days<\/p>\n d)\u00a070\/8 days<\/p>\n Question 20:\u00a0<\/b>A train 450 m long passes a person, walking at 15 km\/hr in the same direction in which the train is going, in 36 seconds. The speed of the train is:<\/p>\n a)\u00a045 km\/hr<\/p>\n b)\u00a060 km\/hr<\/p>\n c)\u00a054 km\/hr<\/p>\n d)\u00a075 km\/hr<\/p>\n 1500+ Free SSC Questions & Answers<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given that L works for only 5 days and L takes 20 days to complete the whole work and so A completes 1\/4th work in 5 days and it is given that N completes the remaining work i.e 3\/4th work in 12 days and so the time required for N to complete the work individually is 16 days i.e 12*(4\/3)=16 days 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n It is given that E is twice as efficient as F and so if F takes x days to complete the work then E takes x\/2 days to complete the same work. 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n It is given that 1\/I + 1\/J +1\/K =1\/5 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n If Steph takes x days to complete the work then Bella takes x\/2 days to complete the work and so Kelly takes x\/6 days to complete the work. 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Total number of units of work to be done is LCM of 6 and 18 =18 units 100+ Free GK Tests for SSC Exams<\/a><\/p>\n Download Free GK PDF<\/a><\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n They both can complete the whole work in x days i.e 7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Total units of work to be done is LCM of 5 and 15 i.e 15 units<\/p>\n Each day A can do 15\/5=3 units of work<\/p>\n Each day B can do 15\/15=1 unit of work<\/p>\n SO total units of work to be done=45 units<\/p>\n Starting from B we have 1+3+1+3\u2026.=45 i.e<\/p>\n 4*11+1=45<\/p>\n So total days=11*2+1<\/p>\n Total days=23<\/p>\n 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Total work in terms of girl days i.e only girls working is 16*5=80 GD 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Total work to de done in terms of MenDays and WomenDays is 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Total units of work that has to be done is lcm of 9 and 27 i.e 27 units. 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given that L works for only 12 days and L takes 24 days to complete the whole work and so L completes 1\/2 th work in 12 days and it is given that N completes the remaining work i.e 50% work in 6 days and so the time required for N to complete the work on its own is 12 days i.e 6*(2\/1)=12 days 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n It is given that A is four times as efficient as B and so if B takes x days to complete the work then A takes x\/4 days to complete the same work. 15000 Questions – Free SSC Study Material<\/a><\/p>\n 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n It is given that 1\/X + 1\/Y +1\/Z =1\/4 Z=20 days<\/p>\n 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n If King takes x days to complete the work then Kong takes x\/2 days to complete the work and so Kim takes x\/8 days to complete the work. 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Total number of units of work to be done is LCM of 10 and 40 =40 units 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n They both can complete the whole work in x days i.e 17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Given 1\/A + 1\/B =1\/19 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Total work in terms of Boy days i.e only boys working is 5*6=30 BD 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Total work to de done in terms of MenDays and WomenDays is substituting 1 MD=3 WD in the 1st equation<\/p>\n Total work is 70 WD i.e 15*3 WD+25 WD= 70 WD<\/p>\n Given 2 Men and 2 Women and so 2*3*x WD+2*x WD=70 WD<\/p>\n 8x=70 WD 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Speed of the train relative to the man= $\\Large\\frac{450}{36}$ m\/sec = $\\Large\\frac{25}{2}\\times\\frac{18}{5}$ km\/hr Let the speed of the train be s km\/hr. Then, relative speed = (s – 15) km\/hr.<\/p>\n s – 15 = 45 $ \\therefore s = 60 km\/hr $<\/p>\n
\nSo time taken for L and N to complete the work working together is (16*20)\/(16+20)=80\/9 days<\/p>\n
\n(1\/x)+(2\/x)=1\/10
\nx=30 days
\nTherefore E takes 30\/2=15 days to complete the work.<\/p>\n
\n(1\/7)+(1\/35)+(1\/K)=1\/5
\n6\/35+1\/K=1\/5
\n1\/K=1\/35
\nK= 35 days<\/p>\n
\nGiven 1\/x + 2\/x + 6\/x = 1\/7
\n9\/x=1\/7
\nx=63 days
\nTherefore Kelly takes 63\/6=10.5 days to complete the work alone.<\/p>\n
\nIn each day M does 3 units of work and N does 1 unit of work
\nSo in first 3 days (3+1)*3=12 units of work is completed and so N takes extra 6 days to complete the remaining 6 units of work.<\/p>\n
\n1\/12 + 1\/48 =1\/x
\nx=48\/5 days
\nFor 75% of the work to get completed it takes (48\/5)*(3\/4)=36\/5 days = 7.2 days.<\/p>\n
\nTotal work in terms of Women days i.e only women working is 15*4=60 WD
\nTherefore 80 GD=60 WD
\n1 WD=4\/3 GD
\nSo total work in terms of given people is 10x GD+9x WD=80 GD
\n10x GD+ 12x GD=80 GD
\n22x=80
\nx=40\/11 days<\/p>\n
\n(14*5)MD+(16*5)WD=70 MD+80 WD
\n(12*10)MD+(6*10)WD=120MD+60 WD
\n70 MD+80 WD=120MD+60 WD
\n50 MD=20 WD
\n1MD =\u2156 WD
\nTotal work is 70MD+80*(5\/2)MD=270 MD
\nGiven 20 Men and 10 Women and so 20x+10*(5\/2)x=270 MD
\n45x=270 MD
\nx=6 days<\/p>\n
\nEach day number of units of work done by W is 27\/9 =3 units.
\nEach day number of units of work done by X is 27\/27=1 unit
\nSo on day 1 X starts and so on day1 1 unit of work is done, day 2 W will work and so 3 units i.e (1+3) units of work is done for 2 days and so total number of units of work to be done is 27 and so in 12 days 24 units of work is done and on 13th day 1 unit is done by X and so 2 units is left it can be done in (2\/3)by W and so toal 13(2\/3) days is required.<\/p>\n
\nSo time taken for L and N to complete the work working together is (12*24)\/(12+24)=8 days<\/p>\n
\n(1\/x)+(4\/x)=1\/7
\nx=35 days
\nTherefore A takes 35\/4=8.75 days to complete the work.<\/p>\n
\n(1\/6)+(1\/30)+(1\/Z)=1\/4
\n6\/30+1\/Z=1\/4
\n1\/Z=1\/20<\/p>\n
\nGiven 1\/x + 2\/x + 8\/x = 1\/4
\n11\/x=1\/4
\nx=44 days
\nTherefore Kim takes 44\/8=5.5 days to complete the work alone.<\/p>\n
\nIn each day A does 4 units of work and B does 1 unit of work
\nSo in first 2 days (4+1)*1=5 units of work is completed and so B takes extra 35 days to complete the remaining 35 units of work.<\/p>\n
\n1\/17 + 1\/51 =1\/x
\nx=51\/4 days
\nFor 50% of the work to get completed it takes (51\/4)*(1\/2)=51\/8 days.<\/p>\n
\n1\/B + 1\/C =1\/95
\nSubtracting these equations we get
\n1\/A – 1\/C = 4\/95
\nGiven that N alone takes 52 days to complete the work and so we have
\n1\/A – 1\/76 =1\/95
\n1\/A=1\/95 + 1\/76
\n1\/A=9\/380
\nA=380\/9 days
\nThe time taken for A and C to complete the work by working together is
\n1\/(380\/9) + 1\/76 =7\/190
\n190\/7 days.<\/p>\n
\nTotal work in terms of Men days i.e only men working is 6*4=24 MD
\nTherefore 30 BD=24 MD
\n1 BD=4\/5 MD
\nSo total work in terms of given people is 2x BD+2x MD=30 BD
\n2x BD + 2x*(5\/4) BD=30 BD
\n(9\/2)x=30
\nx=20\/3 days<\/p>\n
\n(3*5)MD+(5*5)WD=15 MD+25 WD……..1
\n(2*7)MD+(4*7)WD=14MD+28 WD
\n15 MD+25 WD=14 MD+28 WD
\n1 MD=3 WD<\/p>\n
\nx=70\/8 days<\/p>\n
\n= $\\Large\\frac{25}{2}$ m\/sec.<\/p>\n
\n= 45 km\/hr.<\/p>\n