{"id":29245,"date":"2019-05-20T17:55:25","date_gmt":"2019-05-20T12:25:25","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=29245"},"modified":"2019-05-20T17:55:25","modified_gmt":"2019-05-20T12:25:25","slug":"ages-questions-for-rrb-group-d-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ages-questions-for-rrb-group-d-pdf\/","title":{"rendered":"Ages Questions for RRB Group-D PDF"},"content":{"rendered":"

Ages Questions for RRB Group-D PDF<\/strong><\/span><\/h1>\n

Download Top 15 RRB Group-D\u00a0Ages Questions and Answers PDF. RRB Group-D Ages questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download Ages Questions for RRB Group-D PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>The ratio of present ages of a father and a son is 4:7. Father is 24 years older than his son. Then, find present age of father<\/p>\n

a)\u00a048<\/p>\n

b)\u00a056<\/p>\n

c)\u00a062<\/p>\n

d)\u00a032<\/p>\n

Question 2:\u00a0<\/b>The sum of present ages of two brothers is 84 years. Ratio of their present ages is 3:4. Then find the present age of younger brother.<\/p>\n

a)\u00a032<\/p>\n

b)\u00a024<\/p>\n

c)\u00a028<\/p>\n

d)\u00a036<\/p>\n

Question 3:\u00a0<\/b>A is 12 years older than B. After 4 years, B\u2019s age will be half of A\u2019s age. Then, find the present age of A<\/p>\n

a)\u00a024<\/p>\n

b)\u00a020<\/p>\n

c)\u00a018<\/p>\n

d)\u00a016<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

770 Mocks (cracku Pass) Just Rs.199<\/a><\/p>\n\n

Question 4:\u00a0<\/b>The present age of a mother and son are in the ratio 2:1 and the ratio of present ages of father and son is 3:1. If the sum of their ages is 84. Then find present age of son.<\/p>\n

a)\u00a018<\/p>\n

b)\u00a024<\/p>\n

c)\u00a036<\/p>\n

d)\u00a014<\/p>\n

Question 5:\u00a0<\/b>The present age of son is 25% of his father\u2019s age. After 12 years, age of son will be half of his father\u2019s age. Then find present age of father.<\/p>\n

a)\u00a032<\/p>\n

b)\u00a048<\/p>\n

c)\u00a024<\/p>\n

d)\u00a028<\/p>\n

Question 6:\u00a0<\/b>The present ages of a P and Q are in the ratio 3:4. The age of P 4 years ago and the age of Q 6 years ago will be in the ratio of 7:9. Then find the present age of Q.<\/p>\n

a)\u00a024<\/p>\n

b)\u00a018<\/p>\n

c)\u00a012<\/p>\n

d)\u00a032<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

Daily Free RRB Online Test<\/a><\/p>\n

Question 7:\u00a0<\/b>The sum of present ages of a father and a son is 64 years. The age of son is 1\/3rd of the age of his father. Then find the present age of father.<\/p>\n

a)\u00a032<\/p>\n

b)\u00a052<\/p>\n

c)\u00a048<\/p>\n

d)\u00a024<\/p>\n

Question 8:\u00a0<\/b>The present age of B is 50% of present age of A. The difference between their ages after 5 years is 18. Then find the present age of A<\/p>\n

a)\u00a024<\/p>\n

b)\u00a036<\/p>\n

c)\u00a018<\/p>\n

d)\u00a032<\/p>\n

Question 9:\u00a0<\/b>The ratio of ages of A and B 6 years ago was 2:5. After 6 years from now, their ages will be in the ratio 5:8. Then find the present age of B.<\/p>\n

a)\u00a024<\/p>\n

b)\u00a016<\/p>\n

c)\u00a026<\/p>\n

d)\u00a012<\/p>\n

Question 10:\u00a0<\/b>The sum of ages of a father and son is 58. The ratio of ages of them is 19:10. Then find the present age of son.<\/p>\n

a)\u00a020<\/p>\n

b)\u00a032<\/p>\n

c)\u00a018<\/p>\n

d)\u00a010<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 11:\u00a0<\/b>The age of A was double of age of B 5 years ago. 5 years hence, A\u2019s age will be 50% more than B\u2019s age. Then find present age of B<\/p>\n

a)\u00a012<\/p>\n

b)\u00a018<\/p>\n

c)\u00a015<\/p>\n

d)\u00a024<\/p>\n

Question 12:\u00a0<\/b>The present ages of A and B are in the ratio of 2:3. The age of A 4 years hence and the age of B 6 years ago are in the ratio of 5:6. Then find the present age of A<\/p>\n

a)\u00a024<\/p>\n

b)\u00a027<\/p>\n

c)\u00a036<\/p>\n

d)\u00a018<\/p>\n

Question 13:\u00a0<\/b>The present ages of a brother and sister are in the ratio of 5:4. After 18 years, their ages will be in the ratio 8:7. Then find the sum of their present ages<\/p>\n

a)\u00a054<\/p>\n

b)\u00a029<\/p>\n

c)\u00a063<\/p>\n

d)\u00a034<\/p>\n

Question 14:\u00a0<\/b>Which of the answer figures is the right images of the given figure ?
\nP R A Y E R<\/p>\n

a)<\/p>\n

<\/figure>\n

b)<\/p>\n

<\/figure>\n

c)<\/p>\n

<\/figure>\n

d)<\/p>\n

<\/figure>\n

Question 15:\u00a0<\/b>The sum of ages of mother, daughter and son is 87 years. What will be the sum of their ages after 8 years ?<\/p>\n

a)\u00a0110<\/p>\n

b)\u00a0111<\/p>\n

c)\u00a0105<\/p>\n

d)\u00a0101<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the present ages of father and son be 4x and 7x years respectively<\/p>\n

Given 7x-4x = 24 years => x = 8<\/p>\n

Present age of father = 8$\\times$7 = 56 years<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the present ages of two brothers be \u2018x\u2019 and \u2018y\u2019 years respectively<\/p>\n

Given x+y = 84<\/p>\n

x:y = 3:4
\n7 units —-> 84 years
\n1 unit —-> 12 years<\/p>\n

Age of younger brother = 3 units = 36 years<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the present age of B be x years
\nThen the present age of A will be (x+12) years<\/p>\n

After 4 years, their ages will be (x+16) and (x+4) years respectively<\/p>\n

(x+16) = 2(x+4)
\n=> x+16 = 2x+8
\n=> x = 8<\/p>\n

$\\therefore$ Present age of A = x + 12 = 8 + 12 = 20 years<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Ratio of present ages of mother and son is 2:1
\nRatio of ages of father and son is 3:1<\/p>\n

Ratio of father, mother and son is 3:2:1<\/p>\n

Total \u2192 6 units<\/p>\n

6 units —> 84 years
\n1 unit —> 14 years<\/p>\n

Therefore, Present age of son = 14 years<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the present age of father be 4x years.
\nThen the present age of son will be x years<\/p>\n

Age of father after 12 years will be (4x+12) years
\nPresent age of son after 12 years will be (x+12) years
\nGiven (x+12) = $\\large\\frac{1}{2}$(4x+12)<\/p>\n

=> 2x + 24 = 4x + 12
\n=> 2x = 12
\n=> x = 6<\/p>\n

Present age of father = 6$\\times$4 = 24 years<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the present ages of P and Q be 3x and 4x years respectively<\/p>\n

Then age of P 4 years ago will be (3x-4) years<\/p>\n

Age of Q 6 years ago will be (4x-6) years<\/p>\n

Given $\\Large\\frac{3x-4}{4x-6}$ $=$ $\\Large\\frac{7}{9}$<\/p>\n

=> (3x-4)(9) = (4x-6)(7)
\n=> 27x – 36 = 28x – 42
\n=> x = 6<\/p>\n

Present age of Q = 6$\\times$4 = 24 years<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the present ages of father be 3x years.
\nThen the present age of son will be x years<\/p>\n

Given 3x+x = 64 years.
\n=> 4x = 64 => x = 16 years<\/p>\n

Present age of father = 16$\\times$3 = 48 years.<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the present age of A be 2x years
\nThen, the present age of B will be x years<\/p>\n

The difference between their ages 5 years later will be same as now.<\/p>\n

=> 2x-x = 18 => x = 18 years
\nPresent age of A = 18$\\times$2 = 36 years<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the ages of A and B 6 years ago be 2x and 5x years respectively<\/p>\n

Then the ages of A and B after 6 years will be 2x+12 and 5x+12 years respectively<\/p>\n

Given $\\Large\\frac{2x+12}{5x+12}$ $=$ $\\Large\\frac{5}{8}$<\/p>\n

=> (2x+12)(8) = (5x+12)(5)
\n=> 14x + 96 = 25x + 60
\n=> 9x = 36
\n=> x = 4<\/p>\n

Age of B 6 years ago is 5$\\times$4 = 20 years
\nPresent age of B = 20+6 = 26 years<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the ages of Father and son be \u2018F\u2019 and \u2018S\u2019 respectively.
\nGiven F+S = 58<\/p>\n

F : S = 19 : 10<\/p>\n

Total units = 29 units<\/p>\n

29 units —> 58 years => 1 unit —> 2 years<\/p>\n

Son\u2019s age = 10$\\times$2 = 20 years<\/p>\n

11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Ratio of ages of A and B 5 years ago are 2:1<\/p>\n

Ratio of ages of A and B 5 years hence are 3:2<\/p>\n

Difference in time period = 10 years<\/p>\n

Difference in age units = 1 unit<\/p>\n

=> 1 unit = 10 years<\/p>\n

=> Age of B 5 years ago is 1 unit = 10 years<\/p>\n

=> Present age of B = 10+5 = 15 years<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the present ages of A and B be 2x,3x respectively<\/p>\n

Then A\u2019s age 4 years hence will be 2x+4
\nB\u2019s age 6 years ago will be 3x-6<\/p>\n

Given $\\Large\\frac{2x+4}{3x-6}$ $=$ $\\Large\\frac{5}{6}$<\/p>\n

=> 12x+24 = 15x-30
\n=> 3x = 54
\n=> x=18
\n$\\therefore$ Present age of A = 18$\\times$2 = 36 years<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the present ages of brother and sister be 5x , 4x respectively
\nThen after 18 years, their ages will be 5x+18 , 4x+18 respectively<\/p>\n

Given $\\Large\\frac{5x+18}{4x+18}$ $=$ $\\Large\\frac{8}{7}$<\/p>\n

=> (5x+18)(7) = (4x+18)(8)
\n=> 35x+126 = 32x+144
\n=> 3x = 18
\n=> x = 6<\/p>\n

$\\therefore$ Present ages of brother and sister are 5$\\times$6 = 30 years and 4$\\times$6 = 24 years respectively.<\/p>\n

Sum of their ages = 30+24 = 54 years<\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Word\u00a0: P R A Y E R<\/p>\n

In the image of the word, the letters will swap position, i.e. first letter will come at end, second at second last and so on, thus first and last options are not possible. Also, direction of the letters will also be reversed.<\/p>\n

=> Ans – (C)<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let ages of mother, daughter and son are $m,d,s$ respectively.<\/p>\n

According to ques, => $(m+d+s)=87$ ————(i)<\/p>\n

Now, sum of their ages after 8 years,<\/p>\n

= $(m+8)+(d+8)+(s+8)$<\/p>\n

= $(m+d+s)+24$<\/p>\n

= $87+24=111$ years<\/p>\n

=> Ans – (B)<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Ages Questions for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Ages Questions for RRB Group-D PDF Download Top 15 RRB Group-D\u00a0Ages Questions and Answers PDF. RRB Group-D Ages questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0The ratio of present ages of a […]<\/p>\n","protected":false},"author":41,"featured_media":29249,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679],"tags":[489,491,492,1647],"class_list":{"0":"post-29245","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-group-d","14":"tag-rrb-mocks"},"better_featured_image":{"id":29249,"alt_text":"Ages Questions for RRB Group-D PDF","caption":"Ages Questions for RRB Group-D PDF","description":"Ages Questions for RRB Group-D PDF","media_type":"image","media_details":{"width":1200,"height":630,"file":"2019\/05\/fig-20-05-2019_10-30-39.jpg","sizes":{"thumbnail":{"file":"fig-20-05-2019_10-30-39-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-150x150.jpg"},"medium":{"file":"fig-20-05-2019_10-30-39-300x158.jpg","width":300,"height":158,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-300x158.jpg"},"medium_large":{"file":"fig-20-05-2019_10-30-39-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-768x403.jpg"},"large":{"file":"fig-20-05-2019_10-30-39-1024x538.jpg","width":1024,"height":538,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-1024x538.jpg"},"tiny-lazy":{"file":"fig-20-05-2019_10-30-39-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-30x16.jpg"},"td_80x60":{"file":"fig-20-05-2019_10-30-39-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-80x60.jpg"},"td_100x70":{"file":"fig-20-05-2019_10-30-39-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-100x70.jpg"},"td_218x150":{"file":"fig-20-05-2019_10-30-39-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-218x150.jpg"},"td_265x198":{"file":"fig-20-05-2019_10-30-39-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-265x198.jpg"},"td_324x160":{"file":"fig-20-05-2019_10-30-39-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-324x160.jpg"},"td_324x235":{"file":"fig-20-05-2019_10-30-39-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-324x235.jpg"},"td_324x400":{"file":"fig-20-05-2019_10-30-39-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-324x400.jpg"},"td_356x220":{"file":"fig-20-05-2019_10-30-39-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-356x220.jpg"},"td_356x364":{"file":"fig-20-05-2019_10-30-39-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-356x364.jpg"},"td_533x261":{"file":"fig-20-05-2019_10-30-39-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-533x261.jpg"},"td_534x462":{"file":"fig-20-05-2019_10-30-39-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-534x462.jpg"},"td_696x0":{"file":"fig-20-05-2019_10-30-39-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-696x365.jpg"},"td_696x385":{"file":"fig-20-05-2019_10-30-39-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-696x385.jpg"},"td_741x486":{"file":"fig-20-05-2019_10-30-39-741x486.jpg","width":741,"height":486,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-741x486.jpg"},"td_1068x580":{"file":"fig-20-05-2019_10-30-39-1068x580.jpg","width":1068,"height":580,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-1068x580.jpg"},"td_1068x0":{"file":"fig-20-05-2019_10-30-39-1068x561.jpg","width":1068,"height":561,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-1068x561.jpg"},"td_0x420":{"file":"fig-20-05-2019_10-30-39-800x420.jpg","width":800,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39-800x420.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":null,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/05\/fig-20-05-2019_10-30-39.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n