Download SBI Clerk Problems on Ages Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Problems on Ages questions on with solutions.<\/p>\n
Download Problems On Ages For SBI Clerk<\/a><\/p>\n 790+ Mocks – Just Rs. 194. Use coupon: SBIDREAM70<\/a><\/p>\n Question 1:\u00a0<\/b>In 8 years, Ramesh will be twice as old as Farheen was 8 years ago. If Ramesh is now 16 years older than Farheen, the present age of Farheen is :<\/p>\n a)\u00a032<\/p>\n b)\u00a040<\/p>\n c)\u00a036<\/p>\n d)\u00a044<\/p>\n e)\u00a024<\/p>\n Question 2:\u00a0<\/b>A was thrice as old as B when C was 2 years old. A will be twice as old as B when C is 10 years old. How old will B be when the difference between the ages of A and B will be equal to the age of C?<\/p>\n a)\u00a016 years<\/p>\n b)\u00a022 years<\/p>\n c)\u00a018 years<\/p>\n d)\u00a024 years<\/p>\n e)\u00a032 years<\/p>\n Question 3:\u00a0<\/b>The ratio of P\u2019s age 3 years ago and Q\u2019s age after 5 years is 6 : 13. If at present, the ratio of their ages is 11 : 20, then what is the ratio of P\u2019s age 2 years hence and Q\u2019s age 5 years ago?<\/p>\n a)\u00a0$\\frac{9}{11}$<\/p>\n b)\u00a0$\\frac{7}{9}$<\/p>\n c)\u00a0$\\frac{5}{13}$<\/p>\n d)\u00a0$\\frac{7}{11}$<\/p>\n e)\u00a0$\\frac{8}{13}$<\/p>\n Download SBI Clerk Previous Papers PDF<\/a><\/p>\n Take a free mock test for SBI Clerk<\/a><\/p>\n Question 4:\u00a0<\/b>The sum of the ages of a P and Q is 53 years. Four years ago, the product of their ages was two times the square of Q\u2019s age. The present age of P is?<\/p>\n a)\u00a034 years<\/p>\n b)\u00a038 years<\/p>\n c)\u00a032 years<\/p>\n d)\u00a042 years<\/p>\n e)\u00a036 years<\/p>\n Question 5:\u00a0<\/b>The present age of Sanjay is 40 percent of his mother\u2019s present age. 8 years from now, he will be half as old as his mother. What is the sum of present ages of Sanjay and his mother?<\/p>\n a)\u00a042 years<\/p>\n b)\u00a070 years<\/p>\n c)\u00a056 years<\/p>\n d)\u00a084 years<\/p>\n e)\u00a050 years<\/p>\n Question 6:\u00a0<\/b>The age of Visu is 10 more than the age of Kamal. If their ages were in the ratio 9:7 before 10 years, what is the age of Kamal now?<\/p>\n a)\u00a035 years<\/p>\n b)\u00a045 years<\/p>\n c)\u00a055 years<\/p>\n d)\u00a025 years<\/p>\n e)\u00a040 years<\/p>\n Question 7:\u00a0<\/b>A and B are siblings. A\u2019s age before 7 years was twice as that of B. After 5 years, the ratio of age of A and B will be 6:5. What is the age of B now?<\/p>\n a)\u00a013 years<\/p>\n b)\u00a012 years<\/p>\n c)\u00a010 years<\/p>\n d)\u00a06 years<\/p>\n e)\u00a07 years<\/p>\n Banking Study Material – 18000 Questions<\/a><\/p>\n Daily Free SBI Online Tests<\/a><\/p>\n Question 8:\u00a0<\/b>At the time of their marriage, the average age of the couple was 27 years. x years later, they gave birth to twins. After another \u2018x\u2019 years another set of twins were born. When the second set of twins were 5 years old, the average age of the family was 18 years. Find the value of \u2018x\u2019?<\/p>\n a)\u00a02 years<\/p>\n b)\u00a03 years<\/p>\n c)\u00a04 years<\/p>\n d)\u00a05 years<\/p>\n e)\u00a06 years<\/p>\n Question 9:\u00a0<\/b>The average age of a family of 8 members was 25 years before 5 years. Before 3 years, a person passed away at the age of 66. Just after the person passed away, one of the family members married a girl of age 26 years. What is the average age of the family now?<\/p>\n a)\u00a024 years<\/p>\n b)\u00a025 years<\/p>\n c)\u00a026 years<\/p>\n d)\u00a027 years<\/p>\n e)\u00a028 years<\/p>\n Question 10:\u00a0<\/b>Shanti’s age after six years will be four-ninth of her father’s age. Ten years ago the ratio of their ages was 4:19. What is Shanti’s father’s present age?<\/p>\n a)\u00a054 years<\/p>\n b)\u00a049 years<\/p>\n c)\u00a048 years<\/p>\n d)\u00a052 years<\/p>\n e)\u00a050 years<\/p>\n 100+ Free GK Tests<\/a><\/p>\n Question 11:\u00a0<\/b>A family consists of 3 members A, B and C. C is the child of A and B. After 1 year, the age of C will be the difference between the ages of A and B . Also, the average age of the family after a year will be 16 years. What is the age of the eldest member of the family?<\/p>\n a)\u00a022 years<\/p>\n b)\u00a023 years<\/p>\n c)\u00a024 years<\/p>\n d)\u00a025 years<\/p>\n e)\u00a030 years<\/p>\n Question 12:\u00a0<\/b>Four years ago the average age of the family of 5 members was 18. A baby was born in these 4 years such that the current average age of the family increased by 0.5. What is the current age of the baby?<\/p>\n a)\u00a04<\/p>\n b)\u00a02<\/p>\n c)\u00a01<\/p>\n d)\u00a00<\/p>\n e)\u00a03<\/p>\n Question 13:\u00a0<\/b>The product of ages of Harris and Sharma is 240 .If twice the age of Sharma is more than Harris age by 4 years ,what is Sharma age in years?<\/p>\n a)\u00a012<\/p>\n b)\u00a020<\/p>\n c)\u00a010<\/p>\n d)\u00a014<\/p>\n e)\u00a0Data adequate<\/p>\n Question 14:\u00a0<\/b>If the ages of P and R added to twice the age of Q ,the total becomes 59 .If the age of Q and R are added to thrice age of P,the total becomes 68 and if the age of the P is added to thrice age of Q and thrice the age age of R the total becomes 108 .What is the age of P?<\/p>\n a)\u00a015 years<\/p>\n b)\u00a019 years<\/p>\n c)\u00a017 years<\/p>\n d)\u00a012 years<\/p>\n e)\u00a0None of these<\/p>\n Question 15:\u00a0<\/b>Jayesh is twice as old as Vijay and half as old as Suresh .If sum of Suresh\u2019s and Vijay\u2019s age is 85 years what is the Jayesh\u2019s age in years?<\/p>\n a)\u00a034<\/p>\n b)\u00a036<\/p>\n c)\u00a068<\/p>\n d)\u00a0Cannot determined<\/p>\n e)\u00a0None of these<\/p>\n Question 16:\u00a0<\/b>4 years ago, the respective ratio between ${1 \\over 2}$ of A\u2019s age at that time and four times of B\u2019s age at that time was 5: 12. Eight years hence ${1 \\over 2}$ of A\u2019s age at that time will be less than B\u2019s age at that time by 2 years. What is B\u2019s present age ?<\/p>\n a)\u00a010 years<\/p>\n b)\u00a014 years<\/p>\n c)\u00a012 years<\/p>\n d)\u00a05 years<\/p>\n e)\u00a08 years<\/p>\n Question 17:\u00a0<\/b>The sum of the present ages of P and Q is 25 years more than the age of R. The present age of Q is 5 years more than that of R. Find the present age\u00a0 of P<\/p>\n a)\u00a020 years<\/p>\n b)\u00a025 years<\/p>\n c)\u00a021 years<\/p>\n d)\u00a022 years<\/p>\n e)\u00a0None of these<\/p>\n Question 18:\u00a0<\/b>Samir\u2019s age is one-fourth of his father\u2019s age and two-third of his sister Reema\u2019s age. What is the ratio of the ages of Samir, Reema and their father respectively?<\/p>\n a)\u00a03 : 2 : 8<\/p>\n b)\u00a03 : 4 : 8<\/p>\n c)\u00a02 : 3 : 8<\/p>\n d)\u00a04 : 3 : 8<\/p>\n e)\u00a0None of these<\/p>\n Question 19:\u00a0<\/b>The present ages of Trisha and Shalini are in the ratio of 7: 6 respectively . After 8 years the ratio of their ages will be 9 : 8. What is the difference in their ages ?<\/p>\n a)\u00a04 years<\/p>\n b)\u00a08 years<\/p>\n c)\u00a010 years<\/p>\n d)\u00a012 years<\/p>\n e)\u00a0None of these<\/p>\n Question 20:\u00a0<\/b>The ages of Shirish and Kunder are in the ratio of 5 : 6 respectively. After 8 years the ratio of their ages will be 7 : 8. What is the difference in their ages<\/p>\n a)\u00a04 years<\/p>\n b)\u00a08 years<\/p>\n c)\u00a010 years<\/p>\n d)\u00a012 years<\/p>\n e)\u00a0None of these<\/p>\n General Knowledge Questions & Answers PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us assume the present age of Farheen = x years Ramesh\u2019s age after 8 years will be = x+16+8 = x+24 years $\\Rightarrow$ x+24 = 2*(x-8) So the present age of Farheen will be 40 years.<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the age of A and B initially be \u2018a\u2019 and \u2018b\u2019 respectively.<\/p>\n When C = 2, a\/b = 3 When C is as old as the difference between the ages of A and B, i.e, when C is 24-8 = 16 years old, age of B will be 8+14 = 22 years. Therefore, option B is the right answer.<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n We have, Hence, option D is the right answer.<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the age of P and Q be p and q respectively. 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the present age of Sanjay\u2019s mother be \u2018x\u2019. So Sanjay\u2019s present age will be .4x 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the age of Kamal now be k. 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the age of A be $a$ and B be $b$.<\/p>\n We know that $\\frac{a-7}{b-7} = \\frac{2}{1}$ We also know that after 5 years, the ratio of ages of A and B will be $6:5$. (1) can be written as $-5a+10b=35$ 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n We know that the average age at the time of marriage was 27 years. Hence, the sum of their ages will be 27*2 = 54 years. 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Total age of the family before 5 years = 25*8 = 200 years. 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the present age of Shanti and her father be \u2018s\u2019 and \u2018f\u2019 respectively. 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the ages of A and B be \u2018a\u2019 and \u2018b\u2019. Let us assume \u2018a\u2019 to be the eldest person. 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Four years ago the sum of the age of the family = 18*5 = 90 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n let age of sharma = x<\/p>\n let age of harris = y<\/p>\n xy = 240<\/p>\n 2x = y+4<\/p>\n on solving these two equations<\/p>\n y = 20 or -24<\/p>\n age must be positive, so y = 20<\/p>\n x = 12<\/p>\n answer is option A<\/p>\n 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let ages of P,Q and R be $p,q,r$ respectively<\/p>\n According to ques, => $(p+r)+2q=59$ ————(i)<\/p>\n and $(q+r)+3p=68$ ————-(ii)<\/p>\n and $p+3q+3r=108$ ————(iii)<\/p>\n Multiplying equation (ii) by 3, => $3q+3r+9p = 204$ ———-(iv)<\/p>\n Subtracting equation (iii) from (iv), we get\u00a0:<\/p>\n => $(9p-p)=(204-108)$<\/p>\n => $8p=96$<\/p>\n => $p=\\frac{96}{8}=12$ years<\/p>\n => Ans – (D)<\/p>\n 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let Vijay’s age = $x$ years<\/p>\n => Jayesh’s age = $2x$ years and Suresh’s age = $4x$ years<\/p>\n Sum of Suresh’s and Vijay’s ages = $(4x+x)=85$<\/p>\n => $x=\\frac{85}{5}=17$<\/p>\n $\\therefore$ Jayesh’s age = $2x=2 \\times 17=34$ years<\/p>\n => Ans – (A)<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let B’s present age = $x$ years<\/p>\n and A’s present age = $y$ years<\/p>\n Acc. to ques, => $\\frac{\\frac{1}{2} (y – 4)}{4 (x – 4)} = \\frac{5}{12}$<\/p>\n => $6 (y – 4) = 20 (x – 4)$<\/p>\n => $6y – 24 = 20x – 80$<\/p>\n => $10x – 3y = 28$ ————(i)<\/p>\n Also, $(x + 8) – \\frac{1}{2} (y + 8) = 2$<\/p>\n => $2x + 16 – y – 8 = 4$<\/p>\n => $2x – y = -4$ ————-(ii)<\/p>\n Applying the operation, (i) – 3*(ii), we get\u00a0:<\/p>\n => $(10x – 6x) + (-3y + 3y) = 28 + 12$<\/p>\n => $x = \\frac{40}{4} = 10$ years<\/p>\n 17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let present ages of P,Q and\u00a0R be $p,q,r$ years respectively.<\/p>\n => $q = r + 5$ ————(i)<\/p>\n and $p + q = r + 25$ ————(ii)<\/p>\n Subtracting eqn(i) from (ii), we get\u00a0:<\/p>\n => $p = 25 – 5 = 20$<\/p>\n $\\therefore$ Present age of P = 20 years<\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let Samir’s father’s age = $x$ years<\/p>\n => Samir’s age = $\\frac{x}{4}$ years<\/p>\n => Reema’s age = $\\frac{3}{2} \\times \\frac{x}{4}$<\/p>\n = $\\frac{3x}{8}$ years<\/p>\n $\\therefore$ Ratio of\u00a0Samir , Reema and their father’s age<\/p>\n = $\\frac{x}{4} : \\frac{3x}{8} : x$<\/p>\n = 2\u00a0: 3\u00a0: 8<\/p>\n 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let present ages of Trisha and Shalini be $7x$ and $6x$ years respectively.<\/p>\n Acc. to ques, ratio of their ages after 8 years<\/p>\n => $\\frac{7x + 8}{6x + 8} = \\frac{9}{8}$<\/p>\n => $56x + 64 = 54x + 72$<\/p>\n => $56x – 54x = 72 – 64$<\/p>\n => $2x = 8$<\/p>\n => $x = \\frac{8}{2} = 4$<\/p>\n $\\therefore$\u00a0Difference in their ages = $7x – 6x = x$<\/p>\n = 4 years<\/p>\n 20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let present ages of Shirish and Kunder be $5x$ and $6x$ years respectively.<\/p>\n Acc. to ques, ratio of their ages after 8 years<\/p>\n => $\\frac{5x + 8}{6x + 8} = \\frac{7}{8}$<\/p>\n => $40x + 64 = 42x + 56$<\/p>\n => $42x – 40x = 64 – 56$<\/p>\n => $2x = 8$<\/p>\n => $x = \\frac{8}{2} = 4$<\/p>\n $\\therefore$\u00a0Difference in their ages = $6x – 5x = x$<\/p>\n = 4 years<\/p>\n
\nSo present age of Ramesh will be = x + 16 years<\/p>\n
\nFarheen\u2019s age 8 years ago = x – 8 years<\/p>\n
\n$\\Rightarrow$ x= 40 years<\/p>\n
\n=> a = 3b
\nWhen C = 10, 8 years have passed.
\n=> (a+8)\/(b+8) = 2
\na+8 = 2b + 16
\na = 2b+8
\n=> b = 8 years and a = 24 years.<\/p>\n
\n$\\frac{P – 3}{Q + 5} = \\frac{6}{13}$
\nSo, 13P – 39 = 6Q + 30
\n13P – 6Q = 69
\n$\\frac{P}{Q} = \\frac{11}{20}$
\n20P – 11Q = 0
\nSolving both the equations we have,
\nP = 33 years and Q = 60 years
\nSo, $\\frac{P + 2}{Q – 5} = \\frac{35}{55} = \\frac{7}{11}$<\/p>\n
\nWe have, p+q = 53
\n$(p-4)(q-4) = 2 * (q-4)^2$
\np-4 = 2q – 8
\np = 2q – 4
\nSubstituing the value of p in first equation,
\n3q – 4 = 53
\nq = 19
\np = 53 – 19 = 34
\nHence, option A is right choice.<\/p>\n
\nWe have been given that
\n(.4x + 8)*2 = x + 8
\n=> .8x + 16 = x + 8
\n=> .2x = 8
\n=> x = 40
\nHence, the present age of the mother is 40 years. Thus, required sum = 56.<\/p>\n
\nAge of Visu = k+10.
\nWe know that, (k+10 -10)\/(k-10) = 9\/7
\n7k = 9k – 90
\n2k = 90
\nk = 45 years
\nTherefore, option B is the right answer.<\/p>\n
\n$a-7 = 2b – 14$
\n$2b-a = 7$ ———–(1)<\/p>\n
\n$\\frac{a+5}{b+5} = \\frac{6}{5}$
\n$5a + 25 = 6b+30$
\n$5a-6b=5$ ———-(2)<\/p>\n
\n(2) can be written as $5a-6b=5$
\n=> $4b = 40$
\n$b = 10$years.
\nTherefore, option C is the right answer.<\/p>\n
\nAfter \u2018x\u2019 years, the sum of their ages will be 54 + 2x.
\nAfter another \u2018x\u2019 years, the sum of the ages of the entire family will be 54 + 2x + 4x = 54 + 6x.
\nNow when the second set of twins are 5 years old, the sum of the ages of all the members of the family will be 54 + 6x + 30 = 84 + 6x
\nWe have been given that this is equal to 18*6. Hence, we have
\n84 + 6x = 18*6
\n=> 6x = 24
\n=> x = 4<\/p>\n
\nTotal age of the family just before the person passed away = 200 + 2*8 = 216 years.
\nTotal age of the family after the person passed away = 216 – 66 = 150 years
\nTotal age of the family just after the marriage = 150+26 = 176 years.
\nTotal age of the family now = 176+3*8 = 200 years.
\nAverage age of the family now = 200\/8 = 25 years.
\nTherefore, option B is the right answer.<\/p>\n
\nSo we have, s+6 = $\\frac{4}{9}$*(f+6)
\n9s + 30 = 4f
\nAlso, $\\frac{s-10}{f-10} = \\frac{4}{19}$
\n19s = 150 + 4f
\nSolving both the equations we get,
\ns = 18 years
\nSo, f = (18*9+30)\/4 = 48 years
\nHence, option C is the correct choice.<\/p>\n
\nAfter 1 year, the age of C will be a-b.
\nAfter 1 year, the average age of the family will be 16 years.
\n=>(a+1+b+1+a-b)\/3 = 16
\n2a+2 = 48
\n2a = 46
\na = 23 years.
\nTherefore, the age of the eldest person is 23 years. Hence, option B is the right answer.<\/p>\n
\nLet the age of the baby be \u2018x\u2019 years
\nThe current sum of the ages of members of the family = 90 + 4*5 + x = 110 + x
\nThe current average age of the family = 18.5
\nSo, $\\frac{110+x}{6}$ = 18.5
\n110 + x = 111
\nx = 1
\nHence, C is the right choice.<\/p>\n