High Level Pipes And Cistern Questions for SBI PO Prelims and Mains exam. Download SBI PO High Level Pipes And Cistern questions on with solutions.<\/p>\n
Download High Level Simplification Questions For SBI PO PDF<\/a><\/p>\n 105 SBI PO Mocks – Just Rs. 249<\/a><\/p>\n Instructions<\/b><\/p>\n In the following questions, find the approximate value that will replace the question mark (?). (You are not required to calculate the exact value.)<\/b><\/p>\n Question 1:\u00a0<\/b>$\\sqrt[4]{1020}*\\sqrt{7.98} = \\sqrt{63.89} + \\sqrt[3]{?}$<\/p>\n a)\u00a02<\/p>\n b)\u00a08<\/p>\n c)\u00a0729<\/p>\n d)\u00a010<\/p>\n e)\u00a0512<\/p>\n Question 2:\u00a0<\/b>$\\frac{\\sqrt{360} – \\sqrt{290}}{\\sqrt{620} – \\sqrt{575}} + \\frac{\\sqrt[3]{730}-\\sqrt[3]{510}}{\\sqrt[3]{999}-\\sqrt[3]{215}} = ?$<\/p>\n a)\u00a02<\/p>\n b)\u00a02.25<\/p>\n c)\u00a03<\/p>\n d)\u00a02.75<\/p>\n e)\u00a03.25<\/p>\n Question 3:\u00a0<\/b>$\\sqrt{\\frac{24.97}{100} * 27.94 + 2*2.99^2} = ?$<\/p>\n a)\u00a0$4$<\/p>\n b)\u00a0$6$<\/p>\n c)\u00a0$7$<\/p>\n d)\u00a0$5$<\/p>\n e)\u00a0$3$<\/p>\n Question 4:\u00a0<\/b>$19.98$% of $799.42$ + $\\sqrt{?}$ = $12.99^2$<\/p>\n a)\u00a0$9$<\/p>\n b)\u00a0$13$<\/p>\n c)\u00a0$160$<\/p>\n d)\u00a0$81$<\/p>\n e)\u00a0$90$<\/p>\n Instructions<\/b><\/p>\n Which value should replace $?$ in the following questions?<\/p>\n Question 5:\u00a0<\/b>$\\frac{69.97*\\sqrt{170.84} + 19.89*\\sqrt{145}}{50.84}$ = ?<\/p>\n a)\u00a025<\/p>\n b)\u00a029<\/p>\n c)\u00a021<\/p>\n d)\u00a027<\/p>\n e)\u00a023<\/p>\n SBI PO Free Mock Test (Latest Pattern)<\/a><\/p>\n Download SBI PO Previous Papers PDF<\/a><\/p>\n Question 6:\u00a0<\/b>$\\frac{\\sqrt{49.97}*\\sqrt{99.94}*\\sqrt{143}}{\\sqrt{440}}$ = ?<\/p>\n a)\u00a035<\/p>\n b)\u00a042<\/p>\n c)\u00a040<\/p>\n d)\u00a049<\/p>\n e)\u00a050<\/p>\n Question 7:\u00a0<\/b>$34.93$% of $598$ + $118.37$% of $25$ – $63$% of $79.94$ = ?<\/p>\n a)\u00a0200<\/p>\n b)\u00a0190<\/p>\n c)\u00a0210<\/p>\n d)\u00a0180<\/p>\n e)\u00a0220<\/p>\n Question 8:\u00a0<\/b>$ 22 + \\frac{(423 – 174)}{3} * 7 -3$ = ?<\/p>\n a)\u00a0570<\/p>\n b)\u00a0580<\/p>\n c)\u00a0590<\/p>\n d)\u00a0600<\/p>\n e)\u00a0610<\/p>\n Question 9:\u00a0<\/b>$6\\frac{5}{8} + 8\\frac{7}{12} + 12\\frac{19}{24}$ = ?<\/p>\n a)\u00a028<\/p>\n b)\u00a026<\/p>\n c)\u00a027<\/p>\n d)\u00a029<\/p>\n e)\u00a025<\/p>\n Question 10:\u00a0<\/b>$\\frac{34.84*\\sqrt{2.02}}{\\sqrt{97}}$ = ?<\/p>\n a)\u00a02<\/p>\n b)\u00a04<\/p>\n c)\u00a05<\/p>\n d)\u00a03<\/p>\n e)\u00a06<\/p>\n SBI PO Important Questions (download PDF)<\/a><\/p>\n Question 11:\u00a0<\/b>$\\frac{1.98 * 128.34}{\\sqrt{63.14}} + \\frac{3.07*\\sqrt{779}}{\\sqrt{7000}}$ = ?<\/p>\n a)\u00a031<\/p>\n b)\u00a035<\/p>\n c)\u00a029<\/p>\n d)\u00a038<\/p>\n e)\u00a033<\/p>\n Question 12:\u00a0<\/b>$79.87$% of $290.9$ – $59.89$ % of $371.24$ = ?<\/p>\n a)\u00a015<\/p>\n b)\u00a010<\/p>\n c)\u00a07<\/p>\n d)\u00a018<\/p>\n e)\u00a012<\/p>\n Question 13:\u00a0<\/b>$\\frac{\\sqrt{360}*169.8}{37.82}$ = ?<\/p>\n a)\u00a082<\/p>\n b)\u00a088<\/p>\n c)\u00a092<\/p>\n d)\u00a085<\/p>\n e)\u00a079<\/p>\n Question 14:\u00a0<\/b>$37.94$ % of $190$ + $43.89$ % of $49.98$ = ?<\/p>\n a)\u00a090<\/p>\n b)\u00a088<\/p>\n c)\u00a098<\/p>\n d)\u00a094<\/p>\n e)\u00a086<\/p>\n Question 15:\u00a0<\/b>$\\frac{12.92*23.97}{\\sqrt{678}}$ = ?<\/p>\n a)\u00a010<\/p>\n b)\u00a011<\/p>\n c)\u00a012<\/p>\n d)\u00a013<\/p>\n e)\u00a014<\/p>\n Question 16:\u00a0<\/b>$\\frac{\\sqrt{17.96*1.97}}{2.96} *98.92$ = x<\/p>\n a)\u00a0198<\/p>\n b)\u00a0192<\/p>\n c)\u00a0205<\/p>\n d)\u00a0212<\/p>\n e)\u00a0189<\/p>\n Question 17:\u00a0<\/b>$\\frac{15.94 * \\sqrt{ 28^2 – 49.62*5.99}}{31.97}$ = ?<\/p>\n a)\u00a09<\/p>\n b)\u00a011<\/p>\n c)\u00a013<\/p>\n d)\u00a015<\/p>\n e)\u00a017<\/p>\n Question 18:\u00a0<\/b>What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value) a)\u00a0$6$<\/p>\n b)\u00a0$7$<\/p>\n c)\u00a0$8$<\/p>\n d)\u00a0$9$<\/p>\n e)\u00a0$10$<\/p>\n Instructions<\/b><\/p>\n What approximate value will come in place of the question mark (?) in the following equations ?<\/p>\n Question 19:\u00a0<\/b>$1679 + 14.95 \\times 5.02 = ?$<\/p>\n a)\u00a0540<\/p>\n b)\u00a0525<\/p>\n c)\u00a0545<\/p>\n d)\u00a0565<\/p>\n e)\u00a0520<\/p>\n Instructions<\/b><\/p>\n Find the approximate value of the number which should replace (?) in the following questions.<\/p>\n Question 20:\u00a0<\/b>$11.95 \\times \\sqrt {2020} + 14.05 \\times \\sqrt{1230} = ?$<\/p>\n a)\u00a01050<\/p>\n b)\u00a01010<\/p>\n c)\u00a01020<\/p>\n d)\u00a01040<\/p>\n e)\u00a01030<\/p>\n Download SBI PO Syllabus PDF<\/a><\/p>\n Free Banking Online Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $\\sqrt[4]{1020}*\\sqrt{7.98} = \\sqrt{63.89} + \\sqrt[3]{?}$ 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be simplified as follows: 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $\\sqrt{\\frac{24.97}{100} *27.94 + 2*2.99^2} = \\sqrt{\\frac{25}{100} *28 + 2*3^2}$ 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $19.98$% of $799.42$ + $\\sqrt{?}$ = $12.99^2$ 5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The given expression can be simplified as follows: Therefore, option E is the right answer.<\/p>\n 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The given expression can be simplified as follows: 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $34.93$% of $598$ + $118.37$% of $25$ – $63$% of $79.94$ = $35$% of $600$ + $120$% of $25$ – $62.5$% of $80$ 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The given expression can be simplified as follows: 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $6\\frac{5}{8} + 8\\frac{7}{12} + 12\\frac{19}{24}$ = $6 + 8 + 12 + \\frac{5}{8} + \\frac{7}{12} + \\frac{19}{24}$ 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $\\frac{34.84*\\sqrt{2.02}}{\\sqrt{97}}$ = $\\frac{35*\\sqrt{2}}{\\sqrt{98}}$ 11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $\\frac{1.98 * 128.34}{\\sqrt{63.14}} + \\frac{3.07*\\sqrt{779}}{\\sqrt{7000}}$ = $\\frac{2 * 128}{\\sqrt{64}} + \\frac{3*\\sqrt{779}}{\\sqrt{7011}}$ Therefore, option E is the right answer.<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be simplified as follows: 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $\\frac{\\sqrt{360}*169.8}{37.82}$ = $\\frac{\\sqrt{361}*169.8}{38}$ Therefore, option D is the right answer.<\/p>\n 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $37.94$ % of $190$ + $43.89$ % of $49.98$ = $38$% of $190$ + $44$ % of $50$ Therefore, option D is the right answer.<\/p>\n 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The given expression can be simplified as follows:<\/p>\n $\\frac{12.92*23.97}{\\sqrt{678}}$ = $\\frac{13*24}{\\sqrt{676}}$ Therefore, option C is the right answer.<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The given expression can be simplified as $\\frac{\\sqrt{18*2}}{3} *99$ Therefore, option A is the right answer.<\/p>\n 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be simplified as $\\frac{16 * \\sqrt{ 784 – 50*6}}{32}$ 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The given expression can be simplified as $50 – \\frac{36}{42} *49$ 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $1679 + 14.95 \\times 5.02$ can be simplified as 20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The following approximations can applied to each of the terms of the expression.<\/p>\n $11.95 \\approx 12$ Hence, the given expression can be simplified to<\/p>\n $12 \\times 45 + 14 \\times 35 = 540 + 490 = 1030$<\/p>\n
\n$50.011 – \\frac{35.996}{42.007} *48.998$<\/p>\n
\n=> $\\sqrt[4]{1024}*\\sqrt{8} = \\sqrt{64} + \\sqrt[3]{?}$
\n$4\\sqrt{2}*2\\sqrt{2} = 8 + \\sqrt[3]{?}$
\n$16 = 8 + \\sqrt[3]{?}$
\n=> $\\sqrt[3]{?} = 8$
\n$ ? = 512$
\nTherefore, option E is the right answer.<\/p>\n
\n$\\frac{\\sqrt{360} – \\sqrt{290}}{\\sqrt{620} – \\sqrt{575}} + \\frac{\\sqrt[3]{730}-\\sqrt[3]{510}}{\\sqrt[3]{999}-\\sqrt[3]{215}} = \\frac{\\sqrt{361} – \\sqrt{289}}{\\sqrt{625} – \\sqrt{576}} + \\frac{\\sqrt[3]{729}-\\sqrt[3]{512}}{\\sqrt[3]{1000}-\\sqrt[3]{216}}$
\n= $\\frac{19 – 17}{25-24} + \\frac{9-8}{10-6}$
\n=$2+\\frac{1}{4}$
\n=$2.25$
\nTherefore, option B is the right answer.<\/p>\n
\n= $\\sqrt{7+18}$
\n=$\\sqrt{25}$
\n=$5$.
\nTherefore, option D is the right answer.<\/p>\n
\nThe given expression can be simplified as follows:
\n$20$% of $800$ + $\\sqrt{?}$ = $13^2$
\n$160 + \\sqrt{?}$ = $169$
\n=> $\\sqrt{?} = 9$
\n$? = 81$
\nTherefore, option D is the right answer.<\/p>\n
\n$\\frac{69.97*\\sqrt{170.84} + 19.89*\\sqrt{145}}{50.84}$ = $\\frac{70*\\sqrt{169} + 20*\\sqrt{144}}{50}$
\n= $\\frac{70*13 + 20*12}{50}$
\n=$\\frac{910+240}{50}$
\n=$\\frac{1150}{50}$
\n=$23$.<\/p>\n
\n$\\frac{\\sqrt{49.97}*\\sqrt{99.94}*\\sqrt{143}}{\\sqrt{440}}$ = $\\frac{\\sqrt{49}*\\sqrt{100}*\\sqrt{144}}{\\sqrt{441}}$
\n= $\\frac{7*10*12}{21}$
\n=$40$
\nTherefore, option C is the right answer.<\/p>\n
\n= $210$ + $30$ – $50$
\n= $190$
\nTherefore, option B is the right answer.<\/p>\n
\n$ 22 + \\frac{(423 – 174)}{3} * 7 -3$ = $ 22 + \\frac{(249)}{3} * 7 -3$
\n= $ 22 + 83 * 7 -3$
\n= $ 22 + 581- 3$
\n= $600$
\nTherefore, option D is the right answer.<\/p>\n
\n= $26 + \\frac{15+14+19}{24}$
\n= $26 + \\frac{48}{24}$
\n= $28$<\/p>\n
\n= $\\frac{35*\\sqrt{2}}{7\\sqrt{2}}$
\n= $5$
\nTherefore, option C is the right answer.<\/p>\n
\n=$\\frac{2 * 128}{\\sqrt{64}} + \\frac{3*\\sqrt{779}}{3*\\sqrt{779}}$
\n= $32+1$
\n= $33$.<\/p>\n
\n$79.87$% of $290.9$ – $59.89$ % of $371.24$ = $80$% of $290$ -$60$ % of $370$
\n= $ 232- 222$
\n=$10$.
\nTherefore, option B is the right answer.<\/p>\n
\n= $\\frac{19*169.8}{38}$ = $85$<\/p>\n
\n= $72$ + $22$
\n= $94$.<\/p>\n
\n= $\\frac{13*24}{26}$
\n=$12$<\/p>\n
\n= $\\frac{\\sqrt{36}}{3} *99$
\n=$\\frac{6}{3}*99$
\n=$198$<\/p>\n
\n= $\\frac{ \\sqrt{ 484}}{2}$
\n=$\\frac{22}{2}$ = $11$.
\nTherefore, option B is the right answer.<\/p>\n
\n=$50 – \\frac{6}{7} *49$
\n=$50 – 42$
\n= $8$.
\nTherefore, option C is the right answer.<\/p>\n
\n$1680 + 15\\times 5 $
\n= 1680+75
\n= 1755
\n<\/span><\/p>\n
\n$\\sqrt{2020} \\approx \\sqrt{2025} = 45$
\n$\\sqrt{1230} \\approx \\sqrt{1225} = 35$
\n$14.05 \\approx 14$<\/p>\n