490 Banking mocks for Rs. 299 – Enroll here<\/a><\/p>\n Take a free mock test for SBI Clerk<\/a><\/p>\n Download SBI Clerk previous papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>A boat takes 12 hours to reach point B from point A. It takes 6 hours to reach point A from point B. The river flows from A to B. How much time will it take to travel from A to B if the river remains still?<\/p>\n a)\u00a09 hours<\/p>\n b)\u00a010 hours<\/p>\n c)\u00a08 hours<\/p>\n d)\u00a07.5 hours<\/p>\n e)\u00a010.5 hours<\/p>\n Question 2:\u00a0<\/b>A boat develops a leak 18 km from the shore. The ship is still able to move at 12 km\/hr and can move only for 25 minutes. A rescue boat which takes 5 minutes to evacuate the crew of the boat leaves the shore at the same time. What should be the minimum speed of the rescue boat to successfully evacuate the crew from the boat in time?<\/p>\n a)\u00a036 kmph<\/p>\n b)\u00a044 kmph<\/p>\n c)\u00a038 kmph<\/p>\n d)\u00a042 kmph<\/p>\n e)\u00a040 kmph<\/p>\n Question 3:\u00a0<\/b>There is a river which flows from west to east at a speed of 5 m\/s. Arjun, is standing at one bank of the river. He decides to use his motorboat to reach the other bank of the river. His boat travels at a constant speed of 10 m\/s. He wants to travel in such a manner that he reaches a point on the other side which is perpendicularly opposite to his starting point. Find the time he takes to reach other side of the bank if the width of the river is 60 meters.<\/p>\n a)\u00a0$5\\sqrt{2}$ seconds<\/p>\n b)\u00a0$6$ seconds<\/p>\n c)\u00a0$12$ seconds<\/p>\n d)\u00a0$4\\sqrt{3}$ seconds<\/p>\n e)\u00a0$6\\sqrt{2}$ seconds<\/p>\n Question 4:\u00a0<\/b>A boat takes 2 hours to travel from point A to B in still water .To find out it\u2019s speed up-stream ,which of the following information is needed. a)\u00a0All are required<\/p>\n b)\u00a0Even these we cannot found the answer<\/p>\n c)\u00a0Only i,iii, and either ii or iv<\/p>\n d)\u00a0Only i and iii<\/p>\n e)\u00a0None of these<\/p>\n Download SBI Clerk Previous Papers PDF<\/a><\/p>\n Take a free mock test for SBI Clerk<\/a><\/p>\n Question 5:\u00a0<\/b>The speed of the boat in still water is 24 kmph and the speed of the stream is 41cm\/h. The time taken by the boat to travel from A to B downstream is 36 minutes less than the time taken by the same boat to travel from B to\u2019C upstream. If the distance between A and B is 4 km more than the distance between B and C, what is the distance between A and B?<\/p>\n a)\u00a0112 km<\/p>\n b)\u00a01401cm<\/p>\n c)\u00a056 km<\/p>\n d)\u00a0841cm<\/p>\n e)\u00a0281cm<\/p>\n Question 6:\u00a0<\/b>A man takes 2.2 times as long to row a distance upstream as to row the same distance downstream. If he can row 55 km downstream in 2 hours 30 minutes, what is the speed of the boat in still water? (in km\/h)<\/p>\n a)\u00a040<\/p>\n b)\u00a08<\/p>\n c)\u00a016<\/p>\n d)\u00a024<\/p>\n e)\u00a032<\/p>\n Question 7:\u00a0<\/b>A boat takes a total time of twelve hours to travel 105 kms upstream and the same distance downstream. The speed of the boat in still water is six times of the speed of the current. What is the speed of the boat in still water? (in km\/hr)<\/p>\n a)\u00a012<\/p>\n b)\u00a030<\/p>\n c)\u00a018<\/p>\n d)\u00a024<\/p>\n e)\u00a036<\/p>\n Question 8:\u00a0<\/b>A boat takes a total time of eight hours to travel 63 kms upstream and the same distance downstream. The speed of the current is ${1 \\over 8}$th of the speed of the boat in still water. What is the speed of the boat in still water? (in km\/hr)<\/p>\n a)\u00a032<\/p>\n b)\u00a024<\/p>\n c)\u00a016<\/p>\n d)\u00a08<\/p>\n e)\u00a038<\/p>\n Question 9:\u00a0<\/b>A boat takes six hours to travel a certain distance downstream and five hours to travel a certain distance upstream. The distance travelled upstream is half of the travelled downstream. If the speed of the current is 4 km\/hr, what is the speed of the boat in still water? (in km\/hr)<\/p>\n a)\u00a016<\/p>\n b)\u00a020<\/p>\n c)\u00a024<\/p>\n d)\u00a010<\/p>\n e)\u00a018<\/p>\n Banking Study Material – 18000 Questions<\/a><\/p>\n Daily Free SBI Online Tests<\/a><\/p>\n Question 10:\u00a0<\/b>A boatman can row a boat downstream at 13 kmph and upstream at 9 kmph. What will be the speed of boat in still water ? (in kmph).<\/p>\n a)\u00a012<\/p>\n b)\u00a010.5<\/p>\n c)\u00a011<\/p>\n d)\u00a010<\/p>\n e)\u00a011.5<\/p>\n Question 11:\u00a0<\/b>A boat goes downstream at the rate of 9 kmph and upstream at the rate of 6 kmph. Find the speed of current.<\/p>\n a)\u00a01.5 kmph<\/p>\n b)\u00a02 kmph<\/p>\n c)\u00a07.5 kmph<\/p>\n d)\u00a04.5 kmph<\/p>\n e)\u00a0None of these<\/p>\n Question 12:\u00a0<\/b>A boatman rows downstream a distance of 30 km in 6 hours and up stream a distance of 24 km in 6 hours. The ratio of speed of boat in still water and speed of current is<\/p>\n a)\u00a09 : 1<\/p>\n b)\u00a08 : 1<\/p>\n c)\u00a09 : 2<\/p>\n d)\u00a08 : 3<\/p>\n e)\u00a0None of these<\/p>\n Question 13:\u00a0<\/b>A boat starts from A and travels towards B which is 72 km from A. As soon as the boat reaches B, it turns back and heads towards A. If the speed of the boat is 600 percent more than the speed of the stream and total travel time is 7 hours then find the time required the same boat to travel 36 km upstream?<\/p>\n a)\u00a02 hours<\/p>\n b)\u00a04 hours<\/p>\n c)\u00a03.5 hours<\/p>\n d)\u00a02.5 hours<\/p>\n e)\u00a01.5 hours<\/p>\n Question 14:\u00a0<\/b>There is a road along the river. The speed of the river is 2 m\/s and the speed of the boat is 10 m\/s. Two friends decided to have a race in which Arun will cycle till P, which is 96m from the starting point, and return back to the starting point. Sam will use the boat to reach P and return. The speed of the cycle is 10 m\/s. Which of the following is true?<\/p>\n a)\u00a0Arun takes 6% less time than Sam to finish the race<\/p>\n b)\u00a0Both of them reach the starting point at the same time.<\/p>\n c)\u00a0Arun takes 4% less time than Sam to finish the race<\/p>\n d)\u00a0Arun takes 4% more time than Sam to finish the race<\/p>\n e)\u00a0Arun takes 6% less time than Sam to finish the race.<\/p>\n Question 15:\u00a0<\/b>The sum of the speed of the boat A downstream and the speed of the boat B upstream is 27km\/h. If the speed of boat A in still water is 3km\/h less than that of boat B, what is the respective ratio between the speed of boat A in still water and that of boat B in still water? (Considering the speed of current to be constant)<\/p>\n a)\u00a04 : 5<\/p>\n b)\u00a02 : 5<\/p>\n c)\u00a02 : 3<\/p>\n d)\u00a03 : 5<\/p>\n e)\u00a03 : 4<\/p>\n 100+ Free GK Tests<\/a><\/p>\n Question 16:\u00a0<\/b>A boat travels from A to B upstream and then from B to C downstream taking the same time. The respective ratio between the distance from A to B and the distance from B to C is 5 : 7. If the boat takes 2 hours 30 min to travel a distance of 35 km downstream, what is the speed of the stream ? (in km\/h)<\/p>\n a)\u00a02 km\/h<\/p>\n b)\u00a01.5 km\/h<\/p>\n c)\u00a02.5 km\/h<\/p>\n d)\u00a02.2 km\/h<\/p>\n e)\u00a0None of these<\/p>\n Question 17:\u00a0<\/b>The time taken by a boat to travel \u2018x\u2019 km upstream is twice the time taken by the same boat to travel \u2018x\u2019 km downstream. If speed of the boat in still water is 12 km\/h, what is the speed of current ? (in km\/h)<\/p>\n a)\u00a03<\/p>\n b)\u00a04<\/p>\n c)\u00a03.5<\/p>\n d)\u00a04.5<\/p>\n e)\u00a0None of these<\/p>\n Question 18:\u00a0<\/b>The speed of a boat in still water is 500% more than the speed of the current. What is the respective ratio between the speed of the boat downstream and speed of the boat upstream ?<\/p>\n a)\u00a09 : 2<\/p>\n b)\u00a07 : 3<\/p>\n c)\u00a07 : 5<\/p>\n d)\u00a09 : 4<\/p>\n e)\u00a04 : 3<\/p>\n Question 19:\u00a0<\/b>The distance between two points is 36 km. A boat rows in still water at 6 kmph. It takes 8 hours less to cover this distance in downstream in comparison to that in upstream. The rate of stream is<\/p>\n a)\u00a03 kmph<\/p>\n b)\u00a02 kmph<\/p>\n c)\u00a02.5 kmph<\/p>\n d)\u00a04 kmph<\/p>\n e)\u00a0None of these<\/p>\n Question 20:\u00a0<\/b>The speed of a boat B downstream is 40 km\/hr and the speed of the same boat in still water is 30km\/hr. If the speed of the stream suddenly rises by 20%, what is the time taken by the boat to cover 450m in upstream direction?<\/p>\n a)\u00a01 min<\/p>\n b)\u00a01.8 mins<\/p>\n c)\u00a01.2 mins<\/p>\n d)\u00a01.9 mins<\/p>\n e)\u00a01.5 mins<\/p>\n General Knowledge Questions & Answers PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the speed of the boat be \u2018b\u2019 and the speed of the stream be \u2018s\u2019. We know that D\/(b-s) = 12. We also know that D\/(b+s) = 6. Equating (1) and (2), we get, 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Distance between Boat and shore = 18 km 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Since he wants to reach a point which is perpendicularly opposite, he should ensure that the horizontal displacement is zero.<\/p>\n Hence, his horizontal component of the speed should be 5 m\/s east to west.<\/p>\n Let’s represent it in a diagram,<\/p>\n His speed in the horizontal direction = $10 \\sin \\theta$<\/p>\n His speed in the vertical direction = $10 \\cos \\theta$<\/p>\n $10 \\sin \\theta = 5$<\/p>\n Hence, $\\theta$ = 30\u00b0<\/p>\n His speed in vertical direction = $10 \\cos 30$ = $5 \\sqrt{3}$<\/p>\n Time taken to cover a vertical distance of 60m = $\\frac{60}{5\\sqrt{3}}$ = $4\\sqrt{3}$ seconds.<\/p>\n 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Time taken by boat\u00a0to travel from point A to B in still water\u00a0= 2 hours<\/p>\n To find the upstream speed, we definitely need the speed of stream, thus statement (iii) is mandatory.<\/p>\n Also, the distance between points A and B or the speed of boat in still water is needed.<\/p>\n Thus, statements (i) and (iii) are required to find the upstream speed of the boat.<\/p>\n => Ans – (D)<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let speed of boat in still water = $x$ km\/hr<\/p>\n => Speed of current = $y$ km\/hr<\/p>\n Let distance travelled = $d$ km<\/p>\n Acc. to ques, => $2.2 (\\frac{d}{x + y}) = \\frac{d}{x – y}$<\/p>\n => $2.2x – 2.2y = x + y$<\/p>\n => $2.2x – x = y + 2.2y$<\/p>\n => $3x = 8y$ ————-(i)<\/p>\n Also, the man takes 2 hrs 30 mins in travelling 55 km downstream.<\/p>\n => $\\frac{55}{x + y} = 2 + \\frac{1}{2}$<\/p>\n => $\\frac{55}{x + y} = \\frac{5}{2}$<\/p>\n => $x + y = 22$<\/p>\n Multiplying both sides by 8, and using eqn(i), we get\u00a0:<\/p>\n => $8x + 3x = 22 \\times 8$<\/p>\n => $x = \\frac{22 \\times 8}{11} = 16$ km\/hr<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let speed of current = $x$ km\/hr<\/p>\n => Speed of boat in still water = $6x$ km\/hr<\/p>\n Acc. to ques, => $\\frac{105}{7x} + \\frac{105}{5x} = 12$<\/p>\n => $\\frac{15}{x} + \\frac{21}{x} = 12$<\/p>\n => $\\frac{36}{x} = 12$<\/p>\n => $x = \\frac{36}{12} = 3$<\/p>\n $\\therefore$ Speed of boat in still water = $6 \\times 3 = 18$ km\/hr<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let speed of current = $x$ km\/hr<\/p>\n => Speed of boat in still water = $8x$ km\/hr<\/p>\n Acc. to ques, => $\\frac{63}{9x} + \\frac{63}{7x} = 8$<\/p>\n => $\\frac{7}{x} + \\frac{9}{x} = 8$<\/p>\n => $\\frac{16}{x} = 8$<\/p>\n => $x = \\frac{16}{8} = 2$<\/p>\n $\\therefore$ Speed of boat in still water = $8 \\times 2 = 16$ km\/hr<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let speed of boat in still water = $x$ km\/hr<\/p>\n Let distance travelled downstream = $2d$ km<\/p>\n => Distance travelled upstream = $d$ km<\/p>\n Using, $time = \\frac{distance}{speed}$<\/p>\n => $6 = \\frac{2d}{x + 4}$ ———(i)<\/p>\n and $5 = \\frac{d}{x – 4}$ ———(ii)<\/p>\n Dividing eqn(i) from (ii), we get :<\/p>\n => $\\frac{6}{5} = \\frac{\\frac{2d}{x + 4}}{\\frac{d}{x – 4}}$<\/p>\n => $\\frac{6}{5} = \\frac{2 (x – 4)}{x + 4}$<\/p>\n => $6x + 24 = 10x – 40$<\/p>\n => $10x – 6x = 24 + 40 = 64$<\/p>\n => $x = \\frac{64}{4} = 16$ km\/hr<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Speed of boat in still water<\/p>\n = $\\frac{1}{2}$ (downstream + upstream)<\/p>\n = $\\frac{1}{2} (13 + 9) = \\frac{22}{2}$<\/p>\n = $11$ kmph<\/p>\n 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Speed of current = $\\frac{1}{2}$ (downstream – upstream)<\/p>\n = $\\frac{1}{2} (9 – 6)$<\/p>\n = $\\frac{3}{2} = 1.5$ kmph<\/p>\n 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let speed of boat in still water = $x$ km\/h<\/p>\n and speed of current = $y$ km\/h<\/p>\n Now, $\\frac{30}{x + y} = 6$<\/p>\n => $x + y = 5$<\/p>\n and $\\frac{24}{x – y} = 6$<\/p>\n => $x – y = 4$<\/p>\n Solving above equations, we get\u00a0:<\/p>\n $x = \\frac{9}{2}$ and $y = \\frac{1}{2}$<\/p>\n => $x : y = 9 : 1$<\/p>\n 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let speed of the stream be \u2018x\u2019, then the speed of the boat will be 7x 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Arun cycles at a constant speed of 10 m\/s. Sam has to cover upstream in one direction and downstream in the other direction. The difference in their times = 0.8 seconds 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let speed of boat\u00a0A in still water = $x$ kmph<\/p>\n => Speed of boat B in still water = $(x + 3)$ kmph<\/p>\n Let speed of current = $y$ kmph<\/p>\n Acc to ques,<\/p>\n => $(x + y) + (x + 3 – y) = 27$<\/p>\n => $2x = 27 – 3 = 24$<\/p>\n => $x = \\frac{24}{2} = 12$ kmph<\/p>\n Speed of B = 12 + 3 = 15 kmph<\/p>\n $\\therefore$ Required ratio = 12\u00a0: 15<\/p>\n = 4\u00a0: 5<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let distance between AB = $5x$ and BC = $7x$<\/p>\n Downstream speed = $\\frac{35}{2.5} = 14$ km\/h<\/p>\n Let upstream speed = $y$ km\/h<\/p>\n Now, $time = \\frac{distance}{speed}$<\/p>\n => $\\frac{5x}{y} = \\frac{7x}{14}$<\/p>\n => $\\frac{5}{y} = \\frac{1}{2}$<\/p>\n => $y = 5 \\times 2 = 10$ km\/h<\/p>\n Now, speed of stream = $\\frac{1}{2}$ (downstream – upstream)<\/p>\n = $\\frac{1}{2} (14 – 10)$<\/p>\n = $\\frac{4}{2} = 2$ km\/h<\/p>\n 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n REASONING<\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let speed of current = $x$ km\/h<\/p>\n => Speed of boat in still water = $x + (\\frac{500}{100} \\times x)$<\/p>\n = $x + 5x = 6x$ km\/h<\/p>\n => Speed of the boat downstream = $6x + x = 7x$ km\/h<\/p>\n Speed of boat upstream = $6x – x = 5x$ km\/h<\/p>\n $\\therefore$ Required ratio = $\\frac{7x}{5x}$<\/p>\n = $7 : 5$<\/p>\n 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let speed of stream = $x$ kmph<\/p>\n => Speed of boat downstream = $(6 + x)$ kmph<\/p>\n Speed upstream = $(6 – x)$ kmph<\/p>\n Using, $time = \\frac{distance}{speed}$<\/p>\n => $\\frac{36}{6 – x} – \\frac{36}{6 + x} = 8$<\/p>\n => $\\frac{1}{6 – x} – \\frac{1}{6 + x} = \\frac{8}{36}$<\/p>\n => $\\frac{(6 + x) – (6 – x)}{(6 + x) (6 – x)} = \\frac{2}{9}$<\/p>\n => $\\frac{2x}{36 – x^2} = \\frac{2}{9}$<\/p>\n => $\\frac{x}{36 – x^2} = \\frac{1}{9}$<\/p>\n => $36 – x^2 = 9x$<\/p>\n => $x^2 + 9x – 36 = 0$<\/p>\n => $x^2 + 12x – 3x – 36 = 0$<\/p>\n => $x (x + 12) – 3 (x + 12) = 0$<\/p>\n => $x = 3 , -12$<\/p>\n $\\because$ Speed cant be negative, => $x = 3$ kmph<\/p>\n 20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Downstream speed of boat B is = speed of boat B in still water + speed of stream.
\ni. Distance between point A and B
\nIi.Time taken to travel down stream from B to A
\niii. Speed of the stream of the water
\niv. Effective speed of Boat while traveling Downstream from B to A<\/p>\n
\nLet the distance between A and B be \u2018D\u2019.<\/p>\n
\nD = 12b – 12s ——–(1).<\/p>\n
\nD = 6b + 6s ———-(2)<\/p>\n
\n12b – 12s = 6b + 6s
\n=> 6b = 18s
\nb = 3s.
\nD = 12*3s – 12*s
\nD = 24s.
\nTime taken to travel from A to B in still water = D\/b = 24s\/3s = 8 hours.
\nTherefore, option C is the right answer.<\/p>\n
\nThe rescue boat must reach the leaking boat in 20 minutes as 5 minutes is needed for evacuation.
\nLet the relative velocity of the 2 boats be \u2018v\u2019
\nSo, v = $\\frac{18}{20}$ km per min = 18*60\/20 kmph = 54 kmph
\nSo minimum speed of the rescue boat = 54 – 12 = 42 kmph
\nHence, option D is correct option.<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/river_ha65RA3.png\")
<\/figure>\n
\nWe have been given that
\n72\/8x + 72\/6x = 7
\n=> x = 3
\nHence, the speed of the boat is 21 km\/hr
\nHence, required time = 36\/2 = 2 hours
\nThus, the correct answer is option A<\/p>\n
\nHence, he takes 192\/10 = 19.2 seconds to complete the race.<\/p>\n
\nTime taken by him to cover upstream distance = 96\/(10 -2) = 12 seconds.
\nTime taken by him to cover downstream distance = 96\/(10 + 2) = 8 secons
\nHence, he takes 20 seconds to complete the race.<\/p>\n
\nPercentage = 0.8\/20 *100 = 4%<\/p>\n
\nSo Speed of stream = 40-30 = 10 km\/hr.
\nIf speed of stream increase by 20%, new speed = 10 * 1.2 = 12km\/hr
\nSo Time required to cover upstream distance of 450m = 0.45 \/ (30-12) = 0.025 hr = 1.5 mins
\nSo E is the right choice.<\/p>\n