Approximation Questions for SBI PO Prelims and Mains exam. Download SBI PO Approximation questions on with solutions.<\/p>\n
Download sbi po approximation questions pdf<\/a><\/p>\n 105 SBI PO Mocks – Just Rs. 249<\/a><\/p>\n Instructions<\/b><\/p>\n What approximate value will come at the place of question mark \u2018?\u2019 in the following question?<\/p>\n Question 1:\u00a0<\/b>$27\\%$ of $ ?^4 = 24.3 * 6.94$<\/p>\n a)\u00a06.5<\/p>\n b)\u00a04<\/p>\n c)\u00a07<\/p>\n d)\u00a04.5<\/p>\n e)\u00a05<\/p>\n Question 2:\u00a0<\/b>$ 273.98 * \\frac{3}{7} + \\sqrt{840} $ = ?<\/p>\n a)\u00a0172<\/p>\n b)\u00a0146<\/p>\n c)\u00a0158<\/p>\n d)\u00a0134<\/p>\n e)\u00a0150<\/p>\n Question 3:\u00a0<\/b>18.94% of 264 + ? + 33.1% of 327 = 451<\/p>\n a)\u00a0280.38<\/p>\n b)\u00a0314.12<\/p>\n c)\u00a0292.84<\/p>\n d)\u00a0324.72<\/p>\n e)\u00a0286.66<\/p>\n Question 4:\u00a0<\/b>$\\frac{\\sqrt{2} * (97.97 + ?^2)}{4.24} = 49$<\/p>\n a)\u00a09<\/p>\n b)\u00a011.5<\/p>\n c)\u00a08<\/p>\n d)\u00a07<\/p>\n e)\u00a06.5<\/p>\n Question 5:\u00a0<\/b>$27.99^2 \/ 3 + ? = 167.05 + 17*10.4$<\/p>\n a)\u00a065.7<\/p>\n b)\u00a082.5<\/p>\n c)\u00a078.3<\/p>\n d)\u00a073.5<\/p>\n e)\u00a069.3<\/p>\n SBI PO Free Mock Test (Latest Pattern)<\/a><\/p>\n Download SBI PO Previous Papers PDF<\/a><\/p>\n Instructions<\/b><\/p>\n What approximate value will come at the place of question mark \u2018?\u2019 in the following question?<\/p>\n Question 6:\u00a0<\/b>?% of $6.02^4$ = 9.1*19.9<\/p>\n a)\u00a024<\/p>\n b)\u00a012<\/p>\n c)\u00a017<\/p>\n d)\u00a021<\/p>\n e)\u00a014<\/p>\n Question 7:\u00a0<\/b>66.69% of (22.5% of (16.48% of 250.49) = ?<\/p>\n a)\u00a05.4<\/p>\n b)\u00a06.2<\/p>\n c)\u00a06.8<\/p>\n d)\u00a07.2<\/p>\n e)\u00a05.8<\/p>\n Question 8:\u00a0<\/b>51.49% of 636 – 82.08% of 211 = ?<\/p>\n a)\u00a0143.3<\/p>\n b)\u00a0161.3<\/p>\n c)\u00a0154.5<\/p>\n d)\u00a0171.3<\/p>\n e)\u00a0182.5<\/p>\n Question 9:\u00a0<\/b>$\\frac{\\sqrt{421+364} + ?^3}{14.89}$ = 90.6<\/p>\n a)\u00a014<\/p>\n b)\u00a015<\/p>\n c)\u00a013<\/p>\n d)\u00a011<\/p>\n e)\u00a017<\/p>\n Question 10:\u00a0<\/b>$18.98^2 + ? = 31.994 * 17.017 + 574.98\/5$<\/p>\n a)\u00a0324<\/p>\n b)\u00a0298<\/p>\n c)\u00a0276<\/p>\n d)\u00a0282<\/p>\n e)\u00a0304<\/p>\n SBI PO Important Questions (download PDF)<\/a><\/p>\n Question 11:\u00a0<\/b>What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value) a)\u00a0$6$<\/p>\n b)\u00a0$7$<\/p>\n c)\u00a0$8$<\/p>\n d)\u00a0$9$<\/p>\n e)\u00a0$10$<\/p>\n Question 12:\u00a0<\/b>What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value) a)\u00a0$6$<\/p>\n b)\u00a0$7$<\/p>\n c)\u00a0$8$<\/p>\n d)\u00a0$9$<\/p>\n e)\u00a0$10$<\/p>\n Question 13:\u00a0<\/b>What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value) a)\u00a0$64$<\/p>\n b)\u00a0$72$<\/p>\n c)\u00a0$80$<\/p>\n d)\u00a0$81$<\/p>\n e)\u00a0$63$<\/p>\n Question 14:\u00a0<\/b>What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value) a)\u00a0$6$<\/p>\n b)\u00a0$7$<\/p>\n c)\u00a0$8$<\/p>\n d)\u00a0$9$<\/p>\n e)\u00a0$10$<\/p>\n Question 15:\u00a0<\/b>What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value) a)\u00a0$24$<\/p>\n b)\u00a0$27$<\/p>\n c)\u00a0$30$<\/p>\n d)\u00a0$32$<\/p>\n e)\u00a0$36$<\/p>\n Instructions<\/b><\/p>\n What approximate value will come at the place of question mark \u2018?\u2019 in the following question?<\/p>\n Question 16:\u00a0<\/b>? % of $6.998^{3} = 21 \\times 23.7$<\/p>\n a)\u00a0156<\/p>\n b)\u00a0134<\/p>\n c)\u00a0187<\/p>\n d)\u00a0161<\/p>\n e)\u00a0145<\/p>\n Question 17:\u00a0<\/b>125% of 852 + 64.008 * 18.994 = ?<\/p>\n a)\u00a02267<\/p>\n b)\u00a02281<\/p>\n c)\u00a02293<\/p>\n d)\u00a02175<\/p>\n e)\u00a02196<\/p>\n Question 18:\u00a0<\/b>(54.98% of 994.97) \/ (74.08% of 324.05) = ?<\/p>\n a)\u00a02.7<\/p>\n b)\u00a02.1<\/p>\n c)\u00a02.3<\/p>\n d)\u00a03<\/p>\n e)\u00a03.3<\/p>\n Question 19:\u00a0<\/b>$\\frac{\\sqrt[3]{19375 + 5014}+ 28^2}{?}$ = 24.57<\/p>\n a)\u00a027<\/p>\n b)\u00a036<\/p>\n c)\u00a031<\/p>\n d)\u00a033<\/p>\n e)\u00a029<\/p>\n Question 20:\u00a0<\/b>$\\frac{22.98^{3}}{5}$ + ? = 17.97 * 124.005 + 428.79<\/p>\n a)\u00a0199<\/p>\n b)\u00a0228<\/p>\n c)\u00a0217<\/p>\n d)\u00a0245<\/p>\n e)\u00a0194<\/p>\n Download SBI PO Syllabus PDF<\/a><\/p>\n Free Banking Online Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n $27\\%$ of $ ?^4$ = 24.3 * 6.94 can be approximately written as 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $ 273.98 * \\frac{3}{7} + \\sqrt{840} $ = ? can be approximately written as 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 18.94% of 264 + ? + 33.1% of 327 = 451 can be approximately written as 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $\\frac{\\sqrt{2} * (97.97 + ?^2)}{4.24} = 49$ can be approximately written as,<\/p>\n $\\frac{49 * 4.24}{\\sqrt{2}} =98 + ?^2$<\/p>\n $49 * 3 = 2*49 + ?^2$ 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $27.99^2 \/ 3 + ? = 167.05 + 17*10.4$ can be approximately written as Take a free mock test for SBI PO<\/a><\/p>\n 6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n ?% of $6.02^4$ = 9.1*19.9 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 66.69% of (22.5% of (16.48% of 250.49) = ? 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 51.49% of 636 – 82.08% of 211 = ? 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $\\frac{\\sqrt{421+364} + ?^3}{14.89}$ = 90.6 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $18.98^2 + ? = 31.994 * 17.017 + 574.98\/5$ can be approximately written as 100 Free GK Tests for Banking exams<\/a><\/p>\n 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The given expression can be approximated to $\\frac{30}{5} – \\frac{8}{4} + \\frac{32}{8}$ 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be approximated to $\\frac{108}{3*3} – \\frac{45}{9}$ 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be approximated to $\\frac{72}{9} * \\frac{63}{7}$. 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The given expression can be simplified as $50 – \\frac{36}{42} *49$ 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The given expression can be approximated to $\\frac{\\sqrt{81 * 441}}{7}$ 16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n ?% of $6.998^3 = 21 \\times 23.7$ can be written as 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 125% of 852 + 64.008 * 18.994 can be approximately written as 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n (54.98% of 994.97) \/ (74.08% of 324.05) = ? can be written as 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $\\frac{\\sqrt[3]{19375 + 5014}+ 28^2}{?}$ = 24.57 can be written as 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $\\frac{22.98^{3}}{5}$ + ? = 17.97 * 124.005 + 428.99 can be approximately written as
\n$\\frac{29.96}{5.08} – \\frac{7.99}{4.01} + \\frac{31.97}{7.94}$<\/p>\n
\n$\\frac{107.94}{2.99*3.02} – \\frac{44.92}{8.97}$<\/p>\n
\n$\\frac{71.94}{8.99} * \\frac{62.91}{7.02}$<\/p>\n
\n$50.011 – \\frac{35.996}{42.007} *48.998$<\/p>\n
\n$\\frac{\\sqrt{80.98 * 440}}{6.99}$<\/p>\n
\n$0.27 * ?^4 = 24.3 * 7$
\n$0.27 * ?^4 = 170.1$
\n$ ?^4 = 630$
\n? = 5 approx.
\nHence, option E is the correct choice.<\/p>\n
\n$ 273*\\frac{3}{7} + \\sqrt{841} $ = ?
\n117 + 29 = 146 approx.
\nHence, option B is the correct choice.<\/p>\n
\n0.19 of 264 + ? + 0.33 * 327 = 451
\n50.16 + ? + 108 = 451
\n? = 292.84
\nHence, option C is the correct choice.<\/p>\n
\n$?^2 = 49$
\n? = 7
\nHence, option D is the correct option.<\/p>\n
\n$28^2 \/ 3 + ? = 17*10.4 + 167$
\n784\/3 + ? = 176.8 + 167
\n? = 343.8 – 261.33 = 82.5 approx.
\nHence, option B is the correct choice.<\/p>\n
\n?% * 1296 = 180
\n?% = 0.13888
\n? = 14 approx.
\nHence, option E is the correct choice.<\/p>\n
\n$\\frac{2}{3}$ * $\\frac{0.9}{4}$ * $\\frac{0.33}{2} *250 = ?
\n? = 6.1875 = 6.2 approx.
\nHence, option B is the correct choice.<\/p>\n
\n0.515*636 – 0.82*211 = ?
\n? = 327.5 – 173 = 154.5
\nHence, option c is the correct choice.<\/p>\n
\n$\\frac{\\sqrt{785} + ?^3}{15}$ = 90.6
\n$\\frac{28 + ?^3}{15}$ = 90.6
\n28 + $?^3$ = 1359
\n$?^3$ = 1331
\n? = 11
\nHence, option D is the correct option.<\/p>\n
\n$19^2 + ? = 32 * 17 + 575\/5$
\n$361 + ? = 544 + 115$
\n$? = 298$
\nHence, option B is the correct choice.<\/p>\n
\n= $6 – 2 + 4$
\n=$8$.
\nTherefore, option C is the right answer.<\/p>\n
\n=$\\frac{108}{9} – \\frac{45}{9}$
\n=$\\frac{63}{9}$
\n=$7$.
\nTherefore, option B is the right answer.<\/p>\n
\n=$8*9$
\n=$72$
\nTherefore, option B is the right answer.<\/p>\n
\n=$50 – \\frac{6}{7} *49$
\n=$50 – 42$
\n= $8$.
\nTherefore, option C is the right answer.<\/p>\n
\n=$\\frac{9*21}{7}$
\n=$9*3$
\n=$27$.
\nTherefore, option B is the right answer.<\/p>\n
\n?% of $7^{3} = 497.3$
\n?% * 343 = 497.3
\n?% = 1.45
\n? = 145
\nHence, option E is the correct choice.<\/p>\n
\n$\\frac{5}{4}$ * 852 + 64*19
\n= 1065 + 1216
\n= 2281
\nHence, option B is the correct choice.<\/p>\n
\n$\\frac{0.55*995}{0.74*324} = \\frac{547.25}{239.76}$ = 2.3 approx.
\nHence, option C is the correct choice.<\/p>\n
\n$\\frac{\\sqrt[3]{24389}+ 784}{?}$ = 24.57
\n? = $\\frac{29 + 784}{24.57}$ = 33 approx.
\nHence, option D is the correct option.<\/p>\n
\n$\\frac{23^{3}}{5}$ + ? = 18 * 124 + 429
\n$\\frac{12167}{5}$ + ? = 2232 + 429
\n? = 2661 – 2433 = 228
\nHence, option B is the correct choice.<\/p>\n