{"id":28236,"date":"2019-05-01T19:01:38","date_gmt":"2019-05-01T13:31:38","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=28236"},"modified":"2019-05-01T19:01:38","modified_gmt":"2019-05-01T13:31:38","slug":"sbi-po-arithmetic-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/sbi-po-arithmetic-questions-pdf\/","title":{"rendered":"SBI PO Arithmetic Questions PDF"},"content":{"rendered":"

SBI PO Arithmetic Questions PDF<\/strong><\/span><\/h1>\n

Arithmetic Questions for SBI PO Prelims and Mains exam. Download SBI PO Approximation questions on with solutions.<\/p>\n

Download SBI PO Arithmetic Questions PDF<\/a><\/p>\n

105 SBI PO Mocks – Just Rs. 249<\/a><\/p>\n

Instructions<\/b>: What will come in place of question mark (?) in the following questions?<\/p>\n

Question 1:\u00a0<\/b>$(\\sqrt{5} – \\sqrt{10})^2 + (\\sqrt{2} + 5)^2 = (?)^3 – 22$<\/p>\n

a)\u00a0$\\sqrt{2}$<\/p>\n

b)\u00a0$2$<\/p>\n

c)\u00a0$16$<\/p>\n

d)\u00a0$8$<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>55% of $\\sqrt{2116}$\u00a0\u00f7 0.01 = ? \u00d7 20<\/p>\n

a)\u00a0126.5<\/p>\n

b)\u00a0126.6<\/p>\n

c)\u00a0124.6<\/p>\n

d)\u00a0125.4<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>$ \\sqrt {12^2 \\times 16 \\div 24 + 193 + 7 \\times 5} = (?)^2$<\/p>\n

a)\u00a03$\\sqrt{2}$<\/p>\n

b)\u00a04$\\sqrt{2}$<\/p>\n

c)\u00a05$\\sqrt{2}$<\/p>\n

d)\u00a0$18$<\/p>\n

e)\u00a0$32$<\/p>\n

Question 4:\u00a0<\/b>$\\sqrt{31.36}$ \u00f7 $\\sqrt{0.64}$\u00a0\u00d7252 = (?)2<\/sup> \u00d736<\/p>\n

a)\u00a081<\/p>\n

b)\u00a064<\/p>\n

c)\u00a0-8<\/p>\n

d)\u00a0-7<\/p>\n

e)\u00a09<\/p>\n

Question 5:\u00a0<\/b>(1.69)4<\/sup> \u00f7 (2197 \u00f71000)3<\/sup> \u00d7 (0.13\u00d710)3<\/sup> = (1.3)? – 2<\/sup><\/p>\n

a)\u00a06<\/p>\n

b)\u00a02<\/p>\n

c)\u00a04<\/p>\n

d)\u00a00<\/p>\n

e)\u00a0None of these<\/p>\n

SBI PO Free Mock Test (Latest Pattern)<\/a><\/p>\n

Download SBI PO Previous Papers PDF<\/a><\/p>\n

Instructions<\/b><\/p>\n

Instructions: What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)<\/p>\n

Question 6:\u00a0<\/b>68% of 1288 + 26% of 734 -215=?<\/p>\n

a)\u00a0620<\/p>\n

b)\u00a0930<\/p>\n

c)\u00a0540<\/p>\n

d)\u00a0850<\/p>\n

e)\u00a0710<\/p>\n

Question 7:\u00a0<\/b>(32.05)2<\/sup> – (18.9)2<\/sup> –\u00a0(11.9)2<\/sup> = ?<\/p>\n

a)\u00a0670<\/p>\n

b)\u00a0530<\/p>\n

c)\u00a0420<\/p>\n

d)\u00a0780<\/p>\n

e)\u00a0960<\/p>\n

Question 8:\u00a0<\/b>6578 \u00f7 65 \u00d7 15= ? \u00d7 6<\/p>\n

a)\u00a0200<\/p>\n

b)\u00a0250<\/p>\n

c)\u00a0150<\/p>\n

d)\u00a0100<\/p>\n

e)\u00a0300<\/p>\n

SBI PO Important Questions (download PDF)<\/a><\/p>\n

Question 9:\u00a0<\/b>$\\frac{679}{45}$\u00a0\u00f7 $\\frac{23}{2130}$ \u00d7 $\\frac{126}{169}$ = ?<\/p>\n

a)\u00a0540<\/p>\n

b)\u00a0760<\/p>\n

c)\u00a0800<\/p>\n

d)\u00a01260<\/p>\n

e)\u00a01040<\/p>\n

Question 10:\u00a0<\/b>$\\sqrt{5687}$\u00a0\u00d7 $\\sqrt{1245}$\u00a0\u00f7 $\\sqrt{689}$\u00a0= ?\u00f713<\/p>\n

a)\u00a0840<\/p>\n

b)\u00a0910<\/p>\n

c)\u00a01320<\/p>\n

d)\u00a01120<\/p>\n

e)\u00a01550<\/p>\n

Instructions<\/b><\/p>\n

What approximate value will come in place of the question mark (?) in the following question?<\/p>\n

Question 11:\u00a0<\/b>32.05% of 259.99 =?<\/p>\n

a)\u00a092<\/p>\n

b)\u00a088<\/p>\n

c)\u00a078<\/p>\n

d)\u00a090<\/p>\n

e)\u00a083<\/p>\n

Question 12:\u00a0<\/b>$\\frac{1}{8}$ of $\\frac{2}{3}$ of$\\frac{3}{5}$of 1715=?<\/p>\n

a)\u00a080<\/p>\n

b)\u00a085<\/p>\n

c)\u00a090<\/p>\n

d)\u00a095<\/p>\n

e)\u00a075<\/p>\n

Question 13:\u00a0<\/b>$25.05\\times123.95+388.999\\times15.001$=?<\/p>\n

a)\u00a0900<\/p>\n

b)\u00a08950<\/p>\n

c)\u00a08935<\/p>\n

d)\u00a08975<\/p>\n

e)\u00a08995<\/p>\n

Question 14:\u00a0<\/b>$561\\div35.05\\times19.99$=?<\/p>\n

a)\u00a0320<\/p>\n

b)\u00a0330<\/p>\n

c)\u00a0315<\/p>\n

d)\u00a0325<\/p>\n

e)\u00a0335<\/p>\n

Question 15:\u00a0<\/b>$(15.01)^{2}\\times\\sqrt{730}$=?<\/p>\n

a)\u00a06125<\/p>\n

b)\u00a06225<\/p>\n

c)\u00a06200<\/p>\n

d)\u00a06075<\/p>\n

e)\u00a06250<\/p>\n

Instructions<\/b><\/p>\n

What approximate value should come in place of the question mark (?) in the following questions? You are not expected to calculate the exact value.<\/p>\n

Question 16:\u00a0<\/b>$750.0003\\div19.999=?$<\/p>\n

a)\u00a049<\/p>\n

b)\u00a018<\/p>\n

c)\u00a022<\/p>\n

d)\u00a045<\/p>\n

e)\u00a038<\/p>\n

Question 17:\u00a0<\/b>6888.009-487.999-87.898=?<\/p>\n

a)\u00a06000<\/p>\n

b)\u00a06500<\/p>\n

c)\u00a06430<\/p>\n

d)\u00a06200<\/p>\n

e)\u00a06310<\/p>\n

Question 18:\u00a0<\/b>$(9.5)^{2}$=?<\/p>\n

a)\u00a075<\/p>\n

b)\u00a090<\/p>\n

c)\u00a0125<\/p>\n

d)\u00a0110<\/p>\n

e)\u00a080<\/p>\n

Question 19:\u00a0<\/b>$19.003\\times22.998-280.010=?$<\/p>\n

a)\u00a0220<\/p>\n

b)\u00a0110<\/p>\n

c)\u00a0160<\/p>\n

d)\u00a090<\/p>\n

e)\u00a0200<\/p>\n

Question 20:\u00a0<\/b>$5454\\div54\\div5=?$<\/p>\n

a)\u00a015<\/p>\n

b)\u00a025<\/p>\n

c)\u00a030<\/p>\n

d)\u00a020<\/p>\n

e)\u00a010<\/p>\n

Instructions<\/b><\/p>\n

What will come in place of question mark (?) in the following questions:<\/p>\n

Question 21:\u00a0<\/b>$32\\cdot05$% of 259.99=?<\/p>\n

a)\u00a092<\/p>\n

b)\u00a088<\/p>\n

c)\u00a078<\/p>\n

d)\u00a090<\/p>\n

e)\u00a083<\/p>\n

Question 22:\u00a0<\/b>$\\frac{1}{8} of \\frac{2}{3} of \\frac{3}{5}$ of 1715=?<\/p>\n

a)\u00a080<\/p>\n

b)\u00a085<\/p>\n

c)\u00a090<\/p>\n

d)\u00a095<\/p>\n

e)\u00a075<\/p>\n

Question 23:\u00a0<\/b>$25\\cdot05\\times123\\cdot95+388\\cdot999\\times15\\cdot001=?$<\/p>\n

a)\u00a0900<\/p>\n

b)\u00a08950<\/p>\n

c)\u00a08935<\/p>\n

d)\u00a08975<\/p>\n

e)\u00a08995<\/p>\n

Question 24:\u00a0<\/b>$561\\div35\\cdot05\\times19\\cdot99$=?<\/p>\n

a)\u00a0320<\/p>\n

b)\u00a0330<\/p>\n

c)\u00a0315<\/p>\n

d)\u00a0325<\/p>\n

e)\u00a0335<\/p>\n

Question 25:\u00a0<\/b>$(15\\cdot01)^{2}\\times\\sqrt{730}=?$<\/p>\n

a)\u00a06125<\/p>\n

b)\u00a06225<\/p>\n

c)\u00a06200<\/p>\n

d)\u00a06075<\/p>\n

e)\u00a06250<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

($\\sqrt{5}$ – $\\sqrt{10}$)2 <\/sup>
\n= 5 + 10 – 2$\\sqrt{50}$
\n= 15 – 2 x 5$\\sqrt{2}$
\n= 15 – 10$\\sqrt{2}$
\n($\\sqrt{2}$ + 5)2 <\/sup>
\n= 2 + 25 + 10$\\sqrt{2}$
\n= 27 + 10$\\sqrt{2}$<\/p>\n

Sum = 42
\n42 + 22 = 64
\n$\\sqrt[3]{64}$ = 4.<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\sqrt{2116}$ = 46
\n46\u00a0\u00f7 0.01 = 4600
\n55% of 4600 = 2530
\n2530\u00a0\u00f7 20 = 126.5<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

16\u00f724 = 0.666
\n122 <\/sup>= 144
\n0.666 x 144 = 96
\n7 x 5 =35
\n96 + 193 + 35 = 324
\n$\\sqrt{324}$ = 18
\n18 = [3$\\sqrt{2}$]2
\n<\/sup>Hence, Option A is correct answer.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$\\sqrt{31.36}$ = 5.6
\n$\\sqrt{0.64}$ = 0.8
\n5.6\u00a0\u00f7 0.8 = 7
\n7 x 252 = 1764
\n1764\u00a0\u00f7 36 = 49
\n$\\sqrt{49}$ = \u00b17
\n5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

1.694\u00a0<\/sup>= 8.15
\n2.1973 <\/sup>= 10.6
\n1.33<\/sup>\u00a0= 2.197<\/p>\n

[8.15\u00a0\u00f7 10.6 ] x\u00a02.197 = 1.689\u00a0\u2248 1.69 = 1.32<\/sup><\/p>\n

1.34-2<\/sup> =1.32<\/sup><\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

68% of 1288 = 875.84
\n26% of 734 = 190.84
\nSum = 875.84 + 190.84 = 1066.68
\n1066.68 – 215 = 851.68 \u2248 850<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

322\u00a0<\/sup>= 1024
\n192\u00a0<\/sup>= 361
\n122 <\/sup>= 144
\n1024 – 361 -144 = 519\u00a0\u2248 530<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

6578 \u00f7 65 = 101.2
\n101.2 x 15 = 1518
\n1518 \u00f7 6 = 253 \u2248 250<\/p>\n

9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$\\frac{679}{45}$ = 15.08
\n$\\frac{2130}{23}$ = 92.60<\/p>\n

15.08 x 92.60 = 1396.53
\n126\u00a0\u00f7 169 = 0.74<\/p>\n

1033.43\u00a0\u2248 1040<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$\\sqrt{5687}$ = 75.41
\n$\\sqrt{1245}$ = 35.28
\n$\\sqrt{689}$ = 26.24<\/p>\n

75.41 x 35.28 = 2660.46
\n2660.46\u00a0\u00f7 26.24 = 101.38
\n101.38 x 13 = 1318.06\u00a0\u2248 1320<\/p>\n

11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

As we need to find the approximate value only,<\/p>\n

32.05% of 259.99 can be approximated to 32% of 260 = 0.32 *260 = 83.2<\/p>\n

Option (e) is the closest to this and hence is the answer<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

We need to find the approximate value of $\\frac{1}{8}$ of $ \\frac{2}{3}$ of $\\frac{3}{5}$ of 1715<\/p>\n

$\\frac{1}{8}$ of $\\frac{2}{3}$ of $\\frac{3}{5}$ = $\\frac{1}{20}$<\/p>\n

Hence, the approximate value equals $\\frac{1}{20} \\times 1715 = 85.75 \\approx 85$<\/p>\n

Hence, the correct answer is option (b)<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

As we are finding the approximate value of the given equation, let us slightly increase one of the terms and decrease the other time slightly.<\/p>\n

Hence, $25.05\\times123.95+388.999\\times15.001 \\approx 25 \\times 124 + 389\\times 15$<\/p>\n

This equals $3100 + 5835 = 8935$<\/p>\n

So, the correct option is option (c)<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$561\\div35.05\\times19.99 \\approx 560 \\div 35 \\times 20$<\/p>\n

This equals $16 \\times 20 = 320 $<\/p>\n

Hence, the correct option is option (a)<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

As we need to find the approximate value of the given equation, we can make some small approximations.<\/p>\n

$(15.01)^{2}\\times\\sqrt{730} \\approx 15^2 \\times \\sqrt{729}$<\/p>\n

This equals $225*27 = 6075$<\/p>\n

Hence, the correct option is option (d)<\/p>\n

16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The given expression equals $750.0003\\div19.999=?$<\/p>\n

Note that this can be simplified to an approximate value of $750 \\div 20 = 37.5 \\approx 38$<\/p>\n

As the other options are not close enough to $37.5$, we can conclude that the correct answer is option (e)<\/p>\n

17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

In questions like this, the onus is on solving questions with a good level of accuracy.<\/p>\n

Note that $6888.009 \\approx 6888$<\/p>\n

$487.999 \\approx 488$<\/p>\n

$87.898 \\approx 88$<\/p>\n

So, the expression equals $6888 – 488 – 88 = 6888 – 576 = 6312 \\approx 6310$<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

In order to find the approximate value of $9.5^2$, we write $9.5 = 9 + 0.5$<\/p>\n

So, $9.5^2 = (9+0.5)^2 = 9^2 + 2*0.5*9 + 0.5^2 = 81 + 9 +0.25 = 90.25 \\approx 90$<\/p>\n

19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

In order to find the approximate value of $19.003\\times22.998-280.010$, we use the approximate values of each of the entities<\/p>\n

$19.003 \\approx 19$<\/p>\n

$22.998 \\approx 23$<\/p>\n

$280.010 \\approx 280$<\/p>\n

So, the equation is approximately equal to $19 \\times 23 – 280 = 437 – 280 = 157 \\approx 160$<\/p>\n

20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The required expression is $5454 \\div 54 \\div 5 = 101 \\div 5$<\/p>\n

The approximate value of $101 \\div \\approx 20$<\/p>\n

Hence, the correct option is option (d)<\/p>\n

21)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The problem can be solved quickly by rounding off,<\/p>\n

32.05% ~32 and 259.99~ 260<\/p>\n

Now, 32% of 260 = 83.2<\/p>\n

22)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Now, $\\frac{1}{8} of \\frac{2}{3} $= (1\/8)*(2\/3)=1\/12<\/p>\n

Also, ( $\\frac{1}{8} of \\frac{2}{3}$ ) of $\\frac{3}{5}$ = (1\/12) * (3\/5) = 1\/20
\nNow, (1\/20) 0f 1715= (1\/20)*1715 = 85<\/p>\n

23)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Here we are approximating 25.05~25, 123.95~124, 388.99~389, 15.001~15.<\/p>\n

The question can be rewritten as,<\/p>\n

25*123+388*15=8935
\nHence the correct option is 8935.<\/p>\n

24)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

By approximating 561~560, 19.99~20 and 35.05~ 35 for easier calculation,<\/p>\n

the question can be written as,<\/p>\n

560*(20\/35)=320<\/p>\n

25)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The question can be reframed as,<\/p>\n

$15^{2}$*$\\sqrt(729)$=$225\\times27$=607<\/p>\n

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770 Mocks – Just Rs. 199. Enroll Here<\/a><\/p>\n

We Hope this Arithemetic Questions for SBI PO Exam Preparation is very Useful.<\/p>\n","protected":false},"excerpt":{"rendered":"

SBI PO Arithmetic Questions PDF Arithmetic Questions for SBI PO Prelims and Mains exam. Download SBI PO Approximation questions on with solutions. Instructions: What will come in place of question mark (?) in the following questions? Question 1:\u00a0$(\\sqrt{5} – \\sqrt{10})^2 + (\\sqrt{2} + 5)^2 = (?)^3 – 22$ a)\u00a0$\\sqrt{2}$ b)\u00a0$2$ c)\u00a0$16$ d)\u00a0$8$ e)\u00a0None of these […]<\/p>\n","protected":false},"author":21,"featured_media":28418,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,231],"tags":[1922,47],"class_list":{"0":"post-28236","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-sbipo","10":"tag-sbi-2019","11":"tag-sbi-po"},"better_featured_image":{"id":28418,"alt_text":"SBI PO Arithmetic Quetions PDF","caption":"SBI PO Arithmetic Quetions PDF","description":"SBI PO Arithmetic Quetions 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