{"id":28227,"date":"2019-04-30T11:33:37","date_gmt":"2019-04-30T06:03:37","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=28227"},"modified":"2019-04-30T11:33:37","modified_gmt":"2019-04-30T06:03:37","slug":"rrb-group-d-previous-year-maths-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-group-d-previous-year-maths-questions-pdf\/","title":{"rendered":"RRB Group-D Previous Year Maths Questions PDF"},"content":{"rendered":"

RRB Group-D Previous Year Maths Questions PDF<\/strong><\/span><\/h1>\n

Download Top 15 RRB Group-D Previous year Maths Questions and Answers PDF. RRB Group-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download RRB Group-D Previous Year Maths Questions PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>Pipe A can fill a tank in 2 hrs, Pipe B can fill the same tank in 3 hrs, In how many hours both pipes together can fill the tank ?<\/p>\n

a)\u00a0$1\\frac{2}{5}$<\/p>\n

b)\u00a0$1\\frac{1}{5}$<\/p>\n

c)\u00a0$1\\frac{3}{5}$<\/p>\n

d)\u00a0$1\\frac{4}{5}$<\/p>\n

Question 2:\u00a0<\/b>It is known that 0 < \u03b8 < 90 and it is given that cot \u03b8 = 5\/12. Find the value of cosec\u03b8<\/p>\n

a)\u00a05\/13<\/p>\n

b)\u00a013\/12<\/p>\n

c)\u00a012\/5<\/p>\n

d)\u00a012\/13<\/p>\n

Question 3:\u00a0<\/b>$\\frac{sinA+sinB}{cosA-cosB}$ = ?<\/p>\n

a)\u00a0-cot($\\frac{A-B}{2}$)<\/p>\n

b)\u00a0-tan($\\frac{A-B}{2}$)<\/p>\n

c)\u00a0cot($\\frac{A+B}{2}$)<\/p>\n

d)\u00a0tan($\\frac{A+B}{2}$)<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

770 Mocks (cracku Pass) Just Rs.199<\/a><\/p>\n\n

Question 4:\u00a0<\/b>If $a^3+b^3+c^3=3abc$, then find $a^2+b^2+c^2+ab+bc+ca = ?$<\/p>\n

a)\u00a00<\/p>\n

b)\u00a0$-ab-bc-ca$<\/p>\n

c)\u00a0$bc-ca-ab$<\/p>\n

d)\u00a02<\/p>\n

Question 5:\u00a0<\/b>If $x+\\frac{1}{x} = 2$ then find $x^8+\\frac{1}{x^8}$?<\/p>\n

a)\u00a08<\/p>\n

b)\u00a04<\/p>\n

c)\u00a02<\/p>\n

d)\u00a016<\/p>\n

Question 6:\u00a0<\/b>The average of four consecutive odd numbers is 28. Find the smallest number.<\/p>\n

a)\u00a025<\/p>\n

b)\u00a029<\/p>\n

c)\u00a033<\/p>\n

d)\u00a037<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

Daily Free RRB Online Test<\/a><\/p>\n

Question 7:\u00a0<\/b>What is the fourth proportional of 12,36 and 108 ?<\/p>\n

a)\u00a0144<\/p>\n

b)\u00a0162<\/p>\n

c)\u00a0324<\/p>\n

d)\u00a0216<\/p>\n

Question 8:\u00a0<\/b>An airplane has A class tickets and B class tickets,number of people in A class to B class is 1:3 and the fares for A to B class ticket is 6:5. If the total amount collected is 4200. What is the amount collected from B class tickets ?<\/p>\n

a)\u00a03000<\/p>\n

b)\u00a02500<\/p>\n

c)\u00a02000<\/p>\n

d)\u00a01500<\/p>\n

Question 9:\u00a0<\/b>$\\frac{6}{8}\\times \\frac{16}{18} \\times \\frac{3}{4} \\times X = \\frac{4}{7}$, find $1\/X$ ?<\/p>\n

a)\u00a04\/7<\/p>\n

b)\u00a08\/7<\/p>\n

c)\u00a07\/8<\/p>\n

d)\u00a07\/4<\/p>\n

Question 10:\u00a0<\/b>$5\\frac{3}{4}+4\\frac{1}{2}-3\\frac{3}{8} = ?$<\/p>\n

a)\u00a0$6\\frac{7}{8}$<\/p>\n

b)\u00a0$7\\frac{6}{8}$<\/p>\n

c)\u00a0$5\\frac{6}{8}$<\/p>\n

d)\u00a0$5\\frac{7}{8}$<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 11:\u00a0<\/b>A fruit seller had some mangoes. He sold 30% of mangoes and still has 560 mangoes. How many mangoes he had originally?<\/p>\n

a)\u00a0300<\/p>\n

b)\u00a0800<\/p>\n

c)\u00a0600<\/p>\n

d)\u00a0450<\/p>\n

Question 12:\u00a0<\/b>X,Y and Z contested in elections. X got 144 votes and Y got 30% votes of total votes then What is percent of votes received by Z if total number of voters is 300 ?<\/p>\n

a)\u00a020%<\/p>\n

b)\u00a021%<\/p>\n

c)\u00a022%<\/p>\n

d)\u00a019%<\/p>\n

Question 13:\u00a0<\/b>Nithya wants to purchase 12 chocolates, 15 pencils, 13 pens. Cost of 1 pencil is 3\/-, cost of 2 pens is 10\/- and cost of chocolate is 2\/-. Then find the total cost ?<\/p>\n

a)\u00a0124<\/p>\n

b)\u00a0134<\/p>\n

c)\u00a0144<\/p>\n

d)\u00a0154<\/p>\n

Question 14:\u00a0<\/b>A number when divided by 11 leaves a remainder of 10 and when divided by 10 leaves a remainder of 8. Which of the following is a possible value of the number?<\/p>\n

a)\u00a0123<\/p>\n

b)\u00a0194<\/p>\n

c)\u00a062<\/p>\n

d)\u00a098<\/p>\n

Question 15:\u00a0<\/b>Find the slope of the line passing through the points (2, -5) and (6, -7) ?<\/p>\n

a)\u00a0-1\/2<\/p>\n

b)\u00a01\/2<\/p>\n

c)\u00a0-2\/3<\/p>\n

d)\u00a02\/3<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the capacity of tank = LCM of 2&3 = 6 units<\/p>\n

Efficiency of pipe A = 6\/2 = 3<\/p>\n

Efficiency of pipe B = 6\/3 = 2<\/p>\n

Both together can fill the tank in $\\frac{6}{2+3} hrs = \\frac{6}{5} hrs = 1\\frac{1}{5}hrs$<\/p>\n

So the answer is option B.<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\text{cot} \\theta = \\frac{5}{12}$<\/p>\n

$\\text{cosec}^2 \\theta$ = $1+\\text{cot}^2 \\theta = 1+{(\\frac{5}{12})}^2 = \\frac{169}{144}$<\/p>\n

$\\text{cosec}\\theta = \\frac{13}{12}$<\/p>\n

So the answer is option B.<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\frac{sinA+sinB}{cosA-cosB}$<\/p>\n

=$\\frac{2sin(\\frac{A+B}{2})cos(\\frac{A-B}{2})}{-2sin(\\frac{A+B}{2})sin(\\frac{A-B}{2})}$<\/p>\n

=-cot($\\frac{A-B}{2}$)<\/p>\n

So the answer is option A.<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

If $a^3+b^3+c^3=3abc$, then $a+b+c = 0$<\/p>\n

$(a+b+c)^2 = 0$<\/p>\n

$a^2+b^2+c^2+2ab+2bc+2ca = 0$<\/p>\n

$a^2+b^2+c^2+ab+bc+ca = -ab-bc-ca$<\/p>\n

So the answer is option B.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$x+\\frac{1}{x} = 2$<\/p>\n

Squaring on both sides<\/p>\n

$(x+\\frac{1}{x})^2 = 4$<\/p>\n

$x^2+\\frac{1}{x^2}+2 = 4$<\/p>\n

$x^2+\\frac{1}{x^2} = 2$<\/p>\n

Squaring on both sides<\/p>\n

$(x^2+\\frac{1}{x^2})^2 = 4$<\/p>\n

$x^4+\\frac{1}{x^4}+2 = 4$<\/p>\n

$x^4+\\frac{1}{x^4} = 2$<\/p>\n

Squaring on both sides<\/p>\n

$(x^4+\\frac{1}{x^4})^2 = 4$<\/p>\n

$x^8+\\frac{1}{x^8}+2 = 4$<\/p>\n

$x^8+\\frac{1}{x^8} = 2$<\/p>\n

So the answer is option C.<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the smallest odd number be x.
\nGiven, $\\dfrac{x+x+2+x+4+x+6}{4} = 28$
\n\u21d2 4x+12 = 112
\n\u21d2 4x = 100
\n\u21d2 x = 25
\nHence, The smallest odd number = x = 25.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

For fourth proportional we have 12:36::108:x
\nTherefore 12x=36*108
\nx=324<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the people in A class and B class be 1x and 3x respectively
\nand the cost of ticket for A class and B class be 6y and 5y respectively
\nTotal amount from A class is 1x*6y=6xy
\nTotal amount from B class is 3x*5y=15xy
\nTotal amount is 21xy=4200
\nxy=200
\nAmount from B class is 15*200=Rs 3000<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\frac{6}{8}\\times \\frac{16}{18} \\times \\frac{3}{4} \\times X = \\frac{4}{7}$<\/p>\n

$\\frac{3}{4}\\times \\frac{8}{9} \\times \\frac{3}{4} \\times X = \\frac{4}{7}$<\/p>\n

$\\frac{1}{2} \\times X = \\frac{4}{7}$<\/p>\n

$X = 8\/7$<\/p>\n

$1\/X = 7\/8$<\/p>\n

So the answer is option B.<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$5\\frac{3}{4}+4\\frac{1}{2}-3\\frac{3}{8} = (5+4-3)+(\\frac{3}{4}+\\frac{1}{2}-\\frac{3}{8}) = 6+\\frac{7}{8} = 6\\frac{7}{8}$<\/p>\n

So the answer is option A.<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given that he has sold 30% of mangoes.
\nThen he now has 70% of mangoes.
\n70% \u2192 560
\n100% \u2192 ?<\/p>\n

$ = \\dfrac{100\\times560}{70} = 800$<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given total number of votes=300
\nVotes received by Y is (30\/100)*300=90
\nVotes received by Z=300-144-90 i.e 66 votes
\nPercent of votes received by Z=(66\/300)*100
\n=22%<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Cost of 1 pencil is 3\/-, cost of 2 pens is 10\/- and cost of chocolate is 2\/-<\/p>\n

Cost of 1 pencil is 3\/-, cost of 1 pens is 5\/- and cost of chocolate is 2\/-<\/p>\n

Cost of\u00a012 chocolates, 15 pencils, 13 pens = 12(2)+15(3)+13(5) = 24+45+65 = 134\/-<\/p>\n

So the answer is option B.<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

By checking each of the options given above, we can notice that only 98 satisfies the conditions given in the question. Hence the answer is (d)<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$Slope = \\frac{y_2-y_1}{x_2-x_1} = \\frac{-7+5}{6-2} = \\frac{-2}{4} = \\frac{-1}{2}$<\/p>\n

So the answer is option A.<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Previous year Maths Questions for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

RRB Group-D Previous Year Maths Questions PDF Download Top 15 RRB Group-D Previous year Maths Questions and Answers PDF. RRB Group-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0Pipe A can […]<\/p>\n","protected":false},"author":41,"featured_media":28229,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679],"tags":[489,491,1819,1647],"class_list":{"0":"post-28227","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-group-d-exam","14":"tag-rrb-mocks"},"better_featured_image":{"id":28229,"alt_text":"RRB Group-D Previous Year Maths Questions PDF","caption":"RRB Group-D Previous Year Maths Questions PDF","description":"RRB Group-D Previous Year Maths Questions 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