{"id":28215,"date":"2019-04-29T19:01:33","date_gmt":"2019-04-29T13:31:33","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=28215"},"modified":"2019-04-29T19:01:33","modified_gmt":"2019-04-29T13:31:33","slug":"rrb-group-d-lcm-hcf-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-group-d-lcm-hcf-questions-pdf\/","title":{"rendered":"RRB Group-D LCM & HCF Questions PDF"},"content":{"rendered":"

RRB Group-D LCM & HCF Questions PDF<\/strong><\/span><\/h1>\n

Download Top 15 RRB Group-D LCM & HCF Questions and Answers PDF. RRB Group-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download RRB Group-D LCM & HCF Questions PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>Find the LCM and HCF of 0.25, 0.5, 0.75<\/p>\n

a)\u00a01.5, 0.25<\/p>\n

b)\u00a02, 1<\/p>\n

c)\u00a01.5, 0.5<\/p>\n

d)\u00a03, 1<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>Find the HCF of 120, 150,180<\/p>\n

a)\u00a030<\/p>\n

b)\u00a060<\/p>\n

c)\u00a050<\/p>\n

d)\u00a010<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>Find the HCF of 1\/2 and 3\/2<\/p>\n

a)\u00a03\/2<\/p>\n

b)\u00a01\/2<\/p>\n

c)\u00a01<\/p>\n

d)\u00a03<\/p>\n

e)\u00a0None of these<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

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Question 4:\u00a0<\/b>Find the least number which is exactly divisible by 12, 15, 20 and 27.<\/p>\n

a)\u00a0650<\/p>\n

b)\u00a0520<\/p>\n

c)\u00a0600<\/p>\n

d)\u00a0540<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>The HCF of two natural numbers a and b is 7 and a\/b = 1.5. What is the value of a*b?<\/p>\n

a)\u00a0224<\/p>\n

b)\u00a01176<\/p>\n

c)\u00a0294<\/p>\n

d)\u00a0304<\/p>\n

e)\u00a0None of the above<\/p>\n

Question 6:\u00a0<\/b>The LCM of two numbers x and y is 20. Find the number of unordered pairs (x,y)?<\/p>\n

a)\u00a08<\/p>\n

b)\u00a09<\/p>\n

c)\u00a07<\/p>\n

d)\u00a010<\/p>\n

e)\u00a0None of the above<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

Daily Free RRB Online Test<\/a><\/p>\n

Question 7:\u00a0<\/b>The ratio of two numbers is 5:6. The product of the HCF and LCM of the two numbers is 120. What is the HCF of the two numbers?<\/p>\n

a)\u00a02<\/p>\n

b)\u00a04<\/p>\n

c)\u00a06<\/p>\n

d)\u00a08<\/p>\n

e)\u00a01<\/p>\n

Question 8:\u00a0<\/b>The sum of two numbers is 65 and the HCF of the two numbers is 5. If the LCM of the two numbers is 180, what is the sum of the reciprocals of the two numbers?<\/p>\n

a)\u00a011\/13<\/p>\n

b)\u00a011\/625<\/p>\n

c)\u00a013\/625<\/p>\n

d)\u00a011\/180<\/p>\n

e)\u00a013\/180<\/p>\n

Question 9:\u00a0<\/b>The least number which when divided by 3,5 and 7 leaves a remainder 2 and is divisible by 2 is:<\/p>\n

a)\u00a0212<\/p>\n

b)\u00a0210<\/p>\n

c)\u00a0424<\/p>\n

d)\u00a0106<\/p>\n

e)\u00a0none of the above<\/p>\n

Question 10:\u00a0<\/b>The two numbers 15 and x have their LCM as 150. If the HCF of two numbers is 5, what could be the value of x?<\/p>\n

a)\u00a075<\/p>\n

b)\u00a045<\/p>\n

c)\u00a030<\/p>\n

d)\u00a050<\/p>\n

e)\u00a010<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 11:\u00a0<\/b>The two numbers are in the ratio 5:9. If HCF of two numbers is 7, what is the value of the LCM of the numbers?<\/p>\n

a)\u00a0630<\/p>\n

b)\u00a0165<\/p>\n

c)\u00a0315<\/p>\n

d)\u00a0195<\/p>\n

e)\u00a0None of these<\/p>\n

Question 12:\u00a0<\/b>The LCM of two numbers is 360, and their HCF is 15. If one of the numbers is 45, what is the value of the remainder when the other number is divided by 7?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a02<\/p>\n

c)\u00a03<\/p>\n

d)\u00a04<\/p>\n

e)\u00a00<\/p>\n

Question 13:\u00a0<\/b>Which is the largest number that leaves a same remainder on dividing 640, 960 and 1120<\/p>\n

a)\u00a020<\/p>\n

b)\u00a040<\/p>\n

c)\u00a080<\/p>\n

d)\u00a0160<\/p>\n

e)\u00a0320<\/p>\n

Question 14:\u00a0<\/b>What is the HCF of 221, 323, 391 and 289?<\/p>\n

a)\u00a013<\/p>\n

b)\u00a017<\/p>\n

c)\u00a019<\/p>\n

d)\u00a021<\/p>\n

e)\u00a023<\/p>\n

Question 15:\u00a0<\/b>What is the LCM of the following fractions? \u2154, 4\/7, 1\/4<\/p>\n

a)\u00a01<\/p>\n

b)\u00a02<\/p>\n

c)\u00a04<\/p>\n

d)\u00a07<\/p>\n

e)\u00a08<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

LCM of 0.25, 0.5 and 0.75<\/p>\n

he given numbers can be written as of 0.25, 0.50 and 0.75<\/p>\n

Now ignoring the decimals we find LCM of 25, 50, and 75<\/p>\n

5 | 25, 50, 75<\/p>\n

5 | 5, 10, 15<\/p>\n

| 1, 2, 3<\/p>\n

\u2234 LCM = 1 \u00d7 2 \u00d7 3 \u00d7 5 \u00d7 5 = 25 \u00d7 6 = 150<\/p>\n

LCM = 150.<\/p>\n

Similarly we will find out the HCF for 25, 50 and 75.<\/p>\n

Since given numbers are not high, we can follow Prime factorization method to get the HCF easily<\/p>\n

25 = $5^2$<\/p>\n

50 = $2\\times5^2$<\/p>\n

75 = $3\\times5^2$.<\/p>\n

As discussed before HCF = $5^2$ = 25.<\/p>\n

Now we got LCM = 150 and HCF = 25, now after putting decimal places as per given in the question the LCM = 1.5, and HCF = 0.25.<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

since given numbers are not high, we can follow Prime factorization method to get the HCF easily
\n$120 = 2^3 * 3 * 5$
\n$150 = 2 * 3 * 5^2$
\n$180 = 2^2 * 3^2 * 5$
\nIn Prime factorization method after converting the numbers into product of prime factors, take the common factors from all the numbers of the least powers.
\nTherefore HCF is 2 x 3 x 5 = 30<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

HCF of 1\/2 , 3\/2 = (HCF of 1 and 3)\/(LCM of 2 and 2) = 1\/2<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Required number
\n= LCM of 12, 15, 20 and 27 = 540<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let a = hx and b = hy.
\nh = 7 and x\/y = 1.5 = 3\/2
\nSo, x = 3 and y = 2
\na*b = 21*14 = 294<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The pairs of numbers are (1,20), (2,20), (4,20) , (5,20) , (10,20) , (20,20) , (4,5) , (4,10). So, the number of unordered pairs is 8.<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the two numbers be 5h and 6h where h is the HCF of the numbers. Product of the numbers = Product of LCM and HCF.
\n=> $30 h^2$ = 120 => h = 2
\nSo, the HCF of the two numbers is 2<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let the numbers be ha and hb. HCF of the numbers = h and LCM of the numbers = hab.
\nSum of reciprocals = (a+b)\/hab
\nh(a+b) = 65
\nh = 5
\n(a+b) = 13
\nhab = LCM = 180
\nSo, sum of reciprocals = 13\/180<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

L.C.M of 3,5 and 7 is 105.
\nThus, the required number is of the form 105x + 2.
\n212 is the lowest such number also divisible by 2.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

We have learned a formula which says that
\nLCM*HCF = product of the two numbers.
\nSo 15*x = 150*5
\n=> x = $\\frac{150*5}{15}$ = 50<\/p>\n

11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the numbers be 5x and 9x. Now since 5 and nine are co-prime, the HCF of two numbers is x. It is given that HCF is 7, so x = 7.
\nThus the required numbers are 35 and 63.
\nThe LCM of 35 and 63 is 7*5*9 = 315<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

let the second number be x.
\nWe know that LCM*HCF = Product of the two numbers
\nSo 360*15 = x *45
\n=> x = $\\frac{360*15}{45}$
\n=> x = 120
\nNow 120 on being divided by 7, leaves a remainder of 1.<\/p>\n

13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

From the properties of HCF, we know that
\nlargest number which leaves the same remainder on dividing x, y and z are given by HCF (x-y, y-z, z-x).
\nHere x = 640, y = 960, z =1120
\nSo the required number is HCF (960-640, 1120-960, 1120-640)
\n= HCF(320, 160, 480) = 160
\nSo the required number is 160<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

221 = 17 *13
\n323 = 17 * 19
\n391 = 17 * 23
\n289 = 17 * 17
\nHence HCF of the given numbers = 17<\/p>\n

15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

LCM of fractions = LCM of the numerators\/ HCF of the denominators.
\nLCM of 2, 4 and 1 is 4
\nHCF of 3, 7 and 4 is 1
\nSo, the LCM of the given fractions is 4\/1 = 4<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this LCM & HCF Questions for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

RRB Group-D LCM & HCF Questions PDF Download Top 15 RRB Group-D LCM & HCF Questions and Answers PDF. RRB Group-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0Find the LCM […]<\/p>\n","protected":false},"author":41,"featured_media":28220,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679],"tags":[489,491,492,1647],"class_list":{"0":"post-28215","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-group-d","14":"tag-rrb-mocks"},"better_featured_image":{"id":28220,"alt_text":"RRB Group-D LCM & HCF Questions PDF","caption":"RRB Group-D LCM & HCF Questions PDF","description":"RRB Group-D LCM & HCF Questions 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