Take a free mock test for SSC CHSL<\/a><\/p>\n Download SSC CHSL Previous Papers<\/a><\/p>\n Question 1:\u00a0<\/b>Three positions of a cube are given below<\/p>\n a)\u00a01<\/p>\n b)\u00a02<\/p>\n c)\u00a03<\/p>\n d)\u00a04<\/p>\n Question 2:\u00a0<\/b>Three positions of a cube are given below<\/p>\n a)\u00a01<\/p>\n b)\u00a02<\/p>\n c)\u00a03<\/p>\n d)\u00a04<\/p>\n Question 3:\u00a0<\/b>Three positions of a cube are given below<\/p>\n a)\u00a01<\/p>\n b)\u00a02<\/p>\n c)\u00a03<\/p>\n d)\u00a04<\/p>\n Question 4:\u00a0<\/b>Three positions of a cube are given below<\/p>\n a)\u00a01<\/p>\n b)\u00a02<\/p>\n c)\u00a03<\/p>\n d)\u00a04<\/p>\n Question 5:\u00a0<\/b>Which of the following cube in the answer figure cannot be made based on unfolded cube in the question figure?<\/p>\n a)<\/p>\n b)<\/p>\n c)<\/p>\n d)<\/p>\n SSC CHSL PREVIOUS PAPERS<\/a><\/p>\n SSC CHSL Study Material<\/a> (FREE Tests)<\/p>\n Question 6:\u00a0<\/b>What is the next term in the series ? a)\u00a01060<\/p>\n b)\u00a01450<\/p>\n c)\u00a01320<\/p>\n d)\u00a01260<\/p>\n Question 7:\u00a0<\/b>What is the next term in the series ? a)\u00a0150<\/p>\n b)\u00a0180<\/p>\n c)\u00a0210<\/p>\n d)\u00a0240<\/p>\n Question 8:\u00a0<\/b>What is the next term in the series ? a)\u00a015<\/p>\n b)\u00a05<\/p>\n c)\u00a030<\/p>\n d)\u00a045<\/p>\n Question 9:\u00a0<\/b>If HUT is coded as 3360 and TAP is coded as 320, then PUN is coded as?<\/p>\n a)\u00a04304<\/p>\n b)\u00a03904<\/p>\n c)\u00a04704<\/p>\n d)\u00a03604<\/p>\n Question 10:\u00a0<\/b>If 9 & 7 # 6 = 51 and 12 & 7 # 9 = 75, then find the value of 23 & 6 # 7<\/p>\n a)\u00a072<\/p>\n b)\u00a069<\/p>\n c)\u00a065<\/p>\n d)\u00a063<\/p>\n SSC CHSL FREE MOCK TEST<\/a><\/p>\n Instructions<\/b><\/p>\n Which of the following signs should be interchanged so that the given equation is true?<\/p>\n Question 11:\u00a0<\/b>$24-120+30\\times4\\div8$=16<\/p>\n a)\u00a0$\\times$,+<\/p>\n b)\u00a0$\\times$,$\\div$<\/p>\n c)\u00a0+,$\\div$<\/p>\n d)\u00a0-,+<\/p>\n Question 12:\u00a0<\/b>$87+12\\div3-248\\times50$=150<\/p>\n a)\u00a0$\\times$,+<\/p>\n b)\u00a0$\\times$,$\\div$<\/p>\n c)\u00a0-,$\\div$<\/p>\n d)\u00a0-,+<\/p>\n Question 13:\u00a0<\/b>Eye:Ophthalmology::Liver:?<\/p>\n a)\u00a0Osteology<\/p>\n b)\u00a0Dermatology<\/p>\n c)\u00a0Hepatology<\/p>\n d)\u00a0Nephrology<\/p>\n Question 14:\u00a0<\/b>Kidney:Nephrology::Bones:?<\/p>\n a)\u00a0Ophthalmology<\/p>\n b)\u00a0Hepatology<\/p>\n c)\u00a0Osteology<\/p>\n d)\u00a0Dermatology<\/p>\n Question 15:\u00a0<\/b>Waves:Oceans::?:Deserts<\/p>\n a)\u00a0Dust<\/p>\n b)\u00a0Storms<\/p>\n c)\u00a0Ripples<\/p>\n d)\u00a0Sand Dunes<\/p>\n FREE SSC MATERIAL – 18000 FREE QUESTIONS<\/a><\/p>\n Question 16:\u00a0<\/b>If $\\sec \\theta +\\tan \\theta=2$, then the value of $\\sin \\theta$ is:<\/p>\n a)\u00a0$\\frac{4}{5}$<\/p>\n b)\u00a0$\\frac{\\sqrt{3}}{5}$<\/p>\n c)\u00a0$\\frac{2}{5}$<\/p>\n d)\u00a0$\\frac{3}{5}$<\/p>\n Question 17:\u00a0<\/b>If $\\alpha + \\theta$ =\u00a0 $\\frac{7\\pi}{12}$ and $\\tan \\theta = \\sqrt{3}$, then the value of $\\tan \\alpha$ is:<\/p>\n a)\u00a0$\\sqrt{3}$<\/p>\n b)\u00a01<\/p>\n c)\u00a00<\/p>\n d)\u00a0$\\frac{1}{\\sqrt{3}}$<\/p>\n Question 18:\u00a0<\/b>A person sells 40 chairs for Rs 10000 and gets a loss of 4% and if he had sold 30 chairs for Rs 10000 what would be his profit or loss percent ?<\/p>\n a)\u00a024%<\/p>\n b)\u00a028%<\/p>\n c)\u00a026%<\/p>\n d)\u00a022%<\/p>\n Question 19:\u00a0<\/b>Kavya buys 200 erasers at Rs 25 each and she sells 100 erasers at 10% profit. If the total profit to be obtained is 20% then the other 100 erasers should be sold at which price per eraser ?<\/p>\n a)\u00a032<\/p>\n b)\u00a032.5<\/p>\n c)\u00a032.75<\/p>\n d)\u00a032.25<\/p>\n Instructions<\/b><\/p>\n Out of the given alternatives, select the option which can be substituted in place of the given words without altering the meaning.<\/p>\n Question 20:\u00a0<\/b>One who does not follow the usual way of life<\/p>\n a)\u00a0Bohemian<\/p>\n b)\u00a0Codicil<\/p>\n c)\u00a0Dereliction<\/p>\n d)\u00a0Efface<\/p>\n DOWNLOAD APP TO ACESSES DIRECTLY ON MOBILE<\/a><\/p>\n SSC CHSL Important Q&A PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n required answer<\/p>\n 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n required answer<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n required answer<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n required answer<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n When we fold the given figure, the circle with a star sign will become the base of the cube and the side with window sign will become top, and thus they will face each other. Similarly, the sides which will face each other will be\u00a0:<\/p>\n Since, the opposite sides cannot be adjacent in the cube, thus the cube in the last option is not possible.<\/p>\n => Ans – (D)<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In this series 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In this series 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In this series next number is obtained by dividing the previous number by 7,5,3,1 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let us write the alphabets from A to Z in two rows as shown below.<\/p>\n 1\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a03\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a04\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a05\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a06\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a07\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a08\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a09\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 10\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 11\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 12\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a013<\/p>\n 26\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 25\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a024\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 23\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a022\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 21\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a020\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a019\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 18\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a017\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a016\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a015\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 14<\/p>\n Given,<\/p>\n HUT = 3360<\/p>\n H = 8; U = 21; T = 20<\/p>\n HUT = $8 \\times 21\u00a0\\times 20 = 3360$<\/p>\n TAP is coded as 320<\/p>\n T = 20; A=1; P = 16<\/p>\n TAP = $20 \\times 1\u00a0\\times 16 = 320$<\/p>\n Similarly,<\/p>\n PUN = $16 \\times 21\u00a0\\times 14 = 4704$<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given,\u00a09 & 7 # 6 = 51 and 12 & 7 # 9 = 75<\/p>\n Here the symbol $ represents +, and the symbol # represents $\\times$<\/p>\n 9 + 7 $\\times$ 6 = 51<\/p>\n 12 + 7 $\\times$ 9 = 75<\/p>\n $\\therefore$ 23 + 6 $\\times$ 7 = 65<\/p>\n GK Questions And Answers PDF<\/a><\/p>\n 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n After interchanging the signs + and $\\div$ we get 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n After interchanging the signs + and \\times we get 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Study of Eye is known as Ophthalmology.Study of Liver is Hepatology.<\/p>\n 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Study of kidney is known as Nephrology. Study of Bones is Osteology.<\/p>\n 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In Oceans we get Waves and similarly in Deserts we get Sand Dunes.<\/p>\n 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Given\u00a0:\u00a0$\\sec \\theta +\\tan \\theta=2$ ———–(i)<\/p>\n Also, $sec^2\\theta-tan^2\\theta=1$<\/p>\n => $(sec\\theta-tan\\theta)(sec\\theta+tan\\theta)=1$<\/p>\n =>\u00a0$\\sec \\theta -\\tan \\theta=\\frac{1}{2}$ ———-(ii)<\/p>\n Adding equations (i) and (ii), => $2sec\\theta=2+\\frac{1}{2}=\\frac{5}{2}$<\/p>\n => $sec\\theta=\\frac{5}{4}$<\/p>\n =>\u00a0$cos\\theta=\\frac{4}{5}$<\/p>\n $\\therefore$ $sin\\theta=\\sqrt{1-cos^2\\theta}$<\/p>\n = $\\sqrt{1-(\\frac{4}{5})^2}=\\sqrt{1-\\frac{16}{25}}$<\/p>\n = $\\sqrt{\\frac{9}{25}}=\\frac{3}{5}$<\/p>\n => Ans – (D)<\/p>\n 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given\u00a0:\u00a0$\\tan \\theta = \\sqrt{3}$<\/p>\n =>\u00a0$\\tan \\theta = tan(\\frac{\\pi}{3})$<\/p>\n => $\\theta=\\frac{\\pi}{3}$<\/p>\n Also,\u00a0$\\alpha + \\theta$ =\u00a0 $\\frac{7\\pi}{12}$<\/p>\n => $\\alpha=\\frac{7\\pi}{12}-\\frac{\\pi}{3}$<\/p>\n => $\\alpha=\\frac{7\\pi-4\\pi}{12}=\\frac{\\pi}{4}$<\/p>\n $\\therefore$ $tan\\alpha=tan(\\frac{\\pi}{4})=1$<\/p>\n => Ans – (B)<\/p>\n 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n SP of 40 chairs =10000 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Total cost of erasers=200*25=Rs 5000 20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n \u2018Bohemian\u2019 refers the one who does not follow the usual way of life. Hence, option A is the correct answer.<\/p>\n\n![](\"https:\/\/cracku.in\/media\/uploads\/h_JqcdxAK.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/h1_KoRIoNj.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/h2_c1D9NV6.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/h3_IM96SNR.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/h4_OVQPR2q.png\")
<\/figure>\n
\n12,12,36,180,?<\/p>\n
\n6,24,60,120,?<\/p>\n
\n5040,720,145,45,?<\/p>\n<\/figure>\n
\n12*1=12
\n12*3=36
\n36*5=180
\n180*7=1260<\/p>\n
\n1*2*3=6
\n2*3*4=24
\n3*4*5=60
\n4*5*6=120
\n5*6*7=210<\/p>\n
\n5040\/7=720
\n720\/5=145
\n145\/3=45
\n45\/1=45<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/2_jqSlQva.PNG\")
<\/p>\n
\n$24-120\\div30\\times4+8$
\n=24-16+8
\n=16<\/p>\n
\n$87\\times12\\div3-248+50$
\n=348-248+50
\n=150<\/p>\n
\nSP of 1 chair=250
\nGiven a loss of 4% and so CP of 1 chair=250\/0.96
\nCP of 30 chairs=(250\/0.96)*30
\nCP of 30 chairs=7812.5
\nProfit percent=((1000-7812.5)\/7812.5)*100
\n=28%<\/p>\n
\nGiven 100 are sold at 10% profit and so Selling price of 100 erasers=(100*25*1.1)=Rs 2750
\nTotal profit is 20% and so total selling price should be 5000*1.2=6000
\nSelling price of the other 100 erasers is 6000-2750=Rs.3250
\nSelling price of each eraser of other 100 erasers=3250\/100
\n= Rs.32.5<\/p>\n