{"id":27896,"date":"2019-04-24T16:37:21","date_gmt":"2019-04-24T11:07:21","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=27896"},"modified":"2019-04-24T16:37:21","modified_gmt":"2019-04-24T11:07:21","slug":"rrb-ntpc-maths-questions-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-ntpc-maths-questions-set-2-pdf\/","title":{"rendered":"RRB NTPC Maths Questions Set-2 PDF"},"content":{"rendered":"

RRB NTPC Maths Questions Set-2 PDF<\/strong><\/span><\/h1>\n

Download RRB NTPC Maths Set-2 Questions and Answers PDF. Top 15 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download RRB NTPC Maths Questions Set-2 PDF<\/a><\/p>\n

Download RRB NTPC Set-1 Maths Questions PDF<\/a><\/p>\n\n

Take a free mock test for RRB NTPC<\/a><\/p>\n

Download RRB NTPC Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>Find the value of $tan 56^\\circ – tan 11^\\circ – tan 56^\\circ.tan 11^\\circ$<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a0-1<\/p>\n

d)\u00a02<\/p>\n

Question 2:\u00a0<\/b>Minimum value of $2\\sin^{2}x+1\\cos^{2}x$<\/p>\n

a)\u00a01.5<\/p>\n

b)\u00a02<\/p>\n

c)\u00a01<\/p>\n

d)\u00a00<\/p>\n

Question 3:\u00a0<\/b>If (a+b) = 13 and ab = 36, then find (a-b).<\/p>\n

a)\u00a08<\/p>\n

b)\u00a05<\/p>\n

c)\u00a06<\/p>\n

d)\u00a09<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Question 4:\u00a0<\/b>A number is increased by 20 and divided by 13 to get the result as 9 and if the number is decreased by 4 and divided by 27 then the remainder obtained ?<\/p>\n

a)\u00a011<\/p>\n

b)\u00a014<\/p>\n

c)\u00a012<\/p>\n

d)\u00a013<\/p>\n

Question 5:\u00a0<\/b>The product of $(a+b+c) \\times (a+2b-c)$ is ?<\/p>\n

a)\u00a0$a^2+2b^2-c^2+3ab+bc$<\/p>\n

b)\u00a0$a^2+2b^2-c^2+3ab+2bc$<\/p>\n

c)\u00a0$a^2+2b^2-c^2+2ab+bc$<\/p>\n

d)\u00a0$a^2+2b^2-c^2+3ab+3bc$<\/p>\n

RRB NTPC Free Mock Test<\/a><\/p>\n\n

Question 6:\u00a0<\/b>3[2x-4\/3] + 4[2-3x\/2] = 4, then find x ?<\/p>\n

a)\u00a03\/2<\/p>\n

b)\u00a00<\/p>\n

c)\u00a0x can be any number<\/p>\n

d)\u00a01<\/p>\n

Question 7:\u00a0<\/b>Find a-b if a+b = 23, ab = 132 ?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a0-1<\/p>\n

c)\u00a02<\/p>\n

d)\u00a0Either (a) or (b)<\/p>\n

Question 8:\u00a0<\/b>If p, q are the sum and product of the roots of $3x^3-4x^2+5x-6=0$, then find p*q ?<\/p>\n

a)\u00a03\/8<\/p>\n

b)\u00a08\/3<\/p>\n

c)\u00a02\/3<\/p>\n

d)\u00a03\/2<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n\n

Question 9:\u00a0<\/b>Find the value of $3^3+4^3+5^3+…..+10^3$ ?<\/p>\n

a)\u00a03015<\/p>\n

b)\u00a03020<\/p>\n

c)\u00a03025<\/p>\n

d)\u00a03016<\/p>\n

Question 10:\u00a0<\/b>Find the value of $1-\\frac{1}{1-\\frac{1}{1+\\frac{1}{x}}}$ ?<\/p>\n

a)\u00a0$x$<\/p>\n

b)\u00a0$-x$<\/p>\n

c)\u00a01<\/p>\n

d)\u00a0-1<\/p>\n

RRB JE Free Mock Test<\/a><\/p>\n\n

Question 11:\u00a0<\/b>Find x*y, if (x+y) = 14, (x-y) = 4 ?<\/p>\n

a)\u00a040<\/p>\n

b)\u00a056<\/p>\n

c)\u00a045<\/p>\n

d)\u00a050<\/p>\n

Question 12:\u00a0<\/b>Consider the following set of numbers: A = {1, 2, 3, 2, 5, 2, 3, 4, 6, 2, 3, 5, 5, 6, 7, 8, 7, 8, 3, 5, 6, 1, 3, 8, 7}. What is the mode of the set?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a05<\/p>\n

c)\u00a03<\/p>\n

d)\u00a02<\/p>\n

Question 13:\u00a0<\/b>Find the absolute difference between the median and mode of the following data:
\n3, 6, 8, 6, 8, 7, 5, 4, 3, 8, 6, 7, 4, 9, 4, 2, 5, 1, 2, 8<\/p>\n

a)\u00a02<\/p>\n

b)\u00a03<\/p>\n

c)\u00a02.5<\/p>\n

d)\u00a02.75<\/p>\n

Daily Free RRB Online Tests for RRB Exams<\/a><\/p>\n

RRB NTPC Free Mock Test<\/a><\/p>\n

Question 14:\u00a0<\/b>If 0.20 : 4 : : x : 120, then find the value of x.<\/p>\n

a)\u00a00.6<\/p>\n

b)\u00a060<\/p>\n

c)\u00a020<\/p>\n

d)\u00a06<\/p>\n

Question 15:\u00a0<\/b>The run-rate of 12 overs of a cricket match is 8 rpo. What should be the run-rate for the next 8 overs to chase the target of 160 runs?<\/p>\n

a)\u00a08 rpo<\/p>\n

b)\u00a06 rpo<\/p>\n

c)\u00a07.5 rpo<\/p>\n

d)\u00a08.6 rpo<\/p>\n\n

Download Current Affairs Questions & Answers PDF<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$56-11 = 45$
\nApplying \u2018tan\u2019 on both sides
\n$tan (56-11)^\\circ = tan 45^\\circ$ \u2192 (1)
\nWe know that $tan (A-B)^\\circ = \\dfrac{tan A^\\circ – tan B^\\circ}{1+tan A^\\circ.tan B^\\circ}$
\nThen, (1) becomes
\n$\\dfrac{tan 56^\\circ – tan 11^\\circ}{1+tan 56^\\circ.tan 11^\\circ} = 1$ (Since, $tan 45^\\circ = 1$)<\/p>\n

$tan 56^\\circ – tan 11^\\circ = 1+tan 56^\\circ.tan 11^\\circ$
\n\u21d2 $tan 56^\\circ – tan 11^\\circ – tan 56^\\circ.tan 11^\\circ = 1$<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$(\\sin^{2}x+\\cos^{2}x)+\\sin^{2}x$=1+$\\sin^{2}x$
\nMinimum value of $\\sin x$ is when $x$=0 i.e $\\sin 0$=0
\nTherefore 1+0=1
\nHence, option C\u00a0is the correct answer.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

We know that $(a-b)^2 = (a+b)^2-4ab$
\n\u21d2 $(a-b)^2 = 169-4*36 = 169-144 = 25$
\n\u21d2 (a-b) = 5<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

let the number be x
\n(x+20)\/13=9
\nx=117-20
\nx=97
\nAnd then (97-4)=93
\n93\/27 we get 12 as the remainder.<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$(a+b+c)(a+2b-c)$<\/p>\n

=$a^2+2ab-ac+ab+2b^2-bc+ac+2bc-c^2$<\/p>\n

=$a^2+2b^2-c^2+3ab+bc$<\/p>\n

So the answer is option A.<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

3[2x-4\/3] + 4[2-3x\/2] = 4<\/p>\n

6x-4+8-6x = 4<\/p>\n

0 = 0<\/p>\n

here we have 6x and -6x, So for any value of x, 6x-6x = 0<\/p>\n

So the answer is option C.<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$(a-b)^2 = (a+b)^2 – 4ab$<\/p>\n

$(a-b)^2 = (23)^2 – 4(132)$<\/p>\n

$(a-b)^2 = 529 – 528$<\/p>\n

$(a-b)^2 = 1$<\/p>\n

$a-b = +1 or -1$<\/p>\n

So the answer is option D.<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

p = sum of roots = -b\/a = 4\/3<\/p>\n

q = product of roots = -d\/a = 6\/3 = 2<\/p>\n

pq = (4\/3)(2) = 8\/3<\/p>\n

So the answer is option B.<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$3^3+4^3+5^3+…..+10^3 = (1^3+2^3+…..+10^3)-(1^3+2^3) = (\\frac{10^2(11)^2}{4}) – (1+8) = 3025 – 9 = 3016$<\/p>\n

So the answer is option D.<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$1-\\frac{1}{1-\\frac{1}{1+\\frac{1}{x}}}$ =\u00a0$1-\\frac{1}{1-\\frac{1}{\\frac{x+1}{x}}}$ =\u00a0$1-\\frac{1}{1-\\frac{x}{1+x}}$ =\u00a0$1-\\frac{1}{\\frac{1+x-x}{1+x}}$ =\u00a0$1-\\frac{1}{\\frac{1}{1+x}}$ = $1-1-x = -x$<\/p>\n

So the answer is option B.<\/p>\n

11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

x+y = 14<\/p>\n

x-y = 4<\/p>\n

On solving these 2 equations<\/p>\n

x = 9 & y = 5<\/p>\n

Now, x*y = 9*5 = 45<\/p>\n

So the answer is option C.<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The frequency of repetition of the numbers is as follows:<\/p>\n

1 – 2
\n2 – 4
\n3 – 5
\n4 – 1
\n5 – 4
\n6 – 3
\n7 – 3
\n8 – 3
\nSo, the mode is 3.<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

8 occurs the most number of times => 8 is mode.
\nWhen the data is arranged in the ascending order, we get:
\n1, 2, 2, 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7, 8, 8, 8, 8, 9.
\n10th and 11th digits are 5 and 6 respectively.
\n=> Median = (5+6)\/2 = 5.5
\nDifference = |8 – 5.5| = 2.5<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$4\\times x = 0.20\\times120$
\n\u21d2 $x = \\dfrac{0.20\\times120}{4} = 6<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Total score made in first 12 overs = 12*8 = 96 runs
\nTarget = 160 runs
\nRemaining score to be made = 160-96 = 64 runs
\nRequired run-rate = 64\/8 = 8 rpo.<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Maths Set-2\u00a0 Questions for RRB NTPC Exam will be highly useful for your Preparation<\/p>\n","protected":false},"excerpt":{"rendered":"

RRB NTPC Maths Questions Set-2 PDF Download RRB NTPC Maths Set-2 Questions and Answers PDF. Top 15 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Download RRB NTPC Set-1 Maths Questions PDF Take a free mock test for RRB NTPC Download RRB NTPC Previous […]<\/p>\n","protected":false},"author":41,"featured_media":27899,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603],"tags":[489,491,1647,1619],"class_list":{"0":"post-27896","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-mocks","14":"tag-rrb-ntpc-2019"},"better_featured_image":{"id":27899,"alt_text":"RRB NTPC Maths Questions Set-2 PDF","caption":"RRB NTPC Maths Questions Set-2 PDF","description":"RRB NTPC Maths Questions Set-2 PDF","media_type":"image","media_details":{"width":1200,"height":630,"file":"2019\/04\/fig-24-04-2019_10-55-13.jpg","sizes":{"thumbnail":{"file":"fig-24-04-2019_10-55-13-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-150x150.jpg"},"medium":{"file":"fig-24-04-2019_10-55-13-300x158.jpg","width":300,"height":158,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-300x158.jpg"},"medium_large":{"file":"fig-24-04-2019_10-55-13-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-768x403.jpg"},"large":{"file":"fig-24-04-2019_10-55-13-1024x538.jpg","width":1024,"height":538,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-1024x538.jpg"},"tiny-lazy":{"file":"fig-24-04-2019_10-55-13-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-30x16.jpg"},"td_80x60":{"file":"fig-24-04-2019_10-55-13-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-80x60.jpg"},"td_100x70":{"file":"fig-24-04-2019_10-55-13-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-100x70.jpg"},"td_218x150":{"file":"fig-24-04-2019_10-55-13-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-218x150.jpg"},"td_265x198":{"file":"fig-24-04-2019_10-55-13-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-265x198.jpg"},"td_324x160":{"file":"fig-24-04-2019_10-55-13-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-324x160.jpg"},"td_324x235":{"file":"fig-24-04-2019_10-55-13-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-324x235.jpg"},"td_324x400":{"file":"fig-24-04-2019_10-55-13-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-324x400.jpg"},"td_356x220":{"file":"fig-24-04-2019_10-55-13-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-356x220.jpg"},"td_356x364":{"file":"fig-24-04-2019_10-55-13-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-356x364.jpg"},"td_533x261":{"file":"fig-24-04-2019_10-55-13-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-533x261.jpg"},"td_534x462":{"file":"fig-24-04-2019_10-55-13-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-534x462.jpg"},"td_696x0":{"file":"fig-24-04-2019_10-55-13-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-696x365.jpg"},"td_696x385":{"file":"fig-24-04-2019_10-55-13-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-696x385.jpg"},"td_741x486":{"file":"fig-24-04-2019_10-55-13-741x486.jpg","width":741,"height":486,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-741x486.jpg"},"td_1068x580":{"file":"fig-24-04-2019_10-55-13-1068x580.jpg","width":1068,"height":580,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-1068x580.jpg"},"td_1068x0":{"file":"fig-24-04-2019_10-55-13-1068x561.jpg","width":1068,"height":561,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-1068x561.jpg"},"td_0x420":{"file":"fig-24-04-2019_10-55-13-800x420.jpg","width":800,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13-800x420.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":null,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-24-04-2019_10-55-13.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n