{"id":27634,"date":"2019-04-19T18:58:24","date_gmt":"2019-04-19T13:28:24","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=27634"},"modified":"2019-04-19T18:58:24","modified_gmt":"2019-04-19T13:28:24","slug":"rrb-je-previous-year-maths-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-je-previous-year-maths-questions-pdf\/","title":{"rendered":"RRB JE Previous Year Maths Questions PDF"},"content":{"rendered":"

RRB JE Previous Year Maths Questions PDF<\/strong><\/span><\/h1>\n

Download Top 15 RRB JE Maths Questions and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam.<\/p>\n

Download RRB JE Previous Year Maths Questions PDF<\/a><\/p>\n\n

Download RRB JE Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>What is the minimum value of 3 sin \u03b8 + 4 cos \u03b8 ?<\/p>\n

a)\u00a025<\/p>\n

b)\u00a0-25<\/p>\n

c)\u00a05<\/p>\n

d)\u00a0-5<\/p>\n

Question 2:\u00a0<\/b>Minimum value of $2\\sin^{2}x+1\\cos^{2}x$<\/p>\n

a)\u00a01.5<\/p>\n

b)\u00a02<\/p>\n

c)\u00a01<\/p>\n

d)\u00a00<\/p>\n

Question 3:\u00a0<\/b>If a-b = 6, ab = 16, then find $a^2+b^2$.<\/p>\n

a)\u00a048<\/p>\n

b)\u00a068<\/p>\n

c)\u00a052<\/p>\n

d)\u00a072<\/p>\n

FREE RRB JE YOUTUBE VIDEOS<\/a><\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n\n

Question 4:\u00a0<\/b>Find the value of $1+\\dfrac{1}{1+\\dfrac{1}{1+\\dfrac{1}{1+\\dfrac{2}{7}}}}$.<\/p>\n

a)\u00a0$\\frac{37}{25}$<\/p>\n

b)\u00a0$\\frac{41}{22}$<\/p>\n

c)\u00a0$\\frac{41}{25}$<\/p>\n

d)\u00a0$\\frac{35}{19}$<\/p>\n

Question 5:\u00a0<\/b>A number is increased by 12 and divided by 19 to get the result as 9 and if the number is decreased by 40 and divided by 17 then the remainder obtained is ?<\/p>\n

a)\u00a03<\/p>\n

b)\u00a00<\/p>\n

c)\u00a01<\/p>\n

d)\u00a02<\/p>\n

RRB JE Free Mock Test<\/a><\/p>\n

RRB JE Free Mock Test (latest pattern)<\/a><\/p>\n\n

 <\/p>\n

Question 6:\u00a0<\/b>Find the value of $x$ (from the given options), if $5 = 40-12x+x^2$ ?<\/p>\n

a)\u00a03<\/p>\n

b)\u00a04<\/p>\n

c)\u00a05<\/p>\n

d)\u00a06<\/p>\n

Question 7:\u00a0<\/b>Find $ab+bc+ca$, if $a^2+b^2+c^2 = 24$ & $a+b+c=4\\sqrt3$ ?<\/p>\n

a)\u00a012<\/p>\n

b)\u00a013<\/p>\n

c)\u00a014<\/p>\n

d)\u00a015<\/p>\n

Question 8:\u00a0<\/b>What is the value of x if $2^{2x} * 2^{2^{x}} * 2^{x}$ = 32?<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a02<\/p>\n

d)\u00a04<\/p>\n

Question 9:\u00a0<\/b>The average score of a cricketer for his first 10 innings is 132 runs. He scored 0 runs in his next innings. What will be his average score after 6 innings?<\/p>\n

a)\u00a0120 runs<\/p>\n

b)\u00a096 runs<\/p>\n

c)\u00a0100 runs<\/p>\n

d)\u00a084 runs<\/p>\n

Question 10:\u00a0<\/b>What is the third proportional of 12 and 36 ?<\/p>\n

a)\u00a024<\/p>\n

b)\u00a015<\/p>\n

c)\u00a072<\/p>\n

d)\u00a0108<\/p>\n

Daily Free Online Tests for RRB Exams<\/a><\/p>\n

Download RRB GK Material PDF<\/a><\/p>\n\n

Question 11:\u00a0<\/b>A theatre has 1st class tickets and 2nd class tickets. Number of people in 1st class to second class is 3:5 and the fares for 1st class to second class ticket is 5:2. If the total amount collected is 1250. What is the amount collected from second class tickets ?<\/p>\n

a)\u00a0750<\/p>\n

b)\u00a0500<\/p>\n

c)\u00a0250<\/p>\n

d)\u00a0800<\/p>\n

Question 12:\u00a0<\/b>Find the equation of the line passing through (2, 3) and (-4, 15) ?<\/p>\n

a)\u00a0x-2y = 7<\/p>\n

b)\u00a02x-y = 7<\/p>\n

c)\u00a0x+2y = 7<\/p>\n

d)\u00a02x+y = 7<\/p>\n

Question 13:\u00a0<\/b>Find the value of x, if 2x+3y = 4 and 4x+6y = 8 ?<\/p>\n

a)\u00a02<\/p>\n

b)\u00a03<\/p>\n

c)\u00a04<\/p>\n

d)\u00a0can not be determined<\/p>\n

Question 14:\u00a0<\/b>A number when divided by 11 leaves a remainder of 10 and when divided by 10 leaves a remainder of 8. Which of the following is a possible value of the number?<\/p>\n

a)\u00a0123<\/p>\n

b)\u00a0194<\/p>\n

c)\u00a062<\/p>\n

d)\u00a098<\/p>\n

Question 15:\u00a0<\/b>Find the value of x + y+ z if x+2y+5z = 14 and 3x+5y+11z = 46.<\/p>\n

a)\u00a018<\/p>\n

b)\u00a020<\/p>\n

c)\u00a035<\/p>\n

d)\u00a016<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

For the expression asin \u03b8 + bcos \u03b8 + c,<\/p>\n

The maximum value = $c+\\sqrt{a^{2}+b^{2}}$ &<\/p>\n

The minimum value = $c-\\sqrt{a^{2}+b^{2}}$<\/p>\n

for 3 sin \u03b8 + 4 cos \u03b8 , a = 3, b = 4, c = 0<\/p>\n

minimum value = $c-\\sqrt{a^{2}+b^{2}}$
\n$= 0 – \\sqrt{3^{2} + 4^{2}} = -\\sqrt{25} = -5$<\/p>\n

so the answer is option d.<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$(\\sin^{2}x+\\cos^{2}x)+\\sin^{2}x$=1+$\\sin^{2}x$
\nMinimum value of $\\sin x$ is when $x$=0 i.e $\\sin 0$=0
\nTherefore 1+0=1
\nHence, option C\u00a0is the correct answer.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given, a-b = 6, ab = 16
\nWe know that $(a-b)^2 = a^2+b^2-2ab$
\n$6^2 = a^2+b^2-2\\times16$
\n$a^2+b^2 = 36+32 = 68$<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$1+\\dfrac{1}{1+\\dfrac{1}{1+\\dfrac{1}{1+\\dfrac{2}{7}}}} = 1+\\dfrac{1}{1+\\dfrac{1}{1+\\dfrac{1}{\\dfrac{9}{7}}}}$<\/p>\n

$= 1+\\dfrac{1}{1+\\dfrac{1}{1+\\dfrac{7}{9}}}$<\/p>\n

$= 1+\\dfrac{1}{1+\\dfrac{1}{\\dfrac{16}{9}}}$<\/p>\n

$= 1+\\dfrac{1}{1+\\dfrac{9}{16}}$<\/p>\n

$= 1+\\dfrac{1}{\\dfrac{25}{16}}$<\/p>\n

$= 1+\\dfrac{16}{25}$<\/p>\n

$= \\dfrac{41}{25}$<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

let the number be x
\n(x+12)\/19=9
\nx=171-12
\nx=159
\nAnd then (159-40)=119
\n119\/17 we get 0 as the remainder.<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$5 = 40-12x+x^2$<\/p>\n

$x^2-12x+35 = 0$<\/p>\n

$x^2-7x-5x+35 = 0$<\/p>\n

$x(x-7)-5(x-7) = 0$<\/p>\n

$(x-7)(x-5) = 0$<\/p>\n

$x = 7$ or $x = 5$<\/p>\n

So the answer is option C.<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$(a+b+c)^2$=\u00a0$a^2+b^2+c^2+2(ab+bc+ca)$<\/p>\n

$(4\\sqrt3)^2 = 24 + 2(ab+bc+ca)$<\/p>\n

$48 = 24 + 2(ab+bc+ca)$<\/p>\n

$24 = 2(ab+bc+ca)$<\/p>\n

$(ab+bc+ca) = \\frac{24}{2} = 12$<\/p>\n

So the answer is option A.<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given $2^{2x} * 2^{2^{x}} * 2^{x}$ = $2^5$
\nSo, $2x + 2^x + x$ = 5
\nWe can observe that for x = 1, we can get required value.
\nSo, option (b) is the correct answer.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Total score made in his first 10 innings = 10*132 = 1320 runs
\nScore in his 11th innings = 0
\nThen, His new average = 1320\/11 = 120 runs.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

For 3rd proportional we have 12:36::36:x
\nTherefore 12x=36*36
\nx=108<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the people in 1st class and 2nd class be 3x and 5x respectively
\nand the cost of ticket for 1st class and 2nd class be 5y and 2y respectively
\nTotal amount from 1st class is 3x*5y=15xy
\nTotal amount from 2nd class is 5x*2y=10xy
\nTotal amount is 25xy=1250
\nxy=50
\nAmount from 2nd class is 10*50=Rs 500<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Slope = $\\frac{y_2-y_1}{x_2-x_1} = \\frac{15-3}{-4-2} = \\frac{12}{-6} = -2$<\/p>\n

Equation of a line passing through $(x_1, y_1)$ having slope m is $(y-y_1) = m(x-x_1)$<\/p>\n

Equation of a line passing through $(2,3)$ having slope -2 is $(y-3) = (-2)(x-2)$ ==> $y-3 = -2x+4$ ==> $2x+y = 7$<\/p>\n

So the answer is option D.<\/p>\n

13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

(4x+6y=8) is 2*(2x+3y=4)<\/p>\n

So both represents the same equation, hence we cant find x or y<\/p>\n

So the answer is option D.<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

By checking each of the options given above, we can notice that only 98 satisfies the conditions given in the question. Hence the answer is (d)<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Generally, when two equations are given with three variables, we cannot determine the value of any of the variables or their sum. However, in certain cases we can manipulate the equations to reduce them to a two variable form where one of the variables is the sum of the original variable. Let’s try that approach here:<\/p>\n

x+2y+5z = 14 can be written as (x+y+z) + (y+4z) = 14 —(a)<\/p>\n

3x+5y+11z = 46 can be written as 3(x+y+z) + 2(y+4z) = 46 —-(b)<\/p>\n

Let x+y+z=A and y+4z=B. Replacing these in (a) and (b) we get<\/p>\n

A + B = 14 — (c)<\/p>\n

3A + 2B = 46 — (d)<\/p>\n

We subtract 2*(c) from (d)<\/p>\n

(3A+2B) – (2A+2B) = 46-2*14<\/p>\n

A = 18<\/p>\n

Hence, x+y+z=18<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Previous Year Maths Questions for RRB JE Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

RRB JE Previous Year Maths Questions PDF Download Top 15 RRB JE Maths Questions and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam. Download RRB JE Previous Papers PDF Question 1:\u00a0What is the minimum value of 3 sin \u03b8 + 4 cos […]<\/p>\n","protected":false},"author":41,"featured_media":27651,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1605],"tags":[489,491,1635,1647],"class_list":{"0":"post-27634","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-je","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-je","14":"tag-rrb-mocks"},"better_featured_image":{"id":27651,"alt_text":"RRB JE Previous Maths Questions PDF","caption":"RRB JE Previous Maths Questions PDF","description":"RRB JE Previous Maths Questions PDF","media_type":"image","media_details":{"width":1200,"height":630,"file":"2019\/04\/fig-19-04-2019_10-10-42.jpg","sizes":{"thumbnail":{"file":"fig-19-04-2019_10-10-42-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-150x150.jpg"},"medium":{"file":"fig-19-04-2019_10-10-42-300x158.jpg","width":300,"height":158,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-300x158.jpg"},"medium_large":{"file":"fig-19-04-2019_10-10-42-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-768x403.jpg"},"large":{"file":"fig-19-04-2019_10-10-42-1024x538.jpg","width":1024,"height":538,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-1024x538.jpg"},"tiny-lazy":{"file":"fig-19-04-2019_10-10-42-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-30x16.jpg"},"td_80x60":{"file":"fig-19-04-2019_10-10-42-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-80x60.jpg"},"td_100x70":{"file":"fig-19-04-2019_10-10-42-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-100x70.jpg"},"td_218x150":{"file":"fig-19-04-2019_10-10-42-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-218x150.jpg"},"td_265x198":{"file":"fig-19-04-2019_10-10-42-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-265x198.jpg"},"td_324x160":{"file":"fig-19-04-2019_10-10-42-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-324x160.jpg"},"td_324x235":{"file":"fig-19-04-2019_10-10-42-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-324x235.jpg"},"td_324x400":{"file":"fig-19-04-2019_10-10-42-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-324x400.jpg"},"td_356x220":{"file":"fig-19-04-2019_10-10-42-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-356x220.jpg"},"td_356x364":{"file":"fig-19-04-2019_10-10-42-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-356x364.jpg"},"td_533x261":{"file":"fig-19-04-2019_10-10-42-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-533x261.jpg"},"td_534x462":{"file":"fig-19-04-2019_10-10-42-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-534x462.jpg"},"td_696x0":{"file":"fig-19-04-2019_10-10-42-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-696x365.jpg"},"td_696x385":{"file":"fig-19-04-2019_10-10-42-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-696x385.jpg"},"td_741x486":{"file":"fig-19-04-2019_10-10-42-741x486.jpg","width":741,"height":486,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-741x486.jpg"},"td_1068x580":{"file":"fig-19-04-2019_10-10-42-1068x580.jpg","width":1068,"height":580,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-1068x580.jpg"},"td_1068x0":{"file":"fig-19-04-2019_10-10-42-1068x561.jpg","width":1068,"height":561,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-1068x561.jpg"},"td_0x420":{"file":"fig-19-04-2019_10-10-42-800x420.jpg","width":800,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42-800x420.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":null,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/04\/fig-19-04-2019_10-10-42.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n