Take a free mock test for LIC AAO<\/a><\/p>\n Download LIC AAO Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>If a student walks from his house to school at 5 km\/hr, he is late by 30 minutes. However, if he walks at 6 km\/hr, he is late by 5 minutes only. The distance of his school from his house is.<\/p>\n a)\u00a02.5 km<\/p>\n b)\u00a03.6 km<\/p>\n c)\u00a05.5 km<\/p>\n d)\u00a012.5 km<\/p>\n Question 2:\u00a0<\/b>An express train travelled at an average speed of 100km\/hr, stopping for 3 minutes after 75 km. A local train travelled at speed of 50 km\/hr, stopping for 1 minute after every 25 km. If the train began travelling at the same time, how many kms did the local train level in the time it took the express train to travel 600 km ?<\/p>\n a)\u00a0307.5 km<\/p>\n b)\u00a0900 km<\/p>\n c)\u00a01000 km<\/p>\n d)\u00a01200 km<\/p>\n Question 3:\u00a0<\/b>A 10 metre, long ladder is placed against a wall. It is inclined at angle of 30C to the ground. The distance of the foot of the ladder from the wall is<\/p>\n a)\u00a07.32 m<\/p>\n b)\u00a08.26 m<\/p>\n c)\u00a08.66 m<\/p>\n d)\u00a08.16 m<\/p>\n Download LIC AAO Previous Papers PDF<\/a><\/p>\n 100 Free Computer Awareness Tests for LIC<\/a><\/p>\n Question 4:\u00a0<\/b>A squirrel starts climbing up a tree at the speed of 6 metres per minute but after each 6 metre it slips down 4 metres. It will be able to reach a top of 120 metre high in:<\/p>\n a)\u00a020 minutes<\/p>\n b)\u00a060 minutes<\/p>\n c)\u00a058 minutes<\/p>\n d)\u00a0$1\\frac{1}{2}$ hours<\/p>\n Question 5:\u00a0<\/b>Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of the their speed is:<\/p>\n a)\u00a01: 3<\/p>\n b)\u00a03: 2<\/p>\n c)\u00a03: 4<\/p>\n d)\u00a0None of these<\/p>\n Question 6:\u00a0<\/b>A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km\/hr from the usual speed. Its usual speed is:<\/p>\n a)\u00a0720 km\/hr<\/p>\n b)\u00a0730 km\/hr<\/p>\n c)\u00a0740 km\/hr<\/p>\n d)\u00a0750 km\/hr<\/p>\n Question 7:\u00a0<\/b>A 153 metre long train is running at 144 kmph. What time will it take to cross a 207 metre long platform ?<\/p>\n a)\u00a011 seconds<\/p>\n b)\u00a010 seconds<\/p>\n c)\u00a08 seconds<\/p>\n d)\u00a09 seconds<\/p>\n e)\u00a0None of these<\/p>\n Download LIC GK Material PDF<\/a><\/p>\n 100 Free GK Tests for Insurance Exams<\/a><\/p>\n Question 8:\u00a0<\/b>A boatman rows upstream at the rate of 13 kmph and downstream at the rate of 20 kmph for the same distance. Find the rate of boat in still water.<\/p>\n a)\u00a016 kmph<\/p>\n b)\u00a016.5 kmph<\/p>\n c)\u00a017 kmph<\/p>\n d)\u00a017.5 kmph<\/p>\n e)\u00a0None of these<\/p>\n Question 9:\u00a0<\/b>There are 77 equidistant trees on each side of a 1444 metre long road. Find the distance between the two consecutive trees.<\/p>\n a)\u00a019 metre<\/p>\n b)\u00a018 metre<\/p>\n c)\u00a018.75 metre<\/p>\n d)\u00a017 metre<\/p>\n e)\u00a0None of these<\/p>\n Question 10:\u00a0<\/b>Ram takes 30 minutes to reach office from home by car. One day, due to heavy traffic he drove his car at (4\/5)th of original speed for (1\/3)rd of total distance and remaining distance at (2\/5)th of the original speed. Find out the time taken by Ram on that day?<\/p>\n a)\u00a060 minutes<\/p>\n b)\u00a075 minutes<\/p>\n c)\u00a065 minutes<\/p>\n d)\u00a067.5 minutes<\/p>\n e)\u00a062.5 minutes<\/p>\n LIC AAO REASONING QUESTIONS PDF<\/a><\/p>\n LIC AAO Free Mock Test<\/a><\/p>\n\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The express train will cover 600 km in 6hrs and will stop fo 21 minutes in total at different stops. Therfore, the correct option is option A.<\/p>\n 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n This can be represented in diagrammatic form as, Therefore, the correct option is option C. The aggregate distance covered by squirrel in 1 minute = 6-4 = 2 metres. Let the lengths of train be x and y. 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The plane left half an hour late i.e it had to cover the same distance in half hour less time. 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the distance between Ram\u2019s office and home = 150d Distance that Ram covered at (1\/3)rd of original distance = $\\frac{150d}{3}$ = 50d Remaining distance = 150d – 50d = 100d Hence total time taken by Ram = 12.5 + 50 = 62.5 minutes<\/p>\n
\nNow, the distance covered by the local train in 6 hours 21 minutes while subtracting the 1 minute for each halt after 25 minutes = 6.35 * 50 – 250\/25 = 307.5 km.<\/p>\n
\n
\nHence, by 30-60-90 theorem
\nSide opposite to 60 degree angle = $\\sqrt{3}$\/2 *hypotenuse = $\\sqrt{3}$\/2 *10 = 8.66 m<\/p>\n
\n4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n
\nSo, at the end of 1 minute squirrel will climb 2 metres, at the end of 2 minutes squirrel will climb 4 metres and so on.
\nAt the end of the 57 minute squirrel will have climbed 114 metres.
\nNow, at the 58th minute it will advance 6 metres more and reach the top.
\nTherefore, the\u00a0 correct option is option C.
\n5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n
\nNow their speed is (x\/27) and (y\/17)
\nAlso, they cross each other in 23 seconds.
\n(x\/27) + (y\/17) = (x+y)\/23
\nWe get (4\/621)x = (6\/291)y
\n(x\/27)*(4\/23) = (102\/291)*(y\/17)
\n(x\/27)\/(y\/17) = (102\/291)*(23\/4)
\nRatio of speed = (391\/194)
\nOption D is the correct answer.<\/p>\n
\nNow, we know that time = distance\/speed
\nLet the origibal speed of the plane be x.
\nNow, (1500\/x – 1500\/x+250) = 0.5
\nSolving we get x = 750 km\/hr.
\nHence, the correct answer is option D.
\n7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n
\nThen his original speed = $\\frac{150d}{30}$ = 5d<\/p>\n
\n(4\/5)th of original speed = $\\frac{4}{5} * 5d$ = 4d
\nTime taken by Ram to cover this distance = $\\frac{50d}{4d} = 12.5$minutes<\/p>\n
\n(2\/5)th of original speed = $\\frac{2}{5}*5d$ = 2d
\nTime taken by Ram to cover the remaining distance = $\\frac{100d}{2d}$ = 50 minutes<\/p>\n