{"id":27576,"date":"2019-04-18T11:28:36","date_gmt":"2019-04-18T05:58:36","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=27576"},"modified":"2019-04-18T13:22:37","modified_gmt":"2019-04-18T07:52:37","slug":"simple-compound-interest-questions-for-rrb-je-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/simple-compound-interest-questions-for-rrb-je-pdf\/","title":{"rendered":"Simple & Compound Interest Questions For RRB JE PDF"},"content":{"rendered":"

Simple & Compound Interest Questions For\u00a0<\/strong><\/span>RRB JE PDF:<\/strong><\/span><\/span><\/h1>\n

Download Top 15 RRB JE Simple & Compound Interest Questions and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam.<\/p>\n

Download Simple & Compound Interest Questions For RRB JE PDF<\/a><\/p>\n\n

Download RRB JE Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>A lends Rs.15000 to B at 15% per annum Simple Interest for 2 years. B immediately lends it to C at 20% per annum Simple Interest for 2 years. Find the profit of B.<\/p>\n

a)\u00a0Rs.2500<\/p>\n

b)\u00a0Rs.1700<\/p>\n

c)\u00a0Rs.1400<\/p>\n

d)\u00a0Rs.1500<\/p>\n

Question 2:\u00a0<\/b>A person invested an amount of Rs.15000 at 6% per annum Simple Interest for 2 years. How much more interest he would have earned if he had invested the same amount in Compound Interest at same rate of interest and same period?<\/p>\n

a)\u00a0Rs.42<\/p>\n

b)\u00a0Rs.48<\/p>\n

c)\u00a0Rs.54<\/p>\n

d)\u00a0Rs.62<\/p>\n

Question 3:\u00a0<\/b>Value of rate of interest and time period(in years) are equal.If simple interest on certain principal value is (25\/49) times the principle amount, then what is the rate of interest ?<\/p>\n

a)\u00a050\/7 %<\/p>\n

b)\u00a025\/7 %<\/p>\n

c)\u00a030\/7 %<\/p>\n

d)\u00a040\/7 %<\/p>\n

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Question 4:\u00a0<\/b>At simple interest for 5 years principal amounts to Rs 750 and for 7 years it is Rs 900 then what is the principal value ?<\/p>\n

a)\u00a0400<\/p>\n

b)\u00a0375<\/p>\n

c)\u00a0359<\/p>\n

d)\u00a0425<\/p>\n

Question 5:\u00a0<\/b>Rohit invested Rs.20000 in Compound Interest for 2 years. The rate of interest is 4% for first year and 8% for second year compounded annually. Then find overall interest earned.<\/p>\n

a)\u00a0Rs.2442<\/p>\n

b)\u00a0Rs.2240<\/p>\n

c)\u00a0Rs.2048<\/p>\n

d)\u00a0Rs.2464<\/p>\n

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Question 6:\u00a0<\/b>A person invested certain amount of money in Scheme A which offers 10 p.c.p.a Simple Interest for 2 years. Had he invested in Scheme B which offers 10 p.c.p.a Compound Interest for same time period, he would have earned Rs.12 extra. Then find the sum of money.<\/p>\n

a)\u00a0Rs.1000<\/p>\n

b)\u00a0Rs.1200<\/p>\n

c)\u00a0Rs.600<\/p>\n

d)\u00a0Rs.6000<\/p>\n

Question 7:\u00a0<\/b>What is the rate(per annum) of compound interest at which a sum of Rs. 15000\/- becomes Rs. 16391\/- in 3 years.<\/p>\n

a)\u00a03<\/p>\n

b)\u00a04<\/p>\n

c)\u00a05<\/p>\n

d)\u00a06<\/p>\n

 <\/p>\n

Question 8:\u00a0<\/b>If the compound interest on a certain sum of money for 3 years at 2% per annum is Rs. 1530.20\/- Calculate the Simple interest(in Rs.) on the sum of the money at the same rate and for the same time.<\/p>\n

a)\u00a01200<\/p>\n

b)\u00a01400<\/p>\n

c)\u00a02500<\/p>\n

d)\u00a01500<\/p>\n

Question 9:\u00a0<\/b>Calculate the compound interest on the sum of the money at the same rate and for the same time, If the simple interest on a certain sum of money for 2 years at 6% per annum is Rs. 432.<\/p>\n

a)\u00a0464.96<\/p>\n

b)\u00a0484.96<\/p>\n

c)\u00a0444.96<\/p>\n

d)\u00a0454.96<\/p>\n

Question 10:\u00a0<\/b>There are two schemes-Scheme A and Scheme B. Scheme A offers 8% Simple Interest. Scheme B offers 7% per annum Compound Interest. Which scheme offers more interest for overall 2 years?<\/p>\n

a)\u00a0A<\/p>\n

b)\u00a0B<\/p>\n

c)\u00a0Both are equal<\/p>\n

d)\u00a0Can\u2019t be determined<\/p>\n

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Question 11:\u00a0<\/b>Calculate the time period(in years) if the compound interest on Rs. 40000 @ 4% p.a. is 4994.56.<\/p>\n

a)\u00a02<\/p>\n

b)\u00a03<\/p>\n

c)\u00a03.5<\/p>\n

d)\u00a04<\/p>\n

Question 12:\u00a0<\/b>The difference between Simple Interest and Compound interest of certain amount at 15% per annum for 2 years is Rs.9000. Then find the sum.<\/p>\n

a)\u00a0Rs.400000<\/p>\n

b)\u00a0Rs.250000<\/p>\n

c)\u00a0Rs.40000<\/p>\n

d)\u00a0Rs.150000<\/p>\n

Question 13:\u00a0<\/b>Find the difference between compound interest and simple interest on 30000\/- at 12% per annum for 2 years ?<\/p>\n

a)\u00a0342<\/p>\n

b)\u00a04320<\/p>\n

c)\u00a0432<\/p>\n

d)\u00a03420<\/p>\n

Question 14:\u00a0<\/b>The compound interest of a sum of Rs.8000 at 2.5% per annum is Rs.405. Then, find the number of years.<\/p>\n

a)\u00a02.5 years<\/p>\n

b)\u00a01.5 years<\/p>\n

c)\u00a03 years<\/p>\n

d)\u00a02 years<\/p>\n

Question 15:\u00a0<\/b>A borrowed a sum of Rs.5000 at 6% simple interest for 3 years. He then lent it immediately to B at 8% simple interest for 3 years. Then find his gain for 1 year.<\/p>\n

a)\u00a0Rs.140<\/p>\n

b)\u00a0Rs.100<\/p>\n

c)\u00a0Rs.240<\/p>\n

d)\u00a0Rs.180<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Profit of B = $\\dfrac{15000\\times20\\times2}{100} – \\dfrac{15000\\times15\\times2}{100} = 6000-4500 = Rs.1500$<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given, Amount = Rs.15000
\nSimple Interest at 6 p.c.p.a. for 2 years will be $\\dfrac{15000\\times6\\times2}{100} = Rs.1800$
\nAmount at the end of 1st year at 6 p.c.p.a Compound Interest = 106% of 15000 = Rs.15900
\nAmount at the end of 2nd year at 6 p.c.p.a CI = 106% of 15900 = Rs.16854
\nTotal Compound Interest = 16854-15000 = Rs.1854
\nTherefore, Extra amount of money he would have earned = 1854-1800 = Rs.54<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given rate of interest r= time period t
\n(25\/49)P=(P*r*r)\/100
\n$r^{2}$=2500\/49
\nr=50\/7 %<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

For 7 years amount=900
\nFor 5 years amount=750
\nInterest for 2 years =900-750
\n=150
\nInterest for 1 year=75
\nInterest for 5 years=5*75
\n=375
\nPrincipal value at the beginning is 750-375=375
\nHence, option B is the correct answer.<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Amount received in first year = 104% of 20000 = Rs.20800
\nAmount received in second year = 108% of Rs.20800 = Rs.22464
\nHence, Total Compound Interest = Rs.22464 – Rs.20000 = Rs.2464<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the principal be Rs.100
\nInterest earned from Scheme A $= \\dfrac{100\\times10\\times2}{100} = Rs.20$
\nAmount earned from Scheme B:
\nFor 1st year \u2192 $110$% of $100 = Rs.110$
\nFor 2nd year \u2192 $110$% of $110 = Rs.121$
\nInterest earned from Scheme B $= 121-100 = Rs.21$
\nGiven Difference between SI and CI $= Rs.12$
\n$Re.1 \u2192 Rs.12$
\n$Rs.100 \u2192 ?$
\nHence, Total Interest $= 100*12 = Rs.1200$<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Principal(P) = 15000
\nRate of Interest (R) = ?
\nTime period(t) = 3 years<\/p>\n

$ Amount = P(1+ \\Large\\frac{R}{100})^{t} $<\/p>\n

$ 16391 = 15000{(1+ \\Large\\frac{R}{100})^{3}}$<\/p>\n

$ (1+ \\Large\\frac{R}{100})^{3} = \\Large\\frac{16391}{15000} $<\/p>\n

$ (1+ \\Large\\frac{R}{100})^{3}$ $ = 1.0927$<\/p>\n

$ (1+ \\Large\\frac{R}{100})^{3}$ $ = 1.03^3$<\/p>\n

$ (1+ \\Large\\frac{R}{100})^{3}$ = $(\\Large\\frac{103}{100})^{3} $<\/p>\n

$ R = 3$% p.a.<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Principal(P) = ?
\nRate of Interest (R) = 2%
\nTime period(t) = 3 years<\/p>\n

Given, Compound Interest = 1530.20<\/p>\n

$ 1530.20 = P\\Large(1+\\frac{R}{100})^{t}$ $ – P$<\/p>\n

$1530.20 = P[\\Large(1+\\frac{2}{100})^{3}$ $ – 1]$<\/p>\n

$P = \\Large\\frac{1530.2}{(1.02)^3 – 1} $<\/p>\n

$P = Rs. 25,000 \/-$<\/p>\n

Simple Interest = $\\Large\\frac{PTR}{100}$<\/p>\n

$ S.I. = \\Large\\frac{25000\\times2\\times3}{100}$<\/p>\n

$ S.I. = Rs. 1500\/- $<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Simple Interest = $\\Large\\frac{PTR}{100}$<\/p>\n

Principal(P) = ?
\nGiven, Rate of Interest (R) = 6%
\nTime period(t) = 2 years<\/p>\n

$432 = \\Large\\frac{PTR}{100}$<\/p>\n

$P = \\Large\\frac{432\\times100}{TR}$<\/p>\n

$P = \\Large\\frac{432\\times100}{12}$<\/p>\n

P = Rs. 3600\/-<\/p>\n

Compound Interest is calculated by<\/p>\n

$C.I. = P(1+\\Large\\frac{R}{100})^{t}$ $- P$<\/p>\n

$C.I. = 3,600(1+\\Large\\frac{6}{100})^{2} -$ $3600$<\/p>\n

Compound Interest = Rs. 444.96\/-<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Effective Simple Interest for Scheme A for 2 years $= 8\\times2 = 16$%
\nEffective Compound Interest for Scheme B for 2 years $= 7+7+\\dfrac{7\\times7}{100} = 14+0.49 = 14.49$%
\nHence, Scheme A offers more interest than Scheme B.<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given the Principal(P) = Rs. 40,000\/-
\nRate of Interest (R) = 4%
\nTime period(t) = __ years
\nCompound Interest = 4994.56\/-<\/p>\n

$CI = P(1+\\frac{R}{100})^{t} – P$<\/p>\n

$CI = 40,000{(1+\\frac{4}{100})^{t} – 1}$<\/p>\n

$ 4994.56 = 40,000{(1.04)^t – 1}$<\/p>\n

$ \\Large\\frac{4994.56}{40,000}$ = $(1.03)^t – 1$<\/p>\n

$ \\Large\\frac{4994.56}{40,000} +$ 1 = $(1.03)^t $<\/p>\n

$\\Large\\frac{44994.56}{40,000}$ = $(1.03)^t $<\/p>\n

$t = 3 years$<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the sum of money be Rs.10000
\nSimple Interest at 15% per annum for 2 years will be:
\n$\\dfrac{10000\\times15\\times2}{100} = Rs.3000$<\/p>\n

Amount at the end of 1st year with Compound Interest = 115% of Rs.11500
\nAmount at the end of 2nd year with Compound Interest = 115% of 11500 = Rs.13225
\nTotal Compound Interest = 13225 – 10000 = Rs.3225<\/p>\n

Difference between SI and CI = Rs.3225-3000 = Rs.225
\nGiven that the difference = Rs.9000<\/p>\n

225 \u2192 9000
\n10000 \u2192 ?
\n= $\\dfrac{10000\\times9000}{225} = Rs.400000$<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Difference between Compound Interest and Simple Interest for 2 years = $\\frac{P(r)^2}{100} = \\frac{30000(12)^2}{100} = 432$<\/p>\n

So the answer is option C.<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Given Principal = Rs.8000
\nRate of interest = 2.5%
\nCompound interest earned in 1st year = 2.5% of Rs.8000 = Rs.200
\nAmount at the end of 1st year = Rs.8000+Rs.200 = Rs.8200
\nCompound interest earned in 2nd year = 2.5% of Rs.8200 = Rs.205
\nAmount at the end of 2nd year = Rs.8200+Rs.205 = Rs.8405
\nHere, After 2 years, Interest = Rs.8405 – Rs.8000 = Rs.405
\nHence, Required number of years = 2 years<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Gain for 3 years = $\\Large(\\frac{5000\\times8\\times3}{100})-(\\frac{5000\\times6\\times3}{100})$ $= 1200-900 = Rs.300$<\/p>\n

Gain for 1 year $= \\Large\\frac{300}{3}$ $= Rs.100$<\/p>\n\n

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We hope this Simple & Compound Interest Questions for RRB JE Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Simple & Compound Interest Questions For\u00a0RRB JE PDF: Download Top 15 RRB JE Simple & Compound Interest Questions and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam. Download RRB JE Previous Papers PDF Question 1:\u00a0A lends Rs.15000 to B at 15% per […]<\/p>\n","protected":false},"author":41,"featured_media":27578,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1605],"tags":[489,491,1635,1647],"class_list":{"0":"post-27576","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-je","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-je","14":"tag-rrb-mocks"},"better_featured_image":{"id":27578,"alt_text":"Simple & Compound Interest Questions for RRB JE PDF","caption":"Simple & Compound Interest Questions for RRB JE PDF","description":"Simple & Compound Interest Questions for RRB JE 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