{"id":27189,"date":"2019-04-05T18:51:40","date_gmt":"2019-04-05T13:21:40","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=27189"},"modified":"2019-10-28T17:12:21","modified_gmt":"2019-10-28T11:42:21","slug":"ssc-cgl-trigonometry-questions-with-solutions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ssc-cgl-trigonometry-questions-with-solutions-pdf\/","title":{"rendered":"SSC CGL Trigonometry Questions with Solutions PDF"},"content":{"rendered":"<h1>SSC CGL Trigonometry Questions with Solutions PDF<\/h1>\n<p>Download SSC CGL Trignometry questions with answers PDF based on previous papers very useful for SSC CGL exams. 20 Very important Trignometry objective questions for SSC exams.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/3966\" target=\"_blank\" class=\"btn btn-danger  download\">Download SSC CGL Trigonometry Questions with Solutions PDF<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 1:\u00a0<\/b>What is the value of $(cot60^\\circ+1\/\\sqrt{3}) ?$<\/p>\n<p>a)\u00a0$2\\sqrt3$<\/p>\n<p>b)\u00a0$\\frac{\\sqrt3}{2}$<\/p>\n<p>c)\u00a0$\\frac{2}{\\sqrt3}$<\/p>\n<p>d)\u00a0$\\sqrt3$<\/p>\n<p><b>Question 2:\u00a0<\/b>What is the value of $(\\frac{1}{3} &#8211; sec 45^\\circ)$ ?<\/p>\n<p>a)\u00a0$\\frac{(4-\\sqrt3)}{2}$<\/p>\n<p>b)\u00a0$\\frac{(\\sqrt{6}-1)}{\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\frac{(1-3\\sqrt2)}{3}$<\/p>\n<p>d)\u00a0$\\frac{(\\sqrt2-1)}{\\sqrt{2}}$<\/p>\n<p><b>Question 3:\u00a0<\/b>\u0394ABC is right angled at B. If $sec A = \\frac{5}{3}$, then what is the value of $cosec C$ ?<\/p>\n<p>a)\u00a0$\\frac{5}{3}$<\/p>\n<p>b)\u00a0$\\frac{3}{4}$<\/p>\n<p>c)\u00a0$\\frac{4}{5}$<\/p>\n<p>d)\u00a0$\\frac{4}{3}$<\/p>\n<p><b>Question 4:\u00a0<\/b>What is the value of $( \\frac{1}{\\sqrt{3}} + cot 60^\\circ)$ ?<\/p>\n<p>a)\u00a0$\\frac{3\\sqrt3}{2}$<\/p>\n<p>b)\u00a0$\\frac{7}{2\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\frac{(4+\\sqrt3)}{2\\sqrt{3}}$<\/p>\n<p>d)\u00a0$\\frac{2}{\\sqrt{3}}$<\/p>\n<p><b>Question 5:\u00a0<\/b>\u0394ABC is right angled at B. If $cot A = \\frac{7}{24}$, then what is the value of $cosec C$ ?<\/p>\n<p>a)\u00a0$\\frac{7}{25}$<\/p>\n<p>b)\u00a0$\\frac{25}{7}$<\/p>\n<p>c)\u00a0$\\frac{24}{7}$<\/p>\n<p>d)\u00a0$\\frac{7}{24}$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-previous-papers\" target=\"_blank\" class=\"btn btn-alone \">SSC CGL Previous Papers Download PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" class=\"btn btn-danger \">SSC CGL Free Mock Test<\/a><\/p>\n<p><b>Question 6:\u00a0<\/b>What is the value of $(cosec 60^\\circ + \\frac{1}{2})$ ?<\/p>\n<p>a)\u00a0$\\frac{2}{\\sqrt{3}}$<\/p>\n<p>b)\u00a0$\\frac{(2+\\sqrt{3})}{2\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\frac{(4+\\sqrt{3})}{2\\sqrt{3}}$<\/p>\n<p>d)\u00a0$\\frac{(\\sqrt{2}+\\sqrt{3})}{\\sqrt{6}}$<\/p>\n<p><b>Question 7:\u00a0<\/b>\u2206DEF is right angled at E. If m$\\angle$F = $30^\\circ$, then find the value of $(sin D &#8211; \\frac{1}{3})$.<\/p>\n<p>a)\u00a0$\\frac{-1}{2\\sqrt3}$<\/p>\n<p>b)\u00a0$\\frac{(3\\sqrt3-2)}{6}$<\/p>\n<p>c)\u00a0$\\frac{(\\sqrt{2}-\\sqrt3)}{\\sqrt{6}}$<\/p>\n<p>d)\u00a0$\\frac{(2\\sqrt{2}-1)}{\\sqrt{2}}$<\/p>\n<p><b>Question 8:\u00a0<\/b>\u2206DEF is right angled at E. If $cosec D = \\frac{25}{24}$, then what is the value of $cos F$ ?<\/p>\n<p>a)\u00a0$\\frac{25}{7}$<\/p>\n<p>b)\u00a0$\\frac{24}{7}$<\/p>\n<p>c)\u00a0$\\frac{24}{25}$<\/p>\n<p>d)\u00a0$\\frac{7}{24}$<\/p>\n<p><b>Question 9:\u00a0<\/b>\u0394XYZ is right angled at Y. If m\u2220X = $45^\\circ$, then \ufb01nd the value of $(cosec Z +\\frac{\\sqrt{3}}{2})$.<\/p>\n<p>a)\u00a0$\\frac{(2\\sqrt{2}+\\sqrt{3})}{2}$<\/p>\n<p>b)\u00a0$\\frac{5}{6}$<\/p>\n<p>c)\u00a0$\\frac{(1+2\\sqrt{3})}{2}$<\/p>\n<p>d)\u00a0$\\frac{(\\sqrt{2}+1)}{\\sqrt{2}}$<\/p>\n<p><b>Question 10:\u00a0<\/b>\u0394XYZ is right angled at Y. If $sinX = \\frac{4}{5}$, then what is the value of $cos Z$ ?<\/p>\n<p>a)\u00a0$\\frac{3}{4}$<\/p>\n<p>b)\u00a0$\\frac{5}{3}$<\/p>\n<p>c)\u00a0$\\frac{4}{5}$<\/p>\n<p>d)\u00a0$\\frac{4}{3}$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/www.youtube.com\/channel\/UCVFahh7Fd1b4sPUpq2mtxpg?sub_confirmation=1\" target=\"_blank\" class=\"btn btn-warning \">FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-study-material\" target=\"_blank\" class=\"btn btn-alone \">18000+ Questions &#8211; Free SSC Study Material<\/a><\/p>\n<p><b>Question 11:\u00a0<\/b>What is the value of $(cos 30^\\circ + \\frac{1}{2})$ ?<\/p>\n<p>a)\u00a0$\\frac{(\\sqrt{3}+1)}{\\sqrt{3}}$<\/p>\n<p>b)\u00a0$\\frac{(\\sqrt{2}+1)}{\\sqrt{2}}$<\/p>\n<p>c)\u00a0$\\frac{(\\sqrt{3}+1)}{2}$<\/p>\n<p>d)\u00a0$\\frac{(2\\sqrt{3}+1)}{\\sqrt{3}}$<\/p>\n<p><b>Question 12:\u00a0<\/b>\u0394DEF is right angled at E. If $cosec D = \\frac{5}{4}$, then what is the value of $cosec F$ ?<\/p>\n<p>a)\u00a0$\\frac{5}{3}$<\/p>\n<p>b)\u00a0$\\frac{3}{4}$<\/p>\n<p>c)\u00a0$\\frac{4}{5}$<\/p>\n<p>d)\u00a0$\\frac{4}{3}$<\/p>\n<p><b>Question 13:\u00a0<\/b>What is the value of $(2 &#8211; tan 60^\\circ)$ ?<\/p>\n<p>a)\u00a0$\\frac{-1}{\\sqrt{3}}$<\/p>\n<p>b)\u00a0$\\frac{(\\sqrt{3}-4)}{2\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\frac{-1}{2}$<\/p>\n<p>d)\u00a0$2-\\sqrt3$<\/p>\n<p><b>Question 14:\u00a0<\/b>\u0394UVW is right angled at V. If $sin U = \\frac{24}{25}$, then what is the value of $cosW$ ?<\/p>\n<p>a)\u00a0$\\frac{25}{7}$<\/p>\n<p>b)\u00a0$\\frac{24}{7}$<\/p>\n<p>c)\u00a0$\\frac{7}{24}$<\/p>\n<p>d)\u00a0$\\frac{24}{25}$<\/p>\n<p><b>Question 15:\u00a0<\/b>\u0394PQR is right angled at Q. If m$\\angle$P = 60\u00b0, then \ufb01nd the value of $(cot R + \\frac{\\sqrt{3}}{2})$.<\/p>\n<p>a)\u00a0$\\frac{3\\sqrt3}{2}$<\/p>\n<p>b)\u00a0$1+\\sqrt3$<\/p>\n<p>c)\u00a0$\\frac{(2\\sqrt2+1)}{2}$<\/p>\n<p>d)\u00a0$\\frac{(3\\sqrt3+1)}{6}$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" class=\"btn btn-primary \">SSC CGL Free Mock Test<\/a><\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p><b>Question 16:\u00a0<\/b>\u0394ABC is right angled at B. If $cot A = \\frac{8}{15}$, then what is the value of $cos C$ ?<\/p>\n<p>a)\u00a0${15}{8}$<\/p>\n<p>b)\u00a0$\\frac{8}{17}$<\/p>\n<p>c)\u00a0$\\frac{17}{15}$<\/p>\n<p>d)\u00a0$\\frac{15}{17}$<\/p>\n<p><b>Question 17:\u00a0<\/b>What is the value of $(cos 45^\\circ &#8211; \\frac{1}{3})$ ?<\/p>\n<p>a)\u00a0$2-\\sqrt3$<\/p>\n<p>b)\u00a0$\\frac{2}{\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\frac{(3-\\sqrt2)}{3\\sqrt{2}}$<\/p>\n<p>d)\u00a0$\\frac{1}{2\\sqrt{3}}$<\/p>\n<p><b>Question 18:\u00a0<\/b>\u0394UVW is right angled at V. If $sec U = \\frac{5}{3}$, then what is the value of $tan W$ ?<\/p>\n<p>a)\u00a0$\\frac{3}{4}$<\/p>\n<p>b)\u00a0$\\frac{5}{3}$<\/p>\n<p>c)\u00a0$\\frac{4}{5}$<\/p>\n<p>d)\u00a0$\\frac{4}{3}$<\/p>\n<p><b>Question 19:\u00a0<\/b>\u0394DEF is right angled at E. If m$\\angle$F = $30^\\circ$, then \ufb01nd the value of $(cos D &#8211; \\frac{1}{\\sqrt2})$<\/p>\n<p>a)\u00a0$\\frac{-1}{2}$<\/p>\n<p>b)\u00a0$\\frac{(\\sqrt{6}-1)}{\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\frac{(\\sqrt{2}-2)}{2\\sqrt{2}}$<\/p>\n<p>d)\u00a0$\\sqrt{3}-2$<\/p>\n<p><b>Question 20:\u00a0<\/b>\u2206PQR is right angled at Q. If m$\\angle$P = $60^\\circ$, then find the value of $(sec R + \\frac{1}{2})$<\/p>\n<p>a)\u00a0$\\frac{(2\\sqrt{2}+\\sqrt{3})}{2}$<\/p>\n<p>b)\u00a0$\\frac{(\\sqrt{3}+4)}{2\\sqrt{3}}$<\/p>\n<p>c)\u00a0$\\sqrt{3}+2$<\/p>\n<p>d)\u00a0$\\frac{5}{6}$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/free-gk-tests\" target=\"_blank\" class=\"btn btn-primary \">100+ Free GK Tests for SSC Exams<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/blog\/general-knowledge-questions-and-answers-for-competitive-exams-pdf\/\" target=\"_blank\" class=\"btn btn-danger \">Download Free GK PDF<\/a><\/p>\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Expression\u00a0:\u00a0$(cot60^\\circ+1\/\\sqrt{3})$<\/p>\n<p>= $\\frac{1}{\\sqrt3}+\\frac{1}{\\sqrt3}$<\/p>\n<p>=\u00a0$\\frac{2}{\\sqrt3}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Expression\u00a0:\u00a0$(\\frac{1}{3} &#8211; sec 45^\\circ)$<\/p>\n<p>= $\\frac{1}{3}-\\sqrt2$<\/p>\n<p>=\u00a0$\\frac{(1-3\\sqrt2)}{3}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/30222.PNG\" data-image=\"30222.PNG\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\sec A$ = $\\frac{5}{3}$<\/p>\n<p>Also, $\\sec A=\\frac{AC}{AB}=\\frac{5}{3}$<\/p>\n<p>Let AC = 5 cm and AB = 3 cm<\/p>\n<p>To find\u00a0:\u00a0$\\cosec C=\\frac{AC}{AB}$<\/p>\n<p>= $\\frac{5}{3}$<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Expression\u00a0:\u00a0$( \\frac{1}{\\sqrt{3}} + cot 60^\\circ)$<\/p>\n<p>= $\\frac{1}{\\sqrt3}+\\frac{1}{\\sqrt3}$<\/p>\n<p>=\u00a0$\\frac{2}{\\sqrt{3}}$<\/p>\n<p>=&gt; Ans &#8211; (D)<\/p>\n<p><strong>5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/30222_XQHghsA.PNG\" data-image=\"30222.PNG\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\cot A$ = $\\frac{7}{24}$<\/p>\n<p>Also, $\\cot A=\\frac{AB}{BC}=\\frac{7}{24}$<\/p>\n<p>Let AB = 7 cm and BC = 24 cm<\/p>\n<p>Thus, in $\\triangle$ ABC,<\/p>\n<p>=&gt; $(AC)^2=(AB)^2+(BC)^2$<\/p>\n<p>=&gt; $(AC)^2=(7)^2+(24)^2$<\/p>\n<p>=&gt; $(AC)^2=49+576=625$<\/p>\n<p>=&gt; $AC=\\sqrt{625}=25$ cm<\/p>\n<p>To find\u00a0:\u00a0$\\cosec C=\\frac{AC}{AB}$<\/p>\n<p>= $\\frac{25}{7}$<\/p>\n<p>=&gt; Ans &#8211; (B)<\/p>\n<p><strong>6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Expression\u00a0:\u00a0$(cosec 60^\\circ + \\frac{1}{2})$<\/p>\n<p>= $\\frac{2}{\\sqrt3}+\\frac{1}{2}$<\/p>\n<p>=\u00a0$\\frac{(4+\\sqrt{3})}{2\\sqrt{3}}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/blob_DrApzhR\" data-image=\"blob\" \/><\/figure>\n<p>Sum of angles of $\\triangle$ DEF = $\\angle D+\\angle E+\\angle F=180^\\circ$<\/p>\n<p>=&gt; $\\angle D+90^\\circ+30^\\circ=180^\\circ$<\/p>\n<p>=&gt; $\\angle D=180^\\circ-120^\\circ=60^\\circ$<\/p>\n<p>To find\u00a0:\u00a0$(sin D &#8211; \\frac{1}{3})$<\/p>\n<p>= $sin(60^\\circ)-\\frac{1}{3}$<\/p>\n<p>= $\\frac{\\sqrt3}{2}-\\frac{1}{3}$<\/p>\n<p>=\u00a0$\\frac{(3\\sqrt3-2)}{6}$<\/p>\n<p>=&gt; Ans &#8211; (B)<\/p>\n<p><strong>8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28217.PNG\" data-image=\"28217.PNG\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\cosec D$ = $\\frac{25}{24}$<\/p>\n<p>Also, $\\cosec D=\\frac{DF}{EF}=\\frac{25}{24}$<\/p>\n<p>Let DF = 25 cm and EF = 24 cm<\/p>\n<p>To find\u00a0:\u00a0$\\cos F=\\frac{EF}{DF}$<\/p>\n<p>= $\\frac{24}{25}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28221_KQ8rxLS.PNG\" data-image=\"28221.PNG\" \/><\/p>\n<p>Sum of angles of $\\triangle$ XYZ = $\\angle X+\\angle Y+\\angle Z=180^\\circ$<\/p>\n<p>=&gt; $45^\\circ+90^\\circ+\\angle Z=180^\\circ$<\/p>\n<p>=&gt; $\\angle X=180^\\circ-135^\\circ=45^\\circ$<\/p>\n<p>To find\u00a0:\u00a0$(cosec Z +\\frac{\\sqrt{3}}{2})$<\/p>\n<p>= $cosec(45^\\circ)+\\frac{\\sqrt3}{2}$<\/p>\n<p>= $\\sqrt2+\\frac{\\sqrt3}{2}$<\/p>\n<p>=\u00a0$\\frac{(2\\sqrt{2}+\\sqrt{3})}{2}$<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28221_EKKXK7P.PNG\" data-image=\"28221.PNG\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\sin X$ = $\\frac{4}{5}$<\/p>\n<p>Also, $\\sin X=\\frac{YZ}{XZ}=\\frac{4}{5}$<\/p>\n<p>Let YZ = 4 cm and XZ = 5 cm<\/p>\n<p>To find\u00a0:\u00a0$\\cos Z=\\frac{YZ}{XZ}$<\/p>\n<p>= $\\frac{4}{5}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-practice-set\" target=\"_blank\" class=\"btn btn-info \">Free SSC Daily Practice Set<\/a><\/p>\n<p><strong>11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Expression\u00a0:\u00a0$(cos 30^\\circ + \\frac{1}{2})$<\/p>\n<p>= $\\frac{\\sqrt3}{2}+\\frac{1}{2}$<\/p>\n<p>=\u00a0$\\frac{(\\sqrt{3}+1)}{2}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28217_biacgBb.PNG\" data-image=\"28217.PNG\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\cosec D$ = $\\frac{5}{4}$<\/p>\n<p>Also, $\\cosec D=\\frac{DF}{EF}=\\frac{5}{4}$<\/p>\n<p>Let DF = 5 cm and EF = 4 cm<\/p>\n<p>Thus, in $\\triangle$ DEF, =&gt; $(DE)^2=(DF)^2-(EF)^2$<\/p>\n<p>=&gt; $(DE)^2=(5)^2-(4)^2$<\/p>\n<p>=&gt; $(DE)^2=25-16=9$<\/p>\n<p>=&gt; $DE=\\sqrt{9}=3$ cm<\/p>\n<p>To find\u00a0:\u00a0$\\cosec F=\\frac{DF}{DE}$<\/p>\n<p>= $\\frac{5}{3}$<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Expression\u00a0:\u00a0$(2 &#8211; tan 60^\\circ)$<\/p>\n<p>We know that,\u00a0$tan (60^\\circ)=\\sqrt3$<\/p>\n<p>=\u00a0$2-\\sqrt3$<\/p>\n<p>=&gt; Ans &#8211; (D)<\/p>\n<p><strong>14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>&nbsp;<\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/blob_FPiqCV3\" data-image=\"blob\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\sin U$ = $\\frac{24}{25}$<\/p>\n<p>Also, $\\sin U=\\frac{VW}{UW}=\\frac{24}{25}$<\/p>\n<p>Let VW = 24 cm and UW = 25 cm<\/p>\n<p>To find\u00a0:\u00a0$\\cos W=\\frac{VW}{UW}$<\/p>\n<p>= $\\frac{24}{25}$<\/p>\n<p>=&gt; Ans &#8211; (D)<\/p>\n<p><strong>15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28225.PNG\" data-image=\"28225.PNG\" \/><\/figure>\n<p>Sum of angles of $\\triangle$ PQR = $\\angle P+\\angle Q+\\angle R=180^\\circ$<\/p>\n<p>=&gt; $60^\\circ+90^\\circ+\\angle R=180^\\circ$<\/p>\n<p>=&gt; $\\angle R=180^\\circ-150^\\circ=30^\\circ$<\/p>\n<p>To find\u00a0:\u00a0$(cot R + \\frac{\\sqrt{3}}{2})$<\/p>\n<p>= $cot(30^\\circ)+\\frac{\\sqrt3}{2}$<\/p>\n<p>= $\\sqrt3+\\frac{\\sqrt3}{2}$<\/p>\n<p>=\u00a0$\\frac{3\\sqrt3}{2}$<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/30222_XQHghsA.PNG\" data-image=\"30222.PNG\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\cot A$ = $\\frac{8}{15}$<\/p>\n<p>Also, $\\cot A=\\frac{AB}{BC}=\\frac{8}{15}$<\/p>\n<p>Let AB = 8 cm and BC = 15 cm<\/p>\n<p>Thus, in $\\triangle$ ABC,<\/p>\n<p>=&gt; $(AC)^2=(AB)^2+(BC)^2$<\/p>\n<p>=&gt; $(AC)^2=(8)^2+(15)^2$<\/p>\n<p>=&gt; $(AC)^2=64+225=289$<\/p>\n<p>=&gt; $AC=\\sqrt{289}=17$ cm<\/p>\n<p>To find\u00a0:\u00a0$\\cos C=\\frac{BC}{AC}$<\/p>\n<p>= $\\frac{15}{17}$<\/p>\n<p>=&gt; Ans &#8211; (D)<\/p>\n<p><strong>17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>Expression :\u00a0$(cos 45^\\circ &#8211; \\frac{1}{3})$<\/p>\n<p>= $\\frac{1}{\\sqrt2}-\\frac{1}{3}$<\/p>\n<p>=\u00a0$\\frac{(3-\\sqrt2)}{3\\sqrt{2}}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>&nbsp;<\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/blob_FPiqCV3\" data-image=\"blob\" \/><\/figure>\n<p>Given\u00a0:\u00a0$\\sec U$ = $\\frac{5}{3}$<\/p>\n<p>Also, $\\sec U=\\frac{UW}{UV}=\\frac{5}{3}$<\/p>\n<p>Let UW = 5 cm and UV = 3 cm<\/p>\n<p>Thus, in $\\triangle$ UVW, =&gt; $(VW)^2=(UW)^2-(UV)^2$<\/p>\n<p>=&gt; $(VW)^2=(5)^2-(3)^2$<\/p>\n<p>=&gt; $(VW)^2=25-9=16$<\/p>\n<p>=&gt; $VW=\\sqrt{16}=4$ cm<\/p>\n<p>To find\u00a0:\u00a0$\\tan W=\\frac{UV}{VW}$<\/p>\n<p>= $\\frac{3}{4}$<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28217_I8gUTnm.PNG\" data-image=\"28217.PNG\" \/><\/figure>\n<p>Sum of angles of $\\triangle$ DEF = $\\angle D+\\angle E+\\angle F=180^\\circ$<\/p>\n<p>=&gt; $\\angle D+90^\\circ+30^\\circ=180^\\circ$<\/p>\n<p>=&gt; $\\angle D=180^\\circ-120^\\circ=60^\\circ$<\/p>\n<p>To find\u00a0:\u00a0$(cos D &#8211; \\frac{1}{\\sqrt2})$<\/p>\n<p>= $cos(60^\\circ)-\\frac{1}{\\sqrt2}$<\/p>\n<p>= $\\frac{1}{2}-\\frac{1}{\\sqrt2}$<\/p>\n<p>=\u00a0$\\frac{(\\sqrt{2}-2)}{2\\sqrt{2}}$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<figure><img decoding=\"async\" class=\"img-responsive\" src=\"https:\/\/cracku.in\/media\/uploads\/28225_aZQCbqA.PNG\" data-image=\"28225.PNG\" \/><\/figure>\n<p>Sum of angles of $\\triangle$ PQR = $\\angle P+\\angle Q+\\angle R=180^\\circ$<\/p>\n<p>=&gt; $60^\\circ+90^\\circ+\\angle R=180^\\circ$<\/p>\n<p>=&gt; $\\angle R=180^\\circ-150^\\circ=30^\\circ$<\/p>\n<p>To find\u00a0:\u00a0$(sec R + \\frac{1}{2})$<\/p>\n<p>= $sec(30^\\circ)+\\frac{1}{2}$<\/p>\n<p>= $\\frac{2}{\\sqrt3}+\\frac{1}{2}$<\/p>\n<p>=\u00a0$\\frac{(\\sqrt{3}+4)}{2\\sqrt{3}}$<\/p>\n<p>=&gt; Ans &#8211; (B)<\/p>\n<!-- Error, Advert is not available at this time due to schedule\/geolocation restrictions! -->\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_IN\" target=\"_blank\" class=\"btn btn-danger \">SSC Free Previous Papers App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>SSC CGL Trigonometry Questions with Solutions PDF Download SSC CGL Trignometry questions with answers PDF based on previous papers very useful for SSC CGL exams. 20 Very important Trignometry objective questions for SSC exams. Question 1:\u00a0What is the value of $(cot60^\\circ+1\/\\sqrt{3}) ?$ a)\u00a0$2\\sqrt3$ b)\u00a0$\\frac{\\sqrt3}{2}$ c)\u00a0$\\frac{2}{\\sqrt3}$ d)\u00a0$\\sqrt3$ Question 2:\u00a0What is the value of $(\\frac{1}{3} &#8211; sec [&hellip;]<\/p>\n","protected":false},"author":32,"featured_media":27196,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[9,504,1459,1268],"tags":[462],"class_list":{"0":"post-27189","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ssc","8":"category-ssc-cgl","9":"category-ssc-gd","10":"category-ssc-stenographer","11":"tag-ssc-cgl"},"better_featured_image":{"id":27196,"alt_text":"ssc cgl trigonometry questions with solutions pdf","caption":"ssc cgl trigonometry questions with solutions pdf","description":"ssc cgl trigonometry questions with solutions 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