Take a free mock test for LIC AAO<\/a><\/p>\n Download LIC AAO Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>The mean temperature of Monday and Thursday was 36C. If the temperature on Thursday was $\\frac{4}{5}$th of that Monday, then what was the temperature on Thursday ?<\/p>\n a)\u00a036.5C<\/p>\n b)\u00a032C<\/p>\n c)\u00a035.5C<\/p>\n d)\u00a034C<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>The sum of five numbers is 555. The average of first two numbers is 75 and the third number is 115. What is the average of last two-numbers ?<\/p>\n a)\u00a0145<\/p>\n b)\u00a0150<\/p>\n c)\u00a0265<\/p>\n d)\u00a0290<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>The average score of a class of boys and girls in an examination is A. The ratio of boys and girls in the class is 3: 1. If the average score of the boys is (A + 1), the average score of the girls is:<\/p>\n a)\u00a0(A – 1)<\/p>\n b)\u00a0(A – 3)<\/p>\n c)\u00a0(A +1)<\/p>\n d)\u00a0(A + 3)<\/p>\n Download LIC AAO Previous Papers PDF<\/a><\/p>\n 100 Free Computer Awareness Tests for LIC<\/a><\/p>\n Question 4:\u00a0<\/b>The average marks of a class increased by $\\large\\frac{1}{3}$ when a student\u2019s marks were wrongly entered as 64 instead of 46. The number of students in the class are<\/p>\n a)\u00a054<\/p>\n b)\u00a058<\/p>\n c)\u00a063<\/p>\n d)\u00a057<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>The average age of students in a class is 12. If the average age of boys is 18 and the average age of girls is 14 and If the number of boys are 22, then find the total number of students in the class<\/p>\n a)\u00a052<\/p>\n b)\u00a055<\/p>\n c)\u00a060<\/p>\n d)\u00a058<\/p>\n e)\u00a0None of these<\/p>\n Question 6:\u00a0<\/b>In the first 20 overs of a cricket game, the run rate was 4.5, What should be the run rate in the next 30 overs of the game to chase the target of 210?<\/p>\n a)\u00a06<\/p>\n b)\u00a04<\/p>\n c)\u00a08<\/p>\n d)\u00a06.5<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>In a society, 60% of residents own a car and 40% own a bike. Nobody owns car and bike both. Also, 25% of the residents work in the banking sector. If 20% of those who work in the banking sector own a bike, then the residents who own a car and work in non-banking sector form what percentage of the total people?<\/p>\n a)\u00a025%<\/p>\n b)\u00a040%<\/p>\n c)\u00a037.5%<\/p>\n d)\u00a060%<\/p>\n e)\u00a042.5%<\/p>\n Download LIC GK Material PDF<\/a><\/p>\n 100 Free GK Tests for Insurance Exams<\/a><\/p>\n Question 8:\u00a0<\/b>Amit scored 10% less marks than Sumit and 20% more marks than Rakesh. If Tina scored 35 marks more than Amit and Sumit scored 20 marks less than Tina, what is the absolute difference between the marks of Tina and Rakesh?<\/p>\n a)\u00a075<\/p>\n b)\u00a082.5<\/p>\n c)\u00a037.5<\/p>\n d)\u00a057.5<\/p>\n e)\u00a040<\/p>\n Question 9:\u00a0<\/b>Seema spends 30% of her salary on the education of her children. She spends 50% of the rest on household expenditures. Of the rest, she invests 14.28% and deposits the rest in the bank. She invests the money in mutual funds and Government bonds in the ratio 2 : 3. If the money invested in Government bonds is Rs. 2400, how much does Seema spend on the education of her children?<\/p>\n a)\u00a0Rs. 48000<\/p>\n b)\u00a0Rs. 80000<\/p>\n c)\u00a0Rs. 24000<\/p>\n d)\u00a0Rs. 10000<\/p>\n e)\u00a0Rs. 18000<\/p>\n Instructions<\/b><\/p>\n A school conducted 5 tests from test 1 to test 5 one after another. <\/p>\n Question 10:\u00a0<\/b>Who scored the highest marks in Test 3?<\/p>\n a)\u00a0Ankur<\/p>\n b)\u00a0Bunty<\/p>\n c)\u00a0Chandu<\/p>\n d)\u00a0Dinesh<\/p>\n e)\u00a0Esha<\/p>\n LIC AAO REASONING QUESTIONS PDF<\/a><\/p>\n LIC AAO Free Mock Test<\/a><\/p>\n\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let temperature on monday be a and that on thursday be y. 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the numbers be a, b, c, d, and e.<\/p>\n a+b+c+d+e = 555 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the common multiple be x. Let the number of students be ‘x’<\/p>\n Given that the average is increased by $\\Large\\frac{1}{3}$ due to the increase of $18$ marks ( $64$ $-$ $46$ $=$ $18$ marks )<\/p>\n Actual increase in marks $=$ $\\Large\\frac{1}{3}$ $\\times$ x<\/p>\n $\\Rightarrow$ $\\Large\\frac{1}{3}$ $\\times$ x $=$ $18$<\/p>\n $\\therefore$ Number of students(x) $=$ $54$<\/p>\n 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the total age of boys be \u2018B\u2019<\/p>\n Average age of boys = 18<\/p>\n $\\Large\\frac{B}{22}$ $=$ $18$<\/p>\n $\\Rightarrow$ B $=$ $396$<\/p>\n Let the total age of Girls be ‘G’<\/p>\n Let the number of girls be ‘x’<\/p>\n Average age of girls $=$ $14$<\/p>\n $\\Large\\frac{G}{x}$ $=$ $14$<\/p>\n $\\Rightarrow$ G $=$ $14$x<\/p>\n Total average of students $=$ $12$<\/p>\n Total age of students $=$ Total age of boys $+$ Total age of girls $=$ $396$ $+$ $14$x<\/p>\n Total number of students $=$ Number of boys $+$ Number of girls $=$ $22$ $+$ x<\/p>\n Average age of class $=$ $12$<\/p>\n $\\Rightarrow$ $\\Large\\frac{396 + 14x}{22 + x}$ $=$ $12$<\/p>\n $\\Rightarrow$ $396$ $+$ $14$x $=$ $462$ $+$ $12$x<\/p>\n $\\Rightarrow$ $2$x $=$ $66$<\/p>\n $\\Rightarrow$ x $=$ $33$<\/p>\n $\\therefore$ Number of girls $=$ $33$<\/p>\n Total number of students $=$ $22$ $+$ $33$ $=$ $55$<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Run-rate = 4.5 runs per over<\/p>\n $1$ over $\\rightarrow$ $4.5$ runs Total target $=$ $210$ runs<\/p>\n Remaining score $=$ $210$ $-$ $90$ $=$ $120$ runs<\/p>\n Remaining overs $=$ $30$ overs<\/p>\n $\\therefore$ Required run-rate $=$ $\\Large\\frac{120}{30}$ $=$ $4$ runs per over<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the total number of residents be 100x 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let Sumit scored 100x marks 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the total salary be Rs. 100x 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let T1 be test 1, T2 be test 2 and so on. Thus, Esha scored the highest marks in Test 3.
\nThe following table shows the average marks scored in the tests till that test by 5 students in the tests till that test.
\nFor example:- The average marks scored by Ankur in Test 1 and Test 2 = 73
\nThe average marks scored by Ankur in Test 1 ,Test 2 and Test 3 = 69 and so on.
\n![](\"https:\/\/cracku.in\/media\/uploads\/di-509-3-2.PNG\")
<\/p>\n
\n(x+y)\/2 = 36
\nNow, y = 0.8x
\nHence, we get Monday’s temperature as 40
\nTherefore, none of these is the answer.<\/p>\n
\nNow, (a+b)\/2 = 75
\na+b = 150
\nand c = 115
\ntherefore, d+e = 290
\nAverage, (d+e)\/2 = 145<\/p>\n
\nThere are x girls and 3x boys.
\nNow, let girls score be N.
\n$\\frac{N*x+(A+1)*3x}{4x}$ = A
\nN = 4A – 3(A+1)
\n= A – 3
\nHence, the average score of girls is A-3
\n4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n
\n$20$ overs $\\rightarrow$ $20\\times4.5$ $=$ $90$ runs<\/p>\n
\nPeople who own car = 60k
\nPeople who own a bike = 40k
\nPeople who work in the banking sector = 25k
\nPeople in the banking sector who own a bike = 20% of 25k = 5k
\nRest of the people who work in the banking sector must be owning a car
\nNumber of people owning a car and working in banking sector = 25k – 5k = 20k
\nNumber of people owning a car and working in non-banking sector = 60k – 20k = 40k
\nRequired % = 40k\/100k * 100 = 40%
\nHence, option B is the correct answer.<\/p>\n
\nThen, Amit scored 90x marks
\nAmit\u2019s score is 20% more than that of Rakesh.
\nSo, Rakesh\u2019s score = 75x
\nTina\u2019s score = Amit\u2019s score + 35 = 90x + 35…..(i)
\nTina\u2019s score = Sumit\u2019s score + 20 = 100x + 20…(ii)
\nOn comparing (i) and (ii),
\n90x + 35 = 100x + 20
\nOn solving, we get x = 1.5
\nSo, Rakesh\u2019s score = 75x = 75* 1.5 = 112.5
\nAnd Tina\u2019s score = 90x + 35 = 170
\nDifference = (170 – 112.5) = 57.5
\nHence, option D is the correct answer.<\/p>\n
\nAmount spent on education = Rs. 30x
\nAmount left = Rs. 70x
\nAmount spent on household expenditures = 50% of Rs. 70x = Rs. 35x
\nAmount left = Rs. (70x – 35x) = Rs. 35x
\nAmount invested = 14.28% of Rs. 35x = Rs. 5x
\nAmount invested in Government bonds = Rs. $\\frac{3}{5} * 5x$ = Rs. 3x
\nIt is given that, 3x = 2400
\nOr, x = 800
\nSo, Amount spent on education = Rs. 30x = Rs. 24000
\nHence, option C is the correct answer.<\/p>\n
\nThe average marks scored by Ankur in Test 1 = the marks scored by Ankur in test 1 = 68.
\nThe average marks scored by Ankur in Test 1 and Test 2 = 73
\nThus, 73 = (marks scored in T1 + marks scored in T2)\/2
\nThus, marks scored by Ankur in T2 = 73*2 – 68 = 78.
\nThe average marks scored by Ankur in Test 1 ,Test 2and Test 3 = 69
\n69 = (marks scored in T1 + marks scored in T2 + marks scored in T3)\/3
\nThus, marks scored by Ankur in T3 = 207-146 = 61
\nThe average marks scored by Ankur in Test 1 ,Test 2,Test 3 and Test 4 = 70
\n70 = (marks scored in T1 + marks scored in T2 + marks scored in T3+marks scored in T4)\/4
\nThus, marks scored by Ankur in T4 = 280-207 = 63.
\nThe average marks scored by Ankur in Test 1 ,Test 2,Test 3, Test 4 and Test 5 = 72
\n72 = (marks scored in T1 + marks scored in T2 + marks scored in T3+marks scored in T4+marks scored in T5)\/5
\nThus, marks scored by Ankur in T5 = 360-280 = 80
\nSimilarly, we can calculate the marks scored by all the students in all the tests as shown below in the table format:-<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/di-509-3-1.PNG\")
<\/figure>\n
\nHence, option E is the correct answer.<\/p>\n