Download Important Time & Work questions for LIC AAO exam. Top 20 Time & Work questions set-2 with answers based on previous year asked questions.<\/p>\n
Download Time and Work Questions for LIC AAO PDF<\/a><\/p>\n\n Download LIC AAO Time & Work Set-1 Questions PDF<\/a><\/p>\n Take a free mock test for LIC AAO<\/a><\/p>\n Download LIC AAO Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>A-B means A is the father of B. A+B means A is the daughter of B. $A\\div B$ Means A is the son of B. $A\\times B$ means A is the wife of B . Then, what is the relation of P with T in the expression P+S-T?<\/p>\n a)\u00a0Son<\/p>\n b)\u00a0Daughter<\/p>\n c)\u00a0Sister<\/p>\n d)\u00a0Wife<\/p>\n Question 2:\u00a0<\/b>12 year old Mahesh is three times as old as his brother Ramesh. How old will Mahesh be when he is twice as old as Ramesh ?<\/p>\n a)\u00a014 years<\/p>\n b)\u00a020 years<\/p>\n c)\u00a018 years<\/p>\n d)\u00a016 years<\/p>\n Question 3:\u00a0<\/b>9 children can complete a piece of work in 360 days, 18 men can complete the same piece of work in 72 days and 12 women can complete it in 162 days. In how many days can 4 men, 12 women and 10 children together complete the piece of work ?<\/p>\n a)\u00a068 days<\/p>\n b)\u00a081 days<\/p>\n c)\u00a096 days<\/p>\n d)\u00a0124 days<\/p>\n Download LIC AAO Previous Papers PDF<\/a><\/p>\n 100 Free Computer Awareness Tests for LIC<\/a><\/p>\n Question 4:\u00a0<\/b>10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work ?<\/p>\n a)\u00a03<\/p>\n b)\u00a05<\/p>\n c)\u00a07<\/p>\n d)\u00a0Cannot be determined<\/p>\n Question 5:\u00a0<\/b>8 men can finish a piece of work in 40 days. If 2 more men join with them, then the work will be completed in<\/p>\n a)\u00a030 days<\/p>\n b)\u00a032 days<\/p>\n c)\u00a036 days<\/p>\n d)\u00a025 days<\/p>\n Question 6:\u00a0<\/b>A man, a woman and a boy together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman take to complete the work ?<\/p>\n a)\u00a09 days<\/p>\n b)\u00a021 days<\/p>\n c)\u00a024 days<\/p>\n d)\u00a027 days<\/p>\n Question 7:\u00a0<\/b>A, B and C can do a piece of work in 20, 25 and 40 days. They started the work together but B left 4 days before completion. In how many days the work is completed?<\/p>\n a)\u00a013$\\large\\frac{4}{23}$ days<\/p>\n b)\u00a010$\\large\\frac{2}{23}$\u00a0days<\/p>\n c)\u00a012$\\large\\frac{3}{17}$\u00a0days<\/p>\n d)\u00a014$\\large\\frac{5}{17}$\u00a0days<\/p>\n e)\u00a0None of these<\/p>\n Download LIC GK Material PDF<\/a><\/p>\n 100 Free GK Tests for Insurance Exams<\/a><\/p>\n Question 8:\u00a0<\/b>5 men and 13 women can do a piece of work in 5 days while 2 men and 7 women can do the same work in 11 days. Then in how many days can 4 men and 6 women can complete the work?<\/p>\n a)\u00a08$\\large\\frac{1}{2}$ days<\/p>\n b)\u00a06$\\large\\frac{1}{3}$ days<\/p>\n c)\u00a07$\\large\\frac{1}{2}$ days<\/p>\n d)\u00a09 days<\/p>\n e)\u00a0None of these<\/p>\n Question 9:\u00a0<\/b>A can do a piece of work in 24 days. B can do the same work in 36 days. With the help of C, the work has finished in 9 days. If total wage for doing the work is Rs.6400, then the amount received by C is<\/p>\n a)\u00a0Rs. 2400<\/p>\n b)\u00a0Rs.1800<\/p>\n c)\u00a0Rs.1600<\/p>\n d)\u00a0Rs.2000<\/p>\n e)\u00a0None of these<\/p>\n Question 10:\u00a0<\/b>A and B can do a piece of work in 15 days and 20 days respectively. They work in alternate days starting with A. In how many days, total work will be completed?<\/p>\n a)\u00a0$16\\frac{1}{3}$ days<\/p>\n b)\u00a0$17\\frac{1}{4}$ days<\/p>\n c)\u00a017 days<\/p>\n d)\u00a015 days<\/p>\n e)\u00a0None of these<\/p>\n LIC AAO REASONING QUESTIONS PDF<\/a><\/p>\n LIC AAO Free Mock Test<\/a><\/p>\n\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n P + S means P is the daughter of S and S – T means S is the father of T.Thus S is the father of both P and T.\u2234P is the sister of T.<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n age of Mahesh=12<\/p>\n Given, Mahesh is 3 times as old as Ramesh.<\/p>\n So age of Ramesh is=4<\/p>\n From options, we can see that when we put Mahesh’s age to be 16, we get the age Ramesh to be 8.<\/p>\n \u2234 when Mahesh is 16 his age is twice that of Ramesh.<\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the speed of child, man and woman to complete work W be x,y and z respectively. 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the speed of Women be x and that of children be y. Let piece of work be W. Let the work be W and speed of each man be x. Download General Science Material PDF<\/a><\/p>\n\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the man’s, woman’s and boy’s speed be x, y and z. A can do the work in 20 days<\/p>\n B can do the work in 25 days<\/p>\n C can do the work in 40 days<\/p>\n Total work = LCM of 20,25,40 $=$ 200 units<\/p>\n Efficiency of A $=$ $\\Large\\frac{200}{20}$ $=$ 10 units\/day<\/p>\n Efficiency of B $=$ $\\Large\\frac{200}{25}$ $=$ 8 units\/day<\/p>\n Efficiency of C $=$ $\\Large\\frac{200}{40}$ $=$ 5 units\/day<\/p>\n Let the number of days required to complete the work be \u2018X\u2019 days<\/p>\n Total work done by A in X days $=$ 10 $\\times$ X $=$ 10X units<\/p>\n Total work done by C in X days $=$ 5 \\times X $=$ 5X days<\/p>\n B left 4 days before completion<\/p>\n Total work done by B in (X – 4) days $=$ 8(X – 4) $=$ (8X – 32) units<\/p>\n $\\therefore$ 10X + 5X + 8X – 32 $=$ 200<\/p>\n 23X – 32 $=$ 200<\/p>\n $\\therefore$ X $=$ $\\Large\\frac{232}{23}$ $=$ 10$\\Large\\frac{2}{23}$ days<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n No. of men$_{1}$ $\\times$ No. of days$_{1}$ $=$ No. of men$_{2}$ $\\times$ No. of days$_{2}$<\/p>\n $\\Rightarrow$ (5M+13W)5 $=$ (2M+7W)11<\/p>\n $\\Rightarrow$ 25M + 65W $=$ 22M + 77W<\/p>\n $\\Rightarrow$ 3M $=$ 12W<\/p>\n $\\therefore$ 1M $=$ 4W<\/p>\n Let the number of days required for 4 men and 6 women to complete the work be ‘x’ days<\/p>\n (5M + 13W) $\\times$ 5 $=$ (4M + 6W) $\\times$ x<\/p>\n Substituting M $=$ 4W in above equation<\/p>\n $\\Rightarrow$ (20M + 13W) $\\times$ 5 $=$ (16M + 6W) $\\times$ x<\/p>\n $\\Rightarrow$ 33W $\\times$ 5 $=$ 22W $\\times$ x<\/p>\n $\\Rightarrow$ x $=$ $\\Large\\frac{33 \\times 5}{22}$ $=$ $\\Large\\frac{15}{2}$ $=$ 7$\\Large\\frac{1}{2}$ days<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n A can do a piece of work in $24$ days<\/p>\n B can do the same work in $36$ days<\/p>\n A+B+C can do it together in $9$ days<\/p>\n Total work $=$ LCM of $24$,$36$,$9$ $=$ $72$ units<\/p>\n Efficiency of A $=$ $\\Large\\frac{72}{24}$ $=$ $3$ units\/day<\/p>\n Efficiency of B $=$ $\\Large\\frac{72}{36}$ $=$ $2$ units\/day<\/p>\n Efficiency of A $+$ B $+$ C $=$ $\\Large\\frac{72}{9}$ $=$ $8$ units\/day<\/p>\n \\Rightarrow Efficiency of C $=$ $8$ $-$ $5$ $=$ $3$ units\/day<\/p>\n Total efficiency of A $+$ B $+$ C $=$ $8$ units<\/p>\n Total wages $=$ Rs.$6400$<\/p>\n $8$ units $\\rightarrow$ Rs.$6400$ then C’s wage $=$ $3\\times800$ $=$ Rs.$2400$<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n A can do a piece of work in $15$ days<\/p>\n B can do the same in $20$ days<\/p>\n Total work $=$ LCM of $15$ and $20$ days $=$ $60$ units<\/p>\n Efficiency of A $=$ $\\Large\\frac{60}{15}$ $=$ $4$ units\/day<\/p>\n Efficiency of B $=$ $\\Large\\frac{60}{20}$ $=$ $3$ units\/day<\/p>\n They work in alternate days starting with A<\/p>\n So, A and B can do $7$ units in $2$ days<\/p>\n So, $56$ units can be completed in $16$ days<\/p>\n Remaining $4$ units can be completed by A in $1$ day<\/p>\n $\\therefore$ total work can be completed in $17$ days<\/p>\n
\nTherefore, as per given conditions
\nx = W\/3240
\ny= W\/1296
\nand z = W\/1944
\nNow, the combined speed of 4 men, 12 women and 10 children = 4y+12z+10x = W\/81
\nNow, number of days = W\/(W\/81) = 81 days
\nThe correct option is option B<\/p>\n
\n10x=W\/7, x=W\/70
\n10y =W\/14 y= W\/140
\nNow, 5x + 10y = W\/14 + W\/14 = W\/7
\nNumber of day srequired to complete the work = W\/(W\/7) = 7 days.
\nTherefore, the correct option is option C.
\n5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n
\nW\/(8x) = 40
\nx = W\/320
\nIf two more men join, total speed will become = W\/32
\nNow, the work can be done= W\/(W\/32) = 32 days
\nTherefore work will be done in 32 days.<\/p>\n
\nLet the piece of work be W.
\nNow, x+y+z = W\/3
\nAlso, x = W\/6
\nand z=W\/18
\nTherefore, y = W\/3 – W\/6 – W\/18
\ny = W\/9
\nNumber of days required by woman alone to complete the work = W\/y = W\/(W\/9)
\nHence, number of days = 9
\nTherefore, the correct option is option A.
\n7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n
\n$1$ unit $ \\rightarrow$ Rs.$800$<\/p>\n