{"id":26876,"date":"2019-04-01T18:22:44","date_gmt":"2019-04-01T12:52:44","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=26876"},"modified":"2019-04-02T13:41:25","modified_gmt":"2019-04-02T08:11:25","slug":"time-work-questions-for-rrb-je-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-work-questions-for-rrb-je-pdf\/","title":{"rendered":"Time & Work Questions For RRB JE PDF"},"content":{"rendered":"

Time & Work Questions For RRB JE PDF<\/strong><\/span><\/h1>\n

Download Top 20 RRB JE Time & Work Questions and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam<\/p>\n

Download Time & Work Questions For RRB JE PDF<\/a><\/p>\n\n

Download RRB JE Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>84 men can do a piece of work in 16 days. If the work needs to be completed in 12 days, then how many more men are required?<\/p>\n

a)\u00a024<\/p>\n

b)\u00a028<\/p>\n

c)\u00a032<\/p>\n

d)\u00a016<\/p>\n

Question 2:\u00a0<\/b>\u2018P\u2019 can complete a work in 15 days. \u2018Q\u2019 can complete the same work in 45 days.If they want to complete the work by working 3 days each alternatively starting with P then how many days does it take to complete whole work<\/p>\n

a)\u00a030 days<\/p>\n

b)\u00a027 days<\/p>\n

c)\u00a021 days<\/p>\n

d)\u00a024 days<\/p>\n

Question 3:\u00a0<\/b>A and B can do a piece of work individually in 9 days and 15 days respectively. They work on alternate days starting with A. Then in how many days, the work will be completed?<\/p>\n

a)\u00a012 days<\/p>\n

b)\u00a09 days<\/p>\n

c)\u00a011 days<\/p>\n

d)\u00a08 days<\/p>\n

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Question 4:\u00a0<\/b>A and B can do a piece of work individually in 24 days and 16 days respectively. They both started the work together and after 3 days, C with double the efficiency of B joined. Then in how many days, will the work be completed?<\/p>\n

a)\u00a03 days<\/p>\n

b)\u00a06 days<\/p>\n

c)\u00a07 days<\/p>\n

d)\u00a04 days<\/p>\n

Question 5:\u00a0<\/b>5 men and 2 women can complete a work in 3 days. 2 man and 3 women can complete the work in 4 days. In how many days can 12 women finish the work ?<\/p>\n

a)\u00a013\/7 days<\/p>\n

b)\u00a09\/7 days<\/p>\n

c)\u00a011\/7 days<\/p>\n

d)\u00a010\/7 days<\/p>\n

Question 6:\u00a0<\/b>A and B can do a piece of work individually in 12 days and 15 days respectively. They both started the work together but after 4 days, A left. Then in how many days will the total work be completed?<\/p>\n

a)\u00a010 days<\/p>\n

b)\u00a06 days<\/p>\n

c)\u00a08 days<\/p>\n

d)\u00a04 days<\/p>\n

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Question 7:\u00a0<\/b>P can do a work in 50 days, Q can do the same work in 100 days and after working for 20 days, C joins the work and after 10 days work has been completed. How many does C alone take to complete the work ?<\/p>\n

a)\u00a0100<\/p>\n

b)\u00a070<\/p>\n

c)\u00a0125<\/p>\n

d)\u00a050<\/p>\n

Question 8:\u00a0<\/b>P can do a work in 10 days, Q can do the same work in 20 days and after working for 2 days, C joins the work and after 2 days work has been completed. How many days does C alone take to complete the work ?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a03<\/p>\n

c)\u00a05<\/p>\n

d)\u00a06<\/p>\n

Question 9:\u00a0<\/b>\u2018A\u2019 can do a piece of work in 6 days and \u2018B\u2019 can do it in 5 days if B joins with A after 2 days then in how many days will the work get completed ?<\/p>\n

a)\u00a042\/11 days<\/p>\n

b)\u00a041\/11 days<\/p>\n

c)\u00a040\/11 days<\/p>\n

d)\u00a039\/11 days<\/p>\n

Question 10:\u00a0<\/b>A and B can do a piece of work individually in 14 hours and 21 hours respectively. A started the work and will be assisted by B on every alternate hour. Then find the time in which the total work will be completed?<\/p>\n

a)\u00a010 hours 40 minutes<\/p>\n

b)\u00a012 hours 20 minutes<\/p>\n

c)\u00a011 hours 24 minutes<\/p>\n

d)\u00a014 hours 40 minutes<\/p>\n

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Question 11:\u00a0<\/b>Find the time taken by 200m long train, travelling at 81 kmph to cross a man travelling at 9 kmph in the same direction ?<\/p>\n

a)\u00a015 sec<\/p>\n

b)\u00a010 sec<\/p>\n

c)\u00a020 sec<\/p>\n

d)\u00a025 sec<\/p>\n

Question 12:\u00a0<\/b>What is the time taken by a flight to cover 1875 km if it is moving at 500 kmph?<\/p>\n

a)\u00a03hrs 30mins<\/p>\n

b)\u00a03hrs 35mins<\/p>\n

c)\u00a03hrs 40mins<\/p>\n

d)\u00a03hrs 45mins<\/p>\n

Question 13:\u00a0<\/b>Train A of length 300m and Train B of length 600m are travelling with 35kmph and 55kmph respectively. Find the time taken by them to cross each other if they are moving in opposite direction ?<\/p>\n

a)\u00a032 seconds<\/p>\n

b)\u00a034 seconds<\/p>\n

c)\u00a036 seconds<\/p>\n

d)\u00a038 seconds<\/p>\n

 <\/p>\n

Question 14:\u00a0<\/b>A car leaves place A at 10 am and travels at 40 km\/hr. A bus leaves place A at 12 am and travels at 60 km\/hr along the same route as A. A biker leaves A at a certain time and overtakes both the car and the bus at the same time. If the biker travels at 120 km\/hr then find the time at which biker left A.<\/p>\n

a)\u00a01 pm<\/p>\n

b)\u00a02 pm<\/p>\n

c)\u00a02:30 pm<\/p>\n

d)\u00a01:45 pm<\/p>\n

Question 15:\u00a0<\/b>A boat can travel 27 km in one hour in still water and travels the same distance against the stream in 90 minutes. How much time will the boat take to travel 90 km in the direction of the stream?<\/p>\n

a)\u00a04 hours<\/p>\n

b)\u00a04.25 hours<\/p>\n

c)\u00a02.5 hours<\/p>\n

d)\u00a03.5 hours<\/p>\n

Question 16:\u00a0<\/b>Balu travels from his home to office on his bike. After travelling 75% of the total distance, his bike develops a snag and hence, his speed gets reduced to a third of his original speed. He reaches office 30 minutes late. What is the usual time that Balu takes to travel from his home to the office?<\/p>\n

a)\u00a01 hour<\/p>\n

b)\u00a01.5 hours<\/p>\n

c)\u00a02 hour<\/p>\n

d)\u00a02.5 hours<\/p>\n

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Question 17:\u00a0<\/b>A train crosses a platform twice its length in 12 seconds. How much time will it take to cross a stationary pole?<\/p>\n

a)\u00a03 seconds<\/p>\n

b)\u00a04 seconds<\/p>\n

c)\u00a02 seconds<\/p>\n

d)\u00a06 seconds<\/p>\n

Question 18:\u00a0<\/b>A boat goes at a speed of 30 kmph in still water. What time does it take to travel 50 kms upstream and then 70 kms downstream in water of speed 5 kmph?<\/p>\n

a)\u00a02 hours<\/p>\n

b)\u00a04 hours<\/p>\n

c)\u00a06 hours<\/p>\n

d)\u00a08 hours<\/p>\n

Question 19:\u00a0<\/b>The speed of a car, excluding stoppages, is 80 kmph. Including stoppages, the speed of the car is 50kmph. For how many minutes does the car stop per hour?<\/p>\n

a)\u00a015<\/p>\n

b)\u00a022.5<\/p>\n

c)\u00a030<\/p>\n

d)\u00a037.5<\/p>\n

Question 20:\u00a0<\/b>What is the time taken by P and Q to meet for the first time on the circular track of length 500m if they are travelling in the same direction and the speed of P is 90m\/s and the speed of Q is 40m\/s?<\/p>\n

a)\u00a010s<\/p>\n

b)\u00a012s<\/p>\n

c)\u00a08s<\/p>\n

d)\u00a05s<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\text No. of men_1 \\times \\text No. of days _2 = \\text No. of men_2 \\times \\text No. of days_2$
\nLet the number of men required to complete the work in 12 days be ‘x’
\n=> $84\\times16 = 12\\times x$
\n=> $x = 112$
\nTherefore, Number of extra men required $= 112-84 = 28$.<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

LCM of 15 and 45 is 45. Total units of work=45
\nP can do 45\/15 =3 units per day
\nQ can do 15\/15=1 units per day
\nSo starting with P we have 9+3+9+3+9+3+9=45
\nSo total it takes 9*3=21 days<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the total work be 45 units (LCM of 9 and 15)
\nEfficiency of A = 45\/9 = 5 units\/day
\nEfficiency of B = 45\/15 = 3 units\/day
\nThey work on alternate days starting with A.
\nThen, 8 units of work will be completed in 2 days.
\n\u21d2 40 units of work will be completed in 10 days.
\nRemaining work = 5 units.
\n5 units of work will be completed by A in 1 day.
\nHence, Total work will be completed in 11 days.<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the total work be 48 units (LCM of 24 and 16).
\nEfficiency of A = 48\/24 = 2 units\/day
\nEfficiency of B = 48\/16 = 3 units\/day
\nThen, 5 units of work will be completed in a day.
\n15 units of work will be completed in 3 days.
\nNow C joined with double the efficiency of B
\n\u21d2 Efficiency of C = 3*2 = 6 units\/day
\nRemaining work = 33 units
\n33 units will be completed by A,B and C in 33\/11 = 3 days.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given (5*3)MD+(2*3)WD=total work
\n(2*4)MD+(3*4)WD=total work
\n15MD+6WD=8MD+12WD
\n7MD=(6)WD
\nTotal work in terms of women days is
\n8(6\/7)WD+12WD=(48+84)\/7 WD
\nTotal work=132\/7 WD
\nTherefore 12*x=132\/7
\nx=11\/7 days<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the total work be 60 units (LCM of 12 and 15)
\nEfficiency of A = 60\/12 = 5 units\/day
\nEfficiency of B = 60\/15 = 4 units\/day
\nHence, in 1 day, 9 units of work will be completed.
\n\u21d2 In 4 days, 36 units of work will be completed.
\nRemaining work = 60-36 = 24 units.
\n24 units needs to be completed by B.
\n4 units will be completed by B in 1 day
\n24 units will be completed by B in 6 days.
\nHence, Total work will be completed in 6+4 = 10 days.<\/p>\n\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

LCM of 50 and 100 is 100 and so total 100 units of work has to be done.
\nEach day P can do 2 units of work
\nEach day Q can do 1 unit of work
\nAfter 20 days 60 units of work is done so 40 units is left
\nGiven in next 10 days work has been completed along with C.
\nSo 10(1+2+x)=40
\n3+x=4
\nx=1
\nC does 1 unit of work each day and so it takes 100 days for him to complete the whole work.<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

LCM of 10 and 20 is 20 and so total units of work has to be done.
\nEach day P can do 2 units of work
\nEach day Q can do 1 unit of work
\nAfter 2 days 6 units of work is done so 14 units is left
\nGiven in next 2 days work has been completed along with C.
\nSo 2(1+2+x)=14
\n3+x=7
\nx=4
\nC does 4 units of work each day and so it takes 5 days for him to complete the whole work.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

LCM of 6 and 5 is 30 and so 30 units is the total work.
\nOn each day A does (30\/6)=5 units of work
\nOn each day B does (30\/5)=6 units of work
\nSo in first 2 days A completes 10 units of work.
\nSo 20 units of work has to be done by both and each day they can do 11 units of work.
\nSo in $1\\frac{9}{11}$ days remaining work will be completed
\nTotal time taken is 2+$1\\frac{9}{11}$=42\/11 days<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the total work be 42 units (LCM of 14 and 21)
\nEfficiency of A = 42\/14 = 3 units\/hour
\nEfficiency of B = 42\/21 = 2 units\/hour
\nA is assisted by B on every alternate hour
\nA can complete 3 units of work in first hour
\nA and B can complete 5 units of work in second hour.
\nHence, 8 units of work will be completed in 2 hours.
\nThen, 40 units of work will be completed in 10 hours.
\nRemaining work = 2 units.
\nA can do 2 units of work in 2\/3rd of an hour = $\\dfrac{2}{3}\\times60 = 40$ minutes
\nTherefore, Total work will be completed in 10 hours 40 minutes.<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Relative speed = 81-9 = 72 kmph = 72*(5\/18) = 20 m\/s<\/p>\n

Time = distance\/speed = 200\/20 = 10 sec<\/p>\n

So the answer is option B.<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Time = $\\frac{distance}{speed} = \\frac{1875}{500} = 3\\frac{3}{4}hrs = 3hrs.45mins$<\/p>\n

So the answer is option D.<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

relative speed = 35+55 = 90 kmph = 90*(5\/18) = 25 m\/s<\/p>\n

Time taken to cross each other = $\\frac{300+600}{25} = 36 seconds$<\/p>\n

So the answer is option C.<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The bus starts 2 hours after the car. Hence, the car would have covered 80 km in the mean time. Now relative speed of the car and the bus is 20 km\/hr. Hence, bus will take 4 hours to reach the same point as the car. Hence, the distance travelled by the bus will be 60*4 = 240 km.
\nThe biker will need 240\/120 = 2 hours.
\nThus, the biker must have started at 2 pm.<\/p>\n

15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let \u2018s\u2019 be the speed of the boat and \u2018w\u2019 be the speed of the stream.
\nWe have, s = 27 km\/hr and $\\frac{27}{s-w} = 1.5 $ hour
\nSo s – w = 18 so w = 9 km\/hr
\nWe get, $\\frac{90}{18+9} = 2.5$ hour
\nHence, option C is the right choice.<\/p>\n

16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The difference between the time taken to travel one-fourth of the total distance at reduced speed and normal speed is 30 minutes.
\nLet us consider the distance for which the bike travels at the reduced speed to be \u2018d\u2019.
\n=> Total distance = 4d.
\nLet the normal speed of the bike be \u2018s\u2019. => Reduced speed = s\/3.<\/p>\n

Now, we know that,
\nd\/(s\/3) – d\/s = 30
\n(3d-d)\/s = 30
\n2d\/s = 30
\n=>d\/s = 15 minutes.
\nTime taken to travel the distance between Balu\u2019s home and office = 4d\/s = 4*15 = 1 hour.
\nHence, option A is the right answer.<\/p>\n

17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let us assume the length of the train to be \u2018x\u2019.
\nThe total distance that the train has to travel to cross a platform of length \u20182x\u2019 =sum of the lengths of train and platform.
\nDistance travelled = x+2x = 3x.
\nSpeed of the train = 3x\/12 = x\/4.
\nThe time the train will take to cross a stationary pole = x\/(x\/4) = 4 seconds.
\nHence, option B is the right answer.<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The relative speed of the boat in upstream = 30 – 5 = 25 kmph
\nDistance = 50 kms
\nTime = 50 \/ 25 = 2 hours.<\/p>\n

Relative speed in downstream = 30 + 5 = 35 kmph
\nDistance = 70 kms
\nTime = 70\/35 = 2 hours.<\/p>\n

Total time = 2 + 2 = 4 hours.<\/p>\n\n

19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

In 1 hour the car can travel 80 km if stoppages are excluded.
\nIn the same time, the care can travel only 50 km if stoppages are included.
\n=> 30 km less because of stoppages
\nTime taken to cover 30km = $\\frac{30}{80}$ = 0.375 hours = 0.375 * 60 minutes = 22.5 minutes<\/p>\n

20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

As discussed in the concept time taken =$\\frac{2\\pi r}{x-y}$
\n$2\\pi r = 500$
\nTime taken =$\\frac{500}{90-40} = 10$s<\/p>\n

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We hope this Time & Work Questions for RRB JE Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time & Work Questions For RRB JE PDF Download Top 20 RRB JE Time & Work Questions and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam Download RRB JE Previous Papers PDF Question 1:\u00a084 men can do a piece of work in […]<\/p>\n","protected":false},"author":41,"featured_media":26877,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1605],"tags":[489,491,1635,1647],"class_list":{"0":"post-26876","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-je","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-je","14":"tag-rrb-mocks"},"better_featured_image":{"id":26877,"alt_text":"RRB JE Time & Work Questions PDF","caption":"RRB JE Time & Work Questions PDF","description":"RRB JE Time & Work Questions 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