{"id":26272,"date":"2019-03-19T14:34:48","date_gmt":"2019-03-19T09:04:48","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=26272"},"modified":"2019-03-19T14:34:48","modified_gmt":"2019-03-19T09:04:48","slug":"algebra-questions-for-rrb-je-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/algebra-questions-for-rrb-je-pdf\/","title":{"rendered":"Algebra Questions For RRB JE PDF"},"content":{"rendered":"

Algebra Questions For RRB JE PDF<\/span><\/h1>\n

Download RRB JE Algebra Questions and Answers PDF. Top 25 RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam<\/p>\n

Download Algebra Questions For RRB JE PDF<\/a><\/p>\n

10 RRB JE Mocks – Just Rs. 117<\/a><\/p>\n

RRB JE Previous Papers [Download PDF]<\/a><\/p>\n

\"RRB<\/a><\/p>\n

Question 1:\u00a0<\/b>Sum of a natural number and 5 times its reciprocal is 14\/3, then find that number ?<\/p>\n

a)\u00a06<\/p>\n

b)\u00a05<\/p>\n

c)\u00a04<\/p>\n

d)\u00a03<\/p>\n

Question 2:\u00a0<\/b>Find $a \\times b$ if $a+b = 36$ & $a^2+b^2 = 720 ?$<\/p>\n

a)\u00a0288<\/p>\n

b)\u00a0244<\/p>\n

c)\u00a0284<\/p>\n

d)\u00a0248<\/p>\n

Question 3:\u00a0<\/b>Find the value of x if 5*(4x-3\/2) + 2x = 4-3x\/2<\/p>\n

a)\u00a023\/47<\/p>\n

b)\u00a01\/2<\/p>\n

c)\u00a02\/3<\/p>\n

d)\u00a03\/2<\/p>\n

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Question 4:\u00a0<\/b>Find $10^3+9^3+…….+3^3$ ?<\/p>\n

a)\u00a03015<\/p>\n

b)\u00a03020<\/p>\n

c)\u00a03025<\/p>\n

d)\u00a03016<\/p>\n

Question 5:\u00a0<\/b>If $p, q$ are the sum and product of the roots of $3x^3-4x^2+5x-6$, then find $\\frac{q}{p}$ ?<\/p>\n

a)\u00a0$3$<\/p>\n

b)\u00a0$\\frac{1}{3}$<\/p>\n

c)\u00a0$\\frac{2}{3}$<\/p>\n

d)\u00a0$\\frac{3}{2}$<\/p>\n

Question 6:\u00a0<\/b>If $x+\\frac{1}{x} = 2$ then find $x^{32}+\\frac{1}{x^{32}}$?<\/p>\n

a)\u00a02<\/p>\n

b)\u00a016<\/p>\n

c)\u00a04<\/p>\n

d)\u00a08<\/p>\n

Question 7:\u00a0<\/b>2[3x – 4\/5] + 6x\/7 = 8, then find x ?<\/p>\n

a)\u00a04\/5<\/p>\n

b)\u00a05\/6<\/p>\n

c)\u00a06\/7<\/p>\n

d)\u00a07\/5<\/p>\n

Question 8:\u00a0<\/b>If $p, q$ are the sum and product of the roots of $4x^3-3x^2+2x-1$, then find $\\frac{p^2}{q^2}$ ?<\/p>\n

a)\u00a0$4$<\/p>\n

b)\u00a0$9$<\/p>\n

c)\u00a0$\\frac{1}{9}$<\/p>\n

d)\u00a0$\\frac{1}{4}$<\/p>\n

Question 9:\u00a0<\/b>If sum of a number and 4 times its fraction is 4, then find that number ?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a02<\/p>\n

c)\u00a03<\/p>\n

d)\u00a04<\/p>\n

\"RRB<\/a><\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Question 10:\u00a0<\/b>Find a-b if a+b = 23, ab = 132 ?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a0-1<\/p>\n

c)\u00a02<\/p>\n

d)\u00a0Either (a) or (b)<\/p>\n

Question 11:\u00a0<\/b>If $a+b+c = 0$, then $\\frac{a^2+b^2+c^2}{ab+bc+ca} = ?$<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a0-2<\/p>\n

d)\u00a02<\/p>\n

Question 12:\u00a0<\/b>4[$\\frac{x}{3}$ -$\\frac{3}{8}$ ] + $\\frac{x}{6}$ = $\\frac{x}{3}$ -$\\frac{1}{2}$, then find x ?<\/p>\n

a)\u00a0\u00a0$\\frac{6}{7}$<\/p>\n

b)\u00a0\u00a0$\\frac{7}{6}$<\/p>\n

c)\u00a0\u00a0$\\frac{4}{5}$<\/p>\n

d)\u00a0\u00a0$\\frac{5}{4}$<\/p>\n

Question 13:\u00a0<\/b>If $x^2+\\frac{1}{x^2} = 11$ then find $x^4+\\frac{1}{x^4}$?<\/p>\n

a)\u00a0123<\/p>\n

b)\u00a0119<\/p>\n

c)\u00a081<\/p>\n

d)\u00a0108<\/p>\n

Question 14:\u00a0<\/b>Find 7+8+9+10+……+50 = ?<\/p>\n

a)\u00a01275<\/p>\n

b)\u00a01254<\/p>\n

c)\u00a01257<\/p>\n

d)\u00a01244<\/p>\n

Question 15:\u00a0<\/b>Find $a^3-b^3$, if $a-b = 1, ab = 12$ ?<\/p>\n

a)\u00a027<\/p>\n

b)\u00a037<\/p>\n

c)\u00a047<\/p>\n

d)\u00a057<\/p>\n

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Question 16:\u00a0<\/b>If p, q are the sum and product of the roots of $3x^3-4x^2+5x-6=0$, then find p*q ?<\/p>\n

a)\u00a03\/8<\/p>\n

b)\u00a08\/3<\/p>\n

c)\u00a02\/3<\/p>\n

d)\u00a03\/2<\/p>\n

Question 17:\u00a0<\/b>Find the value of $a^2+b^2$, if $a-b = 3, ab = 108$ ?<\/p>\n

a)\u00a0205<\/p>\n

b)\u00a0215<\/p>\n

c)\u00a0225<\/p>\n

d)\u00a0235<\/p>\n

Question 18:\u00a0<\/b>If $2 \\times (\\frac{3x}{4} – \\frac{1}{2}) = \\frac{x}{2} – 2$, then find the value $\\frac{1}{x}$ ?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a0-1<\/p>\n

c)\u00a01\/2<\/p>\n

d)\u00a0-1\/2<\/p>\n

Question 19:\u00a0<\/b>If $x+\\frac{1}{x} = 2$ then find $x^8+\\frac{1}{x^8}$?<\/p>\n

a)\u00a08<\/p>\n

b)\u00a04<\/p>\n

c)\u00a02<\/p>\n

d)\u00a016<\/p>\n

Question 20:\u00a0<\/b>Find the value of $a^3+b^3$, if $a+b = 13, ab = 40$ ?<\/p>\n

a)\u00a0627<\/p>\n

b)\u00a0637<\/p>\n

c)\u00a0647<\/p>\n

d)\u00a0657<\/p>\n

Daily Free Online Tests for RRB Exams<\/a><\/p>\n

Download RRB GK Material PDF<\/a><\/p>\n

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Question 21:\u00a0<\/b>If \u221ax, \u221ay are the quadratic surds and if a+\u221ax = \u221ay , then ?<\/p>\n

a)\u00a0a = 1<\/p>\n

b)\u00a0x = 0<\/p>\n

c)\u00a0y = 0<\/p>\n

d)\u00a0x = y<\/p>\n

Question 22:\u00a0<\/b>Find the value of $3^3+4^3+5^3+…..+10^3$ ?<\/p>\n

a)\u00a03015<\/p>\n

b)\u00a03020<\/p>\n

c)\u00a03025<\/p>\n

d)\u00a03016<\/p>\n

Question 23:\u00a0<\/b>If p, q are the sum and product of the roots of $3x^3-4x^2+5x-6=0$, then find p\/q ?<\/p>\n

a)\u00a03<\/p>\n

b)\u00a01\/3<\/p>\n

c)\u00a02\/3<\/p>\n

d)\u00a03\/2<\/p>\n

Question 24:\u00a0<\/b>If p , q are the roots of the equation $3x^2-4x-4 = 0$, then which of of the following is true ?<\/p>\n

a)\u00a0p, q are not equal and greater than 0.<\/p>\n

b)\u00a0p, q are imaginary numbers<\/p>\n

c)\u00a0p = q<\/p>\n

d)\u00a0p, q are real numbers and unequal<\/p>\n

Question 25:\u00a0<\/b>Find the value of x if 9(8x\/7 + 6\/5) – 4x\/3 = 2<\/p>\n

a)\u00a0235\/231<\/p>\n

b)\u00a0231\/235<\/p>\n

c)\u00a0-231\/235<\/p>\n

d)\u00a0-235\/231<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n

\"RRB<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the number be x<\/p>\n

$x+5(1\/x) = 14\/3$<\/p>\n

$x^2+5 = 14x\/3$<\/p>\n

$3x^2+15 = 14x$<\/p>\n

$3x^2-14x+15 = 0$<\/p>\n

$3x^2-9x-5x+15 = 0$<\/p>\n

$(3x-5)(x-3) = 0$<\/p>\n

$x = 5\/3$ or $x = 3$<\/p>\n

So the answer is option D.<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$(a+b)^2 = a^2+b^2+2ab$<\/p>\n

$(36)^2 = 720+2ab$<\/p>\n

$1296 = 720+2ab$<\/p>\n

$1296 – 720 = 2ab$<\/p>\n

$576 = 2ab$<\/p>\n

$288 = ab$<\/p>\n

So the answer is option A.<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

5(4x-3\/2) + 2x = 4-3x\/2<\/p>\n

20x – 15\/2 + 2x = 4-3x\/2<\/p>\n

22x + 3x\/2 = 4 + 15\/2<\/p>\n

47x\/2 = 23\/2<\/p>\n

x = 23\/47<\/p>\n

So the answer is option A.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$10^3+9^3+…..+3^3=3^3+5^3+…..10^3=(1^3+2^3+….+10^3)-(1^3+2^3)=(\\frac{10^2(11)^2}{4})-(1+8)$
\n=> $3025 – 9 = 3016$<\/p>\n

So the answer is option D.<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$p$ = sum of roots = $\\frac{-b}{a} = \\frac{4}{3}$<\/p>\n

$q$ = product of roots = $\\frac{-d}{a} = \\frac{6}{3}$ = 2<\/p>\n

$\\frac{q}{p} = \\frac{2}{(\\frac{4}{3})} = \\frac{3}{2}$<\/p>\n

So the answer is option D.<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

If\u00a0$x+\\frac{1}{x} = 2$ then\u00a0$x^{2^n}+\\frac{1}{x^{2^n}} = 2$<\/p>\n

put n = 5,\u00a0$x^{32}+\\frac{1}{x^{32}} = 2$<\/p>\n

So the answer is option A.<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

2[3x – 4\/5] + 6x\/7 = 8<\/p>\n

6x – 8\/5 +6x\/7 = 8<\/p>\n

48x\/7 = 8+8\/5<\/p>\n

48x\/7 = 48\/5<\/p>\n

x = 7\/5<\/p>\n

So the answer is option D.<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$p$ = Sum of roots = $\\frac{3}{4}$ ===> $p^2 = 9\/16$<\/p>\n

$q$ = product of roots = $\\frac{1}{4}$ ===> $q^2$ = $\\frac{1}{6}$<\/p>\n

$\\frac{p^2}{q^2}$ = $\\frac{9}{1}$<\/p>\n

So the answer is option B.<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$x+4\/x = 4$<\/p>\n

$x^2+4 = 4x$<\/p>\n

$x^2-4x+4 = 0$<\/p>\n

$(x-2)^2 = 0$<\/p>\n

$x = 2$<\/p>\n

So the answer is option B.<\/p>\n

\"RRB<\/a><\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$(a-b)^2 = (a+b)^2 – 4ab$<\/p>\n

$(a-b)^2 = (23)^2 – 4(132)$<\/p>\n

$(a-b)^2 = 529 – 528$<\/p>\n

$(a-b)^2 = 1$<\/p>\n

$a-b = +1 or -1$<\/p>\n

So the answer is option D.<\/p>\n

11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given $a+b+c = 0$, then<\/p>\n

$(a+b+c)^2 = 0$<\/p>\n

$a^2+b^2+c^2+2ab+2bc+2ca = 0$<\/p>\n

$a^2+b^2+c^2 = -2(ab+bc+ca)$<\/p>\n

$\\frac{a^2+b^2+c^2}{ab+bc+ca} = -2$<\/p>\n

So the answer is option C.<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

4[$\\frac{x}{3}$ – $\\frac{3}{8}$] + $\\frac{x}{6}$ = $\\frac{x}{3}$ –\u00a0$\\frac{1}{2}$<\/p>\n

$\\frac{4x}{3}$ – $\\frac{3}{2}$ + $\\frac{x}{6}$ = $\\frac{x}{3}$ – $\\frac{1}{2}$<\/p>\n

x + $\\frac{x}{6}$ = 1<\/p>\n

$\\frac{7x}{6}$ = 1<\/p>\n

x = $\\frac{6}{7}$<\/p>\n

So the answer is option A.<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$x^2+\\frac{1}{x^2} = 11$<\/p>\n

Squaring on both sides<\/p>\n

$x^4+\\frac{1}{x^4}+2 = 121$<\/p>\n

$x^4+\\frac{1}{x^4} = 121-2 = 119$<\/p>\n

So the answer is option B.<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

WKT, sum of 1st n natural numbers = $\\frac{n(n+1)}{2}$<\/p>\n

$7+8+9+10+……+50 = (1+2+3+…..+50)-(1+2+3+….+6)$<\/p>\n

This equals $\\frac{(50)(51)}{2} – \\frac{(6)(7)}{2} = 1275 – 21 = 1254$<\/p>\n

So the answer is option B.<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$a^3-b^3 = (a-b)^3+3ab(a-b) = 1^3+3(12)(1) = 1+36 = 37$<\/p>\n

So the answer is option B.<\/p>\n

16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

p = sum of roots = -b\/a = 4\/3<\/p>\n

q = product of roots = -d\/a = 6\/3 = 2<\/p>\n

pq = (4\/3)(2) = 8\/3<\/p>\n

So the answer is option B.<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$a^2+b^2 = (a-b)^2+2ab = 3^2+2(108) = 9+216 = 225$<\/p>\n

So the answer is option C.<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

2[3x\/4 – 1\/2] = x\/2 – 2<\/p>\n

3x\/2 – 1 = x\/2 – 2<\/p>\n

2x\/2 = -1<\/p>\n

x = -1<\/p>\n

So the answer is option B.<\/p>\n

19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$x+\\frac{1}{x} = 2$<\/p>\n

Squaring on both sides<\/p>\n

$(x+\\frac{1}{x})^2 = 4$<\/p>\n

$x^2+\\frac{1}{x^2}+2 = 4$<\/p>\n

$x^2+\\frac{1}{x^2} = 2$<\/p>\n

Squaring on both sides<\/p>\n

$(x^2+\\frac{1}{x^2})^2 = 4$<\/p>\n

$x^4+\\frac{1}{x^4}+2 = 4$<\/p>\n

$x^4+\\frac{1}{x^4} = 2$<\/p>\n

Squaring on both sides<\/p>\n

$(x^4+\\frac{1}{x^4})^2 = 4$<\/p>\n

$x^8+\\frac{1}{x^8}+2 = 4$<\/p>\n

$x^8+\\frac{1}{x^8} = 2$<\/p>\n

So the answer is option C.<\/p>\n

20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$a^3+b^3 = (a+b)^3-3ab(a+b) = 13^3-3(40)(13) = 2197 – 1560 = 637$<\/p>\n

So the answer is option B.<\/p>\n

21)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

a+\u221ax = \u221ay+0<\/p>\n

here\u00a0\u221ax, \u221ay are the quadratic surds ( $\\because$ quadratic surd is the square root of an irrational number, example $\\sqrt2,\\sqrt3$etc.)<\/p>\n

so a = 0,\u00a0\u221ax = \u221ay\u00a0 => x = y<\/p>\n

So the answer is option D.<\/p>\n

22)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$3^3+4^3+5^3+…..+10^3 = (1^3+2^3+…..+10^3)-(1^3+2^3) = (\\frac{10^2(11)^2}{4}) – (1+8) = 3025 – 9 = 3016$<\/p>\n

So the answer is option D.<\/p>\n

23)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Sum of roots = p = -b\/a = 4\/3<\/p>\n

Product of roots = -d\/a = 6\/3\u00a0 = 2<\/p>\n

p\/q = (4\/3)\/2 = 2\/3<\/p>\n

So the answer is option C.<\/p>\n

\"RRB<\/a><\/p>\n

24)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Discriminant = $b^2-4ac = (-4)^2-4(3)(-4) = 16+48 = 64 > 0$<\/p>\n

So roots are real and unequal.<\/p>\n

The product of p and q is $-4\/3$, hence one of them is greater than 0 and the other is less than 0.<\/p>\n

So the answer is option D.<\/p>\n

25)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

9[8x\/7 + 6\/5 ] – 4x\/3 = 2<\/p>\n

72x\/7 + 54\/5 -4x\/3 = 2<\/p>\n

72x\/7 – 4x\/3 = 2-54\/5<\/p>\n

216x\/21 – 28x\/21 = -44\/5<\/p>\n

188x\/21 = -44\/5<\/p>\n

47x\/21 = -11\/5<\/p>\n

x = -231\/235<\/p>\n

So the answer is option C.<\/p>\n

Free RRB Online Coaching<\/a><\/p>\n

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We hope this Algebra Questions for RRB JE Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Algebra Questions For RRB JE PDF Download RRB JE Algebra Questions and Answers PDF. Top 25 RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam Question 1:\u00a0Sum of a natural number and 5 times its reciprocal is 14\/3, then find that number ? a)\u00a06 b)\u00a05 […]<\/p>\n","protected":false},"author":41,"featured_media":26274,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1605],"tags":[489,491,1635,42],"class_list":{"0":"post-26272","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-je","11":"tag-railway-exam","12":"tag-rrb","13":"tag-rrb-je","14":"tag-rrb-mock-test"},"better_featured_image":{"id":26274,"alt_text":"Algebra Questions For RRB JE PDF","caption":"Algebra Questions For RRB JE PDF","description":"Algebra 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