{"id":26264,"date":"2019-03-19T13:30:50","date_gmt":"2019-03-19T08:00:50","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=26264"},"modified":"2019-03-19T13:30:50","modified_gmt":"2019-03-19T08:00:50","slug":"mathematical-opeartions-questions-for-rrb-ntpc-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/mathematical-opeartions-questions-for-rrb-ntpc-pdf\/","title":{"rendered":"Mathematical Opeartions Questions For RRB NTPC PDF"},"content":{"rendered":"

Mathematical Opeartions Questions For RRB <\/span>NTPC PDF<\/span><\/strong><\/span><\/h1>\n

Download RRB NTPC Mathematical Operations\u00a0 Questions and Answers PDF. Top 25 RRB NTPC\u00a0 Maths\u00a0 questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Mathematical Opeartions Questions – RRB NTPC PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>If \u2018+\u2019 means \u2018-\u2019, \u2018-\u2019 means \u2018*\u2019, \u2018*\u2019 means \u2018\/\u2019 and \u2018\/\u2019 means \u2018+\u2019, then what is the value of the following expression?
\n13 – 13 \/ 3 – 63 * 9 + 2 -5<\/p>\n

a)\u00a0170<\/p>\n

b)\u00a0180<\/p>\n

c)\u00a0190<\/p>\n

d)\u00a0200<\/p>\n

Question 2:\u00a0<\/b>If \u2018+\u2019 means \u2018*\u2019, \u2018-\u2019 means \u2018+\u2019, \u2018*\u2019 means \u2018\/\u2019 and \u2018\/\u2019 means \u2018-\u2019, then what is the value of the following expression?
\n119*17 + 6 \/ 16 * 2 + 5<\/p>\n

a)\u00a01<\/p>\n

b)\u00a03<\/p>\n

c)\u00a02<\/p>\n

d)\u00a04<\/p>\n

Question 3:\u00a0<\/b>$\\sqrt{0.07+\\sqrt{0.0967-0.0643}}$ = ?<\/p>\n

a)\u00a00.8<\/p>\n

b)\u00a00.7<\/p>\n

c)\u00a00.6<\/p>\n

d)\u00a00.5<\/p>\n

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Question 4:\u00a0<\/b>Find $x^{2018}$, if $3x-4.5+2.4 = – 2.1$<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a0$7^{2018}$<\/p>\n

d)\u00a0$0.7^{2018}$<\/p>\n

Question 5:\u00a0<\/b>2.1221-3.1331+4.1441 = ?<\/p>\n

a)\u00a09.3993<\/p>\n

b)\u00a03.1331<\/p>\n

c)\u00a06.2662<\/p>\n

d)\u00a0none of these<\/p>\n

Question 6:\u00a0<\/b>$\\frac{5}{10}\\times \\frac{100}{125} \\times \\frac{25}{x} = 1$, find $x$ ?<\/p>\n

a)\u00a020<\/p>\n

b)\u00a015<\/p>\n

c)\u00a05<\/p>\n

d)\u00a010<\/p>\n

Question 7:\u00a0<\/b>$\\sqrt{0.9-\\sqrt{0.0234-0.0153}}$ = ?<\/p>\n

a)\u00a00.9<\/p>\n

b)\u00a00.99<\/p>\n

c)\u00a00.999<\/p>\n

d)\u00a09.0<\/p>\n

Question 8:\u00a0<\/b>$\\frac{3}{4}\\times \\frac{16}{27} \\div \\frac{2}{3} = ?$<\/p>\n

a)\u00a02\/3<\/p>\n

b)\u00a03\/2<\/p>\n

c)\u00a09\/4<\/p>\n

d)\u00a04\/9<\/p>\n

Question 9:\u00a0<\/b>0.1123-0.0012+1.0032 – 0.101 = ?<\/p>\n

a)\u00a01.0033<\/p>\n

b)\u00a01.1333<\/p>\n

c)\u00a01.0133<\/p>\n

d)\u00a01.1033<\/p>\n

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Question 10:\u00a0<\/b>Find x, if 4x-0.3+0.22 = 2 ?<\/p>\n

a)\u00a05.002<\/p>\n

b)\u00a05.200<\/p>\n

c)\u00a05.020<\/p>\n

d)\u00a00.520<\/p>\n

Question 11:\u00a0<\/b>$15\\div 3 + 2 \\times 4 – 2 = x + 1$, find $x$ ?<\/p>\n

a)\u00a09<\/p>\n

b)\u00a010<\/p>\n

c)\u00a011<\/p>\n

d)\u00a012<\/p>\n

Question 12:\u00a0<\/b>$\\frac{6}{8}\\times \\frac{16}{18} \\times \\frac{3}{4} \\times X = \\frac{4}{7}$, find $1\/X$ ?<\/p>\n

a)\u00a04\/7<\/p>\n

b)\u00a08\/7<\/p>\n

c)\u00a07\/8<\/p>\n

d)\u00a07\/4<\/p>\n

Question 13:\u00a0<\/b>576.78+456.87-x = 658.65, Find x ?<\/p>\n

a)\u00a0375<\/p>\n

b)\u00a0376<\/p>\n

c)\u00a0373<\/p>\n

d)\u00a0374<\/p>\n

Question 14:\u00a0<\/b>Find $((4096)^{1\/3})^{1\/2}=?$<\/p>\n

a)\u00a02<\/p>\n

b)\u00a03<\/p>\n

c)\u00a04<\/p>\n

d)\u00a05<\/p>\n

Question 15:\u00a0<\/b>3234 + 5678 – 11223 + 4456 = ?<\/p>\n

a)\u00a04585<\/p>\n

b)\u00a03545<\/p>\n

c)\u00a05645<\/p>\n

d)\u00a02145<\/p>\n

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Question 16:\u00a0<\/b>Find $[((16)^{\\frac{1}{4}})^{\\frac{2}{3}}]^{\\frac{6}{2}}$ = ?<\/p>\n

a)\u00a0256<\/p>\n

b)\u00a064<\/p>\n

c)\u00a016<\/p>\n

d)\u00a04<\/p>\n

Question 17:\u00a0<\/b>123.45+45.678-3.1345+13.234 = ?<\/p>\n

a)\u00a0146.3455<\/p>\n

b)\u00a0169.2275<\/p>\n

c)\u00a0156.3455<\/p>\n

d)\u00a0179.2275<\/p>\n

Question 18:\u00a0<\/b>45.23+23.17-12.46+34.67 = ?<\/p>\n

a)\u00a047.86<\/p>\n

b)\u00a056.64<\/p>\n

c)\u00a067.57<\/p>\n

d)\u00a090.61<\/p>\n

Question 19:\u00a0<\/b>$95^2-5^2=?$<\/p>\n

a)\u00a08100<\/p>\n

b)\u00a09000<\/p>\n

c)\u00a09025<\/p>\n

d)\u00a09205<\/p>\n

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Question 20:\u00a0<\/b>Which of the following is divisible by 3, 7, 9 and 11 ?<\/p>\n

a)\u00a02645<\/p>\n

b)\u00a04158<\/p>\n

c)\u00a03791<\/p>\n

d)\u00a01188<\/p>\n

Question 21:\u00a0<\/b>3245 – 123 – 456 – 347 + x = 3650 ?<\/p>\n

a)\u00a02134<\/p>\n

b)\u00a01331<\/p>\n

c)\u00a01567<\/p>\n

d)\u00a01467<\/p>\n

Question 22:\u00a0<\/b>$600\\div 12 \\times \\frac{1}{2} \\div 5 = ?$<\/p>\n

a)\u00a04<\/p>\n

b)\u00a05<\/p>\n

c)\u00a06<\/p>\n

d)\u00a08<\/p>\n

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Question 23:\u00a0<\/b>123.45 + 6789.01 – 2345.67 = ?<\/p>\n

a)\u00a04565.79<\/p>\n

b)\u00a04655.79<\/p>\n

c)\u00a04566.79<\/p>\n

d)\u00a04665.79<\/p>\n

Question 24:\u00a0<\/b>4591.15 – 528.116 = x + 456.123. Find x ?<\/p>\n

a)\u00a03660.911<\/p>\n

b)\u00a03666.911<\/p>\n

c)\u00a03006.911<\/p>\n

d)\u00a03606.911<\/p>\n

Question 25:\u00a0<\/b>987.65-456.78-43.321 = ?<\/p>\n

a)\u00a0478.549<\/p>\n

b)\u00a0487.549<\/p>\n

c)\u00a0487.459<\/p>\n

d)\u00a0478.459<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let us replace the symbols with the actual operators.<\/p>\n

13 – 13 \/ 3 – 63 * 9 + 2 -5 = 13 * 13 + 3*63\/9 – 2*5<\/p>\n

Applying BODMAS rule, we get, 169 + 3*7 – 10 = 180
\nTherefore, option B is the right answer.<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let us replace the symbols with the actual operators.<\/p>\n

119*17 + 6 \/ 16 * 2 + 5 = 119\/17 * 6 – 16\/2 *5<\/p>\n

Applying BODMAS rule, we get,<\/p>\n

119\/17 * 6 – 16\/2 *5 = 7*6 – 8*5
\n= 42 – 40
\n= 2<\/p>\n

Therefore, option C is the right answer.<\/p>\n

3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$\\sqrt{0.07+\\sqrt{0.0967-0.0643}}$ =\u00a0$\\sqrt{0.07+\\sqrt{0.0324}}$ =\u00a0$\\sqrt{0.07+0.18}$ =\u00a0$\\sqrt{0.25}$ =\u00a0$0.5$<\/p>\n

So the answer is option D.<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$3x-4.5+2.4 = – 2.1$<\/p>\n

$3x-2.1 = – 2.1$<\/p>\n

$3x = 0$<\/p>\n

$x = 0$<\/p>\n

$x^{2018} = 0$<\/p>\n

So the answer is option A.<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

2.1221-3.1331+4.1441 = -1.0110+4.1441 = 3.1331<\/p>\n

So the answer is option B.<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$\\frac{5}{10}\\times \\frac{100}{125} \\times \\frac{25}{x} = 1$<\/p>\n

$\\frac{10}{25} \\times \\frac{25}{x} = 1$<\/p>\n

$\\frac{10}{x} = 1$<\/p>\n

$x = 10$<\/p>\n

So the answer is option D.<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\sqrt{0.9-\\sqrt{0.0234-0.0153}}$ =\u00a0$\\sqrt{0.9-\\sqrt{0.0081}}$ =\u00a0$\\sqrt{0.9-0.09}$ =\u00a0$\\sqrt{0.81}$ = $0.9$<\/p>\n

So the answer is option A.<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\frac{3}{4}\\times \\frac{16}{27} \\div \\frac{2}{3}$ =\u00a0$\\frac{3}{4}\\times \\frac{16}{27} \\times \\frac{3}{2}$ = $\\frac{4}{9} \\times \\frac{3}{2} = \\frac{2}{3}$<\/p>\n

So the answer is option A.<\/p>\n

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9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

0.1123-0.0012+1.0032 – 0.101 =\u00a0 0.1111 + 0.9022 = 1.0133<\/p>\n

So the answer is option C.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

4x-0.3+0.22 = 2<\/p>\n

4x-0.08 = 2<\/p>\n

4x = 2.08<\/p>\n

x = 0.52<\/p>\n

So the answer is option D.<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$15\\div 3 + 2 \\times 4 – 2 = x + 1$<\/p>\n

$5 +8 – 2 = x + 1$<\/p>\n

$11 = x + 1$<\/p>\n

$x = 10$<\/p>\n

So the answer is option B.<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\frac{6}{8}\\times \\frac{16}{18} \\times \\frac{3}{4} \\times X = \\frac{4}{7}$<\/p>\n

$\\frac{3}{4}\\times \\frac{8}{9} \\times \\frac{3}{4} \\times X = \\frac{4}{7}$<\/p>\n

$\\frac{1}{2} \\times X = \\frac{4}{7}$<\/p>\n

$X = 8\/7$<\/p>\n

$1\/X = 7\/8$<\/p>\n

So the answer is option B.<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

576.78+456.87-x = 658.65<\/p>\n

1033.65 – x = 658.65<\/p>\n

x = 1033.65 – 658.65<\/p>\n

x = 375<\/p>\n

So the answer is option A.<\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$((4096)^{1\/3})^{1\/2} = 16^{1\/2} = 4$<\/p>\n

So the answer is option C.<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

3234 + 5678 – 11223 + 4456 = 2145.<\/p>\n

So the answer is option D.<\/p>\n

16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$[((16)^{\\frac{1}{4}})^{\\frac{2}{3}}]^{\\frac{6}{2}}$ =\u00a0$[16]^{\\frac{1}{4}\\times\\frac{2}{3}\\times\\frac{6}{2}}$ = $[16]^{\\frac{1}{2}}$ = $4$<\/p>\n

So the answer is option D.<\/p>\n

17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

123.45+45.678-3.1345+13.234 = 179.2275<\/p>\n

So the answer is option D.<\/p>\n

18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

45.23+23.17-12.46+34.67 = 90.61<\/p>\n

So the answer is option D.<\/p>\n

19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$95^2-5^2=(95+5)(95-5) = 100*90 = 9000$<\/p>\n

So the answer is option B.<\/p>\n

20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

3*7*9*11 = 2079<\/p>\n

2079*2 = 4158 is divisible by 3, 7, 9, 11<\/p>\n

So the answer is option B.<\/p>\n

21)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

3245 – 123 – 456 – 347 + x = 3650<\/p>\n

2319 + x = 3650<\/p>\n

x = 1331<\/p>\n

So the answer is option B.<\/p>\n

22)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$600\\div 12 \\times \\frac{1}{2} \\div 5 = 50 \\times 1\/10 = 5$<\/p>\n

So the answer is option B.<\/p>\n

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23)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

123.45 + 6789.01 – 2345.67 =\u00a06912.46 – 2345.67 = 4566.79<\/p>\n

So the answer is option C.<\/p>\n

24)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

4591.15 – 528.116 = x + 456.123<\/p>\n

4063.034 = x + 456.123<\/p>\n

4063.034 – 456.123 = x<\/p>\n

3606.911 = x<\/p>\n

So the answer is option D.<\/p>\n

25)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

987.65-456.78-43.321 = 530.87 – 43.321 = 487.549
\nSo the answer is option B.<\/p>\n

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We hope this Mathematical Operations\u00a0 questions for RRB NTPC Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Mathematical Opeartions Questions For RRB NTPC PDF Download RRB NTPC Mathematical Operations\u00a0 Questions and Answers PDF. Top 25 RRB NTPC\u00a0 Maths\u00a0 questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Question 1:\u00a0If \u2018+\u2019 means \u2018-\u2019, \u2018-\u2019 means \u2018*\u2019, \u2018*\u2019 means \u2018\/\u2019 and \u2018\/\u2019 means \u2018+\u2019, then what is […]<\/p>\n","protected":false},"author":41,"featured_media":26266,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603,1601],"tags":[489,491,42,1619],"class_list":{"0":"post-26264","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"category-rrb-ntpc-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-mock-test","15":"tag-rrb-ntpc-2019"},"better_featured_image":{"id":26266,"alt_text":"Mathematical Operations Questions PDF","caption":"Mathematical Operations Questions PDF","description":"Mathematical Operations 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