{"id":26195,"date":"2019-03-18T17:56:13","date_gmt":"2019-03-18T12:26:13","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=26195"},"modified":"2019-03-29T10:09:04","modified_gmt":"2019-03-29T04:39:04","slug":"rrb-ntpc-lcm-hcf-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/rrb-ntpc-lcm-hcf-questions-pdf\/","title":{"rendered":"RRB NTPC LCM & HCF Questions PDF"},"content":{"rendered":"

RRB NTPC LCM & HCF Questions PDF<\/span><\/h1>\n

Download RRB NTPC LCM & HCF Questions and Answers PDF. Top 25 RRB NTPC\u00a0 Maths\u00a0 questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download RRB NTPC LCM & HCF Questions PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>If the LCM and HCF of two numbers are 72 and 12 respectively. Find the second number if one number is 36 ?<\/p>\n

a)\u00a024<\/p>\n

b)\u00a048<\/p>\n

c)\u00a012<\/p>\n

d)\u00a060<\/p>\n

Question 2:\u00a0<\/b>Find the HCF of two numbers if LCM and product of those two numbers are 45 and 675 respectively ?<\/p>\n

a)\u00a025<\/p>\n

b)\u00a020<\/p>\n

c)\u00a015<\/p>\n

d)\u00a035<\/p>\n

Question 3:\u00a0<\/b>Find the LCM and HCF of 196 and 392 ?<\/p>\n

a)\u00a0196 & 392<\/p>\n

b)\u00a0392 & 196<\/p>\n

c)\u00a0392 & 14<\/p>\n

d)\u00a014 & 392<\/p>\n

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Question 4:\u00a0<\/b>Find LCM of 2\/3 , 3\/6, 4\/12 ?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a02<\/p>\n

c)\u00a03<\/p>\n

d)\u00a06<\/p>\n

Question 5:\u00a0<\/b>Two numbers have their HCF as 9 and they are in the ratio 3:4 find their LCM ?<\/p>\n

a)\u00a072<\/p>\n

b)\u00a036<\/p>\n

c)\u00a0108<\/p>\n

d)\u00a090<\/p>\n

Question 6:\u00a0<\/b>Find the LCM of 7\/2, 9\/4 and 5\/3 ?<\/p>\n

a)\u00a0252<\/p>\n

b)\u00a021<\/p>\n

c)\u00a0126<\/p>\n

d)\u00a0315<\/p>\n

Question 7:\u00a0<\/b>What is the difference between the LCM and HCF of 24, 48 ?<\/p>\n

a)\u00a012<\/p>\n

b)\u00a023<\/p>\n

c)\u00a054<\/p>\n

d)\u00a024<\/p>\n

Question 8:\u00a0<\/b>Find the HCF of two numbers whose LCM is 38 and product of those two numbers is 266 ?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a05<\/p>\n

c)\u00a06<\/p>\n

d)\u00a07<\/p>\n

Question 9:\u00a0<\/b>Find LCM of two numbers, whose product is 864 and HCF is 12 ?<\/p>\n

a)\u00a072<\/p>\n

b)\u00a060<\/p>\n

c)\u00a036<\/p>\n

d)\u00a024<\/p>\n

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Question 10:\u00a0<\/b>Find the HCF of 12, 24, 36, 30 ?<\/p>\n

a)\u00a018<\/p>\n

b)\u00a012<\/p>\n

c)\u00a06<\/p>\n

d)\u00a024<\/p>\n

Question 11:\u00a0<\/b>Find the product of LCM and HCF of 48 and 72 ?<\/p>\n

a)\u00a0432<\/p>\n

b)\u00a0864<\/p>\n

c)\u00a01728<\/p>\n

d)\u00a03456<\/p>\n

Question 12:\u00a0<\/b>Find the HCF of 3\/2, 4\/3, 5\/4 ?<\/p>\n

a)\u00a01\/12<\/p>\n

b)\u00a012<\/p>\n

c)\u00a01\/6<\/p>\n

d)\u00a06<\/p>\n

Question 13:\u00a0<\/b>If $x$ is a prime number, what is the LCM of $x^{18}, x^{24}$ and $x^{36}$<\/p>\n

a)\u00a0$x^{72}$<\/p>\n

b)\u00a0$x^{36}$<\/p>\n

c)\u00a0$x^{48}$<\/p>\n

d)\u00a0$x^{96}$<\/p>\n

Question 14:\u00a0<\/b>Find the least common multiple of the numbers 36, 72 and 108.<\/p>\n

a)\u00a0216<\/p>\n

b)\u00a0108<\/p>\n

c)\u00a0186<\/p>\n

d)\u00a0None of the above<\/p>\n

Question 15:\u00a0<\/b>The HCF and LCM of two numbers are 3 and 150. If the sum of the numbers is 81, what is the sum of the reciprocals of the numbers?<\/p>\n

a)\u00a02\/25<\/p>\n

b)\u00a09\/50<\/p>\n

c)\u00a03\/25<\/p>\n

d)\u00a07\/150<\/p>\n

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Question 16:\u00a0<\/b>The LCM of two numbers is 105. The numbers are in the ratio 7:5. What is the sum of the two numbers?<\/p>\n

a)\u00a036<\/p>\n

b)\u00a021<\/p>\n

c)\u00a015<\/p>\n

d)\u00a045<\/p>\n

Question 17:\u00a0<\/b>What is the HCF of the fractions: \u00bd, 5\/7, 8\/11, \u00be ?<\/p>\n

a)\u00a02\/121<\/p>\n

b)\u00a01\/154<\/p>\n

c)\u00a01\/121<\/p>\n

d)\u00a01\/308<\/p>\n

Question 18:\u00a0<\/b>The least number n, where n>4, which when divided by 9, 11 and 12 leaves a remainder 4 is<\/p>\n

a)\u00a0396<\/p>\n

b)\u00a0400<\/p>\n

c)\u00a0796<\/p>\n

d)\u00a0None of the above<\/p>\n

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Question 19:\u00a0<\/b>The product of HCF and LCM of two numbers is 525. If one of the numbers is 21, what is the other number?<\/p>\n

a)\u00a025<\/p>\n

b)\u00a030<\/p>\n

c)\u00a020<\/p>\n

d)\u00a0Cannot be determined<\/p>\n

Question 20:\u00a0<\/b>Three numbers are in the ratio 1 : 2 : 5. Their LCM is 1600. What is the HCF of the three numbers?<\/p>\n

a)\u00a0400<\/p>\n

b)\u00a0800<\/p>\n

c)\u00a0320<\/p>\n

d)\u00a0160<\/p>\n

Question 21:\u00a0<\/b>The greatest 3 digit number that is divisible by 20, 30, 50 and 60 is<\/p>\n

a)\u00a0990<\/p>\n

b)\u00a0900<\/p>\n

c)\u00a0800<\/p>\n

d)\u00a0750<\/p>\n

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Question 22:\u00a0<\/b>The HCF of two numbers is 13 and the other two factors of their LCM are 5 and 9. What is the larger of the two numbers?<\/p>\n

a)\u00a045<\/p>\n

b)\u00a065<\/p>\n

c)\u00a0117<\/p>\n

d)\u00a0585<\/p>\n

Question 23:\u00a0<\/b>HCF and LCM of two numbers are 11 and 825 respectively. If one number is 275 find the other number.<\/p>\n

a)\u00a053<\/p>\n

b)\u00a045<\/p>\n

c)\u00a033<\/p>\n

d)\u00a043<\/p>\n

Question 24:\u00a0<\/b>Product of two coprime numbers is 117. Then their LCM is<\/p>\n

a)\u00a09<\/p>\n

b)\u00a013<\/p>\n

c)\u00a039<\/p>\n

d)\u00a0117<\/p>\n

Question 25:\u00a0<\/b>Two numbers are in the ratio 3:4. Their L.C.M. is 84. The greater number is<\/p>\n

a)\u00a021<\/p>\n

b)\u00a024<\/p>\n

c)\u00a028<\/p>\n

d)\u00a084<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let x be the second number,<\/p>\n

LCM*HCF = Product of two numbers<\/p>\n

72*12 = 36*x<\/p>\n

x = 24<\/p>\n

So the answer is option A.<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

LCM*HCF = 675<\/p>\n

(45)*HCF = 675<\/p>\n

HCF = 675\/45 = 15<\/p>\n

So the answer is option C.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Here 392 = 2*196, Hence LCM is 392 and HCF is 196<\/p>\n

So the answer is option B.<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

2\/3 , 3\/6, 4\/12 = 2\/3 , 1\/2 , 1\/3<\/p>\n

LCM of fractions = (LCM of numerators)\/(HCF of denominators) = (LCM of 2, 1, 1)\/(HCF of 3,2,3) = 2\/1 = 2<\/p>\n

So the answer is option B.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Two numbers have their HCF as 9 and they are in the ratio 3:4<\/p>\n

Those numbers are 3*9=27 and 4*9=36<\/p>\n

LCM of 27 and 36 is 108.<\/p>\n

So the answer is option C.<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

LCM of fractions = LCM of numerators\/HCF of denominators<\/p>\n

LCM of 7\/2, 9\/4 and 5\/3 = (LCM of 7,9,5)\/(HCF of 2,4,3) = 315\/1 = 315<\/p>\n

So the answer is option A.<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

LCM of 24 and 48 = 48<\/p>\n

HCF of 24 and 48 = 24<\/p>\n

Difference = 24<\/p>\n

So the answer is option D.<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

LCM*HCF = product of two numbers<\/p>\n

(38)*HCF = 266<\/p>\n

HCF = 7<\/p>\n

So the answer is option D.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

LCM*HCF = Product of numbers<\/p>\n

LCM*12 = 864<\/p>\n

LCM = 72<\/p>\n

So the answer is option A.<\/p>\n

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10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

12 = 2*2*3<\/p>\n

24 = 2*2*2*3<\/p>\n

36 = 2*2*3*3<\/p>\n

30 = 2*3*5<\/p>\n

HCF = product of common factors = 2*3 = 6<\/p>\n

So the answer is option C.<\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Product of LCM & HCF of two numbers = product of those two numbers = 48*72 = 3456<\/p>\n

So the answer is option D.<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

HCF of fractions = (HCF of numerators)\/(LCM of denominators) = (HCF of 3,4,5)\/(LCM of 2,3,4) = 1\/12<\/p>\n

So the answer is option A.<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

It is important to note that $x{36} = x^{24} \\times x^{12}$.
\nTherefore, $x^{36}$ divides $x^{24}$
\nSimilarly, $x^{36}$ divides $x^{18}$
\nHence, $x^{36}$ divides both $x^{24}$ and $x^{18}$
\nTherefore, the LCM of $x^{18}, x^{24}$ and $x^{36}$ is $x^{36}$<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$36 = 2^2 * 3^2$
\n$72 = 2^3 * 3^2$
\n$108 = 2^2 * 3^3$
\nSo, the LCM of the three numbers is $2^3 * 3^3$ = 8 * 27 = 216<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the numbers be x and 81-x.
\nLCM * HCF = 450 = x*(81-x)
\n=> $x^2 – 81x + 450 = 0$
\nSo, x = 6 or 75<\/p>\n

So, the sum of the reciprocals of the two numbers is 1\/6 + 1\/75 = (25+2)\/150 = 27\/150 = 9\/50<\/p>\n

16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the two numbers be 7k and 5k.
\nLCM of 7 and 5 is 35. So, the LCM of the two numbers is 35k.
\n35k = 105 => k = 3
\nSo, the two numbers are 7*3 = 21 and 5*3 = 15
\nThe sum of the two numbers is 21+15 = 36<\/p>\n

17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The HCF of fractions is equal to HCF of numerators\/LCM of denominators.
\nHCF of numerators = HCF of 1, 5, 8 and 3 = 1
\nLCM of numerators = LCM of 2, 7, 11 and 4 = 7*11*4 = 308
\nSo, the HCF of the fractions is 1\/308<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$9 = 3^2$
\n$12 = 3 * 2^2$
\nSo, the LCM of 9, 11 and 12 is $3^2 * 2^2 * 11$ = 9 * 4 * 11 = 396
\nSo, the required number should be of the form 396k + 4
\nFor k = 1, the number becomes 396 + 4 = 400<\/p>\n

19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

From the properties of LCM and HCF, we have:
\nProduct of the two numbers = Product of HCF and LCM
\n21 * x = 525
\nSo, the other number is 525\/21 = 25<\/p>\n

20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the numbers be k, 2k and 5k. The LCM of 1, 2 and 5 is 10. So, the LCM of k, 2k and 5k is 10k.
\n10k = 1600 => k = 160
\nSo, the three numbers are 160, 320 and 800. The HCF of the three numbers is 160.<\/p>\n

21)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The LCM of 20, 30 and 60 is 60.
\nThe LCM of 50 and 60 is 300.
\nSo, the number should be of the form 300k.
\nFor k = 3, the number is 300*3 = 900. For k > 3, the number will not be a 3-digit number. So, 900 is the answer.<\/p>\n

22)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the two numbers be a*h and b*h, where \u2018h\u2019 is the HCF of the two numbers. The LCM of the two numbers is a*b*h.
\nSince the other two factors of the LCM are 5 and 9, the two numbers are 5*13 = 65 and 9*13 = 117
\nSo, the larger of the two numbers is 117<\/p>\n

23)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the number = $x$<\/p>\n

HCF = 11 and LCM = 825<\/p>\n

Product of HCF and LCM = Product of the two numbers<\/p>\n

=> $x \\times 275 = 11 \\times 825$<\/p>\n

=> $x = \\frac{11 \\times 825}{275}$<\/p>\n

=> $x = \\frac{825}{25} = 33$<\/p>\n

=> Ans – (C)<\/p>\n

 <\/p>\n

24)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the two numbers be a,b.
\nHence a * b = L.C.M(a,b) * G.C.D(a,b)
\nIt is given that a,b are co-primes, implies G.C.D(a,b) = 1
\nHence from the above equation we get L.C.M(a,b) = a*b = 117<\/p>\n

25)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the numbers be 3x, 4x
\nLCM of 3x and 4x is = 12x
\nSo the number 84 is divisible by 12
\n$\\frac{84}{12}$ = 7
\nThe numbers are 7×3 = 21 , 7x 4 = 28
\nThe greatest number is 28<\/p>\n

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We hope this LCM & HCF\u00a0 questions for RRB NTPC Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

RRB NTPC LCM & HCF Questions PDF Download RRB NTPC LCM & HCF Questions and Answers PDF. Top 25 RRB NTPC\u00a0 Maths\u00a0 questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Question 1:\u00a0If the LCM and HCF of two numbers are 72 and 12 respectively. Find the second […]<\/p>\n","protected":false},"author":41,"featured_media":26196,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603,1601],"tags":[489,491,42,1619],"class_list":{"0":"post-26195","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"category-rrb-ntpc-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-mock-test","15":"tag-rrb-ntpc-2019"},"better_featured_image":{"id":26196,"alt_text":"RRB NTPC LCM & HCF Questions Pdf","caption":"RRB NTPC LCM & HCF Questions Pdf","description":"RRB NTPC LCM & HCF Questions 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