20 RRB NTPC Mocks – Just Rs. 149<\/a><\/p>\n RRB NTPC Free Mock Test<\/a><\/p>\n Question 1:\u00a0<\/b>The sum of the ages of Ravi and his younger brother Chinna is 30. The difference in their ages is 14. What is the ratio of the age of Ravi to the age of Chinna?<\/p>\n a)\u00a011:4<\/p>\n b)\u00a04:11<\/p>\n c)\u00a015:7<\/p>\n d)\u00a07:15<\/p>\n Question 2:\u00a0<\/b>The ratio of the ages of Karthik and his son is 5:1. The present age of his son is 6 years. After how many years will the ratio of their ages be 7:3?<\/p>\n a)\u00a011<\/p>\n b)\u00a012<\/p>\n c)\u00a013<\/p>\n d)\u00a014<\/p>\n Question 3:\u00a0<\/b>Ravi and Rahul invested 12000 and 20000 in a business. Find the ratio of their profits after 19 years ?<\/p>\n a)\u00a03:4<\/p>\n b)\u00a03:5<\/p>\n c)\u00a04:5<\/p>\n d)\u00a01:2<\/p>\n FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n <\/p>\n Question 4:\u00a0<\/b>A, B, C started a business with capital ratio 4:2:3. Their period of investiments is in the ratio 3:5:4. Find their profit ratio ?<\/p>\n a)\u00a01:5:1<\/p>\n b)\u00a06:5:6<\/p>\n c)\u00a02:3:2<\/p>\n d)\u00a08:5:6<\/p>\n Question 5:\u00a0<\/b>The ratio of the present ages of Ravi’s brother and his mother is 1:2. The sum of the ages of all three is 83. It is known known that Ravi is 3 years elder than his brother. How old will Ravi be 5 years from now?<\/p>\n a)\u00a023<\/p>\n b)\u00a025<\/p>\n c)\u00a028<\/p>\n d)\u00a030<\/p>\n Question 6:\u00a0<\/b>Sumeeth and Pranav started a business with initial investments of 3000\/- and 5000\/- respectively. After 8 months, Sumeeth left the business. The business made a profit of 490\/- at the end of the year. What is the share of Pranav?<\/p>\n a)\u00a070<\/p>\n b)\u00a0350<\/p>\n c)\u00a0140<\/p>\n d)\u00a0210<\/p>\n Question 7:\u00a0<\/b>6 years earlier, the ages of Suresh & Ramesh are in the ratio 5:6. Suresh will be 45 years old nine years from now. What is the age of Ramesh 15 years from now?<\/p>\n a)\u00a048<\/p>\n b)\u00a051<\/p>\n c)\u00a054<\/p>\n d)\u00a057<\/p>\n Question 8:\u00a0<\/b>Age of Ravi is $\\frac{4}{5}$th of the age of his brother. If the sum of their ages is 72, find the age of Ravi\u2019s brother 9 years earlier?<\/p>\n a)\u00a033<\/p>\n b)\u00a032<\/p>\n c)\u00a031<\/p>\n d)\u00a030<\/p>\n Question 9:\u00a0<\/b>Sampath and Vishal started a business with initial investments of 20000\/- and 45000\/- respectively. After 6 months, Sampath invested another 30000\/-. If the year end profit is Rs. 32000, what is the share of Vishal?<\/p>\n a)\u00a014000<\/p>\n b)\u00a018000<\/p>\n c)\u00a020000<\/p>\n d)\u00a022000<\/p>\n RRB NTPC Previous Papers Download PDF<\/a><\/p>\n RRB Group-D Previous Papers PDF<\/a><\/p>\n <\/p>\n <\/p>\n Question 10:\u00a0<\/b>The ages of 5 persons are in AP. The youngest person was 31 years old while the oldest person was 39 years old. What is the average age of the 5 persons?<\/p>\n a)\u00a033<\/p>\n b)\u00a034<\/p>\n c)\u00a035<\/p>\n d)\u00a036<\/p>\n Question 11:\u00a0<\/b>Three persons, A,B and C, started a business and earned a profit of 42000\/-. If the investments of A, B and C are are in the ratio 3:5:6, find the profit share of B ?<\/p>\n a)\u00a012000<\/p>\n b)\u00a015000<\/p>\n c)\u00a018000<\/p>\n d)\u00a021000<\/p>\n Question 12:\u00a0<\/b>Suresh appeared for final exams of his class X. He scored an average of 50 marks in English, Hindi, Maths and Computers. His average score in Maths, Social Science, Science and Physical education was 70. If his average score in all 7 subjects was 58 then find his score in Maths.<\/p>\n a)\u00a068<\/p>\n b)\u00a074<\/p>\n c)\u00a072<\/p>\n d)\u00a0Cannot be determined<\/p>\n Question 13:\u00a0<\/b>An alloy contains gold and silver in the ratio 3:4. Another alloy contains silver and tin in the ratio 5:4. In what ratio should the two alloys be mixed so that the ratio of gold and tin in the new mixture is 4:7?<\/p>\n a)\u00a03:4<\/p>\n b)\u00a017:31<\/p>\n c)\u00a016:27<\/p>\n d)\u00a01:2<\/p>\n Question 14:\u00a0<\/b>Two numbers are in the ratio 7 : 9. If 12 is subtracted from each, the new numbers we get are in the ratio 25 : 33. What is the difference of the 2 numbers?<\/p>\n a)\u00a056<\/p>\n b)\u00a032<\/p>\n c)\u00a044<\/p>\n d)\u00a038<\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n Download General Science Notes PDF<\/a><\/p>\n Question 15:\u00a0<\/b>A milk mixture of 120 litres contain milk and water 5 : 3. If we want the ratio of milk to water to be 3 : 5, what additional quantity of water must be added?<\/p>\n a)\u00a095 litres<\/p>\n b)\u00a080 litres<\/p>\n c)\u00a065 litres<\/p>\n d)\u00a070 litres<\/p>\n Question 16:\u00a0<\/b>Eight years ago the age of the father was three times the age of the son. 4 years hence, their ages will be in the ratio 15:7. Find the present age of the father.<\/p>\n a)\u00a062<\/p>\n b)\u00a044<\/p>\n c)\u00a056<\/p>\n d)\u00a060<\/p>\n Question 17:\u00a0<\/b>A and B start a business by investing amounts in the ratio 2:3. After 6 months, A invests some more amount. By the end of the year, A and B split the profit equally. What is the ratio of the amount invested by A at the beginning of the year to the amount invested after 6 months?<\/p>\n a)\u00a02:1<\/p>\n b)\u00a01:2<\/p>\n c)\u00a01:1<\/p>\n d)\u00a02:3<\/p>\n Question 18:\u00a0<\/b>A shopkeeper has two varieties of rice. The cost price of the two varieties is Rs 40 per kg and Rs 54 per kg. The shopkeeper mixes the two varieties in a certain ratio and then sells the mixture at Rs 63 per kg. If the profit made by the shopkeeper is 40 % then find the ratio in which he mixed the two varieties of rice?<\/p>\n a)\u00a04:7<\/p>\n b)\u00a09:5<\/p>\n c)\u00a03:7<\/p>\n d)\u00a03:5<\/p>\n RRB NTPC Free Mock Test<\/a><\/p>\n Question 19:\u00a0<\/b>A mixture contains milk and water in the ratio 3:4. How much pure milk (as compared to pure milk currently in the mixture) should be added to the mixture so that the ratio of milk and water becomes 15:8?<\/p>\n a)\u00a0100 %<\/p>\n b)\u00a0150 %<\/p>\n c)\u00a0125 %<\/p>\n d)\u00a080 %<\/p>\n Question 20:\u00a0<\/b>A shopkeeper has 2 varieties of rice. Rice A costs Rs.12\/kg and Rice B costs Rs.15\/Kg. The shopkeeper mixes the 2 varieties of rice in some ratio and sells the mixture at the cost price of rice B. He realizes a profit percentage of 12.5% by doing so. In what ratio did he mix the 2 rice varieties?<\/p>\n a)\u00a02:3<\/p>\n b)\u00a03:2<\/p>\n c)\u00a05:4<\/p>\n d)\u00a01:1<\/p>\n Question 21:\u00a0<\/b>In a map of scale 1:20,000, what will be the length of the border between Telangana and Andhra Pradesh, if the actual border in 2,250 kms?<\/p>\n a)\u00a011.25 cms<\/p>\n b)\u00a0112.50 cms<\/p>\n c)\u00a01125 cms<\/p>\n d)\u00a011250 cms<\/p>\n Daily Free RRB Online Tests for RRB Exams<\/a><\/p>\n 100+ Free Online G.K Tests<\/a><\/p>\n Question 22:\u00a0<\/b>A student mixes 3 litres of pure river water with 4 litres of seawater. Seawater contains salt. If he able to retrieve 0.5 gms of salt per gram of the mixture, what is the amount of salt in sea water in grams per litre? The density of the final mixutre is .75 grams\/ litre.<\/p>\n a)\u00a00.33 grams\/ litre<\/p>\n b)\u00a00.44 grams\/ litre<\/p>\n c)\u00a00.55 grams\/ litre<\/p>\n d)\u00a00.66 grams\/ litre<\/p>\n Question 23:\u00a0<\/b>The tax on income in India is 30%. A corrupt Income Tax officer reported 24 crores to be the unaccounted income of an accused when the actual value was 30 crores. He gets the accused to pay the relevant tax and siphons off the 6 crores. Compared to the tax that was supposed to be paid, what is the percentage loss to the Indian Revenue Department?<\/p>\n a)\u00a020%<\/p>\n b)\u00a030%<\/p>\n c)\u00a040%<\/p>\n d)\u00a050%<\/p>\n Question 24:\u00a0<\/b>Abdul and Waqar, together drink 2 litres of coconut water a day. If the quantity of coconut water consumed by Abdul is 30% more than Waqar, what is the difference between their water consumption quantity?<\/p>\n a)\u00a00.13 litres<\/p>\n b)\u00a00.26 litres<\/p>\n c)\u00a00.39 litres<\/p>\n d)\u00a00.52 litres<\/p>\n Question 25:\u00a0<\/b>Rahul deposits Rs. 1000 in a bank account and gets compound interest of 10% per annum exactly at the end of the year. He lets the deposit stay for exactly 3 years. For accounting purposes, the bank manager takes note of the daily balance on his account, every day for the three years. If Rahul doesn\u2019t withdraw or deposit any amount in the meanwhile, what is his average daily balance? Assume none of the three years are leap years.<\/p>\n a)\u00a0Rs. 1100<\/p>\n b)\u00a0Rs. 1103<\/p>\n c)\u00a0Rs. 1106<\/p>\n d)\u00a0Rs. 1109<\/p>\n Free RRB Daily Practice Set<\/a><\/p>\n <\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let x, y are the ages of Ravi and chinna<\/p>\n x+y = 30 —-(1)<\/p>\n x-y = 14 —–(2)<\/p>\n add (1) & (2)<\/p>\n x+y+x-y = 30+14<\/p>\n 2x = 44<\/p>\n x = 22 then y = 8<\/p>\n Ratio = x\/y = 22\/8 = 11\/4 = 11:4<\/p>\n So the answer is option A.<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let present age of karthik = 5k and his son = 1k<\/p>\n Given 1k = 6 ==>5k = 30<\/p>\n Let x be the years after which their ages ratio becomes 7:3,<\/p>\n $\\frac{30+x}{6+x} = \\frac{7}{3}$<\/p>\n $90+3x = 42+7x$<\/p>\n $48 = 4x$<\/p>\n $x = 12$<\/p>\n So the answer is option B.<\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Ratio of profits = (12000*19):(20000*19) = 3:5<\/p>\n So the answer is option B.<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Ratio of their shares = (4*3):(2*5):(3*4) = 12:10:12 = 6:5:6<\/p>\n So the answer is option B.<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the age of Ravi’s brother = x<\/p>\n His mother age = 2x<\/p>\n Ravi’s age = x+3<\/p>\n Sum of all 3 ages = 83<\/p>\n x+2x+x+3 = 83<\/p>\n 4x = 80<\/p>\n x = 20<\/p>\n Age of Ravi = x+3 = 23<\/p>\n Age of Ravi after 5 years = 23+5 = 28<\/p>\n So the answer is option C.<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Sumeeth : pranav = (3000*8):(5000*120) = 24 : 60 = 2 : 5<\/p>\n Share of pranav = $\\frac{5}{2+5}\\times 490 = \\frac{5}{7}\\times 490 = 350$\/-<\/p>\n So the answer is option B.<\/p>\n 7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Age of Suresh after 9 years from now is 45 ==> present age of suresh = 45-9 = 36<\/p>\n Let x be the present age of Ramesh<\/p>\n Before 6 years, Age of suresh = 36-6 = 30 & age of ramesh = x-6<\/p>\n Their ratio = 5::6<\/p>\n 30\/(x-6) = 5\/6<\/p>\n x = 42<\/p>\n Age of Ramesh after 15 years = 42+15 = 57<\/p>\n So the answer is option D.<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Age of Ravi = 4x , And age of his brother = 5x<\/p>\n Sum of their ages = 72<\/p>\n 4x + 5x = 72<\/p>\n 9x = 72<\/p>\n x = 8<\/p>\n Age of ravi’s brother before 9 years = 5x-9 = 5(8)-9 = 40-9 = 31<\/p>\n So the answer is option C.<\/p>\n 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Sampath : Vishal = (20000*12 + 30000*6) : (45000*12) = (24+18) : (54) = (42) : (54) = 7 : 9<\/p>\n Share of Vishal = $\\frac{9}{7+9}\\times 32000 = \\frac{9}{16}\\times 32000 = 18000$<\/p>\n So the answer is option B.<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given that their ages are in AP and least age is 31 and highest age is 39<\/p>\n 1st term = a = 31<\/p>\n 5th term = l = 39<\/p>\n Sum of their ages is $S_n = \\frac{n}{2}[a+l]$ = $\\frac{5}{2}[31+39]$ = $\\frac{5}{2}[70]$ = $175$<\/p>\n Hence average = $\\frac{175}{5} = 35$<\/p>\n So the answer is option C.<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n B’s share = $\\frac{5}{3+5+6}\\times 42000 = \\frac{5}{14}\\times 42000 = 15000$\/-<\/p>\n So the answer is option B.<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us assume that his scores in English be a, Hindi be b, Maths be c, computers be d, Social Science be e, Science be f and Physical Education be g. So we have 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let us assume that we have 63x units of first alloy be mixed with 63y units of second alloy. 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the two numbers be 7x and 9x respectively 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Total quantity of mixture = 120 litres 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let F,S are the present ages of father and son.<\/p>\n F-8 = 3(S-8)<\/p>\n 3S-F = 16 ——-(1)<\/p>\n $\\frac{F+4}{S+4} = \\frac{15}{7}$<\/p>\n 7F+28 = 15S+60<\/p>\n 15S-7F = -32——-(2)<\/p>\n On solving (1) & (2)<\/p>\n 15S-5F = 80<\/p>\n 15S-7F = -32<\/p>\n we will get 2F = 112, F = 56<\/p>\n So the answer is option C.<\/p>\n 17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the amounts invested by A and B be 2x and 3x. 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n We know that by selling rice for Rupees 63 per kg, the shopkeeper makes a profit of 40 %. Hence, the cost price of the mixture for him will be 63\/1.4 = 45 per kg. Let us say that he mixes \u2018a\u2019 kg of 40 rupees rice with \u2018b\u2019 kg of 54 rupees rice. Hence, we have So the answer is option B.<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the quantity of initial mixture be 35 litres. So it will have 15 litres milk and 20 litres of water. Now in the new mixture the total water is 8\/23 times the total quantity. We know that no new water has been added. Hence, the total quantity of final mixture will be 20*23\/8 = 57.5 litres. 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the quantity of rice A be \u2018a\u2019 and rice B be \u2018b\u2019. 21)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The length on the map = 2,250 * 1,00,000 cms\/20,000 = 11,250 cms<\/p>\n 22)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Total weight of water is 7 litres * 0.75 grams\/litre = 5.25 grams So, the amount of salt in seawater = 2.63\/4 = 0.66 grams\/ litre<\/p>\n 23)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The tax on 30 crores = 30 * 30% = 9 crores. 24)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the amount consumed by Waqar be x litres 25)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The deposit is Rs. 1000 for 365 days, 1000 * 1.1=1100 for 365 days and 1000*1.1*1.1=1210 for 365 days. <\/p>\n![\"RRB](\"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/RRB-NTPC-Mock-Test.png\")
<\/a><\/p>\n<\/a><\/p>\n
\na + b + c + d = 50*4 = 200
\nSimilarly,
\nc + e + f + g = 70*4 = 280
\nAdding both equations, we get
\na + b + 2c + d + e + f + g = 480
\nWe have been given that
\na + b + c + d + e + f + g = 58*7 = 406
\nSubtracting both, we get c = 74
\nHence, his marks in Maths must be 74.<\/p>\n
\n63x units of alloy 1 will contain 27x units of gold and 36x units of silver.
\n63y units of alloy 2 will contain 35y units of silver and 28y units of tin.
\nSo we have
\n$\\frac{27x}{28y} = \\frac{4}{7}$
\n=> $\\frac{x}{y} = \\frac{4*28}{7*27} = \\frac{16}{27}$
\nHence, option C is the correct answer.<\/p>\n
\nAlso we have, $\\frac{7x – 12}{9x – 12} = \\frac{25}{33}$
\n231x – 396 = 225x – 300
\n6x = 96
\nx = 16
\nSo the two numbers are 112 and 144.
\nRequired difference = 144 – 112 = 32
\nHence, option B is the right choice.<\/p>\n
\nQuantity of milk = 5*120\/8 = 75 litres and quantity of water = 120 – 75 = 45 litres
\nLet the quantity of water to be added be \u2018x\u2019 litres to get the ratio of 3 : 5.
\nWe get, 75 : (45 + x) = 3 : 5
\n375 = 135 + 3x
\n240 = 3x
\nx = 80 litres
\nHence, option B is the right choice.<\/p>\n
\nAfter 1 year, A\u2019s share and B\u2019s share will be 2x*12:3x*12 = 24x:36x
\nA invests some amount after 6 months due to which its share also becomes 36x.
\nTherefore, amount invested by A after 6 months would have contributed 12x.
\nLet y be the amount invested by A after 6 months.
\n6*y = 12x
\n=> y = 2x.
\nRatio of amounts invested by A at the beginning and after 6 months = 2x:2x = 1:1.
\nTherefore, option C is the right answer.<\/p>\n
\n40*a + 54*b = 45(a + b)
\n=> 40a + 54b = 45a + 45b
\n=> 5a = 9b
\n=> a\/b = 9\/5
\nHence, the required ratio is 9:5<\/p>\n
\nHence, 22.5 litres of milk must be added. It would be 150 %<\/p>\n<\/a><\/p>\n
\n(12a + 15b)\/(a+b) is the cost price of a Kg of the mixed rice.
\nWe know that the shopkeeper realizes a profit of 12.5% by selling it at Rs.15.
\n=> 1.125*(12a+15b)\/(a+b) = 15
\n13.5a + 16.875b = 15a + 15b
\n1.5a = 1.875b
\na\/b = 1.875\/1.5 = 5\/4.
\nHence, option C is the right answer.<\/p>\n
\nThe amount of salt in the mixture = 5.25 * 0.5 = 2.63 grams.<\/p>\n
\nThe tax on 25 crores = 24 * 30% = 7.2 crores
\nLoss = 9 – 7.2 = 1.8 crores.
\nSo, percentage loss = 100 * $\\frac{1.8}{9}$ = 20%<\/p>\n
\nAmount consumed by Abdul = 1.3x
\nSo, x + 1.3 x = 2 litres
\n2.3x = 2
\nSo, x = 2\/2.3 = 0.87
\nThe required value = 1.3x – x = 0.3x = 0.3 * 0.87 = 0.26 litres<\/p>\n
\nSo, the average daily balance = $\\frac{1000*365 + 1100*365+1210*365}{3*365}$
\n= Rs. 1103.33<\/p>\n