20 RRB NTPC Mocks – Just Rs. 149<\/a><\/p>\n RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n Instructions<\/b><\/p>\n Answer each question accordingly.<\/p>\n Question 1:\u00a0<\/b>Which of the given options lie between \u00bc an \u2153 ?<\/p>\n a)\u00a03\/10 and 4\/7<\/p>\n b)\u00a027\/100 an 2\/7<\/p>\n c)\u00a0\u215c and 31\/90<\/p>\n d)\u00a02\/5\/ and 14\/32<\/p>\n Question 2:\u00a0<\/b>What is the value of a)\u00a064\/25<\/p>\n b)\u00a064\/125<\/p>\n c)\u00a032\/50<\/p>\n d)\u00a032\/125<\/p>\n Question 3:\u00a0<\/b>Cena spends 30% of his income for trips, 25% for his parents and pays 2400 for his rent. If his income is 30000 then what is the percent of income left with him ?<\/p>\n a)\u00a030%<\/p>\n b)\u00a033%<\/p>\n c)\u00a037%<\/p>\n d)\u00a035%<\/p>\n FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n RRB NTPC Free Mock Test<\/a><\/p>\n Question 4:\u00a0<\/b>Srujay made an error by multiplying a number with 5\/6 inplace of 6\/5. What is the percentage error ?<\/p>\n a)\u00a031.55%<\/p>\n b)\u00a030.55%<\/p>\n c)\u00a032.55%<\/p>\n d)\u00a033.33%<\/p>\n Question 5:\u00a0<\/b>Vivek has some number of oranges. He sells 45 oranges and left with 70% of the total oranges. How many oranges are left with him if again sells 40% of remaining oranges ?<\/p>\n a)\u00a061<\/p>\n b)\u00a062<\/p>\n c)\u00a063<\/p>\n d)\u00a064<\/p>\n Question 6:\u00a0<\/b>Length and breadth of a rectangle is increased by 10% and 20% respectively. What is the percentage change in the area ?<\/p>\n a)\u00a030%<\/p>\n b)\u00a031%<\/p>\n c)\u00a032%<\/p>\n d)\u00a033%<\/p>\n Question 7:\u00a0<\/b>Kavya has got 25% of marks required to pass in the exam and 40% of total marks is considered as pass marks. What is the percent of marks Kavya got out of total marks ?<\/p>\n a)\u00a05%<\/p>\n b)\u00a010%<\/p>\n c)\u00a07%<\/p>\n d)\u00a08%<\/p>\n Question 8:\u00a0<\/b>X,Y and Z contested in elections. X got 144 votes and Y got 30% votes of total votes then What is percent of votes received by Z if total number of voters is 300 ?<\/p>\n a)\u00a020%<\/p>\n b)\u00a021%<\/p>\n c)\u00a022%<\/p>\n d)\u00a019%<\/p>\n Question 9:\u00a0<\/b>What is the value of 1.0474747\u2026.?<\/p>\n a)\u00a0$\\dfrac{1047}{9999}$<\/p>\n b)\u00a0$\\dfrac{1037}{99}$<\/p>\n c)\u00a0$\\dfrac{1037}{990}$<\/p>\n d)\u00a0$\\dfrac{1047}{9900}$<\/p>\n RRB NTPC Previous Papers Download PDF<\/a><\/p>\n RRB JE PREVIOUS PAPERS DOWNLOAD<\/a><\/p>\n Question 10:\u00a0<\/b>0.343434\u2026 = ?<\/p>\n a)\u00a0$\\dfrac{3}{5}$<\/p>\n b)\u00a0$\\dfrac{3}{10}$<\/p>\n c)\u00a0$\\dfrac{34}{100}$<\/p>\n d)\u00a0$\\dfrac{34}{99}$<\/p>\n Question 11:\u00a0<\/b>In which of the following options, fractions are arranged in ascending order?<\/p>\n a)\u00a0$\\dfrac{1}{7},\\dfrac{3}{5},\\dfrac{5}{8},\\dfrac{9}{11}$<\/p>\n b)\u00a0$\\dfrac{1}{2},\\dfrac{4}{9},\\dfrac{5}{8},\\dfrac{3}{7}$<\/p>\n c)\u00a0$\\dfrac{6}{13},\\dfrac{2}{9},\\dfrac{3}{11},\\dfrac{1}{7}$<\/p>\n d)\u00a0$\\dfrac{4}{13},\\dfrac{3}{11},\\dfrac{9}{17},\\dfrac{5}{18}$<\/p>\n Question 12:\u00a0<\/b>Which of the following fractions is the smallest?<\/p>\n a)\u00a0$\\dfrac{3}{4}$<\/p>\n b)\u00a0$\\dfrac{2}{3}$<\/p>\n c)\u00a0$\\dfrac{5}{7}$<\/p>\n d)\u00a0$\\dfrac{4}{5}$<\/p>\n Question 13:\u00a0<\/b>Find 12% of 40% of 120% of 200 ?<\/p>\n a)\u00a011.25<\/p>\n b)\u00a011.52<\/p>\n c)\u00a012.15<\/p>\n d)\u00a012.51<\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n Download General Science Notes PDF<\/a><\/p>\n Question 14:\u00a0<\/b>Find 80% of 40% of 150% of 2000 ?<\/p>\n a)\u00a0920<\/p>\n b)\u00a0940<\/p>\n c)\u00a0960<\/p>\n d)\u00a0980<\/p>\n Question 15:\u00a0<\/b>If 16% of 40% of a number is 8, then the number is ?<\/p>\n a)\u00a0125<\/p>\n b)\u00a0136<\/p>\n c)\u00a0145<\/p>\n d)\u00a0156<\/p>\n Question 16:\u00a0<\/b>5 out of 2250 parts of earth is sulpher. What is the percentage of sulpher in earth ?<\/p>\n a)\u00a02\/9 %<\/p>\n b)\u00a01\/9 %<\/p>\n c)\u00a01\/3 %<\/p>\n d)\u00a04\/9 %<\/p>\n Question 17:\u00a0<\/b>In a cricket match, Dhoni scored 46 runs while Raina scored 23 runs. By what percentage did Dhoni outscore Raina?<\/p>\n a)\u00a050%<\/p>\n b)\u00a075%<\/p>\n c)\u00a0100%<\/p>\n d)\u00a0150%<\/p>\n Question 18:\u00a0<\/b>FInd 20% of 220% of 50% of 120 ?<\/p>\n a)\u00a026<\/p>\n b)\u00a026.2<\/p>\n c)\u00a026.4<\/p>\n d)\u00a026.6<\/p>\n RRB NTPC Free Mock Test<\/a><\/p>\n RRB JE Free Mock Test<\/a><\/p>\n Question 19:\u00a0<\/b>20% of 30% of 400% of 50% of 60 = ?<\/p>\n a)\u00a08.4<\/p>\n b)\u00a07.2<\/p>\n c)\u00a06.8<\/p>\n d)\u00a08.2<\/p>\n Question 20:\u00a0<\/b>Which of the following fraction is the largest?<\/p>\n a)\u00a0$\\frac{16}{19}$<\/p>\n b)\u00a0$\\frac{13}{14}$<\/p>\n c)\u00a0$\\frac{11}{12}$<\/p>\n d)\u00a0$\\frac{7}{9}$<\/p>\n Question 21:\u00a0<\/b>A certain sum of money was distributed between A, B, C. A got three fifth the amount that B got and B got two third the amount that C got. If the difference in the amount that A and C got was 1350, then find the amount that C got.<\/p>\n a)\u00a03000<\/p>\n b)\u00a02250<\/p>\n c)\u00a03600<\/p>\n d)\u00a02700<\/p>\n Daily Free RRB Online Tests for RRB Exams<\/a><\/p>\n 100+ Free Online G.K Tests<\/a><\/p>\n Question 22:\u00a0<\/b>Rahul spends 30 % of his salary on rent. 20 % of the remaining salary is spent on food. He deposits 50 percent of his remaining salary in the bank. If the amount spent on food was 3500 then what amount did he deposit in the bank?<\/p>\n a)\u00a08750<\/p>\n b)\u00a07000<\/p>\n c)\u00a06250<\/p>\n d)\u00a09100<\/p>\n Question 23:\u00a0<\/b>When a number (greater than 0) is added to 5 times its reciprocal, its value increases by one-twentieth of its original value. What is the original number?<\/p>\n a)\u00a05<\/p>\n b)\u00a020<\/p>\n c)\u00a025<\/p>\n d)\u00a010<\/p>\n Question 24:\u00a0<\/b>What is the value of $\\sqrt{0.03610}$<\/p>\n a)\u00a0$0.23$<\/p>\n b)\u00a0$0.21$<\/p>\n c)\u00a0$0.19$<\/p>\n d)\u00a0$0.17$<\/p>\n Question 25:\u00a0<\/b>If 30% of a number is four fifths of a second number, what is the ratio between the first number and the second number?<\/p>\n a)\u00a03: 8<\/p>\n b)\u00a08:3<\/p>\n c)\u00a03:7<\/p>\n d)\u00a07:3<\/p>\n Free RRB Daily Practice Set<\/a><\/p>\n Download Current Affairs Questions & Answers PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n values of \u00bc and \u2153 are 0.25 and 0.33 respectively 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $\\frac{475}{525}\\times\\frac{256}{91}\\times\\frac{169}{250}\\times\\frac{84}{104}\\times\\frac{49}{19}$ 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Total income=30000 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us assume the number to be 30 as it is lcm of 5 and 6. 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given that he sells 45 oranges. Let the total oranges be x. 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n let us assume length and breadth to be l and b. 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us assume total marks as t,marks obtained by kavya as k and pass marks as p. 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given total number of votes=300 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let x = 1.0474747\u2026 \u2192 (1) 10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let x = 0.343434\u2026 \u2192 (1) 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Option A) $\\dfrac{3}{5} = 0.60$<\/p>\n $\\dfrac{5}{8} = 0.62$<\/p>\n $\\dfrac{9}{11} = 0.81$<\/p>\n Hence, All the fractions in Option A are arranged in ascending order.<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $\\dfrac{3}{4} = 0.75$<\/p>\n $\\dfrac{2}{3} = 0.67$<\/p>\n $\\dfrac{5}{7} = 0.71$<\/p>\n $\\dfrac{4}{5} = 0.80$<\/p>\n Hence, $\\dfrac{2}{3}$ is the smallest fraction.<\/p>\n 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 12% of 40% of 120% of 200 = (0.12)(0.4)(1.2)(200) = (0.12)(0.4)(240) = (0.12)(96) = 11.52<\/p>\n So the answer is option B.<\/p>\n 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 80% of 40% of 150% of 2000 = (0.8)(0.4)(1.5)(2000) = (0.32)(3000) = 960<\/p>\n So the answer is option C.<\/p>\n 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let x be the number<\/p>\n (0.16)(0.4)(x) = 8<\/p>\n (0.064)(x) = 8<\/p>\n x = 125<\/p>\n So the answer is option A.<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n $\\frac{5}{2250}\\times 100 = 500\/2250 = 2\/9$%<\/p>\n So the answer is option A.<\/p>\n 17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Dhoni’s score = 46<\/p>\n Raina’s score = 23<\/p>\n Difference = 46 – 23 = 23<\/p>\n answer = $\\frac{46-23}{23}\\times 100 = \\frac{23}{23}\\times 100 = 100$%<\/p>\n So the answer is option C.<\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $(0.2)(2.2)(0.5)(120) = (0.2)(2.2)(60) = (0.2)(132) = 26.4$<\/p>\n So the answer is option C.<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $(0.2)(0.3)(4)(0.5)(60) = (0.2)(0.3)(120) = (0.06)(120) = 7.2$<\/p>\n So the answer is option B.<\/p>\n 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $\\frac{16}{19}$ = 0.8421 21)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us assume that B got 10x. Hence, A must have got 6x and C must have got 15x. We have been given that 15x – 6x = 1350 22)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let his total salary be 100x. So he spends 30 % on rent. Now, remaining salary is 70x. Thus, 14x is spent on food. After this 56x will remain and hence he must deposit 28x in bank. Thus, amount deposited in the bank is twice the amount spent on food. Hence, the required answer will be 700.<\/p>\n 23)\u00a0Answer\u00a0(D)<\/strong><\/p>\n We have been given that x + (5\/x) – x = x\/20 24)\u00a0Answer\u00a0(C)<\/strong><\/p>\n We know that $19^2 = 361$ 25)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the numbers be x and y 3x\/10 = 4y\/5<\/p>\n So, x: y = 40: 15 = 8 : 3<\/p>\n Free RRB Online Coaching<\/a><\/p>\n![\"RRB](\"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/RRB-NTPC-Mock-Test.png\")
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\n$\\frac{475}{525}\\times\\frac{256}{91}\\times\\frac{169}{250}\\times\\frac{84}{104}\\times\\frac{49}{19}$<\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n
\nOption 1:0.3 and 0.5
\nOption 2:0.27 and 0.285
\nOption 3:0.37 and 0.32
\nOption 4:0.4 and 0.43
\nand so the correct answer is b.<\/p>\n
\nBy simplifying we get 64\/125<\/p>\n
\nFor rent (2400\/30000)*100=8%
\nSo he is left with 100-(30+25+8)
\n=37%<\/p>\n
\nOriginal value will be (6\/5)*30=36
\nWrong value obtained is (5\/6)*30=25
\nPercentage error =((36-25)\/36)*100
\n=30.55%<\/p>\n
\nWe have x-45=0.7x
\n0.3x=45
\nx=150
\nHe again sells 60% of the the remaining oranges an so 60% of oranges will be left i.e
\n(60\/100)* (150-45)=63<\/p>\n
\nArea=l*b
\nnew length =1.1l
\nnew breadth=1.2b
\nnew area=1.1l*1.2b
\n=1.32lb
\nPercentage change=((1.32lb-lb)\/lb)*100
\n=32%
\nEndGroup:<\/p>\n
\nk=p\/4
\np=(2\/5)t
\nk=(1\/4)*(2\/5)*t
\nk=(t\/10)
\nTherefore 10%.<\/p>\n
\nVotes received by Y is (30\/100)*300=90
\nVotes received by Z=300-144-90 i.e 66 votes
\nPercent of votes received by Z=(66\/300)*100
\n=22%<\/p>\n
\nHere, 47 is repeating.
\nHence, Multiplying (1) by 1000 to get decimal to the right of 47.
\n1000x = 1047.474747\u2026 \u2192 (2)
\nMultiplying (1) by 10 to get decimal to the left of 47.
\n10x = 10.474747\u2026 \u2192 (3)
\nSubtracting (3) from (2)
\n1000x – 10x = 1047.474747\u2026 – 10.474747\u2026
\n\u21d2 990x = 1037
\n\u21d2 x = $\\dfrac{1037}{990}$<\/p>\n
\nHere, two digits i.e., 34 are repeated. Hence, 100 must be multiplied on both sides.
\n100x = 34.343434\u2026 \u2192 (2)
\nSubtracting (1) from (2)
\n100x – x = 34.343434\u2026 – 0.343434\u2026
\n\u21d2 99x = 34
\n\u21d2 x = $\\dfrac{34}{99}<\/p>\n<\/a><\/p>\n
\n$\\dfrac{1}{7} = 0.14$<\/p>\n
\n$\\frac{13}{14}$ = 0.9286
\n$\\frac{11}{12}$ = 0.9166
\n$\\frac{7}{9}$ = 0.7778
\nHence, option B is the right answer.<\/p>\n
\n=> 9x = 1350
\n=> x = 150
\nThus, C must have got 150*15 = 2250<\/p>\n
\n5\/x = x\/20
\n=>x*x = 100
\nTherefore, x = 10.
\nHence, option D is the right answer.<\/p>\n
\nand the value of $0.03610 = 361 \\times 10^{-4}$
\nTherefore, $\\sqrt{0.03610} = 19 \\times 10^{-2} = 0.19$<\/p>\n
\n30% * x = 4y\/5<\/p>\n