{"id":25866,"date":"2019-03-08T17:17:39","date_gmt":"2019-03-08T11:47:39","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=25866"},"modified":"2019-09-09T16:49:32","modified_gmt":"2019-09-09T11:19:32","slug":"ssc-cgl-boat-and-stream-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ssc-cgl-boat-and-stream-questions-pdf\/","title":{"rendered":"SSC CGL Boat and Stream Questions PDF"},"content":{"rendered":"

SSC CGL Boat and Stream Questions PDF:<\/span><\/strong><\/h2>\n

Download SSC CGL Boat and Stream questions with answers PDF based on previous papers very useful for SSC CGL exams. 25 Very important Boat and Stream objective questions for SSC exams.<\/p>\n

Download SSC CGL Boat and Stream Questions PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>A boat covers 12 km upstream in 4 hours and can cover the same distance downstream in 3 hours. What is the speed (in km\/hr) of the boat in still water?<\/p>\n

a)\u00a03.5
\nb)\u00a03
\nc)\u00a02.5
\nd)\u00a02<\/p>\n

Question 2:\u00a0<\/b>Two boat are travelling with speed of 36 km\/hr and 54 km\/hr respectively towards each other. What is the distance (in metres) between the two boats one second before they collide?<\/p>\n

a)\u00a010
\nb)\u00a015
\nc)\u00a025
\nd)\u00a05<\/p>\n

Question 3:\u00a0<\/b>A boat goes 15 km upstream and 22 km downstream is 5 hours. It goes 20 km upstream and $\\ \\frac{55}{2}\\ $km downstream in $\\ \\frac{13}{2}\\ $hours. What is the speed (in km\/hr) of stream ?<\/p>\n

a)\u00a03
\nb)\u00a05
\nc)\u00a08
\nd)\u00a011<\/p>\n

Question 4:\u00a0<\/b>A boat travels 60 kilometers downstream and 20 kilometers upstream in 4 hours. The same boat travels 40 kilometers downstream and 40 kilometers upstream in 6 hours. What is the speed (in km\/hr) of the stream?<\/p>\n

a)\u00a024
\nb)\u00a016
\nc)\u00a018
\nd)\u00a020<\/p>\n

Question 5:\u00a0<\/b>A man rows 750 m in 675 seconds against the stream and returns in $\\ 7\\frac{1}{2}\\ $minutes. Its rowing speed in still water is (in km\/hr).<\/p>\n

a)\u00a05.5
\nb)\u00a05.75
\nc)\u00a05
\nd)\u00a05.25<\/p>\n

SSC CGL Previous Papers Download PDF<\/a><\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

 <\/p>\n

Question 6:\u00a0<\/b>If a boat goes a certain distance at 20 km\/hr and comes back the same distance at 30 km\/hr. What is the average speed (in km\/hr) for the total journey?<\/p>\n

a)\u00a012
\nb)\u00a024
\nc)\u00a026
\nd)\u00a025<\/p>\n

Question 7:\u00a0<\/b>A boat took 4 hours to travel 20km upstream. Find the speed of the boat in still water if the speed of the stream is 2 kmph ?<\/p>\n

a)\u00a05 kmph
\nb)\u00a06 kmph
\nc)\u00a07 kmph
\nd)\u00a08 kmph<\/p>\n

Question 8:\u00a0<\/b>A boat goes 8 km upstream and 12 km downstream in 7hours. It goes 9 km upstream and 18 km downstream in 9 hours. What is the speed (in km\/h) of the boat in still water?<\/p>\n

a)\u00a05
\nb)\u00a04
\nc)\u00a02
\nd)\u00a03<\/p>\n

Question 9:\u00a0<\/b>A boat covers 143 km upstream in 13 hours and the same distance downstream in 11 hours. What is the speed (in km\/hr) of the boat in still water?<\/p>\n

a)\u00a010
\nb)\u00a012
\nc)\u00a014
\nd)\u00a08<\/p>\n

Question 10:\u00a0<\/b>A boat covers a distance of 14 km upstream and 16 km downstream in 9 hours. It covers a distance of 12 km upstream and 40 km downstream in 11 hours. What is the speed (in km\/hr) of the boat in still water?<\/p>\n

a)\u00a05
\nb)\u00a02
\nc)\u00a03
\nd)\u00a04<\/p>\n

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Question 11:\u00a0<\/b>Speed of a boat along and against the current are 14 kms\/hr and 8 kms\/hr respectively. The speed of the current is<\/p>\n

a)\u00a011 kms\/hr
\nb)\u00a06 kms\/hr
\nc)\u00a05.5 kms\/hr
\nd)\u00a03 kms\/hr<\/p>\n

Question 12:\u00a0<\/b>Speed of a boat is 8 km\/hr in still water and the speed of the stream is 2 km\/hr. If the boat takes 8 hours to go to a place and come back, then what is the distance (in km) of the place?<\/p>\n

a)\u00a024
\nb)\u00a030
\nc)\u00a045
\nd)\u00a042<\/p>\n

Question 13:\u00a0<\/b>Speeds of a boat along the current and against the current are 14 km\/hr and 7 km\/hr respectively. What is the speed of boat (in km\/hr) in still water?<\/p>\n

a)\u00a03.5
\nb)\u00a07.5
\nc)\u00a010.5
\nd)\u00a09.5<\/p>\n

Question 14:\u00a0<\/b>Speeds of a boat along the current and against the current are 16 km\/hr and 12 km\/hr respectively. What is the speed (in km\/hr) of the current?<\/p>\n

a)\u00a01
\nb)\u00a02
\nc)\u00a03
\nd)\u00a04<\/p>\n

Question 15:\u00a0<\/b>A man can row 32 km upstream in 8 hours and the same distance downstream can be covered in 4 hours. If the speed of the stream and boat is constant throughout then what is the speed of stream?<\/p>\n

a)\u00a01 km\/hr
\nb)\u00a01.5 km\/hr
\nc)\u00a02 km\/hr
\nd)\u00a02.5 km\/hr<\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

Question 16:\u00a0<\/b>A boat going upstream can cover a certain distance in 6 hours. The speed of the stream is half the speed of boat in still water. How much time will the boat take to cover the same distance downstream?<\/p>\n

a)\u00a03 hours
\nb)\u00a02 hours
\nc)\u00a01 hour
\nd)\u00a0Cannot be determined<\/p>\n

Question 17:\u00a0<\/b>A boat goes 4 km upstream and 4 km downstream in 1 hour. The same boat goes 5 km downstream and 3 km upstream in 55 minutes. What is the speed (in km\/hr) of boat in still water?<\/p>\n

a)\u00a06.5
\nb)\u00a07.75
\nc)\u00a09
\nd)\u00a010.5<\/p>\n

Question 18:\u00a0<\/b>A boat is sailing towards a lighthouse of height 20\u221a3 m at a certain speed. The angle of elevation of the top of the lighthouse changes from 30\u00b0 to 60\u00b0 in 10 seconds. What is the time taken (in seconds) by the boat to reach the lighthouse from its initial position?<\/p>\n

a)\u00a010
\nb)\u00a015
\nc)\u00a020
\nd)\u00a060<\/p>\n

Question 19:\u00a0<\/b>If a boat goes a certain distance at 30 km\/hr and comes back the same distance at 60 km\/hr. What is the average speed (in km\/hr) for the total journey?<\/p>\n

a)\u00a045
\nb)\u00a05
\nc)\u00a040
\nd)\u00a035<\/p>\n

Question 20:\u00a0<\/b>The average weight of 15 oarsmen in a boat is increased by 1.6 kg when one of the crew, who weighs 42 kg is replaced by a new man. Find the weight of the new man (in kg).<\/p>\n

a)\u00a067
\nb)\u00a065
\nc)\u00a066
\nd)\u00a043<\/p>\n

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Question 21:\u00a0<\/b>If the speed of a boat in still water is 20 km\/hr and the speed of the current is 5 km\/hr, then the time taken by the boat to travel 100 km with the current is<\/p>\n

a)\u00a02 hrs
\nb)\u00a03 hrs
\nc)\u00a04 hrs
\nd)\u00a07 hrs<\/p>\n

Question 22:\u00a0<\/b>A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is<\/p>\n

a)\u00a08 km\/hr
\nb)\u00a09 km\/hr
\nc)\u00a012 km\/hr
\nd)\u00a010 km\/hr<\/p>\n

Question 23:\u00a0<\/b>A boat can travel with a speed of 13 km\/hr in still water. If the speed of stream is 4 km\/hr in the same direction, time taken by boat to go 63 km in opposite direction is<\/p>\n

a)\u00a09 hrs
\nb)\u00a04 hrs
\nc)\u00a07 hrs
\nd)\u00a0$3\\frac{9}{17}$ hrs<\/p>\n

Question 24:\u00a0<\/b>A person can row a distance of one km upstream in ten minutes and downstream in four minutes. What is the speed of the stream ?<\/p>\n

a)\u00a04.5 km\/h
\nb)\u00a04 km\/h
\nc)\u00a09 km\/h
\nd)\u00a05.6 km\/h<\/p>\n

Question 25:\u00a0<\/b>Ravi rows a boat upstream in a river from point A to B in 4 hours. Had the river been still, he could have completed the journey in 3 hours. How much time will it take for Ravi to row the boat from point B to A?<\/p>\n

a)\u00a02 hour 24 minutes
\nb)\u00a02 hours
\nc)\u00a02 hour 48 minutes
\nd)\u00a02 hour 12 minutes.<\/p>\n

1500+ Free SSC Questions & Answers<\/a><\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr and speed of current = $y$ km\/hr
\nSpeed upstream = $(x-y)$ km\/hr
\nUsing, speed = distance\/time
\n=> $x-y=\\frac{12}{4}=3$ —————-(i)
\nSimilarly, downstream speed = $x+y=\\frac{12}{3}=4$ —————(ii)
\nAdding equations (i) and (ii), we get : $2x=3+4=7$
\n=> $x=\\frac{7}{2}=3.5$ km\/hr
\n=> Ans – (A)<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Relative speed of boats (since they are travelling towards each other = $36+54=90$ km\/hr
\n= $(90\\times\\frac{5}{18})$ m\/s = $25$ m\/s
\nDistance between them one second before they collide = Distance covered in 1 second = 25 m
\n<\/strong>=> Ans – (C)
\n
\n3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let speed of boat = $x$ km\/hr and speed of stream = $y$ km\/hr
\n=> Downstream speed = $(x+y)$ km\/hr and Upstream speed = $(x-y)$ km\/hr
\nAccording to ques,
\n=> $\\frac{15}{x-y}+\\frac{22}{x+y}=5$
\nand $\\frac{20}{x-y}+\\frac{27.5}{x+y}=6.5$
\nLet $\\frac{1}{x-y}=m$ and $\\frac{1}{x+y}=n$
\n=> $15m+22n=5$ and $20m+27.5n=6.5$
\nSolving above equations, we get : $m=\\frac{1}{5}$ and $n=\\frac{1}{11}$
\nThus, $x-y=5$ and $x+y=11$
\nSubtracting both equation, => $2y=11-5=6$
\n=> $y=\\frac{6}{2}=3$
\n$\\therefore$ Speed of stream = 3 km\/hr
\n=> Ans – (A)<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let speed of boat = $x$ km\/hr and speed of stream = $y$ km\/hr
\nThus, downstream speed = $(x+y)$ km\/hr and upstream speed = $(x-y)$ km\/hr
\nUsing, time = distance\/speed
\n=> $(\\frac{60}{x+y})+(\\frac{20}{x-y})=4$
\n=> $\\frac{15}{x+y}+\\frac{5}{x-y}=1$ —————(i)
\nSimilarly, $(\\frac{40}{x+y})+(\\frac{40}{x-y})=6$
\n=> $\\frac{1}{x+y}+\\frac{1}{x-y}=\\frac{3}{20}$ ————(ii)
\nSolving equations (i) and (ii), we get : $x=24$ and $y=16$
\n$\\therefore$ Speed of stream = 16 km\/hr
\n<\/strong>=> Ans – (B)<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Boat’s upstream speed($S_{u}$) $= \\frac{750}{675} = \\frac{10}{9}$ m\/sec
\nBoat’s downstream speed($S_{d}$) $= \\frac{750}{450} = \\frac{5}{3}$ m\/sec
\nBoat’s speed in still water $= \\frac{1}{2}\\times(S_{u}+(S_{d})$
\n$= \\frac{1}{2}\\times(\\frac{10}{9}+\\frac{5}{3})$
\n$= \\frac{1}{2}\\times(\\frac{25}{9})$
\n$= \\frac{25}{18}$ m\/sec
\nConverting it into km\/hr
\n$= \\frac{25}{18}\\times\\frac{18}{5} = 5$ km\/hr<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

average speed = $\\frac{2ab}{a+b}=\\frac{2(20)(30)}{20+30}=24$
\nSo the answer is option B.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let x be the speed of the boat in still water
\nDuring upstream, speed = x-2 kmph
\nSpeed = Distance\/time
\nx-2 = 20\/4
\nx-2 = 5
\nx = 7 kmph
\nSo the answer is option C.<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr and speed of current = $y$ km\/hr
\nAccording to ques,
\n=> $\\frac{12}{x+y}+\\frac{8}{x-y}=7$ —————-(i)
\nand $\\frac{18}{x+y}+\\frac{9}{x-y}=9$ —————-(ii)
\nApplying the operation : $3\\times(i)-2\\times(ii)$
\n=> $\\frac{24}{x-y}-\\frac{18}{x-y}=21-18$
\n=> $\\frac{6}{x-y}=3$
\n=> $x-y=\\frac{6}{3}=2$ ————–(iii)
\nSubstituting it in equation (i), => $\\frac{12}{x+y}+\\frac{8}{2}=7$
\n=> $\\frac{12}{x+y}=7-4=3$
\n=> $x+y=\\frac{12}{3}=4$ ————(iv)
\nNow, adding equations (iii) and (iv), we get :
\n=> $2x=2+4=6$
\n=> $x=\\frac{6}{2}=3$
\n=> Ans – (D)<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let speed of the boat in still water = $x$ km\/hr and speed of current = $y$ km\/hr
\nAccording to ques,
\n=> $x-y=\\frac{143}{13}=11$ ————-(i)
\nand $x+y=\\frac{143}{11}=13$ ———–(ii)
\nAdding both equations, we get : $2x=11+13=24$
\n=> $x=\\frac{24}{2}=12$ km\/hr
\n=> Ans – (B)<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr and speed of current = $y$ km\/hr
\nAccording to ques,
\n=> $\\frac{16}{x+y}+\\frac{14}{x-y}=9$ —————-(i)
\nand $\\frac{40}{x+y}+\\frac{12}{x-y}=11$ —————-(ii)
\nApplying the operation : $5\\times(i)-2\\times(ii)$
\n=> $\\frac{70}{x-y}-\\frac{24}{x-y}=45-22$
\n=> $\\frac{46}{x-y}=23$
\n=> $x-y=\\frac{46}{3}=2$ ————–(iii)
\nSubstituting it in equation (i), => $\\frac{16}{x+y}+\\frac{14}{2}=9$
\n=> $\\frac{16}{x+y}=9-7=2$
\n=> $x+y=\\frac{16}{2}=8$ ————(iv)
\nNow, adding equations (iii) and (iv), we get :
\n=> $2x=2+8=10$
\n=> $x=\\frac{10}{2}=5$
\n=> Ans – (A)<\/p>\n

Free SSC Daily Practice Set<\/a><\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

If Upstream speed = $x$ km\/hr and downstream speed = $y$ km\/hr
\nThe, speed of boat = $\\frac{x+y}{2}$ km\/hr and speed of current = $\\frac{y-x}{2}$ km\/hr
\nAccording to ques, upstream speed (x) = 8 km\/hr
\nDownstream speed (y) = 14 km\/hr
\n=> Speed of current = $\\frac{14-8}{2}$
\n= $\\frac{6}{2}=3$ km\/hr
\n=> Ans – (D)<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Speed of boat in still water = 8 km\/hr and speed of stream = 2 km\/hr
\nLet distance covered = $d$ km
\nAccording to ques,
\n=> $\\frac{d}{(8-2)}+\\frac{d}{(8+2)}=8$
\n=> $\\frac{d}{6}+\\frac{d}{10}=8$
\n=> $\\frac{10d+6d}{60}=8$
\n=> $\\frac{4d}{15}=8$
\n=> $d=\\frac{15\\times8}{4}=30$ km
\n=> Ans – (B)<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Downstream speed of boat = 14 km\/hr
\nUpstream speed of boat = 7 km\/hr
\n=> Speed of boat (in km\/hr) in still water = $\\frac{1}{2}\\times(14+7)$
\n= $\\frac{21}{2}=10.5$ km\/hr
\n=> Ans – (C)<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Downstream speed of boat = 16 km\/hr
\nUpstream speed of boat = 12 km\/hr
\n=> Speed of current (in km\/hr) = $\\frac{1}{2}\\times(16-12)$
\n= $\\frac{4}{2}=2$ km\/hr
\n=> Ans – (B)<\/p>\n

15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We have been given that speed while travelling upstream is 4 km\/hr and while rowing downstream it is 8 km\/hr.
\nSo if x is the speed of the boat and y is the speed of the stream then we have
\nx + y = 8
\nx – y = 4
\nHence, 2x = 12 => x = 6
\n=> y = 2<\/p>\n

16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the speed of the boat be 2x. Hence, the speed of the stream will be \u2018x\u2019. Thus, net speed while going upstream = x and net speed while going downstream = 3x. Hence, the time taken while travelling downstream will be one third of the time taken while going upstream. Thus, the correct answer will 6\/3 = 2 hours<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr and speed of current = $y$ km\/hr
\nThe boat goes 4 km upstream and 4 km downstream in 1 hour
\nUsing, time = distance\/speed
\n=> $\\frac{4}{x+y}+\\frac{4}{x-y}=1$
\nSimilarly, $\\frac{5}{x+y}+\\frac{3}{x-y}=\\frac{55}{60}$
\nLet $\\frac{1}{x+y}=w$ and $\\frac{1}{x-y}=z$
\n=> $4w+4z=1$ and $5w+3z=\\frac{55}{60}$
\nSolving above equations, we get : $w=\\frac{1}{12}$ and $z=\\frac{1}{6}$
\n=> $x+y=12$ ———(i)
\nand $x-y=6$ ———–(ii)
\nAdding equations (i) and (ii), => $2x=12+6=18$
\n=> $x=\\frac{18}{2}=9$ km\/hr
\n=> Ans – (C)<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

 <\/p>\n

<\/figure>\n

Given : CD = $20\\sqrt3$ m and time taken to reach B from A = 10 seconds
\nTo find : Time taken to reach D from A
\nSolution : In $\\triangle$ BCD,
\n=> $tan(60^\\circ)=\\frac{CD}{BD}$
\n=> $\\sqrt3=\\frac{20\\sqrt3}{BD}$
\n=> $BD=20$ m
\nSimilarly, in $\\triangle$ ACD,
\n=> $tan(30^\\circ)=\\frac{CD}{AD}$
\n=> $\\frac{1}{\\sqrt3}=\\frac{20\\sqrt3}{20+AB}$
\n=> $AB+20=60$
\n=> $AB=60-20=40$ m
\n=> Speed of boat (while travelling from A to B) = distance\/time
\n= $\\frac{40}{10}=4$ m\/s
\n=> AD = BD + AB = 20 + 40 = 60 m
\n$\\therefore$ Time taken to reach D from A = $\\frac{60}{4}=15$ seconds
\n=> Ans – (B)<\/p>\n

19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

average speed = $\\frac{2ab}{a+b}=\\frac{2(30)(60)}{30+60}=40$
\nSo the answer is option C.<\/p>\n

20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the average weight of the original 15 oarsmen = $A$
\n=> Total weight of 15 oarsmen = $15A$
\nLet the weight of new man be $x$
\nAfter he replaces the man with weight 42 kg, the average weight increases by 1.6 kg
\n=> $\\frac{15A + x – 42}{15} = A + 1.6$
\n=> $ 15A + x – 42 = 15A + 24$
\n=> $x = 24+42 = 66$<\/p>\n

SSC CHSL Free Mock Test<\/a><\/p>\n

21)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Speed of boat = 20 km\/hr and speed of current = 5 km\/hr
\nDistance to travel = 100 km
\nSpeed downstream (with the current) = 20 + 5 = 25 km\/hr
\n=> Time taken = distance \/ speed
\n= $\\frac{100}{25}=4$ hours
\n=> Ans – (C)<\/p>\n

22)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/h
\nand speed of stream = $y$ km\/h
\n=> Upstream speed of boat = $(x-y)$ km\/h
\nDownstream speed = $(x+y)$ km\/h
\nAcc to ques :
\n=> $\\frac{24}{x-y} + \\frac{28}{x+y} = 6$
\nand $\\frac{30}{x-y} + \\frac{21}{x+y} = 6\\frac{1}{2}$
\nSolving above equations, we get :
\n$x$ = 10 km\/h and $y$ = 4 km\/h<\/p>\n

23)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Speed of boat = 13 km\/hr and speed of stream = 4 km\/hr
\nWhen going in opposite direction i.e. upstream, relative speed = 13-4 = 9 km\/hr
\n=> Time taken to go 63 km upstream = $\\frac{distance}{speed}$
\n= $\\frac{63}{9}$ = 7 hours<\/p>\n

24)\u00a0Answer\u00a0(A)
\n<\/strong>
\nDistance(D) is given as 1 km
\nLet the speed of boat and river be B km\/hr and R km\/hr
\nin case of upstream , the speed of boat = (B-R) km\/hr
\nin case of downstream, the speed of boat = (B+R) km\/hr
\nin upstream it takes 10 minutes to move 1 km and takes 4 minutes in downstream for the
\nsame distance
\nSo , using distance = speed x time
\n$\\frac{1}{B-R}$ = $\\frac{10}{60}$
\n$\\frac{1}{B+R}$ = $\\frac{4}{60}$
\nB-R = 6 …..(1)
\nB+R = 15 ………(2)
\nSolving equations 1 and 2
\nB = 10.5 km\/hr and R = 4.5 Km\/hr<\/p>\n

25)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the distance between the 2 points A and B be D, the speed of Ravi be r and the speed of the stream be s.<\/p>\n

D\/(r-s) = 4
\nD = 4r – 4s ——-(1)<\/p>\n

Had the water been still:
\nD\/r = 3
\nD = 3r ——–(2).<\/p>\n

Substituting (2) in (1), we get,<\/p>\n

3r = 4r – 4s
\nr = 4s<\/p>\n

While moving downstream, Ravi will travel at r + s = 4s + s = 5s
\nDistance to be covered = 3r = 3*4s = 12s
\nTime taken = 12s\/5s = 2.4 hours = 2 hours 24 minutes.
\nTherefore, option A is the right answer.<\/p>\n

 <\/p>\n

SSC Free Previous Papers App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

SSC CGL Boat and Stream Questions PDF: Download SSC CGL Boat and Stream questions with answers PDF based on previous papers very useful for SSC CGL exams. 25 Very important Boat and Stream objective questions for SSC exams.   Question 1:\u00a0A boat covers 12 km upstream in 4 hours and can cover the same distance […]<\/p>\n","protected":false},"author":21,"featured_media":25875,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,504],"tags":[],"class_list":{"0":"post-25866","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc-cgl"},"better_featured_image":{"id":25875,"alt_text":"SSC CGL Boat and Stream Questions PDF","caption":"SSC CGL Boat and Stream Questions PDF","description":"SSC CGL Boat and Stream Questions 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