{"id":25830,"date":"2019-03-07T17:53:03","date_gmt":"2019-03-07T12:23:03","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=25830"},"modified":"2019-03-07T17:53:03","modified_gmt":"2019-03-07T12:23:03","slug":"ssc-cgl-compound-interest-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ssc-cgl-compound-interest-questions-pdf\/","title":{"rendered":"SSC CGL Compound Interest Questions PDF"},"content":{"rendered":"

SSC CGL Compound Interest Questions PDF:<\/strong><\/span><\/h1>\n

Download SSC CGL Compound Interest questions with answers PDF based on previous papers very useful for SSC CGL exams. 25 Very important Compound Interest objective questions for SSC exams.<\/p>\n

Download SSC CGL Compound Interest Questions PDF<\/a><\/p>\n

25 SSC CGL Mocks – Just Rs. 149<\/a><\/p>\n

\"SSC<\/a><\/p>\n

Question 1:\u00a0<\/b>In how many years will a sum of Rs. 800 at 10% per annum compound interest, compounded semiannually becomes Rs. 926.10 ?<\/p>\n

a)\u00a01$\\frac{1}{2}$
\nb)\u00a01$\\frac{2}{3}$
\nc)\u00a02$\\frac{1}{3}$
\nd)\u00a02$\\frac{1}{2}$<\/p>\n

Question 2:\u00a0<\/b>A sum of Rs. 12,000, deposited at compoundd interest becomes double after 5 years. How much will it be after 20 years ?<\/p>\n

a)\u00a0Rs. 1,44,000
\nb)\u00a0Rs. 1,20,000
\nc)\u00a0Rs. 1, 50,000
\nd)\u00a0Rs. 1,92,000<\/p>\n

Question 3:\u00a0<\/b>The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is Rs. 48. Then the sum is<\/p>\n

a)\u00a0Rs. 1,000
\nb)\u00a0Rs. 1,200
\nc)\u00a0Rs. 1,500
\nd)\u00a0Rs. 2,000<\/p>\n

Question 4:\u00a0<\/b>A sum of Rs. 12,000 deposited at compound interest becomes double after 5 years. After 20 years, it will become<\/p>\n

a)\u00a0Rs. 48,000
\nb)\u00a0Rs. 96,000
\nc)\u00a0Rs. 1,90,000
\nd)\u00a0Rs. 1,92,000<\/p>\n

Question 5:\u00a0<\/b>The difference between the compound interest and simple interest for the amount Rs. 5,000 in 2 years is Rs.32. The rate of interest is<\/p>\n

a)\u00a05%
\nb)\u00a08%
\nc)\u00a010%
\nd)\u00a012%<\/p>\n

SSC CGL Previous Papers Download PDF<\/a><\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

\"SSC<\/a><\/p>\n

Question 6:\u00a0<\/b>There is 100% increase to an amount in 8 years, at simple interest. Find the compound interest of Rs. 8000 after 2 years at the same rate of interest.<\/p>\n

a)\u00a0Rs. 2500
\nb)\u00a0Rs. 2000
\nc)\u00a0Rs. 2250
\nd)\u00a0Rs. 2125<\/p>\n

Question 7:\u00a0<\/b>The compound interest generated on a sum of Rs 5000, in two years at 5% per annum, the interest is being compounded half yearly is.<\/p>\n

a)\u00a0Rs 557
\nb)\u00a0Rs 489
\nc)\u00a0Rs 519
\nd)\u00a0Rs 362<\/p>\n

Question 8:\u00a0<\/b>The difference between simple interest and compound interest (at the same rate of interest) for two years on a sum of Rs. 25000 is Rs. 1000. What is the common rate of interest?<\/p>\n

a)\u00a010%
\nb)\u00a020%
\nc)\u00a030%
\nd)\u00a040%<\/p>\n

Question 9:\u00a0<\/b>Sohan deposited Rs 1 lac in a bank at a certain simple interest rate such that the amount got doubled after 5 years. If Sohan had deposited the same amount at the same interest rate compounded annually, the amount after 2 years would have been<\/p>\n

a)\u00a0Rs 1.44 lacs
\nb)\u00a0Rs 1.21 lacs
\nc)\u00a0Rs 1.25 lacs
\nd)\u00a0Rs 1.69 lacs<\/p>\n

Question 10:\u00a0<\/b>A certain sum of money will amount to 24200 in 2 years at 10% per annum compounded annually. What will this sum amount to if it is invested at 8% per annum simple interest for 3 years?<\/p>\n

a)\u00a025000
\nb)\u00a024800
\nc)\u00a024200
\nd)\u00a024000<\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

\"SSC<\/a><\/p>\n

Question 11:\u00a0<\/b>What is the difference between simple interest and compound interest (at the same rate of interest) for two years on a sum of Rs. 20000? The common rate of interest is 10%.<\/p>\n

a)\u00a0Rs. 200
\nb)\u00a0Rs. 400
\nc)\u00a0Rs. 600
\nd)\u00a0Rs. 800<\/p>\n

Question 12:\u00a0<\/b>The interest accrued when a sum of Rs 1,20,000 is deposited in a bank at an interest of 10% compounded annually for 4 years is X. Similarly, the interest accrued when a sum of Rs 1,20,000 is deposited in a bank at an interest rate of \u2018r\u2019 compounded annually for 2 years is Y. For what value of \u2018r\u2019 will X be equal to Y?<\/p>\n

a)\u00a020%
\nb)\u00a024%
\nc)\u00a021%
\nd)\u00a030%<\/p>\n

Question 13:\u00a0<\/b>If the difference between simple interest and compound interest for two years on a sum of Rs. 50000 is Rs. 12500 when the rate of interest is the same, what is the common rate of interest?<\/p>\n

a)\u00a040%
\nb)\u00a050%
\nc)\u00a045%
\nd)\u00a035%<\/p>\n

Question 14:\u00a0<\/b>Mr. Sharma invested a sum of money in a bank account at an interest rate of 10% compounded annually which yielded him an interest of Rs 3780 after 2 years. If Mr. Sharma invested the same amount of money at simple interest for double time period but half the interest rate, the interest accrued would be<\/p>\n

a)\u00a0Rs 3200
\nb)\u00a0Rs 2700
\nc)\u00a0Rs 3600
\nd)\u00a0Rs 4800<\/p>\n

Question 15:\u00a0<\/b>A sum of money is invested for 2 years in a bank which pays a simple interest of 8% pa. If the same money had been invested in another bank which was paying a compound interest of 8% pa, the returns would have differed by Rs 80. What is the sum which is deposited?<\/p>\n

a)\u00a010000
\nb)\u00a012500
\nc)\u00a015000
\nd)\u00a020000<\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

Question 16:\u00a0<\/b>At what rate of compound interest per annum will a sum of Rs 10000 become Rs 12321 in 2 years?<\/p>\n

a)\u00a022 percent
\nb)\u00a011 percent
\nc)\u00a07 percent
\nd)\u00a015 percent<\/p>\n

Question 17:\u00a0<\/b>At what rate of compound interest per annum will a sum of Rs 20000 become Rs 23328 in 2 years?<\/p>\n

a)\u00a08 percent
\nb)\u00a016 percent
\nc)\u00a024 percent
\nd)\u00a012 percent<\/p>\n

Question 18:\u00a0<\/b>If the amount received at the end of 2nd and 3rd year at Compound Interest on a certain Principal is Rs<\/p>\n

a)\u00a04 percent
\nb)\u00a08 percent
\nc)\u00a016 percent
\nd)\u00a013 percent<\/p>\n

Question 19:\u00a0<\/b>The effective annual rate of interest corresponding to a nominal rate of 7% per annum payable half\u00adyearly is<\/p>\n

a)\u00a014 percent
\nb)\u00a014.25 percent
\nc)\u00a07 percent
\nd)\u00a07.12 percent<\/p>\n

Question 20:\u00a0<\/b>Sumit invested a sum of money in a bank at a certain simple interest rate. After 5 years, the amount got doubled. If he had invested the same amount, at the same rate compounded annually, the amount would have doubled<\/p>\n

a)\u00a0During the second year
\nb)\u00a0During the third year
\nc)\u00a0During the fourth year
\nd)\u00a0During the fifth year<\/p>\n

100+ Free GK Tests for SSC Exams<\/a><\/p>\n

Download Free GK PDF<\/a><\/p>\n

Question 21:\u00a0<\/b>A bank offers 12% compound interest on a sum of Rs. 10,000 compounded every quarter. What will be the approximate interest earned at the end of 1 year?<\/p>\n

a)\u00a0Rs 1055
\nb)\u00a0Rs 1155
\nc)\u00a0Rs 1255
\nd)\u00a0Rs 1355<\/p>\n

Question 22:\u00a0<\/b>The compound interest on a certain sum of money for 2 years at 5% per annum is 410. The simple interest on the same sum at the same rate and for the same time is<\/p>\n

a)\u00a0400
\nb)\u00a0300
\nc)\u00a0350
\nd)\u00a0405<\/p>\n

Question 23:\u00a0<\/b>The compound interest on =1,800 at 10% per annum for a certain period of time is 378. Find the time in years.<\/p>\n

a)\u00a02.0 years
\nb)\u00a02.8 years
\nc)\u00a03.0 years
\nd)\u00a02.5 year<\/p>\n

Question 24:\u00a0<\/b>The time in which 80,000 ambunts to 92,610 at 10% p.a. at compound interest, interest being compounded semi annually is :<\/p>\n

a)\u00a01.5 years
\nb)\u00a02 years
\nc)\u00a02.5 years
\nd)\u00a03 years<\/p>\n

Question 25:\u00a0<\/b>A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to four times itself ?<\/p>\n

a)\u00a012 years
\nb)\u00a013 years
\nc)\u00a08 years
\nd)\u00a016 years<\/p>\n

1500+ Free SSC Questions & Answers<\/a><\/p>\n

\"SSC<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

When we are compounding it semiannually its rate becomes 5% and number of years will 2n
\nso for compound interest:
\n926.10=$800\\times(1+\\frac{10}{100})^{2n}$
\nsolve for n.<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

For compound interest A = $p(1+\\frac{r}{100})^{n}$ where p is principal amount, r is rate and t is time
\nafter 5 years it gets doubled
\nhence putting the values we will get $(1+\\frac{r}{100})^{5}$ = 2
\nnow after 20 years total amount will be $p((1+\\frac{r}{100})^{5})^{4}$ = 16p = $16 \\times 12000$ = 192000<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Difference between simple interest and compound interest for two years will be
\n48 = $\\frac{2pr}{100} – ( \\frac{2pr}{100} + \\frac{pr^2}{10^4})$ (where p is principal amount and r is rate per annum)
\nPutting r=20% and solving above equation for p, we will get p = 1200 rs.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

As we know $P(1+ \\frac{r}{100})^t$ is amount of compound interest where r is rate, P is principal amount and t is time.
\nSo $12000(1+ \\frac{r}{100})^5 = 2 \\times 12000$
\nor $(1+ \\frac{r}{100}) = 2^(\\frac{1}{5})$ eq(1)
\nNow after 20 years compound interest will be = $12000(1+ \\frac{r}{100})^20$
\nor $12000 (2^{(\\frac{1}{5})})^{20}$ (from eq.(1))
\nor $ 12000 \\times 16 = 192000$<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Difference between compound interest and simple interest for 2 years will be
\n= $(P((1+\\frac{r}{100})^2) – P) – 2P \\frac{r}{100} = 32$ (where P is principal amount 5000 and r is rate )
\nafter solving above equation we will get r = 8%<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

I = PTR\/100
\nthere is 100% increase in amount means, interest = principle.
\ngiven, T = 8yrs.
\nI = P
\nP = P*8*R\/100
\nR = 12.5%
\ncompound interest of 8000\/- at 12.5% for 2 years is
\nCI = total amount – 8000\/-
\n= P$(1+R\/100)^{n}$ – 8000\/-
\n= 8000$(1+12.5\/100)^{2}$ – 8000\/-
\n= 10125 – 8000
\n= 2125\/-
\nso the answer is option D.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The formula to calculate compound interest is,
\n$A=P(1+\\frac{r}{n})^{nt}$ where,
\nA = Amount
\nP = Principal
\nr = rate of interest
\nn = number of times compounded in a year
\nt = time period in years
\nApplying the above formula we get,
\nCompound interest generated after two years is
\n= Amount – Principal
\n= $5000 (1 + \\frac{0.05}{2})^{(2*2)}$ – $5000$= $1.0509*5000 – 5000$ = $5519 –
\n5000$ = Rs $519$
\nHence Option C.<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Simple interest for 2 years on Rs. 25000 at rate \u2018r\u2019 = $\\frac{25000*2*r}{100}=500r$
\nSimple interest for each year = $250r$
\nCompound interest for 2 years on Rs. 25000 at rate \u2018r\u2019 =
\nSimple interest for 1st year + Simple interest for 2nd year
\nSimple interest for 1st year = $250r$
\nSimple interest for 2nd year = $\\frac{(25000+250r)*r}{100}$ = $250r + 2.5r^2$
\nThe difference between interest is given as Rs. 1000
\nSo we get,
\n$250 + 2.5r^2 + 250r – 500r = 1000$
\n$2.5r^2 = 1000$
\n$r^2 = 400$
\n$ r = 20$%
\nThus, Option B.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

If the amount gets doubled after 5 years, the simple interest accrued will be equal to P (principal amount).
\n=> $P = \\frac{P \\times r \\times 5}{100}$ => r = 20%
\nSo, the amount after 2 years under compound interest will be
\n$1(1+\\frac{20}{100})^2 = 1(1.2)^2 = 1.44$ lacs.
\nThus, A is the correct answer.<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

We know that the formula for compound interest is given by
\nA = $P( 1 + \\frac{r}{100})^n$
\nHere A = 24200, n = 2 and r = 10, so on putting these values in the equation, we get
\n24200 = $P( 1 + \\frac{10}{100})^2$
\n=> P = 24200\/1.21 = 20,000
\nIf it is invested at 8% per annum simple interest for 3 years, the interest earned would be
\nI = (P*R*T)\/100 = 20000*3*8\/100 = 4800
\nHence, the amount will be 20,000 + 4800 = 24800<\/p>\n

Free SSC Daily Practice Set<\/a><\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Simple interest for 2 years on Rs. 20000 at rate 10% = $\\frac{20000*2*10}{100}=4000$ rupees
\nCompound interest for 2 years on Rs. 20000 at rate 10% =
\nSimple interest for 1st year + Simple interest for 2nd year
\nSimple interest for 1st year = $2000$ rupees
\nPrincipal for the second year will be 20000+2000 = Rs. 22000
\nSimple interest for 2nd year = $\\frac{(22000)*10}{100}=2200$ rupees
\nTotal simple interest = Rs. 4000
\nTotal compound interest = Rs. 2000 + Rs. 2200 = Rs. 4200
\nThe difference is Rs. 200
\nThus, Option A.<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We know that in compound interest, amount = $P(1+\\frac{r}{100})^n$
\nWhere P = principal, r = rate of interest, and n = time period
\nThe amount after 4 years in the first case will be-
\n$A1 = 120000(1.1)^4$
\n=> Interest = $120000(1.1)^4 = 120000[(1.1)^4-1]$
\nSimilarly, in the second case,
\n$A2 = 120000(1+\\frac{r}{100})^2$
\nSo, interest = $120000[(1+\\frac{r}{100})^2-1]$
\n=> $120000[(1+\\frac{r}{100})^2-1] = 120000[(1.1)^4-1]$
\n=> $(1.1)^4 = (1+\\frac{r}{100})^2$
\n=> r\/100 = 1.21 – 1 =.21
\nThus, C is the correct answer.<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Simple interest for 2 years on Rs. 50000 at rate \u2018r\u2019 = $\\frac{50000*2*r}{100}=1000r$
\nSimple interest for each year = $500r$
\nCompound interest for 2 years on Rs. 50000 at rate \u2018r\u2019 = Simple interest for 1st year + Simple interest for 2nd year
\nSimple interest for 2nd year = Simple interest for 1st year +simple interest on interest of first year
\n=$(500r)+(500r)+500r(\\frac{r}{100})$ =$1000r+5r^{2}$
\nDifference between the simple and the compound interest = $1000r+5r^{2} – 1000r$ = $5r^{2}$
\n$5r^{2} = 12500$
\n$r = 50$%
\nHence, Option B.<\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the principal amount be P.
\nSo, amount after 2 years of compound interest is $P(1+\\frac{r}{100})^n = P(1.1)^2 = 1.21P$
\nSo, the interest is 0.21 P = 3780
\n=> P = 18000
\nNow, time period for SI = 4 years and Interest = 5%
\n=> SI = 18000 * 0.05 * 4 = 3600<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the amount which has been invested be P. Then the simple interest which will be earned will be given by
\nI = P*8*2\/100 = .16P
\nWe know that the formula for compound interest is given by
\nA = $P( 1 + \\frac{r}{100})^n$
\nSo interest would be $P( 1 + \\frac{8}{100})^2 – P = .1664P$
\nWe have been given that
\n(.1664 – .16)P = 80
\n=> P = 12500
\nThus, option B is the correct answer.<\/p>\n

16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let rate of interest = $r \\%$
\nSum under compound interest = Rs. 10,000 and time period = 2 years
\n=> Amount = $P (1 + \\frac{R}{100})^T = 12,321$
\n=> $10,000 (1 + \\frac{r}{100})^2 = 12,321$
\n=> $(1 + \\frac{r}{100})^2 = \\frac{12321}{10000} = 1.2321$
\n=> $1 + \\frac{r}{100} = \\sqrt{1.2321} = 1.11$
\n=> $\\frac{r}{100} = 1.11 – 1 = 0.11$
\n=> $r = 0.11 \\times 100 = 11\\%$
\n=> Ans – (B)<\/p>\n

17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let rate of interest = $r\\%$ and time period = 2 years
\nPrincipal = Rs. 20,000 and Amount = Rs. 23,328
\nAmount after compound interest = $P(1 + \\frac{R}{100})^T$
\n=> $20,000 (1 + \\frac{r}{100})^2 = 23328$
\n=> $(1 + \\frac{r}{100})^2 = \\frac{23328}{20000} = 1.1664$
\n=> $(1 + \\frac{r}{100}) = \\sqrt{1.1664} = 1.08$
\n=> $\\frac{r}{100} = 1.08 – 1 = 0.08$
\n=> $r = 0.08 \\times 100 = 8\\%$
\n=> Ans – (A)<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let sum be = Rs. $100x$
\nRate of interest = 7% under compound interest half yearly
\nAmount after 1 year = $P (1 + \\frac{R}{2 \\times 100})^{2 \\times T}$
\n= $100x (1 + \\frac{7}{200})^{2 \\times 1}$
\n= $100x (\\frac{207}{200})^2 = \\frac{207 \\times 207 \\times x}{400}$
\n= Rs. $107.12 x$
\n=> Compound Interest = Rs. $(107.12 x – 100x)$ = Rs. $7.12 x$
\n$\\therefore$ Effective rate of interest = $\\frac{7.12 x}{100x} \\times 100$
\n= $7.12 \\%$<\/p>\n

20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The amount got doubled after 5 years.
\nSo, interest accrued in 5 years would have been P. (P is the principal amount.)
\n=> P = P X r X 5\/100
\n=> r = 20%
\nIn compound interest, amount at any time is given by $P(1+\\frac{r}{100})^n$
\nWe want to find at what \u2018n\u2019 does this amount becomes 2P.
\n=> $2P = P(1+\\frac{r}{100})^n$
\n=> $2 = (1.2)^n$
\nAt n = 3, $1.2^n = 1.728$ and at n=4 $1.2^n = 2.0736$
\nSo, the amount must have got doubled in the 4th year.<\/p>\n

SSC CHSL Free Mock Test<\/a><\/p>\n

21)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

If the rate of interest is 12% per annum, the corresponding rate for 3 months in 12%\/4 = 3% per quarter.
\nSo, the amount at the end of the year = $10,000 * (1+\\frac{3}{100})^4$ = Rs 11255.09
\nHence the interest earned = Amount – Principal = 11255.09 – 10000 = Rs 1255.09<\/p>\n

22)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

we know that
\n1. For first year , compound interest and simple interest is same if the principal amount and rate of interest is same in both cases.2. From 2nd year onwards ,the compound interest is normal interest plus the interest on accumulated amount due to interest untill last cycle.<\/p>\n

3. Every year simple interest remains same if Rate of Interest and principal amount remains same .<\/p>\n

Let the compound interest for 1st year be be Rs y
\nFor two years ,CI = Rs 410
\ny + y + $\\frac{5}{100}$y = 410
\n$\\frac{41y}{20}$ = 410
\ny = 200
\nSo for two years , Simple Interest = 200 + 200 = Rs 400<\/p>\n

23)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Principal Amount (P) = Rs 1800
\nRate of Interest = 10%
\nCompound Interest = Rs 378
\nLet the time period be T
\nSo, C.I = P$(1+ \\frac{R}{100})^T$ – P
\n378 = 1800$(1+ \\frac{10}{100})^T$ – 1800
\nT = 2 years<\/p>\n

24)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given that Rs 80000 becomes Rs 92610 at 10% per annum .
\nsemi-annual Rate become = $\\frac{10}{2}$ = 5%
\nLet number of semi-annual cycles required = T
\nSo Using ,
\nCompounded Amount = P$(1+\\frac{R}{100})^T$
\n92610 = 80000$(1+\\frac{5}{100})^T$
\nT = 3 semi annual cycles = 1.5 years<\/p>\n

25)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

it is given that A sum of money placed at compound interest doubles itself in 4 years
\nhere we need to make the money 4 times
\nimagine that we invested Rs P
\nand hence ,
\nP becomes 2P in 4 years and so this 2P will become 4P in another 4 years and hence total 8 years are required to make Rs P –> Rs 4P<\/p>\n

\"SSC<\/a><\/p>\n

SSC Free Previous Papers App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

SSC CGL Compound Interest Questions PDF: Download SSC CGL Compound Interest questions with answers PDF based on previous papers very useful for SSC CGL exams. 25 Very important Compound Interest objective questions for SSC exams. Question 1:\u00a0In how many years will a sum of Rs. 800 at 10% per annum compound interest, compounded semiannually becomes […]<\/p>\n","protected":false},"author":21,"featured_media":25832,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,504],"tags":[1519],"class_list":{"0":"post-25830","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc-cgl","10":"tag-ssc-cgl-2019"},"better_featured_image":{"id":25832,"alt_text":"SSC CGL Compound Interest Questions PDF","caption":"SSC CGL Compound Interest Questions PDF","description":"SSC CGL Compound Interest Questions PDF","media_type":"image","media_details":{"width":900,"height":472,"file":"2019\/03\/fig-07-03-2019_11-05-10.jpg","sizes":{"thumbnail":{"file":"fig-07-03-2019_11-05-10-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-150x150.jpg"},"medium":{"file":"fig-07-03-2019_11-05-10-300x157.jpg","width":300,"height":157,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-300x157.jpg"},"medium_large":{"file":"fig-07-03-2019_11-05-10-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-768x403.jpg"},"tiny-lazy":{"file":"fig-07-03-2019_11-05-10-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-30x16.jpg"},"td_80x60":{"file":"fig-07-03-2019_11-05-10-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-80x60.jpg"},"td_100x70":{"file":"fig-07-03-2019_11-05-10-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-100x70.jpg"},"td_218x150":{"file":"fig-07-03-2019_11-05-10-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-218x150.jpg"},"td_265x198":{"file":"fig-07-03-2019_11-05-10-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-265x198.jpg"},"td_324x160":{"file":"fig-07-03-2019_11-05-10-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-324x160.jpg"},"td_324x235":{"file":"fig-07-03-2019_11-05-10-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-324x235.jpg"},"td_324x400":{"file":"fig-07-03-2019_11-05-10-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-324x400.jpg"},"td_356x220":{"file":"fig-07-03-2019_11-05-10-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-356x220.jpg"},"td_356x364":{"file":"fig-07-03-2019_11-05-10-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-356x364.jpg"},"td_533x261":{"file":"fig-07-03-2019_11-05-10-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-533x261.jpg"},"td_534x462":{"file":"fig-07-03-2019_11-05-10-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-534x462.jpg"},"td_696x0":{"file":"fig-07-03-2019_11-05-10-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-696x365.jpg"},"td_696x385":{"file":"fig-07-03-2019_11-05-10-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-696x385.jpg"},"td_741x486":{"file":"fig-07-03-2019_11-05-10-741x472.jpg","width":741,"height":472,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-741x472.jpg"},"td_0x420":{"file":"fig-07-03-2019_11-05-10-801x420.jpg","width":801,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10-801x420.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":null,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/fig-07-03-2019_11-05-10.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n