10 RRB JE Mocks – Just Rs. 117<\/a><\/p>\n RRB JE Previous Papers [Download PDF]<\/a><\/p>\n Question 1:\u00a0<\/b>Find the number which should replace \u2018?\u2019. a)\u00a0121<\/p>\n b)\u00a0110<\/p>\n c)\u00a0100<\/p>\n d)\u00a0108<\/p>\n Question 2:\u00a0<\/b>Find the number which will replace \u2018?\u2019. a)\u00a0200<\/p>\n b)\u00a0136<\/p>\n c)\u00a0152<\/p>\n d)\u00a0180<\/p>\n <\/p>\n Question 3: <\/b>Which of the following numbers replaces the question mark in the given sequence? a) 1236 FREE RRB JE YOUTUBE VIDEOS<\/a><\/p>\n RRB NTPC Free Mock Test<\/a><\/p>\n <\/p>\n Question 4:\u00a0<\/b>A series is given with one missing term. Choose the correct alternative from the given optons that will complete the series. a)\u00a082<\/p>\n b)\u00a074<\/p>\n c)\u00a078<\/p>\n d)\u00a068<\/p>\n Question 5:\u00a0<\/b>Identify the term which will come next in the following number series. a)\u00a0447<\/p>\n b)\u00a0348<\/p>\n c)\u00a0512<\/p>\n d)\u00a0391<\/p>\n Question 6:\u00a0<\/b>Find the next number in the series. a)\u00a0432<\/p>\n b)\u00a081<\/p>\n c)\u00a072<\/p>\n d)\u00a0512<\/p>\n Question 7:\u00a0<\/b>A series is given with one missing term. Choose the correct alternative from the given optons that will complete the series. a)\u00a03552<\/p>\n b)\u00a03486<\/p>\n c)\u00a03628<\/p>\n d)\u00a03494<\/p>\n RRB NTPC Previous Papers Download PDF<\/a><\/p>\n Question 8:\u00a0<\/b>What number comes in the place of the question mark? a)\u00a021<\/p>\n b)\u00a031<\/p>\n c)\u00a020<\/p>\n d)\u00a041<\/p>\n Question 9:\u00a0<\/b>In the figure given below, find the number that can come in the place of the question mark? a)\u00a013<\/p>\n b)\u00a014<\/p>\n c)\u00a015<\/p>\n d)\u00a016<\/p>\n Question 10:\u00a0<\/b>Find the missing number ? a)\u00a035<\/p>\n b)\u00a047<\/p>\n c)\u00a053<\/p>\n d)\u00a051<\/p>\n Question 11:\u00a0<\/b>From the alternatives, select the set which is most like the given set. Given set (23,29,31)-<\/p>\n a)\u00a0(17,21,29)<\/p>\n b)\u00a0(31,37,49)<\/p>\n c)\u00a0(13,15,23)<\/p>\n d)\u00a0(41,43,47)<\/p>\n Question 12:\u00a0<\/b>Find the next number in the series: a)\u00a032<\/p>\n b)\u00a036<\/p>\n c)\u00a042<\/p>\n d)\u00a016<\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n Question 13:\u00a0<\/b>Find the missing number in the series. a)\u00a050<\/p>\n b)\u00a049<\/p>\n c)\u00a048<\/p>\n d)\u00a0102<\/p>\n Question 14:\u00a0<\/b>If \u201cCLASS\u201d is coded as \u201cBKZRR\u201d then how will \u201cRIGHT\u201d be coded?<\/p>\n a)\u00a0QHFGS<\/p>\n b)\u00a0RGEFT<\/p>\n c)\u00a0SFDGU<\/p>\n d)\u00a0VEGHW<\/p>\n Question 15:\u00a0<\/b>Complete the following series: 10, 17, 25, 34, 44, ?<\/p>\n a)\u00a054<\/p>\n b)\u00a055<\/p>\n c)\u00a064<\/p>\n d)\u00a061<\/p>\n RRB NTPC Free Mock Test<\/a><\/p>\n RRB JE Free Mock Test<\/a><\/p>\n Question 16:\u00a0<\/b>Find the median of the following numbers a)\u00a015<\/p>\n b)\u00a020<\/p>\n c)\u00a017<\/p>\n d)\u00a011<\/p>\n Question 17:\u00a0<\/b>How many 4\u2019sare there in the following number – series which are preceded by 5 but NOT followed by 7 ? a)\u00a0Three<\/p>\n b)\u00a0Four<\/p>\n c)\u00a0Five<\/p>\n d)\u00a0None<\/p>\n Question 18:\u00a0<\/b>Consider the natural number 88935. Then the least natural number by which we can divide or multiply the number to make it a square number is<\/p>\n a)\u00a03<\/p>\n b)\u00a05<\/p>\n c)\u00a015<\/p>\n d)\u00a0None of these<\/p>\n Question 19:\u00a0<\/b>Which number comes next in the series a)\u00a039<\/p>\n b)\u00a049<\/p>\n c)\u00a043<\/p>\n d)\u00a050<\/p>\n Daily Free Online Tests for RRB Exams<\/a><\/p>\n Question 20:\u00a0<\/b>Identify the wrong number in the following series- 842, 790, 739, 686, 634, 582<\/p>\n a)\u00a0842<\/p>\n b)\u00a0739<\/p>\n c)\u00a0686<\/p>\n d)\u00a0634<\/p>\n Instructions<\/b><\/p>\n In the following question, select the missing number from the given series.<\/p>\n Question 21:\u00a0<\/b>9, 19, 37, 75, 149, ?<\/p>\n a)\u00a0297<\/p>\n b)\u00a0298<\/p>\n c)\u00a0300<\/p>\n d)\u00a0299<\/p>\n Question 22:\u00a0<\/b>In the following question, select the missing number from the given series. a)\u00a038<\/p>\n b)\u00a036<\/p>\n c)\u00a040<\/p>\n d)\u00a039<\/p>\n Question 23:\u00a0<\/b>A series is given with one missing term. Choose the correct alternative from the given options that will complete the series. a)\u00a039<\/p>\n b)\u00a043<\/p>\n c)\u00a037<\/p>\n d)\u00a041<\/p>\n Download RRB GK Material PDF<\/a><\/p>\n Question 24:\u00a0<\/b>A series is given with one missing term. Choose the correct alternative from the given options that will complete the series. a)\u00a0261<\/p>\n b)\u00a0304<\/p>\n c)\u00a0245<\/p>\n d)\u00a0273<\/p>\n Question 25:\u00a0<\/b>In the following question, select the missing number from the given series.<\/p>\n 8, 16, 43, 107, 232, ?<\/strong><\/p>\n a)\u00a0342<\/p>\n b)\u00a0448<\/p>\n c)\u00a0248<\/p>\n d)\u00a0528<\/p>\n Question 26:\u00a0<\/b>In the following question, select the missing number from the given series. a)\u00a0193<\/p>\n b)\u00a0203<\/p>\n c)\u00a0163<\/p>\n d)\u00a0218<\/p>\n Question 27:\u00a0<\/b>Insert the correct missing number from the choices given below<\/p>\n a)\u00a036<\/p>\n b)\u00a015<\/p>\n c)\u00a051<\/p>\n d)\u00a069<\/p>\n Question 28:\u00a0<\/b>Select the missing number from the given responses : a)\u00a030<\/p>\n b)\u00a055<\/p>\n c)\u00a060<\/p>\n d)\u00a070<\/p>\n Question 29:\u00a0<\/b>If 1 + 4=9, 2 + 8=18, 3+6 = 15 then 7 + 8 = ?<\/p>\n a)\u00a041<\/p>\n b)\u00a023<\/p>\n c)\u00a030<\/p>\n d)\u00a032<\/p>\n Question 30:\u00a0<\/b>40% of 1620 + 30% of 960 = ? % of 5200<\/p>\n a)\u00a012<\/p>\n b)\u00a024<\/p>\n c)\u00a016<\/p>\n d)\u00a018<\/p>\n General Science Notes for RRB Exams (PDF)<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The series follows the following pattern: 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The series follows the following pattern – $n^3 – n^2$<\/p>\n $2^3 – 2^2 = 4$ 3)\u00a0Answer: (D)<\/b><\/p>\n 4 = 2*1*2 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 18 + 1*8 = 26 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The pattern which is being followed is that the square of the sum of the digits of the number is being added to the number to get the next number. For example, $11 + 2^2 = 15$ 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The series follows the following pattern: 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 2256 – 1937 = 319 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In the left column, 1 + $3^2$ = 10 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The given list is the list of prime numbers from 2 to 23. So, 13 comes in the place of the question mark.<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The difference between the numbers alternates between 2 and 4. For example, the first number is 2 less than the second number. And the second number is 4 less than the third and the third number is 2 less than the fourth and so on.<\/p>\n 11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The numbers in the given set are prime numbers.Similarly, the numbers in the set of option D are also prime.<\/p>\n 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n We see that the differences between consecutives terms is -512, -256, -128, -64. Hence, each term is half of the previous term.<\/p>\n Thus next term = 64\/2 = 32.<\/p>\n 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n We see that the differences between consecutives terms is -4, -5, -6, -7. Thus, the differences are in arithmetic progression. Thus, the previous difference would have been -4+1=-3 and -3+1=-2. Thus, the term missing is 2 lesser than 51 and 3 greater than 46 i.e. 51-2=49.<\/p>\n 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n In the coded language every letter is 1 back from the original word in alphabetical series. Hence, \u201cRight\u201d will be coded as \u201cQHFGS\u201d<\/p>\n 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 10+7 = 17; 17+8 = 25 ; 25+9 = 34 ; 34+10 = 44 ; 44+11 = 55<\/p>\n 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n To find the median, we have the arrange the numbers in the ascending order and then pick the number that’s at the centre of the list. So,<\/p>\n the list in arranging order is: 9, 11, 12, 14, 15, 17, 20, 21, 23, 24, 25. Since 17 is at the centre of the list, it is the median of the group.<\/p>\n 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n There are 3 4s that are preceeded by 5s but are also followed by 7s. So, the answer is “none”.<\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 88935=11$^{2}$\u00d77$^{2}$\u00d715<\/p>\n Thus, if we multiply or divide with 15 we get square numbers.<\/p>\n 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Each term is 7 greater than the previous term. Hence, the next number should be 36+7 = 43.<\/p>\n 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 842 – 52 = 790 21)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The pattern followed is :<\/p>\n 9 $\\times$ $2+1$ = 19<\/p>\n 19 $\\times$ $2-1$ = 37<\/p>\n 37 $\\times$ $2+1$ = 75<\/p>\n 75 $\\times$ $2-1$ = 149<\/p>\n 149 $\\times$ $2+1$ = 299<\/strong><\/p>\n => Ans – (D)<\/p>\n 22)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 3 is subtracted from all the numbers.<\/p>\n 54 – 3 = 51<\/p>\n 51 – 3 = 48<\/p>\n 48 – 3 = 45<\/p>\n 45 – 3 = 42<\/p>\n 42 – 3 = 39<\/strong><\/p>\n => Ans – (D)<\/p>\n 23)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 15 + 1 + 5 = 21 24)\u00a0Answer\u00a0(A)<\/strong><\/p>\n $795 – 13^2 = 626$ 25)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Cubes of consecutive integers are added.<\/p>\n 8 $+(2)^3$ = 16<\/p>\n 16 $+(3)^3$ = 43<\/p>\n 43 $+(4)^3$ = 107<\/p>\n 107 $+(5)^3$ = 232<\/p>\n 232 $+(6)^3$ = 448<\/strong><\/p>\n => Ans – (B)<\/p>\n 26)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Multiples of 15 are added.<\/p>\n 43 + 15 = 58<\/p>\n 58 + 30 = 88<\/p>\n 88 + 45 = 133<\/p>\n 133 + 60 = 193<\/strong><\/p>\n 193 + 75 = 268<\/p>\n => Ans – (A)<\/p>\n 27)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 28)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Value in row 1 $\\times$ value in row 2 $\\times$ Value in Row 3 = Value in Row 4<\/p>\n Let the unknown be $x$. Hence Option A is the correct answer<\/p>\n 29)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Here we are given :<\/p>\n 1 + 4=9<\/p>\n 2 + 8=18<\/p>\n 3+6 = 15<\/p>\n So if the number is , x + y then it is equal to [(x+y) + y]<\/p>\n here we need to calculate value of 7 + 8 = [(7 + 8) + 8] = 23<\/p>\n 30)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 40% of 1620 = $\\frac{40 \\times 1620}{100}$ = $ 648 $ Hence option D is the correct answer.<\/p>\n![\"RRB](\"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/03\/RRB-JE-Mock-Test.png\")
<\/p>\n
\n2, 3, 7, 25, ?<\/p>\n
\n4, 18, 48, 100, ?<\/p>\n
\n2, 4, 32, 576, ?<\/p>\n
\nb) 1048
\nc) 894
\nd) None of these<\/p>\n<\/p>\n
\n18, 26, 38, 62, ? , 102<\/p>\n
\n11, 15, 51, 87, 312, ?<\/p>\n
\n243, 486, 162, 324, 108, 216, ?<\/p>\n
\n1937, 2256, 2577, 2900, 3225, ?<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/1%20copy.jpg\")
<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/12_C0NpDon.JPG\")
<\/p>\n<\/p>\n
\n11,13,17,19,23,25,29,31\u2026\u2026\u2026..<\/p>\n
\n1024, 512, 256, 128, 64, _____<\/p>\n
\n51, ?, 46, 42, 37, 31, 24<\/p>\n
\n14, 23, 20, 12, 11, 15, 24, 17, 9, 21, 25<\/p>\n<\/p>\n
\n23423425473243192547547234529546<\/p>\n
\n1, 8, 15, 22, 29, 36, ?<\/p>\n<\/p>\n
\n54, 51, 48, 45, 42, ?<\/p>\n
\n15, 21, 24, 30, 33, ?<\/p>\n
\n795, 626, 482, 361, ?, 180<\/p>\n
\n43, 58, 88, 133, ?, 268<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/68720.PNG\")
<\/p>\n<\/p>\n
\n1! + 1 = 2
\n2! + 1 = 3
\n3! + 1 = 7
\n4! + 1 = 25
\n5! + 1 = 121<\/p>\n
\n$3^3 – 3^2 = 18$
\n$4^3 – 4^2 = 48$
\n$5^3 – 5^2 = 100$
\n$6^3 – 6^2 = 180$<\/p>\n
\n32 = 4*2*4
\n576 = 32*3*6
\nTherefore, the next number in the sequence should be 576*4*8 = 18432.
\nSince there is no such option, the correct option to choose is D.<\/p>\n
\n26 + 6*2 = 38
\n38 + 3*8 = 62
\n62 + 6*2 = 74
\n74 + 7*4 = 102
\nHence, option B is the right answer.<\/p>\n
\n$15 + 6^2 = 51$
\n$51 + 6^2 = 87$
\n$87 + 15^2 = 312$
\nHence, using the same logic the next term will be
\n$312 + (3+1+2)^2 = 348$
\nHence, option B is the correct answer.<\/p>\n
\n243
\n243 * 2 = 486
\n486 \/3 = 162
\n162 * 2 = 324
\n324\/3 = 108
\n108 * 2 = 216
\n216 \/ 3 = 72<\/p>\n
\n2577 – 2256 = 319 + 2
\n2900 – 2577 = 319 + 4
\n3225 – 2900 = 319 + 6
\n? = 3225 + 319 + 8 = 3552
\nHence, option A is the right answer.<\/p>\n
\nIn the right column, 2 + $7^2$ = 51
\nSo, the middle column = 5 * $6^2$ = 41<\/p>\n<\/p>\n
\n790 – 52 = 738
\n738 – 52 = 686
\n686 – 52 = 634
\n634 – 52 = 582
\nSo, 739 is the wrong number in the series. It should be replaced with 738.<\/p>\n
\n21 + 2 + 1 = 24
\n24 + 2 + 4 = 30
\n30 + 3 + 0 = 33
\n33 + 3 + 3 = 39
\nHence, option A is the right answer.<\/p>\n
\n$626 – 12^2 = 482$
\n$482 – 11^2 = 361$
\n$361- 10^2 = 261$
\n$261 – 9^2 = 180$
\nHence, option A is the right answer.<\/p>\n
\n$6 \\times x \\times 5 = 900$
\nHence $x$ = $\\frac{900}{30}$
\n$x$ =$ 30$<\/p>\n
\n30% of 960 = $\\frac{30 \\times 960}{100}$ = $ 288 $
\n648 + 288 = 936
\nLet the unknown percentage be $x$.
\n$ 936 = x \\% of 5200$
\n$x = \\frac{936 \\times 100}{5200} = 18 $<\/p>\n