Coded Equation Questions For SSC GD PDF<\/p>\n
SSC GD Constable Coded Equation Question paper with answers download PDF based on SSC GD exam previous papers. 40 Very important Coded Equation questions for GD Constable.<\/p>\n
DOWNLOAD CODED EQUATION QUESTIONS FOR SSC GD PDF<\/a><\/p>\n GET 20 SSC GD MOCK FOR JUST RS. 117<\/a><\/p>\n FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n Download SSC GD Important Questions PDF<\/a><\/p>\n 1500<\/strong>+ Must Solve Questions for SSC Exams<\/a> (Question bank)<\/p>\n Question 1:\u00a0<\/b>If $\u2018+\u2019 means \u2018\\times\u2019, \u2018-\u2019 means \u2018\\div\u2019, \u2018\\times\u2019 means \u2018-\u2019, \u2018\\div\u2019 means \u2018+\u2019$ $33+11\\div15\\times4-7$=?<\/p>\n a)\u00a018<\/p>\n b)\u00a020<\/p>\n c)\u00a022<\/p>\n d)\u00a016<\/p>\n Question 2:\u00a0<\/b>If $\u2018+\u2019 means \u2018\\times\u2019, \u2018-\u2019 means \u2018\\div\u2019, \u2018\\times\u2019 means \u2018-\u2019, \u2018\\div\u2019 means \u2018+\u2019$ $72+4\\div12\\times7-8$=?<\/p>\n a)\u00a066<\/p>\n b)\u00a064<\/p>\n c)\u00a062<\/p>\n d)\u00a060<\/p>\n Question 3:\u00a0<\/b>If $\u2018+\u2019 means \u2018\\times\u2019, \u2018-\u2019 means \u2018\\div\u2019, \u2018\\times\u2019 means \u2018-\u2019, \u2018\\div\u2019 means \u2018+\u2019$ $32+2\\div4\\times13-6$=?<\/p>\n a)\u00a090<\/p>\n b)\u00a080<\/p>\n c)\u00a070<\/p>\n d)\u00a060<\/p>\n Question 4:\u00a0<\/b>In the following question, correct the equation by interchanging two signs. a)\u00a0+,-<\/p>\n b)\u00a0$\\div,\\times$<\/p>\n c)\u00a0$\\div,+$<\/p>\n d)\u00a0$\\div,-$<\/p>\n Instructions<\/b><\/p>\n Which of the following signs should be interchanged so that the given equation is true?<\/p>\n Question 5:\u00a0<\/b>$153\\div51\\times17+3-21 = 33$<\/p>\n a)\u00a0$\\times$ and +<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Download SSC GD FREE PREVIOUS PAPERS<\/a><\/p>\n LATEST FREE SSC GD MOCK 2019<\/a><\/p>\n Question 6:\u00a0<\/b>$144+9\\div19\\times6-24 = 96$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Instructions<\/b><\/p>\n Which of the following signs should be interchanged so that the given equation is true?<\/p>\n Question 7:\u00a0<\/b>$104\\div13\\times6-7+34 = 0$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Question 8:\u00a0<\/b>$84\\div6-7\\times13 = 85$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Question 9:\u00a0<\/b>$108-12\\div19+6\\times8 = 38$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Question 10:\u00a0<\/b>$119\\times17+15\\div6-8 = 89$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n DOWNLOAD APP TO ACESS DIRECTLY ON MOBILE<\/a><\/p>\n Daily Free SSC Practice Set<\/a><\/p>\n Question 11:\u00a0<\/b>$92+23\\div6\\times3-2 = 20$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Question 12:\u00a0<\/b>$102\\times6+7\\div14-12 = 103$<\/p>\n a)\u00a0$\\times$ and –<\/p>\n b)\u00a0+ and $\\div$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Question 13:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $189-21\\div112-7\\times25$<\/p>\n a)\u00a00<\/p>\n b)\u00a07<\/p>\n c)\u00a013<\/p>\n d)\u00a02<\/p>\n Question 14:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $133-19+4\\times78-13$<\/p>\n a)\u00a016<\/p>\n b)\u00a08<\/p>\n c)\u00a022<\/p>\n d)\u00a031<\/p>\n Question 15:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $63-3+2\\times117-13$<\/p>\n a)\u00a026<\/p>\n b)\u00a021<\/p>\n c)\u00a042<\/p>\n d)\u00a033<\/p>\n SSC CGL Free Mock Test<\/a><\/p>\n Download SSC GD Constable Syllabus PDF<\/a><\/p>\n Question 16:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $91-7+2\\times4+6$<\/p>\n a)\u00a08<\/p>\n b)\u00a02<\/p>\n c)\u00a00<\/p>\n d)\u00a012<\/p>\n Question 17:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $82-2+3\\div51-17$<\/p>\n a)\u00a0134<\/p>\n b)\u00a082<\/p>\n c)\u00a098<\/p>\n d)\u00a0126<\/p>\n Question 18:\u00a0<\/b>In a certain code, 3 @ 4 & 2 = 5 and 8 @ 5 & 7=6, then 8 @ 6 & 14 = ?<\/p>\n a)\u00a012<\/p>\n b)\u00a06<\/p>\n c)\u00a00<\/p>\n d)\u00a01<\/p>\n Question 19:\u00a0<\/b>In a certain code, 35 # 7 % 2 = 10 and 24 # 8 % 3 = 9, then find the value of 16 # 2 % 4<\/p>\n a)\u00a028<\/p>\n b)\u00a032<\/p>\n c)\u00a041<\/p>\n d)\u00a016<\/p>\n Question 20:\u00a0<\/b>In a certain code, 3 $ 7 @ 6 = 27, 4 $ 5 @ 3 = 23, then 13 $ 3 @ 2 = ?<\/p>\n a)\u00a039<\/p>\n b)\u00a052<\/p>\n c)\u00a041<\/p>\n d)\u00a027<\/p>\n Question 21:\u00a0<\/b>Which of the following signs should be interchanged so that the given equation is true? a)\u00a0$\\div$ and –<\/p>\n b)\u00a0+ and –<\/p>\n c)\u00a0+ and $\\div$<\/p>\n d)\u00a0$\\times$ and +<\/p>\n Question 22:\u00a0<\/b>Which of the following signs should be interchanged so that the given equation is true? a)\u00a0$\\div$ and –<\/p>\n b)\u00a0$\\times$ and +<\/p>\n c)\u00a0+ and –<\/p>\n d)\u00a0+ and $\\div$<\/p>\n Question 23:\u00a0<\/b>Which of the following signs should be interchanged so that the given equation is true? a)\u00a0+ and –<\/p>\n b)\u00a0+ and $\\times$<\/p>\n c)\u00a0$\\times$ and $\\div$<\/p>\n d)\u00a0– and $\\div$<\/p>\n Question 24:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $93-3+2\\div14\\times38$<\/p>\n a)\u00a042<\/p>\n b)\u00a018<\/p>\n c)\u00a028<\/p>\n d)\u00a038<\/p>\n Question 25:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $84-21+2\\times6\\div14$<\/p>\n a)\u00a012<\/p>\n b)\u00a026<\/p>\n c)\u00a018<\/p>\n d)\u00a016<\/p>\n Question 26:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $72-9+2\\div86$<\/p>\n a)\u00a0107<\/p>\n b)\u00a0102<\/p>\n c)\u00a096<\/p>\n d)\u00a0108<\/p>\n Question 27:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $29\\times7\\div24-8+2$<\/p>\n a)\u00a024<\/p>\n b)\u00a016<\/p>\n c)\u00a032<\/p>\n d)\u00a028<\/p>\n Question 28:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $16-4+12\\div7\\times2$<\/p>\n a)\u00a051<\/p>\n b)\u00a067<\/p>\n c)\u00a053<\/p>\n d)\u00a029<\/p>\n Question 29:\u00a0<\/b>Which of the following signs should be interchanged so that the given equation is true? a)\u00a0$\\times$ and +<\/p>\n b)\u00a0$\\div$ and –<\/p>\n c)\u00a0+ and $\\times$<\/p>\n d)\u00a0+ and $\\div$<\/p>\n Question 30:\u00a0<\/b>Which of the following signs should be interchanged so that the given equation is true? a)\u00a0$\\times$ and +<\/p>\n b)\u00a0$\\div$ and –<\/p>\n c)\u00a0+ and $\\times$<\/p>\n d)\u00a0+ and $\\div$<\/p>\n Question 31:\u00a0<\/b>Which of the following signs should be interchanged so that the given equation is true? a)\u00a0$\\div$ and $\\times$<\/p>\n b)\u00a0$\\div$ and –<\/p>\n c)\u00a0$\\times$ and –<\/p>\n d)\u00a0– and +<\/p>\n Question 32:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019-, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $64-16+2\\times8-4\\div2$<\/p>\n a)\u00a06<\/p>\n b)\u00a04<\/p>\n c)\u00a08<\/p>\n d)\u00a02<\/p>\n Question 33:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019-, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $54-9+2\\div24-8$<\/p>\n a)\u00a012<\/p>\n b)\u00a024<\/p>\n c)\u00a016<\/p>\n d)\u00a015<\/p>\n Question 34:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019-, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $27-3+6\\div5\\times4-2$<\/p>\n a)\u00a052<\/p>\n b)\u00a057<\/p>\n c)\u00a062<\/p>\n d)\u00a073<\/p>\n 100+ Free GK Tests for SSC Exams<\/a><\/p>\n Download Free GK PDF<\/a><\/p>\n Question 35:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018-\u2019-, \u2018$\\div$\u2019 means \u2018+\u2019, then find the value of $69-23\\div25+4-10$?<\/p>\n a)\u00a011<\/p>\n b)\u00a023<\/p>\n c)\u00a013<\/p>\n d)\u00a017<\/p>\n Question 36:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018+\u2019, \u2018$\\div$\u2019 means \u2018-\u2019. Then find the value of $34-17+2\\times16\\times20-5+4$<\/p>\n a)\u00a032<\/p>\n b)\u00a028<\/p>\n c)\u00a024<\/p>\n d)\u00a036<\/p>\n Question 37:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018+\u2019, \u2018$\\div$\u2019 means \u2018-\u2019. Then find the value of $63-3-21\\times16-4+2$<\/p>\n a)\u00a06<\/p>\n b)\u00a07<\/p>\n c)\u00a09<\/p>\n d)\u00a011<\/p>\n Question 38:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018+\u2019, \u2018$\\div$\u2019 means \u2018-\u2019. Then find the value of $23\\times25-5+2\\div3$<\/p>\n a)\u00a020<\/p>\n b)\u00a025<\/p>\n c)\u00a030<\/p>\n d)\u00a035<\/p>\n Question 39:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018+\u2019, \u2018$\\div$\u2019 means \u2018-\u2019. Then find the value of $12\\times4-2+8-4$<\/p>\n a)\u00a010<\/p>\n b)\u00a012<\/p>\n c)\u00a016<\/p>\n d)\u00a014<\/p>\n Question 40:\u00a0<\/b>If \u2018+\u2019 means \u2018$\\times$\u2019, \u2018-\u2019 means \u2018$\\div$\u2019, \u2018$\\times$\u2019 means \u2018+\u2019, \u2018$\\div$\u2019 means \u2018-\u2019. Then find the value of $16+4-2\\times8\\div4$<\/p>\n a)\u00a032<\/p>\n b)\u00a036<\/p>\n c)\u00a024<\/p>\n d)\u00a020<\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n By decoding it becomes as $33\\div11-15+4\\times7$=16<\/p>\n 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n By decoding it becomes as $72\\div4-12+7\\times8$=62<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n By decoding it becomes as $32\\div2-4+13\\times6$=90<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n By decoding we get $12\\div5\\times5+6-5$ 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n After interchanging + and $\\times$, we get SSC GD FREE STUDY MATERIAL<\/a><\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n After interchanging + and $\\div$, we get 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n After interchanging $\\times$ and -, we get 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n After interchanging $\\times$ and -, we get 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n After interchanging $\\div$ and -, we get 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n After interchanging $\\div$ and $\\times$, we get 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n After interchanging + and \\div in the given equation, we get 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n After interchanging $\\times$ and $\\div$ in the given equation, we get<\/p>\n $102\\div6+7\\times14-12$ = 17+98-12 = 103<\/p>\n 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Decoding $189-21\\div112-7\\times25$, we get 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Decoding $133-19+4\\times78-13$, we get<\/p>\n $133\\div19\\times4-78\\div13 = 28-6 = 22$<\/p>\n 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Decoding $63-3+2\\times117-13$, we get 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Decoding $91-7+2\\times4+6$, we get<\/p>\n $91\\div7\\times2-4\\times6 = 26-24 = 2$<\/p>\n 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Decoding $82-2+3\\div51-17$, we get 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 3+4-2 = 5 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $35\\div7\\times2 = 10$ Here, $\\div$ is coded as # and $\\times$ is coded as %. 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $3\\times7+6 = 27$ Then, the code for $\\times$ is ‘$’ and the code for + is ‘@’.<\/p>\n $\\therefore$ 13 $ 3 @ 2 $= 13\\times3+2 = 41$<\/p>\n 21)\u00a0Answer\u00a0(B)<\/strong><\/p>\n After interchanging – and + in the given equation, we get<\/p>\n $14\\times2-7+8\\div2 = 28-7+4 = 25$<\/p>\n 22)\u00a0Answer\u00a0(A)<\/strong><\/p>\n After interchanging $\\div$ and – in the given equation, we get 23)\u00a0Answer\u00a0(A)<\/strong><\/p>\n After interchanging + and – in the given equation, we get 24)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $93-3+2\\div14\\times38 = 93\\div3\\times2+14-38 = 62+14-38 = 38$<\/p>\n 25)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $84-21+2\\times6\\div14 = 84\\div21\\times2-6+14 = 8-6+14 = 16$<\/p>\n 26)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $72-9+2\\div86 = 72\\div9\\times2+86 = 16+86 = 102$<\/p>\n 27)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $29\\times7\\div24-8+2 = 29-7+24\\div8\\times2 = 22+6 = 28$<\/p>\n 28)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $16-4+12\\div7\\times2 = 16\\div4\\times12+7-2$ 29)\u00a0Answer\u00a0(B)<\/strong><\/p>\n After interchanging $\\div$ and -, $34\\div17+16-2\\times4 = 2+8 = 10$<\/p>\n 30)\u00a0Answer\u00a0(D)<\/strong><\/p>\n After interchanging + and $\\div$, $24\\div6\\times3+4-2 = 12+2 = 14$<\/p>\n 31)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Interchanging $\\div$ and – 32)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $64-16+2\\times8-4\\div2 $= $64\\div16\\times2-8\\div4+2$ = 8-2+2 = 8<\/p>\n 33)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $54-9+2\\div24-8$ = $54\\div9\\times2+24\\div8 = 12+3 = 15$<\/p>\n 34)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $27-3+6\\div5\\times4-2 = 27\\div3\\times6+5-4\\div2 = 54+3 = 57$<\/p>\n 35)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $69-23\\div25+4-10 = 69\\div23+25\\times4\\div10$ 36)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $34-17+2\\times16\\times20-5+4 = 34\\div17\\times2+16+20\\div5\\times4 = 4+16+16 = 36$<\/p>\n 37)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $63-3-21\\times16-4+2 = 63\\div3\\div21+16\\div4\\times2$<\/p>\n $= 1+\\frac{16}{4}\\times2 = 1+8 = 9$<\/p>\n 38)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $23\\times25-5+2\\div3 = 23+25\\div5\\times2-3 = 23+10-3 = 30$<\/p>\n 39)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $12\\times4-2+8-4 = 12+4\\div2\\times8\\div4 = 12+4 = 16$<\/p>\n 40)\u00a0Answer\u00a0(B)<\/strong><\/p>\n $16+4-2\\times8\\div4 = 16\\times4\\div2+8-4$
\n$12\\div5\\times5+6-5$<\/p>\n
\n$14\\times2+7-8\\div2 = 25$<\/p>\n
\n$28-7+56\\div7\\times6 $= 18<\/p>\n
\n$33\\div11-24+4\\times3 = 15$<\/p>\n
\n$34-17+16\\div2\\times4 = 10$<\/p>\n
\n$24+6\\times3\\div4-2 = 14$<\/p>\n
\n$63-21+8\\div2\\times5 = 1$<\/p>\n
\nInto $12\\times5\\div5+6-5$=13
\nSo the option b is correct<\/p>\n
\n$153\\div51+17\\times3-21 = 3+51-21 = 33$<\/p>\n
\n$144\\div9+19\\times6-24 = 16+114-24 = 96$<\/p>\n
\n$104\\div13-6\\times7+34 = 8-42+34 = 0$<\/p>\n
\n$84\\div6\\times7-13 = 98-13 = 85$<\/p>\n
\n$108\\div12-19+6\\times8 = 9-19+48 = 38$<\/p>\n
\n$119\\div17+15\\times6-8 = 7+90-8 = 89$<\/p>\n
\n$92\\div23+6\\times3-2 = 4+18-2 = 20$<\/p>\n
\n$189\\div21+112\\div7-25 $= 9+16-25 = 0<\/p>\n
\n$63\\div3\\times2-117\\div13 = 42-9 = 33$<\/p>\n
\n$82\\div2\\times3+51\\div17 = 123+3 = 126$<\/p>\n
\n8+5-7 = 6.
\nHere, + is coded as @ and – is coded as &
\nThen, 8 @ 6 & 14 = 8+6-14 = 0<\/p>\n
\n$24\\div8\\times3 = 9$<\/p>\n
\nHence, $16\\div2\\times4 = 8\\times4 = 32$<\/p>\n
\n$4\\times5+3 = 23$<\/p>\n
\n$28\\div7+56-7\\times6 = 60-42 = 18$<\/p>\n
\n$33\\div11+24-4\\times3 = 3+24-12 = 3+12 = 15$<\/p>\n
\n$= 48+7-2 = 53$<\/p>\n
\n$63\\div21+8-2\\times5 = 3+20 = 23$<\/p>\n
\n$= 3+10 = 13$<\/p>\n
\n$= 32+8-4 = 40-4 = 36$<\/p>\n