SSC Stenographer Constable Number System Question and Answers download PDF based on previous year question paper of SSC Stenographer exam. 20 Very important Number System questions for Stenographer Constable.<\/p>\n
NUMBER SYSTEM QUESTIONS FOR SSC CHSL PDF<\/a><\/p>\n Get 1 Year Cracku Pass – Rs. 299<\/a><\/p>\n Download Topic Wise SSC CHSL Important Questions PDF<\/a><\/p>\n SSC CHSL Study Material<\/a> (FREE Tests)<\/p>\n Question 1:\u00a0<\/b>The number 323 has<\/p>\n a)\u00a0three prime factors<\/p>\n b)\u00a0five prime factors<\/p>\n c)\u00a0two prime factors<\/p>\n d)\u00a0no prime factor<\/p>\n Question 2:\u00a0<\/b>The difference of a number consisting of two digits from the number formed by interchanging the digits is always divisible by<\/p>\n a)\u00a010<\/p>\n b)\u00a09<\/p>\n c)\u00a011<\/p>\n d)\u00a06<\/p>\n Question 3:\u00a0<\/b>Find the least number which when divided by 12, 18, 36 and 45 leaves the remainder 8, 14, 32 and 41 respectively.<\/p>\n a)\u00a0186<\/p>\n b)\u00a0176<\/p>\n c)\u00a0180<\/p>\n d)\u00a0178<\/p>\n Question 4:\u00a0<\/b>The least prime number is<\/p>\n a)\u00a02<\/p>\n b)\u00a00<\/p>\n c)\u00a01<\/p>\n d)\u00a03<\/p>\n Question 5:\u00a0<\/b>What is the arithmetic mean of first 20 odd natural numbers ?<\/p>\n a)\u00a019<\/p>\n b)\u00a017<\/p>\n c)\u00a022<\/p>\n d)\u00a020<\/p>\n SSC CHSL PREVIOUS PAPERS<\/a><\/p>\n SSC CHSL FREE MOCK TEST<\/a><\/p>\n Question 6:\u00a0<\/b>The least number which when divided by 6, 9, 12, 15 and 18 leaves the same remainder 2 in each case is :<\/p>\n a)\u00a0180<\/p>\n b)\u00a0182<\/p>\n c)\u00a0178<\/p>\n d)\u00a0176<\/p>\n Question 7:\u00a0<\/b>The least number that should be added to 2055, so that the sum is exactly divisible by 27 is<\/p>\n a)\u00a028<\/p>\n b)\u00a024<\/p>\n c)\u00a027<\/p>\n d)\u00a031<\/p>\n FREE SSC MATERIAL – 18000 FREE QUESTIONS<\/a><\/p>\n Question 8:\u00a0<\/b>There are 40 hens and cats in a shed. The total number of legs in the shed is 128. How many cats are there in the shed?<\/p>\n a)\u00a016<\/p>\n b)\u00a020<\/p>\n c)\u00a024<\/p>\n d)\u00a028<\/p>\n Question 9:\u00a0<\/b>A number leaves a remainder of 2 when divided by 3, 6 when divided by 7, and 10 when divided by 11. Find the smallest such number.<\/p>\n a)\u00a0188<\/p>\n b)\u00a0153<\/p>\n c)\u00a0230<\/p>\n d)\u00a0461<\/p>\n Question 10:\u00a0<\/b>Two numbers \u2018a\u2019 and \u2018b\u2019 are such that the sum of 8% of a and 4% of b is equal to three fourth of the sum of 9% of a and 8% of b. Find the ratio of a and b?<\/p>\n a)\u00a04:3<\/p>\n b)\u00a08:5<\/p>\n c)\u00a07:4<\/p>\n d)\u00a02:1<\/p>\n DOWNLOAD APP TO ACESSES DIRECTLY ON MOBILE<\/a><\/p>\n Question 11:\u00a0<\/b>Five-seventh of three-eighth of five-sixth of a number is 225. What is the number?<\/p>\n a)\u00a0976<\/p>\n b)\u00a01008<\/p>\n c)\u00a01024<\/p>\n d)\u00a01076<\/p>\n SSC STENOGRAPHER PREVIOUS PAPERS<\/a><\/p>\n Question 12:\u00a0<\/b>A three digit number is greater than the number formed by reversing its digits by 693. How many such three digit numbers are possible?<\/p>\n a)\u00a020<\/p>\n b)\u00a030<\/p>\n c)\u00a040<\/p>\n d)\u00a0None of the above<\/p>\n Question 13:\u00a0<\/b>There are three natural numbers such that the second natural number is 4 times the first and the third number is 3 times the second. If the average of the 3 numbers is 34, then what is the difference between the largest and the smallest numbers?<\/p>\n a)\u00a078<\/p>\n b)\u00a082<\/p>\n c)\u00a098<\/p>\n d)\u00a066<\/p>\n Question 14:\u00a0<\/b>There are some hens and dogs in a shed. The total number of animals is 42 and the number of legs of all the animals is 120. What is the number of hens in the shed?<\/p>\n a)\u00a018<\/p>\n b)\u00a020<\/p>\n c)\u00a022<\/p>\n d)\u00a024<\/p>\n Question 15:\u00a0<\/b>A number when divided by 253 leaves a remainder of 128, find the remainder when the same number is divided by 23.<\/p>\n a)\u00a016<\/p>\n b)\u00a012<\/p>\n c)\u00a013<\/p>\n d)\u00a017<\/p>\n FREE SSC PRACTICE SET (DAILY TEST)<\/a><\/p>\n Question 16:\u00a0<\/b>Two positive numbers have a difference of 3. Sum of the squares of the numbers is 369, then the sum of the numbers would be<\/p>\n a)\u00a027<\/p>\n b)\u00a025<\/p>\n c)\u00a024<\/p>\n d)\u00a030<\/p>\n Question 17:\u00a0<\/b>The smallest natural number when divided by 4,5,6 gives a remainder of 3,4,5 respectively is?<\/p>\n a)\u00a051<\/p>\n b)\u00a049<\/p>\n c)\u00a061<\/p>\n d)\u00a059<\/p>\n Question 18:\u00a0<\/b>6\/7 of a number is 8 more than the 2\/3 of the same number. What is 1\/3 of the number?<\/p>\n a)\u00a084<\/p>\n b)\u00a0126<\/p>\n c)\u00a014<\/p>\n d)\u00a042<\/p>\n Question 19:\u00a0<\/b>The least number which when divided by 7, 8, and 9 leaves a remainder of 6, 7, and 8 respectively is<\/p>\n a)\u00a01007<\/p>\n b)\u00a0251<\/p>\n c)\u00a02015<\/p>\n d)\u00a0None of these<\/p>\n Question 20:\u00a0<\/b>Sowmith wrote all the numbers from 100 to 200 on a black board. What is the number of one\u2019s that have been used to write these numbers?<\/p>\n a)\u00a0111<\/p>\n b)\u00a0115<\/p>\n c)\u00a0120<\/p>\n d)\u00a0122<\/p>\n FREE MOCK TEST FOR SSC STENOGRAPHER<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The number 323 can be written as :<\/p>\n 323 = 17 * 19<\/p>\n where, both 17 and 19 are prime numbers.<\/p>\n Thus, 323 has 2 prime factors.<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n let the digits of the no. be X and Y<\/p>\n number = 10x+y<\/p>\n reverse of no. = 10y+ x<\/p>\n now (10x+y) – (10y+x) = 9x-9y = 9(x-y)<\/p>\n as shown above that 9 will always be the factor, irrespective of the difference and the number<\/p>\n so it can be concluded that the resulting number will always be divisible by 9<\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Since, (12-8) = (18-14) = (36-32) = (45-41) = 4<\/p>\n we, need to find the L.C.M. of 12,18,36,45 and subtract 4 from it to get the required answer.<\/p>\n => L.C.M. of 12, 18, 36 and 45 = 180<\/p>\n => 180 – 4 = 176<\/p>\n Ans – (B)<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 0 and 1 are not prime numbers<\/p>\n Between 2 and 3(both prime numbers), 2 is smaller<\/p>\n 2 is the least prime number. (It is also the only even prime number).<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n NOTE :- Sum of first ‘n’ odd natural numbers = n$^{2}$<\/p>\n Sum of first ‘n’ even natural numbers = n(n+1)<\/p>\n Sum of first 20 odd natural numbers = $20^{2}$ = 400<\/p>\n Arithmetic mean = 400\/20 = 20<\/p>\n FREE SSC STUDY MATERIAL<\/a><\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The numbers 6,9,12,15,18 leaves same remainder 2 in each case.<\/p>\n So, what we need to do is find the L.C.M. of these numbers and add 2 to it<\/p>\n => L.C.M. of 6,9,12,15,18 = 180<\/p>\n => Required no. = 180+2 = 182<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The remainder obtained by dividing 2055 by 27 = 3<\/p>\n So, the least number that should be ‘subtracted’ from 2055 to make it perfectly divisible by 27 = 3<\/p>\n and the least number that should be added = 27-3 = 24<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the number of hens and cats in the shed be \u2018h\u2019 and \u2018c\u2019 respectively. 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the number be N. 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n We have been given that sum of 8% of a and 4% of b is equal to three fourth of the sum of 9% of a and 8% of b 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the number be \u2018N\u2019 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the number be abc. So, the reversed number is cba. 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the first number be x. Then the second number would be 4x and the third number will be 12x. Hence the sum of the three numbers is x + 4x + 12x = 17x 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the number of hens be \u2018$h$\u2019 and the number of dogs be \u2018$d$\u2019 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the number be x 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the two numbers be $x$ and $(x+3)$ 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the number be N GK QUESTIONS AND ANSWERS PDF<\/a><\/p>\n CURRENT AFFAIRS QUESTION AND ANSWERS PDF<\/a><\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the required number be x, then 19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Remainder of 6 when divided 7 is essentially a remainder of -1. 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Among the numbers from 100 to 200:
\nWe know that h+c = 40 —– (1)
\nThe number of hen legs = 2h
\nThe number of cat legs = 4c
\nTotal number of legs = 2h+4c
\nIt is given that 2h+4c = 128 —– (2)
\nSolving equations (1) and (2) we get,
\nh=16 and c=24.<\/p>\n
\n=> N = 3a -1 = 7b-1 = 11c – 1
\nOr N+1 is divisible by all 3, 7, and 11
\nThe smallest number which is divisible by 3, 7, and 11 is LCM (3,7,11) = 231
\nSo, N+1 = 231 or N = 230
\nThus, C is the correct answer.<\/p>\n
\nSo we have
\n$\\frac{8a}{100} + \\frac{4b}{100} = \\frac{3}{4}(\\frac{9a}{100} + \\frac{8b}{100})$
\n=> $ 8a + 4b = \\frac{3}{4}(9a + 8b)$
\n$ 32a + 16b = 27a + 24b$
\n=> 5a = 8b
\n=> $\\frac{a}{b} = \\frac{8}{5}$<\/p>\n
\nIt is given that,
\n$\\frac{5}{7}*\\frac{3}{8}*\\frac{5}{6}*N=225$
\n$=>N=225*\\frac{7}{5}*\\frac{8}{3}*\\frac{6}{5}$
\n$=>N=1008$<\/p>\n
\n=> (100a +10b + c) – (100c + 10b + a) = 693
\n=> 99(a-c) = 693
\n=> a-c=7
\nSo, (a,c) can be (7,0), (8,1), and (9,2). The digit in the tenth’s place can be any number from 0 to 9.
\nSo, 3*10 = 30 numbers are possible.<\/p>\n
\nThus average = 17x\/3
\nHence we get, 17x\/3 = 34
\n=> x = 6
\nThus the largest number is 12*6 = 72 and smallest number is 6. Hence the required difference is 72 – 6 = 66<\/p>\n
\nIt is given that $h+d = 42$ —– (1)
\nWe know that a hen has two legs and a dog has 4 legs.
\nSo the total number of legs = $2h+4d$
\nIt is given that $2h+4d=120$ —– (2)
\nSolving equations (1) and (2) we get,
\n$h=24$ and $d=18$
\nThus the number of hens is 24.<\/p>\n
\nBased on the given information, x can be represented as 253a+128
\nx\/23 = (253a+128)\/23 = (11a + 5) + 13\/23
\nTherefore, the remained when the number is divided by 23 is 13.<\/p>\n
\n$\\implies x^2+(x+3)^2=369$
\n$\\implies 2x^2+6x-360 = 0$
\n$\\implies x^2+3x-180 = 0$
\n$\\implies (x+15)(x-12) = 0$
\nThe numbers are positive, $x$ = $12$, Therefore, the given numbers are $12$ and $15$
\nTherefore, sum of the numbers is $(12+15)$ = $27$
\nHence, the correct Option is A<\/p>\n
\nIf the remainder 4 is 3, the remainder is essentially -1
\nN = 4p-1 = 5q-1 = 6r-1
\nN+1 is a multiple of 4,5,6
\nSmallest value of N+1 is the LCM of 4,5,6
\nLCM (4,5,6) = 60
\nHence, the required number is 59.<\/p>\n
\n6x\/7 – 2x\/3 = 8
\n=> (18x – 14x) = 168
\n4x = 168
\n=> x = 42
\nHence 1\/3 of the given number would be 42\/3 = 14<\/p>\n
\nSimilarly for other two divisors as well the remainder is -1.
\nLet us assume the number to be N
\n=> N = 7a-1 = 8b-1 = 9c-1
\nNor, N+1 is a multiple of all 7, 8, and 9
\nSo smallest such N+1 will be the LCM (7,8,9) = 504
\nSo, smallest N will be 503.<\/p>\n
\nOne in hundred\u2019s place is present in 100 numbers
\nOne in ten\u2019s place is present in 10 numbers
\nOne in unit\u2019s place is present in 10 numbers
\nThus the total number of one\u2019s used = 100+10+10 = 120.
\nHence, Option C.<\/p>\n