{"id":24038,"date":"2018-12-20T12:19:45","date_gmt":"2018-12-20T06:49:45","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=24038"},"modified":"2018-12-26T16:34:35","modified_gmt":"2018-12-26T11:04:35","slug":"ssc-gd-constable-maths-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ssc-gd-constable-maths-questions-pdf\/","title":{"rendered":"SSC GD Constable Maths Questions PDF"},"content":{"rendered":"

SSC GD Constable Maths Questions 2019 PDF:<\/strong><\/span><\/h2>\n

SSC GD Constable Question and Answers download PDF based on previous year question paper of SSC GD 2018-19 exam. Latest 20 Very important Maths questions in Quant for GD Constable.<\/p>\n

Download SSC GD Constable 2018 Maths Questions PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>A man spends 75% of his income. His income increases by 20% and his expenditure also increases by 10%. The percentage of increase in his savings is<\/p>\n

a)\u00a040%
\nb)\u00a030%
\nc)\u00a050%
\nd)\u00a025%<\/p>\n

Question 2:\u00a0<\/b>A fruit-seller buys some oranges and by selling 40% of them he realises the cost price of all the oranges. As the oranges being to grow over-ripe, he reduces the price and sells 80% of the remaining oranges at half the previous rate of profit. The rest of the oranges being rotten are thrown away. The overall percentage of profit is<\/p>\n

a)\u00a080
\nb)\u00a084
\nc)\u00a094
\nd)\u00a096<\/p>\n

Question 3:\u00a0<\/b>A dishonest dealer professes to sell his goods at the cost price but uses a false weight of 850 g instead of 1 kg. His gain percent is<\/p>\n

a)\u00a0$17\\frac{12}{7}$%
\nb)\u00a0$17\\frac{11}{17}$%
\nc)\u00a0$71\\frac{11}{17}$%
\nd)\u00a0$11\\frac{11}{17}$%<\/p>\n

Question 4:\u00a0<\/b>The ratio of present ages of Golu and Polu is 17 : 19. After 5 years the age of Polu will be 81 years. What is the present age of Golu?<\/p>\n

a)\u00a056 years
\nb)\u00a068 years
\nc)\u00a052 years
\nd)\u00a074 years<\/p>\n

Question 5:\u00a0<\/b>The ratio of present ages of Y and Z is 5 : 8. 9 years ago, the age of Y was 7\/13th the age of Z. What is the present age of Z?<\/p>\n

a)\u00a046years
\nb)\u00a052 years
\nc)\u00a048 years
\nd)\u00a040 years<\/p>\n

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Question 6:\u00a0<\/b>The ratio of the present age of Monu and Sonu is 13:11. The ratio of the age of Monu 4 years from now and the age of Sonu 4 years earlier is 5:3. What is the difference between the ages of Sonu and Monu?<\/p>\n

a)\u00a04 years
\nb)\u00a06 years
\nc)\u00a08 years
\nd)\u00a010 years<\/p>\n

Question 7:\u00a0<\/b>Two successive price increase of 10% and 10% of an article are equivalent to a single price increase of<\/p>\n

a)\u00a019%
\nb)\u00a020%
\nc)\u00a021%
\nd)\u00a022%<\/p>\n\n

Question 8:\u00a0<\/b>If each side of a square is increased by 10%. its area will be increased by:<\/p>\n

a)\u00a010%
\nb)\u00a021%
\nc)\u00a044%
\nd)\u00a0100%<\/p>\n

Question 9:\u00a0<\/b>The marked price of an item is Rs. 480. The shopkeeper allows a discount at 10% and gains 8%. If no discount is allowed, his gain percent would be<\/p>\n

a)\u00a018%
\nb)\u00a018.5%
\nc)\u00a020.5%
\nd)\u00a020%<\/p>\n

Question 10:\u00a0<\/b>The sum of a fraction and its reciprocal is $\\frac{113}{56}$. Find the fraction.<\/p>\n

a)\u00a0$\\frac{7}{8}$
\nb)\u00a0$\\frac{5}{8}$
\nc)\u00a0$\\frac{8}{9}$
\nd)\u00a0$\\frac{3}{7}$<\/p>\n

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Question 11:\u00a0<\/b>Arrange the fractions $\\frac{3}{4},\\frac{5}{12},\\frac{13}{16},\\frac{16}{29},\\frac{3}{8}$ in their descending order of magnitude.<\/p>\n

a)\u00a0$\\frac{3}{4}>\\frac{3}{8}>\\frac{13}{16}>\\frac{16}{29}>\\frac{5}{12}$
\nb)\u00a0$\\frac{3}{8}>\\frac{5}{12}>\\frac{16}{29}>\\frac{3}{4}>\\frac{13}{16}$
\nc)\u00a0$\\frac{13}{16}>\\frac{3}{4}>\\frac{16}{29}>\\frac{5}{12}>\\frac{3}{8}$
\nd)\u00a0$\\frac{13}{16}>\\frac{16}{29}>\\frac{3}{4}>\\frac{5}{12}>\\frac{3}{8}$<\/p>\n

Question 12:\u00a0<\/b>Manish can complete a work in 21 days and Karan can complete the same work in 28 days. If both together work for 7 days, then what fraction of total work is left?<\/p>\n

a)\u00a0$\\frac{3}{5}$
\nb)\u00a0$\\frac{2}{3}$
\nc)\u00a0$\\frac{7}{12}$
\nd)\u00a0$\\frac{5}{12}$<\/p>\n\n

Question 13:\u00a0<\/b>Arrangement of the factions $\\frac{4}{3},-\\frac{2}{9},-\\frac{7}{8},\\frac{5}{12}$ into ascending order are<\/p>\n

a)\u00a0$-\\frac{7}{8},-\\frac{2}{9},\\frac{5}{12},\\frac{4}{3}$
\nb)\u00a0$-\\frac{2}{9},-\\frac{7}{8},\\frac{5}{12},\\frac{4}{3}$
\nc)\u00a0$-\\frac{2}{9},-\\frac{7}{8},\\frac{4}{3},\\frac{5}{12}$
\nd)\u00a0$-\\frac{7}{8},-\\frac{2}{9},\\frac{4}{3},\\frac{5}{12}$<\/p>\n

Question 14:\u00a0<\/b>If a sum of money doubles itself in 8 yrs, then the interest rate in percentage is ?<\/p>\n

a)\u00a08 \u00bd%
\nb)\u00a010%
\nc)\u00a010 \u00bd %
\nd)\u00a012 \u00bd %<\/p>\n

Question 15:\u00a0<\/b>A certain principal is invested in a scheme of compound interest. The amount obtained after 1 year is Rs 2400 and the amount obtained after 2 years is Rs 2880. What is the rate of interest (in percentage)?<\/p>\n

a)\u00a020
\nb)\u00a015
\nc)\u00a025
\nd)\u00a010<\/p>\n

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Question 16:\u00a0<\/b>A person borrows some money for 8 years at a rate of simple interest. If the ratio of principal and total interest is 5: 8, then what is the rate ( in percentage) of interest?<\/p>\n

a)\u00a010
\nb)\u00a020
\nc)\u00a025
\nd)\u00a030<\/p>\n

Question 17:\u00a0<\/b>The marked price of a pen is Rs 3000. The shopkeeper gives two successive discounts of 15% and a% to the customer. If the customer pays Rs 2142 for the pen, then what is the value (in percentage) of a?<\/p>\n

a)\u00a016
\nb)\u00a014
\nc)\u00a018
\nd)\u00a017<\/p>\n\n

Question 18:\u00a0<\/b>The marked price of a book is Rs 4200. The shopkeeper gives two successive discounts of 25% and y% to the customer. If the customer pays Rs 2898 for the book, then what is the value (in percentage) of y?<\/p>\n

a)\u00a07
\nb)\u00a08
\nc)\u00a06
\nd)\u00a05<\/p>\n

Question 19:\u00a0<\/b>A man purchased an article for \u20b91500 and sold it at 25% above the cost price. If he has to pay \u20b975 as tax on it, his net profit percentage will be:<\/p>\n

a)\u00a025%
\nb)\u00a030%
\nc)\u00a015%
\nd)\u00a020%<\/p>\n

Question 20:\u00a0<\/b>A shopkeeper marks his goods 20% higher than the cost price and allows a discount of 5%. The percentage of his profit is.<\/p>\n

a)\u00a014%
\nb)\u00a015%
\nc)\u00a010%
\nd)\u00a020%<\/p>\n

Download General Science Questions PDF<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

let the income of person be Rs y So his expenditure be 75% of income which is = 0.75y Saving = y- 0.75y = 0.25yNow after increment of 20 % in income the new income becomes = 1.2y Given that bew expenditure is 10% more than previous one.So , new expenditure is = 1.1 \u00d7 0.75y = 0.825y New savings = 1.2y – 0.825y = 0.375yPercentage increase in savings =$\\frac {0.375y-0.25y}{0.25y}$\u00d7100 = 50%<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let us assume that the fruit seller buys 100 oranges for Rs. 100
\nHe sells 40 oranges for Rs. 100
\nProfit obtained = 100 – 40 = Rs. 60
\n% Profit = $\\frac{60}{40} \\times 100 = 150$%
\nNow, he sells 80% of the remaining oranges at half the profit
\ni.e., he sells 48 oranges at 75% profit.
\nSelling Price of 48 oranges = 48 + 75% of 48 = Rs. 84
\nRest of them are thrown away.
\nTotal SP = 100 + 84 = 184
\nProfit = 184 – 100 = 84
\n% Profit = 84%<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let assume that he buys 1000 gram of quantity at 1000 Rs So, Cost Price of 1 gram = 1 Rs Now as it is mentioned that he is selling only 850 gram in 1000 Rs So , selling Price of 1 gram = $\\frac{1000}{850}$ = Rs 1.1764 So profit percentage = $\\frac{SellingPrice-CostPrice}{CostPrice}$ = $\\frac{1.1764-1}{1}\\times100$ = 17.64 % = $17\\frac{11}{17}$%<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the present age of Golu and Polu be \u2018x\u2019 and \u2018y\u2019 years
\nThus, $\\frac{x}{y} = \\frac{17}{19}$
\nAfter 5 years the age of Polu will be 81 years.
\nSo, y+5 = 81
\ny = 76
\nSo, x = $\\frac{17*76}{19}$ = 68 years
\nHence, option B is the right answer.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the present age of Y and Z be y and z respectively.
\nSo, y:z = 5:8
\nAlso,
\ny-9 = 7*(z-9)\/13
\n13y-117 = 7z – 63
\n13y-7z = 54
\n13*5z\/8 – 7z = 54
\n9z\/8 = 54
\nz = 48 years
\nHence, option C is the right answer.<\/p>\n

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6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the present age of Monu and Sonu be \u2018x\u2019 and \u2018y\u2019 respectively.
\nSo, x:y = 13:11
\nIt is given that,
\n$\\frac{x+4}{y-4} = \\frac{5}{3}$
\n3x + 12 = 5y – 20
\n3x-5y = -32
\n3*$\\frac{13y}{11}$ – 5y = -32
\n-16y = -32*11
\ny = 22
\nSo, x = 26
\nThus, y-x = – 22 + 26 = 4 years
\nHence, option A is the right answer.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let’s say price of article is 100
\nAfter first increase its price will be 100(1+ $\\frac{10}{100}$) = 110
\nNow second increment will be applied on 110
\nHence new price will be 110(1+ $\\frac{10}{100}$ ) = 121
\nWhich is 21 more than before any increment
\nHence total percentage increment = 21<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let’s say side of square is 100 unit
\nits area will be $10^{4} unit^{2}$
\nafter 10% increment its value will be 110 unit
\nand area will become $1.21 \\times 10^{4} unit^{2}$
\nchange in area $ .21 \\times 10^{4} unit^{2}$
\npercentage change will be 21<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Marked price = 480
\ndiscount = 10%
\nSelling price = 480 – $\\frac{480 \\times 10}{100}$ = 432
\nGain = 8%
\nCost price = $ 432 \\times (\\frac{100}{108})$ = 400
\nAfter no discount ,gain will be = 480-400 = 80
\nPercentage gain = $\\frac{80}{400} \\times 100$ = 20%<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the fraction be $x$ According to ques, => $x+\\frac{1}{x}=\\frac{113}{56}$ => $\\frac{x^2+1}{x}=\\frac{113}{56}$ => $56x^2-113x+56=0$ => $56x^2-49x-64x+56=0$=> $7x(8x-7)-8(8x-7)=0$=> $(7x-8)(8x-7)=0$=> $x=\\frac{8}{7},\\frac{7}{8}$=> Ans – (A)<\/p>\n

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11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$\\frac{3}{4}=0.75$$\\frac{5}{12}=0.42$
\n$\\frac{13}{16}=0.81$
\n$\\frac{16}{29}=0.55$
\n$\\frac{3}{8}=0.37$Descending order = $\\frac{13}{16}>\\frac{3}{4}>\\frac{16}{29}>\\frac{5}{12}>\\frac{3}{8}$
\n=> Ans – (C)<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let total work to be done = L.C.M. (21,28) = 84Manish can complete the work in 21 days, => Manish’s efficiency = $\\frac{84}{21}=4$ units\/day
\nSimilarly, Karan’s efficiency = $\\frac{84}{28}=3$ units\/dayNow, (Manish+Karan)’s 7 day’s work = $(4+3)7=49$ unitsFraction of work that is left = $\\frac{(84-49)}{84}=\\frac{35}{84}=\\frac{5}{12}$=> Ans – (D)<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given factions $\\frac{4}{3},-\\frac{2}{9},-\\frac{7}{8},\\frac{5}{12}$ Multiply 72(LCM) with each fraction, then we get96, -16, -63, 30Arrange them in ascending order i.e $-63 < -16 < 30 < 96$ (or) $-\\frac{7}{8}<-\\frac{2}{9}<\\frac{5}{12}<\\frac{4}{3}$Hence, option A is the correct answer.<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the sum = $Rs.$ $x$ and rate of interest = $r\\%$=> Amount after 8 years = $Rs.$ $2x$=> Simple interest = $(2x-x)=Rs.$ $x$Also, SI = $\\frac{P \\times r \\times t}{100}$=> $\\frac{x \\times r \\times 8}{100}=x$=> $r=\\frac{100}{8}=12\\frac{1}{2}\\%$=> Ans – (D)<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Amount obtained after 1 year = Rs. 2400Amount obtained after 2 years = Rs. 2880=> Rate of interest = $\\frac{(2880-2400)}{2400}\\times100$= $\\frac{480}{24}=20\\%$=> Ans – (A)<\/p>\n\n

16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let Principal amount = Rs. $5x$ and interest = Rs. $8x$Let rate of interest = $r\\%$ and time period = 8 years=> Simple interest = $\\frac{P\\times R\\times T}{100}$
\n=> $\\frac{5x\\times r \\times 8}{100}=8x$=> $\\frac{5r}{100}=1$=> $r=\\frac{100}{5}=20\\%$=> Ans – (B)<\/p>\n

17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Marked price = Rs. 3000After first discount of 15%, price of pen = $3000-(\\frac{15}{100}\\times3000)$= $3000-450=Rs.$ $2550$After 2nd discount of $a\\%$, price = $2550-(\\frac{a}{100}\\times2550)=2142$=> $25.5a=2550-2142$=> $25.5a=408$=> $a=\\frac{408}{25.5}=16\\%$=> Ans – (A)<\/p>\n

18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Marked price = Rs. 4200 After first discount of 25%, price of pen = $4200-(\\frac{25}{100}\\times4200)$ = $4200-1050=Rs.$ $3150$ After 2nd discount of $y\\%$, price = $3150-(\\frac{y}{100}\\times3150)=2898$ => $31.5y=3150-2898$ => $31.5y=252$ => $y=\\frac{252}{31.5}=8\\%$ => Ans – (B)<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Cost price = Rs. 1500Markup % = 25%=> Selling price = $1500+(\\frac{25}{100}\\times1500)$= $1500+375=Rs.$ $1875$Total cost price (including tax) = $1500+75=Rs.$ $1575$$\\therefore$ Profit % = $\\frac{(1875-1575)}{1575}\\times100$= $\\frac{300}{15.75}\\approx 20\\%$=> Ans – (D)<\/p>\n

20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let cost price = Rs. $100$Markup % = 20%=> Marked price = $100+(\\frac{20}{100}\\times100)$= $100+20=Rs.$ $120$After allowing discount of 5%, => Selling price = $120-(\\frac{5}{100}\\times120)$ = $120-6=Rs.$ $114$$\\therefore$ Profit % = $\\frac{(114-100)}{100}\\times100=14\\%$=> Ans – (A)<\/p>\n

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We hope this SSC GD Constable maths questions will be very useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

SSC GD Constable Maths Questions 2019 PDF: SSC GD Constable Question and Answers download PDF based on previous year question paper of SSC GD 2018-19 exam. Latest 20 Very important Maths questions in Quant for GD Constable. Take a free mock test for SSC GD Constable 2019 (latest pattern) Download all General Knowledge Questions & […]<\/p>\n","protected":false},"author":21,"featured_media":24047,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,1459],"tags":[1461,1463,1467,1465],"class_list":{"0":"post-24038","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc-gd","10":"tag-ssc-gd","11":"tag-ssc-gd-free-mock","12":"tag-ssc-gd-mocks","13":"tag-ssc-gd-previous-papers"},"better_featured_image":{"id":24047,"alt_text":"SSC GD Maths Questions PDF","caption":"SSC GD Maths Questions PDF","description":"SSC GD Maths Questions 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