{"id":23610,"date":"2018-11-29T18:12:34","date_gmt":"2018-11-29T12:42:34","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=23610"},"modified":"2018-11-30T16:58:40","modified_gmt":"2018-11-30T11:28:40","slug":"quadratic-equations-for-ibps-clerk-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/quadratic-equations-for-ibps-clerk-pdf\/","title":{"rendered":"Quadratic Equations For IBPS Clerk PDF"},"content":{"rendered":"

Quadratic Equations For IBPS Clerk PDF:<\/strong><\/span><\/h1>\n

Download Quadratic Equations For IBPS Clerk PDF. Practice Quadratic Equation Questions and Answers for Banking Exams based on asked questions in previous papers.<\/p>\n

Download Quadratic Equations For IBPS Clerk PDF<\/a><\/p>\n

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Download IBPS Clerk Previous papers PDF<\/a><\/p>\n

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Question 1:<\/strong><\/p>\n

I.$2a^{2}+a-1=0$
\nII.$12b^{2}-17b+6=0$<\/p>\n

a)\u00a0$a<b$
\nb)\u00a0$a\\leq b$
\nc)\u00a0Relationship between $a$ & $b$ cannot be established
\nd)\u00a0$a>b$
\ne)\u00a0$a\\geq b$<\/p>\n

Question 2:\u00a0<\/strong><\/p>\n

I.$a^{2}-5a+6=0$
\nII. $2b^{2}-13b+21=0$<\/p>\n

a)\u00a0$a<b$
\nb)\u00a0$a\\leq b$
\nc)\u00a0Relationship between $a$ & $b$ cannot be established
\nd)\u00a0$a>b$
\ne)\u00a0$a\\geq b$<\/p>\n\n

Question 3:\u00a0<\/strong><\/p>\n

I.$a^{2}+5a+6=0$
\nII.$b^{2}+7b+12=0$<\/p>\n

a) $a<b$
\nb)\u00a0$a \\leq b$
\nc)\u00a0Relationship between $a$ & $b$ cannot be established
\nd)\u00a0$a>b$
\ne)\u00a0$a \\geq b$<\/p>\n

Question 4:<\/strong><\/p>\n

I.$16a^{2}=1$
\nII.$3b^{2}+7b+2=0$<\/p>\n

a)\u00a0$a<b$
\nb)\u00a0$a\\leq b$
\nc)\u00a0Relationship between $a$ & $b$ cannot be established
\nd)\u00a0$a>b$
\ne)\u00a0$a\\geq b$<\/p>\n

Question 5:\u00a0<\/strong><\/p>\n

I.$a^{2}+2a+1=0$
\nII.$b^{2}=\\pm4$<\/p>\n

a)\u00a0$a<b$
\nb)\u00a0$a \\leq b$
\nc)\u00a0Relationship between $a$ & $b$ cannot be established
\nd)\u00a0$a>b$
\ne)\u00a0$a \\geq b$<\/p>\n

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Instructions:<\/strong> What approximate value should come in place of question mark (?) in the following questions? (Note: You are not expected to calculate the exact value.)<\/p>\n

Question 6:<\/strong><\/p>\n

I.$p^{2}-7p=-12$
\nII.$q^{2}-3q+2=0$<\/p>\n

a)\u00a0if p<q
\nb)\u00a0if p>q
\nc)\u00a0if $p\\leq$q
\nd)\u00a0if $p\\geq$q
\ne)\u00a0if p=q<\/p>\n\n

Question 7:<\/strong><\/p>\n

I. $12p^{2}-7p=-1$
\nII. $6q^{2}-7q+2=0$<\/p>\n

a)\u00a0if $p < q$
\nb)\u00a0if $p > q$
\nc)\u00a0if $p\\leq q$
\nd)\u00a0if $p\\geq q$
\ne)\u00a0if $p = q$<\/p>\n

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Question 8:<\/strong><\/p>\n

I.$p^{2}+12p+35=0$
\nII.$2q^{2}+22q+56=0$<\/p>\n

a)\u00a0if p < q
\nb)\u00a0if p>q
\nc)\u00a0if $p \\leq q$
\nd)\u00a0if $p\\geq q$
\ne)\u00a0if p=q or no relationship can be established<\/p>\n

Question 9:\u00a0<\/strong><\/p>\n

I.$p^{2}-8p+15=0$
\nII.$q^{2}-5q=-6$<\/p>\n

a)\u00a0if p < q
\nb)\u00a0if p>q
\nc)\u00a0if $p\\leq q$
\nd)\u00a0if $p\\geq q$
\ne)\u00a0if p=q<\/p>\n

Question 10:<\/strong><\/p>\n

I.$2p^{2}+20p+50=0$
\nII.$q^{2}=25$<\/p>\n

a)\u00a0if p<q
\nb)\u00a0if p>q
\nc)\u00a0if $p \\leq q$
\nd)\u00a0if $p\\geq q $
\ne)\u00a0\u00a0if p = q<\/p>\n

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Question 11:<\/strong><\/p>\n

I. $6p^{2}+5p+1=0$
\nII. $20q^{2}+9q=-1$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.
\nb)\u00a0Give answer (B) if p is smaller than q.
\nc)\u00a0Give answer (C) if p is equal to q.
\nd)\u00a0Give answer (D) if p is either equal to or greater than q.
\ne)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 12:<\/strong>\u00a0I. $3p^{2}+2p-1=0$ II. $2q^{2}+7q+6=0$<\/p>\n

a)\u00a0\u200b<\/span>Give answer (A) if p is greater than q.\u200b<\/span>
\nb)\u00a0Give answer (B) if p is smaller than q.
\nc)\u00a0Give answer (C) if p is equal to q.
\nd)\u00a0Give answer (D) if p is either equal to or greater than q.
\ne)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n\n

Question 13:\u00a0I. <\/strong>$3p^2+15p=-18$ II. $q^2+7q+12=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.
\nb)\u00a0Give answer (B) if p is smaller than q.
\nc)\u00a0Give answer (C) if p is equal to q.
\nd)\u00a0Give answer (D) if p is either equal to or greater than q.
\ne)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 14:<\/strong>\u00a0I. $p=\\frac{\\sqrt{4}}{\\sqrt{9}}$ II. $9q^{2}-12q+4=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.
\nb)\u00a0Give answer (B) if p is smaller than q.
\nc)\u00a0Give answer (C) if p is equal to q.
\nd)\u00a0Give answer (D) if p is either equal to or greater than q.
\ne)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 15:<\/strong>\u00a0I. $p^{2}+13p+42=0$ II. $q^{2}=36$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.
\nb)\u00a0Give answer (B) if p is smaller than q.
\nc)\u00a0Give answer (C) if p is equal to q.
\nd)\u00a0Give answer (D) if p is either equal to or greater than q.
\ne)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1) Answer (A)<\/strong><\/p>\n

$2a^{2}+a-1=0$
\nWe get the factor as:
\na=-1, a=0.5<\/p>\n

$12b^{2}-17b+6=0$
\nSolving, we get the factor as,
\nb= 1.5, b= .75<\/p>\n

Hence, b>a
\nOption A is correct option.<\/p>\n

2) Answer (B)<\/strong><\/p>\n

Soving the quadratic equations we get,
\n$a^{2}-5a+6=0$
\ni.e (a-2)(a-3)=0
\ni.e a=2, a=3<\/p>\n

$2b^{2}-13b+21=0$
\ni.e (b-3.5)(b-3)=0
\ni.e b= 3.5 and b=3<\/p>\n

Hence, we can deduce that $a\\leq b$
\nTherefore, option B is correct.<\/p>\n\n

3) Answer (E)<\/strong><\/p>\n

$a^{2}+5a+6=0$
\ni.e (a+2)(a+3)=0
\ni.e a=-2, a=-3<\/p>\n

.$b^{2}+7b+12=0$
\ni.e (b+4)(b+3)=0
\ni.e b=-4, b=-3<\/p>\n

Hence, we can deduce that $a \\geq b$.
\nTherefore, option E is correct.<\/p>\n

4) Answer (D)<\/strong><\/p>\n

$16a^{2}=1$
\nSolving we get, a=-.25, a=+.25<\/p>\n

$3b^{2}+7b+2=0$
\nSolving we get, b= -2. b = -1\/3<\/p>\n

Hence, a>b. Option D is correct.<\/p>\n

5) Answer (C)<\/strong><\/p>\n

We can easily solve equation I to get a = -1
\nBut we cannot solve $b^{2}=\\pm4$. Square root of negative number is not a real number.
\nHence, we cannot find a value of b. Therefore, we cannot establish a relationship between a and b.<\/p>\n

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6) Answer (B)<\/strong><\/p>\n

$p^2-7p+12 = 0$
\n$(p-3)(p-4) = 0$
\n$p = 3, 4$<\/p>\n

$q^2-3q+2 = 0$
\n$(q-1)(q-2) = 0$
\n$q = 1, 2$<\/p>\n

$\\therefore p > q$<\/p>\n

7) Answer (A)<\/strong><\/p>\n

$12p^2-7p+1 = 0$
\n$(4p-1)(3p-1) = 0$
\n$p = \\frac{1}{3}, \\frac{1}{4}$<\/p>\n

$6q^2-7q+2 = 0$
\n$(2q-1)(3q-2) = 0$
\n$q = \\frac{1}{2}, \\frac{2}{3}$<\/p>\n

$\\therefore p < q$<\/p>\n

8) Answer (E)<\/strong><\/p>\n

$p^2+12p+35 = 0$
\n$(p+5)(p+7) = 0$
\n$p = -5, -7$<\/p>\n

$2q^2+22q+56 = 0$
\n$q^2+11q+28 = 0$
\n$(q+4)(q+7) = 0$
\n$q = -4, -7$<\/p>\n

As we can see $p$ can be greater than, less than or equal to $q$. No relationship can be established between $p$ and $q$ and hence, option E is the right answer.<\/p>\n

9) Answer (D)<\/strong><\/p>\n

$p^2-8p+15 = 0$
\n$(p-3)(p-5) = 0$
\n$p = 3, 5$<\/p>\n

$q^2-5q+6 = 0$
\n$(q-2)(q-3) = 0$
\n$q = 2, 3$<\/p>\n

$p\\geq q$<\/p>\n

10) Answer (C)<\/strong><\/p>\n

$2p^2+20p+50 = 0$
\n$p^2+10p+25 = 0$
\n$(p+5)^2 = 0$
\n$p = -5$<\/p>\n

$q^2 = 25$
\n$q = 5, -5$<\/p>\n

$p\\leq q$<\/p>\n

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11) Answer (B)<\/strong><\/p>\n

$6p^2+5p+1 = 0$
\n$(2p+1)(3p+1) = 0$
\n$p = -\\frac{1}{2}, -\\frac{1}{3}$<\/p>\n

$20q^2+9q+1 = 0$
\n$(4q+1)(5q+1) = 0$
\n$q = -\\frac{1}{4}, -\\frac{1}{5}$<\/p>\n

$p < q$<\/p>\n

12) Answer (A)<\/strong><\/p>\n

$3p^2+2p-1 = 0$
\n$(3p-1)(p+1) = 0$
\n$p = -1, \\frac{1}{3}$<\/p>\n

$2q^2+7q+6 = 0$
\n$(2q+3)(q+2) = 0$
\n$q = -2, -\\frac{3}{2}$<\/p>\n

p > q<\/p>\n

13) Answer (D)<\/strong><\/p>\n

$3p^2+15p+18 = 0$
\n$p^2+5p+6 = 0$
\n$(p+2)(p+3) = 0$
\n$p = -3, -2$<\/p>\n

$q^2+7q+12 = 0$
\n$(q+4)(q+3) = 0$
\n$q = -4, -3$<\/p>\n

$p\\geq q$<\/p>\n

14) Answer (C)<\/strong><\/p>\n

$p = \\frac{\\sqrt{4}}{\\sqrt{9}}$
\n$p = \\frac{2}{3}$<\/p>\n

$9q^2-12q+4 = 0$
\n${(3q-2)}^2 = 0$
\n$q = \\frac{2}{3}$<\/p>\n

p = q<\/p>\n

15) Answer (E)<\/strong><\/p>\n

$p^2+13p+42 = 0$
\n$(p+6)(p+7) = 0$
\n$p = -6, -7$<\/p>\n

$q^2 = 36$
\n$q = -6, 6$<\/p>\n

$p\\leq q$<\/p>\n

Highly Rated IBPS Preparation App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Quadratic Equations For IBPS Clerk PDF: Download Quadratic Equations For IBPS Clerk PDF. Practice Quadratic Equation Questions and Answers for Banking Exams based on asked questions in previous papers. Take Free IBPS Clerk Mock Test Download IBPS Clerk Previous papers PDF Go to Free Banking Study Material (15,000 Solved Questions) Question 1: I.$2a^{2}+a-1=0$ II.$12b^{2}-17b+6=0$ a)\u00a0$a<b$ […]<\/p>\n","protected":false},"author":34,"featured_media":23623,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,229],"tags":[50],"class_list":{"0":"post-23610","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ibpsclerk","10":"tag-ibps-clerk"},"better_featured_image":{"id":23623,"alt_text":"Quadratic Equations For IBPS Clerk PDF","caption":"Quadratic Equations For IBPS Clerk PDF","description":"Quadratic Equations For IBPS Clerk 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