Download Ratio and Proportion Questions for TISSNET PDF \u2013 TISSNET Ratio and Proportion questions PDF by Cracku. Practice TISSNET solved Ratio and Proportion Questions paper tests, and these are the practice question to have a firm grasp on the Ratio and Proportion topic in the TISSNET exam. Top 20 very Important Ratio and Proportion Questions for TISSNET based on asked questions in previous exam papers. \u00a0The TISSNET question papers contain actual questions asked with answers and solutions.<\/p>\n
Download Ratio and Proportion Questions for TISSNET<\/a><\/p>\n Enroll to TISSNET 2023 Crash Course<\/a><\/p>\n Question 1:\u00a0<\/b>Five eighth of a number is equal to 60% of another number.\u00a0What is the ratio between the first number and the second number respectively ?<\/p>\n a)\u00a013:12<\/p>\n b)\u00a012:13<\/p>\n c)\u00a025:24<\/p>\n d)\u00a024:25<\/p>\n e)\u00a0None of these<\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the two numbers be X and Y. Hence, the required ratio is 24:25<\/p>\n Question 2:\u00a0<\/b>Salaries of A, B and C are in the ratio 2 : 3 : 5. If their salaries were increased by 15%, 10% and 20% respectively, what will be the new ratio of their salaries ?<\/p>\n a)\u00a03: 3: 10<\/p>\n b)\u00a023: 33: 60<\/p>\n c)\u00a010: 11: 20<\/p>\n d)\u00a0Can\u2019t be determined<\/p>\n e)\u00a0None of these<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the salaries of A, B and C be 2S,3S and 5S. Hence, the new ratio of their salaries becomes 2.3:3.3:6 = 23:33:60<\/p>\n Question 3:\u00a0<\/b>Ratio of the earnings of A and B is 4 : 7. If the earnings of A increase by 50% and the earnings of B decrease by 25% the new ratio of their earnings becomes 8 : 7. What are A\u2019s earnings ?<\/p>\n a)\u00a0Rs. 26, 000<\/p>\n b)\u00a0Rs. 28, 000<\/p>\n c)\u00a0Rs. 21, 000<\/p>\n d)\u00a0Data inadequate<\/p>\n e)\u00a0None of these<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the earnings of A and B be 4X and 7X respectively. This information doesn’t give any new information about the value of X and hence it’s value can’t be determined.<\/p>\n Question 4:\u00a0<\/b>The number of students studying in College A and B are in the ratio of 3:4. If 50 more students join College A and there is no change in the number of students in College B the ratio becomes 5:6 What is the number of students in College B ?<\/p>\n a)\u00a0450<\/p>\n b)\u00a0500<\/p>\n c)\u00a0400<\/p>\n d)\u00a0600<\/p>\n e)\u00a0None of these<\/p>\n 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the number of students in college A and B be 3s and 4s respectively. Hence, $\\frac{3s+50}{4s}=\\frac{5}{6}$ Therefore, the number of students in college B equals $4s=600$<\/p>\n Question 5:\u00a0<\/b>Four-seventh of a number is equal to 40% of another number. What is the ratio between the first number and the second number respectively ?<\/p>\n a)\u00a05:4<\/p>\n b)\u00a04:5<\/p>\n c)\u00a010:7<\/p>\n d)\u00a07:10<\/p>\n e)\u00a0None of these<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the two numbers be X and Y respectively. Therefore, X:Y = 7:10<\/p>\n Question 6:\u00a0<\/b>Populations of two villages X and Y are in the ratio of 5:7 respectively.If the population of village Y increases by 25000 and the population of village X remains unchanged the respective ratio of their populations becomes 25:36 What is the population of village X ?<\/p>\n a)\u00a06,25,000<\/p>\n b)\u00a06,75,000<\/p>\n c)\u00a08,75,000<\/p>\n d)\u00a09,00,000<\/p>\n e)\u00a0None of these<\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n As the ratio of populations of the two villages are in the ratio 5:7, let the respective populations be 5p and 7p Hence, $\\frac{5p}{7p+25000}=\\frac{25}{36}$ Therefore, the population of X = 5p = 6,25,000<\/p>\n Question 7:\u00a0<\/b>Seats for Maths, Physics and Biology are in the ratio of 5:7:8 respectively. There is a proposal to increase these seats by 40% 50% and 75% respectively. What will be the respective ratio of increased seats ?<\/p>\n a)\u00a02:3:4<\/p>\n b)\u00a06:7:8<\/p>\n c)\u00a0:6:8:9<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the original number of seats in Maths, Physics and Biology be 5X, 7X and 8X. Hence, the final number of seats equals 5X+2X,7X+3.5X and 8X+6X = 7X,10.5X,14X Question 8:\u00a0<\/b>Ratio of earnings of A and B is 8 : 9 respectively. If the earnings of A increased by 50% and the earnings of B decrease by 25%, the new ratio of their earnings becomes 16:9 respectively. What are \u2018A\u2019 earnings ?<\/p>\n a)\u00a0Rs. 37,000<\/p>\n b)\u00a0Rs. 28,500<\/p>\n c)\u00a0Rs. 22,000<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the earnings of A and B be 8k and 9k respectively.<\/p>\n New earnings of A = 150\/100 * 8k = 12k<\/p>\n New earnings of B = 3\/4 * 9k = 6.75k<\/p>\n So, 12k : 6.75k = 16 : 9<\/p>\n But, from this equation, we cannot determine the value of k.<\/p>\n So, option d) is the correct answer.<\/p>\n Question 9:\u00a0<\/b>Ravi is older than Simar by 4 years. Four years from now, the respective ratio between Ravi\u2019s age and Simar\u2019s age will be 9:8. What will be the Ravi\u2019s age 15 years ago? (in years)<\/p>\n a)\u00a019<\/p>\n b)\u00a036<\/p>\n c)\u00a017<\/p>\n d)\u00a025<\/p>\n e)\u00a021<\/p>\n 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let Ravi’s age be x and Simar’s be y. Question 10:\u00a0<\/b>The respective ratio of two numbers is 16 : 21. If the first number is increased by 30% and the second number is decreased by 20%, what will be the respective ratio of the first and the second number?<\/p>\n a)\u00a032 : 21<\/p>\n b)\u00a026 : 21<\/p>\n c)\u00a025 : 21<\/p>\n d)\u00a020 : 21<\/p>\n e)\u00a022 : 21<\/p>\n 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the numerator and denominator be x and y. Option B is the correct answer.<\/p>\n Question 11:\u00a0<\/b>A sum of money is divided among A, B, C, and D in the ratio of 2:3:7:11. If the share of C is Rs 2,755 more than the share of A then what is the total amount of money of B and D together ?<\/p>\n a)\u00a0Rs 4,408<\/p>\n b)\u00a0Rs 5,510<\/p>\n c)\u00a0Rs 6,612<\/p>\n d)\u00a0Rs 7,714<\/p>\n e)\u00a0None of these<\/p>\n 11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let x be the total amount of money. <\/p>\n Question 12:\u00a0<\/b>Profit earned by an organization is distributed among officers and clerks in the ration 5 : 3 respectively. If the number of officers is 45 and the number of clerks 80 and the amount received by each officer is Rs. 25,000\/-, what was the total amount of profit earned?<\/p>\n a)\u00a0Rs. 22 lakhs<\/p>\n b)\u00a0Rs. 18.25 lakhs<\/p>\n c)\u00a0Rs. 18 lakhs<\/p>\n d)\u00a0Rs. 23.25 lakhs<\/p>\n e)\u00a0None of these<\/p>\n 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the amount recieved by each clerk be x<\/p>\n $\\frac{45*25000}{80*x} = \\frac{5}{3}$<\/p>\n x = 8437.5<\/p>\n Total profit = (8437.5*80)+(25000*45) = 18 lakh<\/p>\n Question 13:\u00a0<\/b>Mr. X invested a certain amount in Debt and Equity funds in the ratio of 4 : 5 respectively. At the end of one year, he earned a total divided by 30%on his investment. After one year he reinvested the amount including dividend in the ratio of 6 : 7 in Debt and Equity Funds. If the amount reinvested in Equity Funds was Rs. 94,500\/-, what was the original amount invested in Equity Funds?<\/p>\n a)\u00a0Rs. 75,000<\/p>\n b)\u00a0Rs. 81,000<\/p>\n c)\u00a0Rs. 60,000<\/p>\n d)\u00a0Rs. 65,000<\/p>\n e)\u00a0None of these<\/p>\n 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Since the amount reinvested is in the ratio 6:7,<\/p>\n the amount reinvested in equity is $\\frac{7}{6+7}$ of total amount.<\/p>\n $\\frac{7}{13}$ x = 94500<\/p>\n x = 94500*13\/7<\/p>\n Since there was a 30% profit on this amount,<\/p>\n Original amount = (94500*13)\/(7*1.3) = 135000<\/p>\n Amount invested in equity =$\\frac{5}{5+4}*135000$ = 75000<\/p>\n Question 14:\u00a0<\/b>At present Anil is 1.5 times Purvi\u2019s age. Eight years hence the respective ratio between Anil and Purvi\u2019s age then will be 25: 18. What is the Purvi\u2019s present age?<\/p>\n a)\u00a050 yr<\/p>\n b)\u00a028 yr<\/p>\n c)\u00a042 yr<\/p>\n d)\u00a036 yr<\/p>\n e)\u00a0None of these<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Since Anil’s age is 1.5 times the Purvi’s age,<\/p>\n Purvi’s age = x<\/p>\n Anil’s age = 1.5x<\/p>\n $\\frac{1.5x+8}{x+8} = \\frac{25}{18}$<\/p>\n (1.5x+8)18 = 25(x+8)<\/p>\n 27x+144 = 25x+200<\/p>\n 2x = 56<\/p>\n x = 28<\/p>\n Question 15:\u00a0<\/b>The respective ratio of A and B is 8:7. If the salary of B increases by 20% and the salary of A increases by 21% the new ratio becomes 96: 97 respectively. What is A\u2019s salary?<\/p>\n a)\u00a022560<\/p>\n b)\u00a021600<\/p>\n c)\u00a020640<\/p>\n d)\u00a023040<\/p>\n e)\u00a0Cannot be determined<\/p>\n 15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n As we are not given any absolute figures, a unique value of A’s salary cannot be determined.<\/p>\n Question 16:\u00a0<\/b>Rs.73,689 are divided between A and B in the ratio of 4 : 7. What is the difference between thrice the share of A and twice of the share of B?<\/p>\n a)\u00a0Rs.36,699<\/p>\n b)\u00a0Rs.46,893<\/p>\n c)\u00a0Rs.20,097<\/p>\n d)\u00a0Rs.26,796<\/p>\n e)\u00a0Rs.13,398<\/p>\n 16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n Share of A =\u00a0$\\frac{4}{11}$ x 73689 = 26796 Question 17:\u00a0<\/b>A certain amount was to be distributed among A, B and C in the ratio 2 : 3 : 4 respectively, but was erroneously distributed in the ratio 7 : 2 : 5 respectively. As a result of this, B got Rs.40 Less. What is the amount?<\/p>\n a)\u00a0Rs.210<\/p>\n b)\u00a0Rs.270<\/p>\n c)\u00a0Rs.230<\/p>\n d)\u00a0Rs.280<\/p>\n e)\u00a0None of these<\/p>\n 17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the amount be x Question 18:\u00a0<\/b>The ratio of the present age of Manisha and Deepali is 5 : X. Manisha is 9 years younger than Parineeta. Parineeta\u2019s age after 9 years will be 33 years. The difference between Deepali\u2019s and Manisha\u2019s age is the same as the present age of Parineeta. What should come in place of X?<\/p>\n a)\u00a023<\/p>\n b)\u00a039<\/p>\n c)\u00a015<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n 18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n Parineeta\u2019s present age = 33 – 9 = 24 yrs. Question 19:\u00a0<\/b>Six years ago Jagannath was twice as old as Badri if the ratio of their present age is 9:5 respectively .What is the difference between their present ages?<\/p>\n a)\u00a024<\/p>\n b)\u00a030<\/p>\n c)\u00a050<\/p>\n d)\u00a0Cannot determined<\/p>\n e)\u00a0None of these<\/p>\n 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let present age of Jagannath = $9x$ years<\/p>\n => Badri’s present age = $5x$ years<\/p>\n According to ques, => $(9x-6)=2 \\times (5x-6)$<\/p>\n => $9x-6=10x-12$<\/p>\n => $10x-9x=12-6$<\/p>\n => $x=6$<\/p>\n $\\therefore$ Difference between their present ages = $9x-5x=4x$<\/p>\n = $4 \\times 6=24$<\/p>\n => Ans – (A)<\/p>\n Question 20:\u00a0<\/b>An amount of Rs 1,25,000 is to be distributed among the Sudhir,Soni,Shakunthala in the respective ratio of 2 : 3 : 5.What will be the difference between Soni’s and Sudhir’s \u00a0Share?<\/p>\n a)\u00a025000<\/p>\n b)\u00a012500<\/p>\n c)\u00a018750<\/p>\n d)\u00a02500<\/p>\n e)\u00a0None of these<\/p>\n 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let amount received by\u00a0Sudhir,Soni and Shakunthala be $2x,3x$ and $5x$ respectively.<\/p>\n => Total amount = $(2x+3x+5x)=125,000$<\/p>\n => $10x=125,000$<\/p>\n => $x=\\frac{125,000}{10}=12500$<\/p>\n $\\therefore$ Difference between Soni’s and Sudhir’s \u00a0Share = $3x-2x=x = Rs.$ $12,500$<\/p>\n => Ans – (B)<\/p>\n
\nSo, $\\frac{5}{8}*X = 60 \\% Y$
\nOr, $\\frac{5}{8}*X = \\frac{3}{5}*Y$
\nSo, $\\frac{X}{Y} = \\frac{24}{25}$<\/p>\n
\nIf salary of A is increased by 15%, the salary becomes 2S*115% = 2.3S
\nIf salary of B is increased by 10%, the salary becomes 3S*110% = 3.3S
\nIf salary of C is increased by 20%, the salary becomes 5S*120% = 6S<\/p>\n
\nIf earnings of A increase by 50%, he earns 4X*150% = 6X
\nIf earnings of B decrease by 50%, he earns 7X*75% = 21\/4X
\nSo, the new ratio becomes 6X:21\/4X = 8:7<\/p>\n
\nIf 50 more students join college A, it will have 3s+50 students and the ratio with respect to college B will be 3s+50:4s
\nThis ratio is equal to 5:6<\/p>\n
\nTherefore, $18s+300 = 20s$ or $s=150$<\/p>\n
\nSo, $\\frac{4}{7}*X = 40 \\% *Y$
\nSo, $\\frac{4}{7}*X = \\frac{4}{10} * Y$<\/p>\n
\nIf the population of Y increases by 25000, the population of Y is 7p+25000 and the new ratio equals 5p:7p+25000
\nThis new ratio is 25:36<\/p>\n
\nOr, $180p = 175p + 625000$
\nor $p = 125000$<\/p>\n
\nSo, the respective increases in seats equals 5X*0.4, 7X*0.5 and 8X*0.75
\nThat is 2X, 3.5X and 6X<\/p>\n
\nSo, the final ratio is 7:10.5:14 = 2:3:4<\/p>\n
\nx=y+4
\nAfter 4 years,
\n(x+4)\/(y+4) = 9\/8
\n8x-9y = 4
\nAfter solving we get Ravi’s age be 32 years.
\n15 years before his age is 32-17=17 years.<\/p>\n
\n(x\/y) = (16\/21)
\nNow, if the first number is increased by 30% and the second number is decreased by 20% then the ratio is $\\frac{1.3*16}{0.8*21}$
\nWhich equals $\\frac{208}{168}$
\nWhich equals $\\frac{26}{21}$<\/p>\n
\nHere, share of C is Rs 2,755 more than the share of A i.e
\nShare of C – Share of A = 2755
\ni.e (7x\/23) – (2x\/23) = 2755
\nHence, x= 12,673
\nTotal amount of money with B and D together = (3+11)x\/23 = 14x\/23 = (14*12673)\/23 = 7714
\nCorrect option is D.<\/p>\n
\nThrice share of A = 80388
\nShare of B =\u00a0$\\frac{7}{11}$ x 73689 = 46893
\nTwice the share of B = 93786
\nDifference = 13398<\/p>\n
\nIf the amount is divided into 9 parts , each part =\u00a0$\\frac{x}{9}$
\nB’s supposed amount = 3 x\u00a0$\\frac{x}{9}$ =\u00a0$\\frac{x}{3}$
\nBut B’s actual amount = 2 x\u00a0$\\frac{x}{14}$ =\u00a0$\\frac{x}{7}$
\n$\\frac{x}{3}$ –\u00a0$\\frac{x}{7}$ = 40
\nx = 210<\/p>\n
\nManisha\u2019s present age = 24 – 9 = 15yrs
\nDifference between Manisha and Deepali’s prresent ages = Parineeta’s present age
\nDeepali\u2019s present age = Parineeta’s present age + Manisha’s present age = 24 + 15 = 39 yrs.
\nRatio of the present age of Manisha and Deepali = 15 : 39 = 5 : 13
\nx = 13<\/p>\n