Download Number Series Questions for TISSNET PDF \u2013 TISSNET Number Series questions PDF by Cracku. Practice TISSNET solved Number Series Questions paper tests, and these are the practice question to have a firm grasp on the Number Series topic in the TISSNET exam. Top 20 very Important Number Series Questions for TISSNET based on asked questions in previous exam papers. \u00a0The TISSNET question papers contain actual questions asked with answers and solutions.<\/p>\n
Download Number Series Questions for TISSNET<\/a><\/p>\n Enroll to TISSNET 2023 Crash Course<\/a><\/p>\n Instructions<\/b><\/p>\n In each of the following questions a number series is given.After the series , a number is given followed by a (a),(b),(c),(d) and (e).You are required to complete the series starting with the number given following the sequences of the given series?<\/p>\n Question 1:\u00a0<\/b>12 \u00a024 \u00a096 \u00a0576 \u00a04608 a)\u00a01080<\/p>\n b)\u00a0676<\/p>\n c)\u00a03608<\/p>\n d)\u00a03456<\/p>\n e)\u00a0None of these<\/p>\n 1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is that all the even natural numbers are multiplied.<\/p>\n 12 $\\times 2$ = 24<\/p>\n 24 $\\times 4$ = 96<\/p>\n 96 $\\times 6$ =\u00a0576<\/p>\n 576 $\\times 8$ =\u00a04608<\/p>\n Similarly,<\/p>\n 5\u00a0$\\times 2$ = 10<\/p>\n 10\u00a0$\\times 4$ =\u00a040<\/p>\n 40\u00a0$\\times 6$ =\u00a0240<\/strong><\/p>\n => Ans – (E)<\/p>\n Question 2:\u00a0<\/b>150 \u00a0 299 \u00a0 \u00a0601 \u00a01197 2401 \u00a0 4793 a)\u00a01917.2<\/p>\n b)\u00a01913<\/p>\n c)\u00a01922<\/p>\n d)\u00a0861<\/p>\n e)\u00a0None of these<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is :<\/p>\n 150 $\\times 2 – 1$ = 299<\/p>\n 299\u00a0$\\times 2 + 3$ =\u00a0601<\/p>\n 601\u00a0$\\times 2 – 5$ =\u00a01197<\/p>\n 1197\u00a0$\\times 2 + 7$ =\u00a02401<\/p>\n 2401\u00a0$\\times 2 – 9$ =\u00a04793<\/p>\n Similarly,<\/p>\n 60\u00a0$\\times 2 – 1$ =\u00a0119<\/p>\n 119 $\\times 2 + 3$ =\u00a0241<\/p>\n 241 $\\times 2 – 5$ =\u00a0477<\/p>\n 477 $\\times 2 + 7$ =\u00a0961<\/p>\n 961 $\\times 2 – 9$ =\u00a01913<\/strong><\/p>\n => Ans – (B)<\/p>\n Question 3:\u00a0<\/b>3 \u00a0 \u00a0 9 \u00a0 \u00a0 \u00a081 \u00a0 \u00a06561 a)\u00a0656<\/p>\n b)\u00a04374<\/p>\n c)\u00a01024<\/p>\n d)\u00a065536<\/p>\n e)\u00a0None of these<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is that each number is squared<\/p>\n $3^2$ = 9<\/p>\n $9^2$ =\u00a081<\/p>\n $81^2$ =\u00a06561<\/p>\n Similarly,<\/p>\n $2^2$ = 4<\/p>\n $4^2$ =\u00a016<\/p>\n $16^2$ =\u00a0256<\/p>\n $256^2$ =\u00a065536<\/strong><\/p>\n => Ans – (D)<\/p>\n Question 4:\u00a0<\/b>3 \u00a0 \u00a07 \u00a0 \u00a0 \u00a024 \u00a0 \u00a0101 \u00a0 512 a)\u00a055<\/p>\n b)\u00a0149<\/p>\n c)\u00a0168<\/p>\n d)\u00a0752<\/p>\n e)\u00a0None of these<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 3 $\\times 2+1$ = 7<\/p>\n 7\u00a0$\\times 3+3$ =\u00a024<\/p>\n 24\u00a0$\\times 4+5$ =\u00a0101<\/p>\n 101\u00a0$\\times 5+7$ =\u00a0512<\/p>\n Similarly,<\/p>\n 5 $\\times 2+1$ = 11<\/p>\n 11 $\\times 3+3$ =\u00a036<\/p>\n 36 $\\times 4+5$ =\u00a0149<\/strong><\/p>\n => Ans – (B)<\/p>\n Instructions<\/b><\/p>\n What will come in place of the question mark (?) in each of the following number series.<\/p>\n Question 5:\u00a0<\/b>8, 5.5, 8.5, 23, 89.5, ?<\/p>\n a)\u00a0455<\/p>\n b)\u00a0420.5<\/p>\n c)\u00a0445<\/p>\n d)\u00a0415.5<\/p>\n e)\u00a0433<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 8 $\\times 1 – 2.5$ = 5.5<\/p>\n 5.5\u00a0$\\times 2 – 2.5$ =\u00a08.5<\/p>\n 8.5\u00a0$\\times 3 – 2.5$ =\u00a023<\/p>\n 23\u00a0$\\times 4 – 2.5$ =\u00a089.5<\/p>\n 89.5\u00a0$\\times 5 – 2.5$ =\u00a0445<\/strong><\/p>\n Question 6:\u00a0<\/b>31, 15, 21, 50, ?, 767.25<\/p>\n a)\u00a0160.5<\/p>\n b)\u00a0171.5<\/p>\n c)\u00a0156.5<\/p>\n d)\u00a0122.5<\/p>\n e)\u00a0143.5<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 31 $\\times 0.5 – 0.5$ = 15<\/p>\n 15\u00a0$\\times 1.5 – 1.5$ =\u00a021<\/p>\n 21\u00a0$\\times 2.5 – 2.5$ =\u00a050<\/p>\n 50\u00a0$\\times 3.5 – 3.5$ =\u00a0171.5<\/strong><\/p>\n 171.5\u00a0$\\times 4.5 – 4.5$ =\u00a0767.25<\/p>\n Question 7:\u00a0<\/b>402, 400, 388, 358, 302, ?<\/p>\n a)\u00a0212<\/p>\n b)\u00a0236<\/p>\n c)\u00a0190<\/p>\n d)\u00a0182<\/p>\n e)\u00a0210<\/p>\n 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 402 $- (1 \\times 2)$ = 400<\/p>\n 400\u00a0$- (3 \\times 4)$ =\u00a0388<\/p>\n 388\u00a0$- (5 \\times 6)$ =\u00a0358<\/p>\n 358\u00a0$- (7 \\times 8)$ =\u00a0302<\/p>\n 302\u00a0$- (9 \\times 10)$ =\u00a0212<\/strong><\/p>\n Question 8:\u00a0<\/b>16, 19, 24, 33, 50, ?<\/p>\n a)\u00a083<\/p>\n b)\u00a066<\/p>\n c)\u00a099<\/p>\n d)\u00a074<\/p>\n e)\u00a0102<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern is\u00a0:<\/p>\n 16 + 3 = 19<\/p>\n 19 + 5 (= 3 + 2) = 24<\/p>\n 24 + 9\u00a0(= 5 + 4) =\u00a033<\/p>\n 33 + 17\u00a0(= 9 + 8) =\u00a050<\/p>\n 50 + 33\u00a0(= 17 + 16) =\u00a083<\/strong><\/p>\n Question 9:\u00a0<\/b>158, 78, 38, 18, 8, ?<\/p>\n a)\u00a03<\/p>\n b)\u00a05<\/p>\n c)\u00a02<\/p>\n d)\u00a07<\/p>\n e)\u00a06<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Each number is divided by 2 and then 1 is subtracted.<\/p>\n 158 $\\div 2 – 1$ = 78<\/p>\n 78\u00a0$\\div 2 – 1$ =\u00a038<\/p>\n 38\u00a0$\\div 2 – 1$ =\u00a018<\/p>\n 18\u00a0$\\div 2 – 1$ =\u00a08<\/p>\n 8\u00a0$\\div 2 – 1$ =\u00a03<\/strong><\/p>\n Instructions<\/b><\/p>\n What should come in place of question mark (?) in the following number series?<\/p>\n Question 10:\u00a0<\/b>89250 17850 7140 1428 571.2 ?<\/p>\n a)\u00a0228.48<\/p>\n b)\u00a0126.12<\/p>\n c)\u00a0114.24<\/p>\n d)\u00a0246.48<\/p>\n e)\u00a0None of these<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The numbers are alternatively divided by 5 and 2.5<\/p>\n 89250 $\\div 5$ = 17850<\/p>\n 17850\u00a0$\\div 2.5$ =\u00a07140<\/p>\n 7140\u00a0$\\div 5$ =\u00a01428<\/p>\n 1428\u00a0$\\div 2.5$ =\u00a0571.2<\/p>\n 571.2\u00a0$\\div 5$ =\u00a0114.24<\/strong><\/p>\n Question 11:\u00a0<\/b>1.5 4 20 129 ? 10505<\/p>\n a)\u00a01044<\/p>\n b)\u00a01048<\/p>\n c)\u00a01548<\/p>\n d)\u00a01052<\/p>\n e)\u00a0None of these<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Consecutive even numbers are multiplied and then square of natural numbers are added.<\/p>\n 1.5 $\\times 2 + 1^2$ = 4<\/p>\n 4\u00a0$\\times 4 + 2^2$ =\u00a020<\/p>\n 20\u00a0$\\times 6 + 3^2$ =\u00a0129<\/p>\n 129\u00a0$\\times 8 + 4^2$ =\u00a01048<\/strong><\/p>\n 1048\u00a0$\\times 10 + 5^2$ =\u00a010505<\/p>\n Question 12:\u00a0<\/b>6 349 565 ? 754 781<\/p>\n a)\u00a0629<\/p>\n b)\u00a0590<\/p>\n c)\u00a0601<\/p>\n d)\u00a0690<\/p>\n e)\u00a0None of these<\/p>\n 12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Cubes of natural numbers are added.<\/p>\n 6 $+ 7^3$ = 349<\/p>\n 349\u00a0$+ 6^3$ =\u00a0565<\/p>\n 565\u00a0$+ 5^3$ =\u00a0690<\/strong><\/p>\n 690\u00a0$+ 4^3$ =\u00a0754<\/p>\n 754\u00a0$+ 3^3$ =\u00a0781<\/p>\n Question 13:\u00a0<\/b>4 12 60 420 ? 41580<\/p>\n a)\u00a04620<\/p>\n b)\u00a03780<\/p>\n c)\u00a04200<\/p>\n d)\u00a05040<\/p>\n e)\u00a0None of these<\/p>\n 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Consecutive odd numbers starting from 3 are multiplied.<\/p>\n 4 $\\times 3$ = 12<\/p>\n 12\u00a0$\\times 5$ =\u00a060<\/p>\n 60\u00a0$\\times 7$ =\u00a0420<\/p>\n 420\u00a0$\\times 9$ =\u00a03780<\/strong><\/p>\n 3780\u00a0$\\times 11$ =\u00a041580<\/p>\n Question 14:\u00a0<\/b>3 4 12 ? 576 27648<\/p>\n a)\u00a064<\/p>\n b)\u00a096<\/p>\n c)\u00a036<\/p>\n d)\u00a052<\/p>\n e)\u00a0None of these<\/p>\n 14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n Each number is multiplied by the next number<\/p>\n 3 $\\times 4$ = 12<\/p>\n 4\u00a0$\\times 12$ =\u00a048<\/strong><\/p>\n 12\u00a0$\\times 48$ =\u00a0576<\/p>\n 48\u00a0$\\times 576$ =\u00a027648<\/p>\n Instructions<\/b><\/p>\n What will come in place of the question mark (?) in the following series ?<\/p>\n Question 15:\u00a0<\/b>15 \u00a0 \u00a017 \u00a0 \u00a021 \u00a0 \u00a0 29 \u00a0 \u00a0 45 \u00a0 \u00a0 77 ?<\/p>\n a)\u00a0109<\/p>\n b)\u00a0125<\/p>\n c)\u00a0141<\/p>\n d)\u00a0173<\/p>\n e)\u00a0None of these<\/p>\n 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 15 $+ 2^1$ = 17<\/p>\n 17\u00a0$+ 2^2$ =\u00a021<\/p>\n 21\u00a0$+ 2^3$ =\u00a029<\/p>\n 29\u00a0$+ 2^4$ =\u00a045<\/p>\n 45\u00a0$+ 2^5$ =\u00a077<\/p>\n 77\u00a0$+ 2^6$ =\u00a0141<\/strong><\/p>\n Question 16:\u00a0<\/b>15 \u00a0 \u00a017 \u00a0 \u00a032 \u00a0 49 \u00a0 \u00a081 \u00a0 130 \u00a0 \u00a0?<\/p>\n a)\u00a0179<\/p>\n b)\u00a0211<\/p>\n c)\u00a0194<\/p>\n d)\u00a0226<\/p>\n e)\u00a0None of these<\/p>\n 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Previous number is added to each number to get the next number<\/p>\n 17 + 15 = 32<\/p>\n 32 + 17 = 49<\/p>\n 49 + 32 = 81<\/p>\n 81 + 49 = 130<\/p>\n 130 + 81 =\u00a0211<\/strong><\/p>\n Question 17:\u00a0<\/b>104 \u00a0 \u00a0153 \u00a0 \u00a0189 \u00a0 \u00a0214 \u00a0 ?<\/p>\n a)\u00a0239<\/p>\n b)\u00a0225<\/p>\n c)\u00a0264<\/p>\n d)\u00a0235<\/p>\n e)\u00a0None of these<\/p>\n 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n Squares of natural numbers are added.<\/p>\n 104 $+ 7^2$ = 153<\/p>\n 153\u00a0$+ 6^2$ =\u00a0189<\/p>\n 189\u00a0$+ 5^2$ =\u00a0214<\/p>\n 214\u00a0$+ 4^2$ =\u00a0230<\/strong><\/p>\n Question 18:\u00a0<\/b>1\u00a0 \u00a0 ??\u00a0 \u00a027 \u00a0 \u00a0 \u00a064 \u00a0 \u00a0 125<\/p>\n a)\u00a014<\/p>\n b)\u00a04<\/p>\n c)\u00a09<\/p>\n d)\u00a08<\/p>\n e)\u00a0None of these<\/p>\n 18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n This is a series of cubes of natural numbers.<\/p>\n $1^3$ = 1<\/p>\n $2^3$ =\u00a08<\/strong><\/p>\n $3^3$ =\u00a027<\/p>\n $4^3$ =\u00a064<\/p>\n $5^3$ =\u00a0125<\/p>\n Question 19:\u00a0<\/b>12 \u00a0 22 \u00a0 \u00a069 \u00a0 \u00a0272 \u00a0 \u00a01365 ?<\/p>\n a)\u00a08196<\/p>\n b)\u00a08184<\/p>\n c)\u00a08195<\/p>\n d)\u00a06830<\/p>\n e)\u00a0None of these<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 12 $\\times 2 – 2$ = 22<\/p>\n 22\u00a0$\\times 3 + 3$ =\u00a069<\/p>\n 69\u00a0$\\times 4 – 4$ =\u00a0272<\/p>\n 272\u00a0$\\times 5 + 5$ =\u00a01365<\/p>\n 1365\u00a0$\\times 6 – 6$ =\u00a08184<\/strong><\/p>\n Question 20:\u00a0<\/b>What will come in place of the question mark (?) in the following number series? a)\u00a095<\/p>\n b)\u00a090<\/p>\n c)\u00a0100<\/p>\n d)\u00a0105<\/p>\n e)\u00a096<\/p>\n 20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Numbers of the form $n^2 – (n-1)$ are added, where $n$ is an integer starting from 2<\/p>\n 23 $+ 2^2 – 1$ = 23<\/p>\n 23\u00a0$+ 3^2 – 2$ =\u00a030<\/p>\n 30\u00a0$+ 4^2 – 3$ =\u00a043<\/p>\n 43\u00a0$+ 5^2 – 4$ =\u00a064<\/p>\n 64\u00a0$+ 6^2 – 5$ =\u00a095<\/strong><\/p>\n
\n5 \u00a0 (a) \u00a0(b) \u00a0(c) \u00a0 \u00a0 (d) \u00a0 \u00a0 \u00a0 (e)
\nWhat will come in place of (c) ?<\/p>\n
\n60 \u00a0 \u00a0 (a) \u00a0 \u00a0( b) \u00a0 \u00a0 (c) \u00a0 \u00a0(d) \u00a0 \u00a0 \u00a0(e)
\nWhat will come in place of (e) ?<\/p>\n
\n2 \u00a0 \u00a0(a) \u00a0 \u00a0(b) \u00a0 \u00a0 \u00a0(c) \u00a0 \u00a0 \u00a0(d) \u00a0 \u00a0(e)
\nWhat will come in place of (d) ?<\/p>\n
\n5 \u00a0 (a) \u00a0 (b) \u00a0 \u00a0 (c) \u00a0 \u00a0 (d) \u00a0 (e)
\nWhat will come in place of (c) ?<\/p>\n
\n20\u00a0 23\u00a0 30\u00a0 43\u00a0 64\u00a0 ?<\/p>\n