Enroll to XAT 2023 Crash Course<\/a><\/p>\n Instructions<\/b><\/p>\n Study the following graph carefully to answer these questions. Question 1:\u00a0<\/b>What was the effective percentage increase in population of state \u2018A\u2019 from 1999 to 2001 ?<\/p>\n a)\u00a0103<\/p>\n b)\u00a085<\/p>\n c)\u00a0118<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the population of State A in 1999 = $100x$<\/p>\n => Population in 2000 = $\\frac{140}{100} \\times 100x = 140x$<\/p>\n Population in 2001 = $\\frac{145}{100} \\times 140x = 203x$<\/p>\n $\\therefore$ Effective % increase = $\\frac{203x – 100x}{100x} \\times 100$<\/p>\n = $\\frac{103}{100} \\times 100$ = 103%<\/p>\n Question 2:\u00a0<\/b>If the population of state A in 1998 was 67.5 lakhs, what was its population in 1996 ?<\/p>\n a)\u00a050 lakhs<\/p>\n b)\u00a042 lakhs<\/p>\n c)\u00a045 lakhs<\/p>\n d)\u00a040 lakhs<\/p>\n e)\u00a0None of these<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the population of State A in 1996 = $100x$ lakhs<\/p>\n => Population in 1997 = $\\frac{125}{100} \\times 100x = 125x$ lakhs<\/p>\n Population in 2008 = $\\frac{135}{100} \\times 125x = 168.75x$ lakhs<\/p>\n Acc to ques,<\/p>\n => $168.75x = 67.5$<\/p>\n => $x = 0.4$<\/p>\n $\\therefore$ Population of State A in 1996 = 100 * 0.4 = 40 lakhs<\/p>\n Question 3:\u00a0<\/b>If population of state B in 1996 was 20 lakhs, what was the average population of the state in 1997 and 1998 ?<\/p>\n a)\u00a022.5 lakhs<\/p>\n b)\u00a025 lakhs<\/p>\n c)\u00a027.6 lakhs<\/p>\n d)\u00a024 lakhs<\/p>\n e)\u00a0None of these<\/p>\n 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Population of State B in 1996 = 20 lakhs<\/p>\n => Population in 1997 = $\\frac{120}{100} \\times 20 = 24$ lakhs<\/p>\n Population in 1998 = $\\frac{130}{100} \\times 24 = 31.20$ lakhs<\/p>\n $\\therefore$ Required Average<\/p>\n = $\\frac{24 + 31.2}{2} = 27.6$ lakhs<\/p>\n Question 4:\u00a0<\/b>Total population of the two states in 1996 was 87.5 lakhs, what was the total population of the two states in 1998 ?<\/p>\n a)\u00a0107 lakhs<\/p>\n b)\u00a022 lakhs<\/p>\n c)\u00a0105 lakhs<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n We do not know the individual population of the two states. Thus, we cannot calculate the % increase in population of each states.<\/p>\n => Ans – (D)<\/p>\n Question 5:\u00a0<\/b>If the ratio between the population of states A & B in year 2000 was 3 : 4 respectively, what was the respective ratio in 2001 ?<\/p>\n a)\u00a07 : 9<\/p>\n b)\u00a029 : 36<\/p>\n c)\u00a081 : 116<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the population of State A in 2000 = $300x$<\/p>\n Population of State B in 2000 = $400x$<\/p>\n => Population of State A in 2001 =\u00a0$\\frac{145}{100} \\times 300x = 435x$<\/p>\n Population of State B in 2001 = $\\frac{135}{100} \\times 400x = 540x$<\/p>\n $\\therefore$ Required ratio = $\\frac{435x}{540x}$<\/p>\n = 29\u00a0: 36<\/p>\n Instructions<\/b><\/p>\n Study the following table to answer these questions. Number of Officers in various Departments of an Organization in different Scales Take XAT 2023 Mock Tests<\/a><\/p>\n Question 6:\u00a0<\/b>What percentage of Scale IV officers are deployed in \u2018Operations\u2019 department ?<\/p>\n a)\u00a026.5<\/p>\n b)\u00a028<\/p>\n c)\u00a028.5<\/p>\n d)\u00a027<\/p>\n e)\u00a0None of these<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total number of scale IV employees = 40 + 126 + 144 + 60 + 30 + 50<\/p>\n = 450<\/p>\n $\\therefore$ Required % = $\\frac{126}{450} * 100$<\/p>\n = 28 %<\/p>\n Question 7:\u00a0<\/b>Out of the total number of employees in \u2018Personnel\u2019 department, approximately what per cent of employees are in scale II ?<\/p>\n a)\u00a030<\/p>\n b)\u00a028<\/p>\n c)\u00a022<\/p>\n d)\u00a020<\/p>\n e)\u00a025<\/p>\n 7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n Number of employees in Personnel department = 225 + 120 + 75 + 40 + 25 + 4<\/p>\n = 489<\/p>\n Number of employees in Scale II = 120<\/p>\n $\\therefore$ Required % = $\\frac{120}{489} * 100$<\/p>\n $\\approx \\frac{120}{490} * 100 = 24.48$<\/p>\n = 25% (approx.)<\/p>\n Question 8:\u00a0<\/b>In Public Relations department the number of employees in Scale II is less than that in Scale I by what percent? (rounded off to two digits after decimal).<\/p>\n a)\u00a014.67<\/p>\n b)\u00a016.67<\/p>\n c)\u00a014.29<\/p>\n d)\u00a016.27<\/p>\n e)\u00a0None of these<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Number of employees in Public Relations department in\u00a0:<\/p>\n Scale I = 175<\/p>\n Scale II = 150<\/p>\n Difference = 175 – 150 = 25<\/p>\n => Required % = $\\frac{25}{175} * 100$<\/p>\n = 14.29%<\/p>\n Question 9:\u00a0<\/b>Total number of employees in Scale VI is what per cent of the total number of employees in Scale-I ?<\/p>\n a)\u00a02.8<\/p>\n b)\u00a02.4<\/p>\n c)\u00a03.6<\/p>\n d)\u00a03.2<\/p>\n e)\u00a0None of these<\/p>\n 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total number of employees in Scale I = 225 + 725 + 750 + 300 + 325 + 175 = 2500<\/p>\n Total number of employees in\u00a0Scale VI = 4 + 20 + 28 + 15 + 8 + 5 = 80<\/p>\n => Required % = $\\frac{80}{2500} * 100$<\/p>\n = $\\frac{80}{25}$ = 3.2 %<\/p>\n Question 10:\u00a0<\/b>What is the ratio between the total number of employees in Scale III and Scale IV respectively?<\/p>\n a)\u00a019 : 9<\/p>\n b)\u00a09 : 19<\/p>\n c)\u00a017 : 9<\/p>\n d)\u00a09 : 17<\/p>\n e)\u00a0None of these<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Number of employees in Scale III = 75 + 250 + 320 + 120 + 85 + 100 = 950<\/p>\n Number of employees in Scale IV = 40 + 126 + 144 + 60 + 30 + 50 = 450<\/p>\n => Required ratio = $\\frac{950}{450}$<\/p>\n = 19\u00a0: 9<\/p>\n
\nPer cent rise in population of two states from the previous year<\/strong><\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/77841.png\")
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