Enroll to XAT 2023 Crash Course<\/a><\/p>\n Question 1:\u00a0<\/b>If 29 January 2003 is a Wednesday, then what day of the week will be 26 February 2005?<\/p>\n a)\u00a0Thursday<\/p>\n b)\u00a0Saturday<\/p>\n c)\u00a0Friday<\/p>\n d)\u00a0Sunday<\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,\u00a029 January 2003 is a Wednesday<\/p>\n Number of days between 29 January 2003 and January 29 2004 = 365 days<\/p>\n Number of days between 29 January 2004 and January 29 2005 = 366 days<\/p>\n Number of days between 29 January 2005 and 26 February 2005 = 28 days<\/p>\n Number of days between 29 January 2003 and 26 February 2005 = 365 + 366 + 28 = 759 days<\/p>\n Number of odd days between 29 January 2003 and 26 February 2005 = Remainder of $\\frac{759}{7}$ = 3<\/p>\n $\\therefore\\ $The day on 26 February 2005 = Wednesday + 3 = Saturday<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 2:\u00a0<\/b>What day of the week was 5 February 2008?<\/p>\n a)\u00a0Thursday<\/p>\n b)\u00a0Monday<\/p>\n c)\u00a0Tuesday<\/p>\n d)\u00a0Wednesday<\/p>\n 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Odd days in year 2007 = 6 +\u00a02 = 8 Question 3:\u00a0<\/b>What day of the week was 31 January 2007?<\/p>\n a)\u00a0Monday<\/p>\n b)\u00a0Tuesday<\/p>\n c)\u00a0Thursday<\/p>\n d)\u00a0Wednesday<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Number of odd days in 2006 = 7 Question 4:\u00a0<\/b>What day of the week was 29 June 2010 ?<\/p>\n a)\u00a0Sunday<\/p>\n b)\u00a0Monday<\/p>\n c)\u00a0Wednesday<\/p>\n d)\u00a0Tuesday<\/p>\n 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Odd day till 2009 = 7 +\u00a02 + 2 = 11 Question 5:\u00a0<\/b>A watch reads 4:30. If the minute hand points East in which direction will the hour hand point?<\/p>\n a)\u00a0North-East<\/p>\n b)\u00a0North<\/p>\n c)\u00a0South-West<\/p>\n d)\u00a0south<\/p>\n 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n According to the question, the given information is represented as shown below<\/p>\n $\\therefore\\ $The hour hand is pointing towards North-East<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 6:\u00a0<\/b>If it was a Saturday on 10 November 2018, what was the day of the week on 15 August 2017?<\/p>\n a)\u00a0Monday<\/p>\n b)\u00a0Tuesday<\/p>\n c)\u00a0Sunday<\/p>\n d)\u00a0Friday<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,\u00a010 November 2018 was Saturday<\/p>\n Number of days between 15 August 2017 and 15 August 2018 = 365 days<\/p>\n Number of days between 15 August 2018 and 10 November 2018 = 16 + 30 + 31 + 10 = 87 days<\/p>\n Number of days between 15 August 2017 and 10 November 2018 = 452 days<\/p>\n Number of odd days between 29 January 2003 and 26 February 2005 = Remainder of\u00a0$\\frac{452}{7}$ = 4<\/p>\n $\\therefore\\ $The day on 15 August 2017 = Saturday – 4 = Tuesday<\/p>\n Hence, the correct answer is Option B<\/p>\n Take XAT 2023 Mock Tests<\/a><\/p>\n Question 7:\u00a0<\/b>What was the day of the week on 15 August 2013?<\/p>\n a)\u00a0Thursday<\/p>\n b)\u00a0Monday<\/p>\n c)\u00a0Wednesday<\/p>\n d)\u00a0Tuesday<\/p>\n 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n 15th August 2013 = (2013 years + period between 1-1-2013 to 15-8-2013)<\/p>\n odd days in 2000 = 0<\/p>\n in remaining 13 years = (3 leap years + 9 normal years) = (3 * 2 + 9 * 1) = 15 – 14 = 1 odd days<\/p>\n Total number of days in\u00a0period between 1-1-2013 to 15-8-2013 = 227 days = 32 weeks + 3 days = 3 odd days<\/p>\n Total number of odd days = (1 + 3) = 4 days<\/p>\n Hence, given day is thursday (0 odd day means sunday, 1 odd day means mon and so on )<\/p>\n Question 8:\u00a0<\/b>If it was a Friday on 1 January 2016, what was the day of the week on 31 December 2016?<\/p>\n a)\u00a0Sunday<\/p>\n b)\u00a0Saturday<\/p>\n c)\u00a0Monday<\/p>\n d)\u00a0Friday<\/p>\n 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Year 2016 was a leap year<\/p>\n Therefore, number of days in 2016 = 366 days = 52 weeks + 2 odd days<\/p>\n Now 1st january 2016 was Friday so, 30th december 2016 was also Friday<\/p>\n Hence, 31th december 2016 was Saturday.<\/p>\n Question 9:\u00a0<\/b>If it was a Sunday on 1 January 2017, what was the day of the week on 31 December 2017?<\/p>\n a)\u00a0Tuesday<\/p>\n b)\u00a0Monday<\/p>\n c)\u00a0Sunday<\/p>\n d)\u00a0Friday<\/p>\n 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Year 2017 was normal year,<\/p>\n Number of days in 2017 = 365<\/p>\n So, 52 weeks and one odd day<\/p>\n 1st January 2017 was Sunday means 30th December 2016 is Saturday<\/p>\n So, 31st December 2017 would be Sunday<\/p>\n Question 10:\u00a0<\/b>If it was a Monday on 1 January 2018, what was the day of the week on 31 December 2018 ?<\/p>\n a)\u00a0Monday<\/p>\n b)\u00a0Friday<\/p>\n c)\u00a0Sunday<\/p>\n d)\u00a0Tuesday<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n 2018 is not a leap year. So there will be 365 days in the given year. These 365 days can also be said as 52 weeks and one day. As in the question, it is given that on\u00a01st January 2018 the day was Monday. So on 30th December 2018, 52 weeks will be completed. It means that\u00a0on 30th December 2018, the day was Sunday. Hence on\u00a031st December 2018, the day will be Monday.<\/p>\n
\n($\\because$ 2004 is the leap year and odd days till 2000 is 0.)
\nOdd days in 5 February = odd days in January\u00a0+ 5 = 3 +\u00a05 = 8
\nTotal odd days = 8 +\u00a08 = 16
\nOdd days\u00a0= 16 = 2 weeks + 2 odd days
\nSo day\u00a0of the week was Tuesday.
\n$\\therefore$ The correct answer is option C.<\/p>\n
\n($\\because$ number of\u00a0Leap year from 2000 to 2007 = 1(2004))
\nOdd days in 31 January = 31
\nTotal odd days = (31 + 7) = 38
\nOdd day = 38\/7 = 3 remaining
\nThe day of the week was Wednesday.
\n$\\therefore$ The correct answer is option D.<\/p>\n
\n($\\because$ Year 2004 and 2008 are leap year and odd days till 2000 = 0)
\nOdd days in 29 June = Odd days in (January + February +\u00a0March +\u00a0April +\u00a0May + June) =\u00a0\u00a03 + 0 +\u00a03 +\u00a02 +\u00a03 + 1 = 12
\nTotal odd days = 11 +\u00a012 = 23
\nOdd days = 23\/7 = 2 remaining
\nThe days\u00a0of the week was Tuesday.
\n$\\therefore$ The correct answer is option D.<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/269871.png\")
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