Download Pie Charts Graph Questions for SNAP<\/a><\/p>\n Enroll to SNAP 2022 Crash Course<\/a><\/p>\n Instructions<\/b><\/p>\n Please answer the following three questions based on the data given in the following table Notes: Question 1:\u00a0<\/b>If this data is represented in a pie chart, then how many degrees of arc in the pie chart\u00a0represent each response in the survey results?<\/p>\n a)\u00a04<\/p>\n b)\u00a08<\/p>\n c)\u00a06<\/p>\n d)\u00a02<\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n There are total 360 degrees in pie chart and there are total of 180 responses. Therefore, each response is represented by two degrees of arc in the pie chart.<\/p>\n Answer is option D.<\/p>\n Question 2:\u00a0<\/b>Table shows District-wise data of number of primary school teachers posted in schools of a city. a)\u00a0735<\/p>\n b)\u00a0771<\/p>\n c)\u00a0110<\/p>\n d)\u00a0545<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n The total number of male teachers in the districts East, North, West taken together = 1650 + 1075 + 1280<\/p>\n = 4005<\/p>\n The total number of female teachers in the districts East and South = 2375 + 1085<\/p>\n = 3460<\/p>\n Required difference = 4005 – 3460<\/p>\n = 545<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 3:\u00a0<\/b>The pie graph shows the distribution of employees working in five departments A, B, C, D and E of a company. a)\u00a0725<\/p>\n b)\u00a0850<\/p>\n c)\u00a01000<\/p>\n d)\u00a0915<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Number of employees working in department A = x = $\\frac{64.2^{\\circ\\ }}{360^{\\circ\\ }}\\times9000$ = 1605<\/p>\n x = 1605<\/p>\n Number of\u00a0employees working in department C =\u00a0$\\frac{72^{\\circ\\ }}{360^{\\circ\\ }}\\times9000$ = 1800<\/p>\n Number of employees working in department E = $\\frac{93^{\\circ\\ }}{360^{\\circ\\ }}\\times9000$ = 2325<\/p>\n The total number of employees working in departments C and E = y = 1800 + 2325 = 4125<\/p>\n y = 4125<\/p>\n y – 2x = 4125 – 2(1605) = 4125 – 3210 = 915<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 4:\u00a0<\/b>The following Pie chart represents the percentage-wise distribution of 800 students of class XII in a school in six different sections A, B, C, D, E and F. a)\u00a050<\/p>\n b)\u00a076.25<\/p>\n c)\u00a065.75<\/p>\n d)\u00a080<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Number of students in section A = $\\frac{20}{100}\\times$800 = 160<\/p>\n Number of boys in section A = 160 – 102 = 58<\/p>\n Number of students in section B = $\\frac{18}{100}\\times$800 = 144<\/p>\n Number of boys in section B = 144 – 80 = 64<\/p>\n Number of students in section D = $\\frac{17}{100}\\times$800 = 136<\/p>\n Number of boys in section D = 136 – 98 = 38<\/p>\n Total number of boys in sections A, B and D together = 58 + 64 + 38 = 160<\/p>\n Total number of girls in sections B, C and D together = 80 + 104 + 98 = 282<\/p>\n Required percentage = $\\frac{282-160}{160}\\times$100<\/p>\n =\u00a0$\\frac{122}{160}\\times$100<\/p>\n = 76.25%<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 5:\u00a0<\/b>Pie-Chart shows the degree wise breakup of expenditure of a family in a month. Total income of the family is \u20b9144000. a)\u00a012000<\/p>\n b)\u00a024000<\/p>\n c)\u00a036000<\/p>\n d)\u00a020000<\/p>\n 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The expenditure on education = $\\frac{60}{360}\\times$144000<\/p>\n =\u00a0\u20b924000<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 6:\u00a0<\/b>The pie-chart shows the percentage-wise distribution of the number of students in five different schools P, Q, R, S and T. The total number of students in all five schools together is 10,500. a)\u00a040%<\/p>\n b)\u00a035%<\/p>\n c)\u00a025%<\/p>\n d)\u00a030%<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, total number of students in all schools = 10,500<\/p>\n From the pie-chart,<\/p>\n Number of students in school R = $\\frac{12}{100}\\times10500=1260$<\/p>\n Number of students in school Q and T together =\u00a0$\\frac{16+24}{100}\\times10500=\\frac{40}{100}\\times10500=4200$<\/p>\n $\\therefore\\ $Required percentage = $\\frac{1260}{4200}\\times100=$ 30%<\/p>\n Hence, the correct answer is Option D<\/p>\n Take\u00a0 SNAP mock tests here<\/strong><\/span><\/a><\/p>\n Enrol to 10 SNAP Latest Mocks For Just Rs. 499<\/a><\/strong><\/span><\/p>\n Question 7:\u00a0<\/b>The pie-chart shows the percentage-wise distribution of the number of students in five different schools P, Q, R, S and T. The total number of students in all five schools together is 10,500. a)\u00a0$42.8^\\circ$<\/p>\n b)\u00a0$44^\\circ$<\/p>\n c)\u00a0$43.2^\\circ$<\/p>\n d)\u00a0$34.5^\\circ$<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n From the pie-chart,<\/p>\n Central angle corresponding to school T = $\\frac{24}{100}\\times360^{\\circ}$ =\u00a0$86.4^{\\circ\\ }$<\/p>\n Central angle corresponding to school R =\u00a0$\\frac{12}{100}\\times360^{\\circ}$ =\u00a0$43.2^{\\circ\\ }$<\/p>\n $\\therefore\\ $The difference between the central angles corresponding to schools T and R = $86.4^{\\circ}-43.2^{\\circ}=43.2^{\\circ}$<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 8:\u00a0<\/b>The given pie-chart represents the percentage of students enrolled in five different sports. The total number of students is 2800. a)\u00a0560<\/p>\n b)\u00a0580<\/p>\n c)\u00a0540<\/p>\n d)\u00a0460<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, total number of students = 2800<\/p>\n From the pie-chart,<\/p>\n Number of students enrolled in Hockey =\u00a0$\\frac{26}{100}\\times2800=728$<\/p>\n Number of students enrolled in Tennis =\u00a0$\\frac{14}{100}\\times2800=392$<\/p>\n $\\therefore\\ $Average number of students enrolled in Hockey and Tennis together =\u00a0$\\frac{728+392}{2}=\\frac{1120}{2}=560$<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 9:\u00a0<\/b>The given pie-chart represents the percentage of students enrolled in five different sports. The total number of students is 2800. a)\u00a031 : 18<\/p>\n b)\u00a030 : 17<\/p>\n c)\u00a031 : 16<\/p>\n d)\u00a030 : 13<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, Total number of students = 2800<\/p>\n From the pie-chart,<\/p>\n Number of students enrolled for Cricket $=\\frac{23}{100}\\times2800=644$<\/p>\n Number of students enrolled for Kabaddi $=\\frac{12}{100}\\times2800=336$<\/p>\n After 24 students playing cricket are shifted to Kabaddi,<\/p>\n Number of students playing Cricket\u00a0$=644-24=620$<\/p>\n Number of students playing Kabaddi\u00a0$=336+24=360$<\/p>\n $\\therefore\\ $The new ratio of the number of students in Cricket to those in Kabaddi = 620 : 360 = 31 : 18<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 10:\u00a0<\/b>The given pie chart shows the marks obtained in an examination by a student (in degrees). Observe the pie chart and answer the question that follows. If the total marks are 720, then the difference between the total marks obtained in Physics, Maths and Physical education and the total marks in Chemistry, Biology, and English out of the total marks is:<\/p>\n a)\u00a090<\/p>\n b)\u00a0100<\/p>\n c)\u00a080<\/p>\n d)\u00a0110<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, total marks = 720<\/p>\n From the pie chart,<\/p>\n Total marks obtained in Physics, Maths, Physical education =\u00a0$\\frac{70^{\\circ}+80^{\\circ}+50^{\\circ}}{360^{\\circ}}\\times720$ = 400<\/p>\n Total marks obtained in Chemistry, Biology, English = $\\frac{45^{\\circ}+55^{\\circ}+60^{\\circ}}{360^{\\circ}}\\times720$ = 320<\/p>\n $\\therefore\\ $Required difference = 400 – 320 = 80<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 11:\u00a0<\/b>The given pie chart shows the marks obtained in an examination by a student (in degrees). Observe the pie chart and answer the question that follows. If the total marks are 720, then the marks obtained in Mathematics are:<\/p>\n a)\u00a0140<\/p>\n b)\u00a0160<\/p>\n c)\u00a0120<\/p>\n d)\u00a080<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, total marks = 720<\/p>\n From the pie chart,<\/p>\n Marks obtained in Mathematics =\u00a0$\\frac{80^{\\circ\\ }}{360^{\\circ\\ }}\\times720$ = 160<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 12:\u00a0<\/b>The given pie chart shows the marks obtained in an examination by a student (in degrees). Observe the pie chart and answer the question that follows. a)\u00a050%<\/p>\n b)\u00a030%<\/p>\n c)\u00a060%<\/p>\n d)\u00a040%<\/p>\n 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, total marks = 720<\/p>\n Marks obtained in Chemistry, Biology and Maths together = $\\frac{45^{\\circ\\ }+55^{\\circ\\ }+80^{\\circ\\ }}{360^{\\circ\\ }}\\times720$ = $\\frac{180^{\\circ\\ }}{360^{\\circ\\ }}\\times720$ = 360<\/p>\n $\\therefore\\ $Required percentage = $\\frac{360}{720}\\times100$ = 50%<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 13:\u00a0<\/b>The given pie chart shows the marks obtained in an examination by a student (in degrees). Observe the pie chart and answer the question that follows. a)\u00a050%<\/p>\n b)\u00a055%<\/p>\n c)\u00a075%<\/p>\n d)\u00a060%<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given total marks = 720<\/p>\n Marks obtained by the student in English =\u00a0$\\frac{60^{\\circ\\ }}{360^{\\circ\\ }}\\times720$ = 120<\/p>\n Marks obtained by the student in Maths =\u00a0$\\frac{80^{\\circ\\ }}{360^{\\circ\\ }}\\times720$ =160<\/p>\n $\\therefore\\ $Required percentage = $\\frac{120}{160}\\times100$ = 75%<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 14:\u00a0<\/b>Study the following pie-chart and answer the given question. a)\u00a0$52^\\circ$<\/p>\n b)\u00a0$45^\\circ$<\/p>\n c)\u00a0$56^\\circ$<\/p>\n d)\u00a0$54^\\circ$<\/p>\n 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n From the pie-chart,<\/p>\n Percentage expenditure on D = 15%<\/p>\n The central angle of the sector representing expenditure on head D = $\\frac{15}{100}\\times360^{\\circ\\ }$ =\u00a0$54^\\circ$<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 15:\u00a0<\/b>Study the following pie-chart and answer the given question. a)\u00a0\u20b9 400<\/p>\n b)\u00a0\u20b9 320<\/p>\n c)\u00a0\u20b9 350<\/p>\n d)\u00a0\u20b9 300<\/p>\n 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n From the pie-chart,<\/p>\n Percentage expenditure on A = 55%<\/p>\n Let the total expenditure in 2018 = T<\/p>\n Expenditure on A = $\\frac{55}{100}\\times T$<\/p>\n According to the problem, expenditure on A = \u20b9 165 crore<\/p>\n $\\Rightarrow$ \u00a0$\\frac{55}{100}\\times T=165$<\/p>\n $\\Rightarrow$\u00a0 T = \u20b9 300 crore<\/p>\n $\\therefore\\ $Total expenditure in 2018 = \u20b9 300 crore<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 16:\u00a0<\/b>The given pie chart shows the percentage of students enrolled into the colleges A, B, C, D, E and F in a city, and the table shows the ratio of boys to girls in the college. a)\u00a0504<\/p>\n b)\u00a0560<\/p>\n c)\u00a0280<\/p>\n d)\u00a01008<\/p>\n 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n From the data,<\/p>\n Number of students in college B = $\\frac{16}{100}\\times9800=1568$<\/p>\n Ratio of boys to girls in college B = 5 : 9<\/p>\n $\\therefore\\ $Number of girls in college B =\u00a0$\\frac{9}{5+9}\\times1568=\\frac{9}{14}\\times1568=9\\times112=1008$<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 17:\u00a0<\/b>Study the given pie-chart and table carefully and answer the question that follows. The percentage-wise distribution of lecturers in five different subjects in a university is shown in the pie-chart. The total number of lecturers is 500. a)\u00a046<\/p>\n b)\u00a042<\/p>\n c)\u00a044<\/p>\n d)\u00a040<\/p>\n 17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n From the pie chart,<\/p>\n Percentage of lecturers in Physics = 22%<\/p>\n Number of lecturers in Physics = $\\frac{22}{100}\\times500$ = 110<\/p>\n Ratio of male to female lecturers in Physics = 2 : 3<\/p>\n $\\therefore\\ $Number of male lecturers in Physics =\u00a0$\\frac{2}{2+3}\\times110=\\frac{2}{5}\\times110=44$<\/p>\n Hence, the correct answer is Option C<\/p>\n
\nand the notes below.<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_63_OpSYUtf.png\")
<\/p>\n
\nA. 1 in 8 of the people who cycled to work were found to be over 65 years of age.
\nB. 1 in 3 of the cyclists stated that they travelled to work by bus on rainy days.<\/p>\n
\n![](\"https:\/\/media-cdn.cracku.in\/uploads\/Screenshot_543_xD6nmgz.png\")
\nWhat is the difference between the total number of male teachers in the districts East, North, West taken together and the total number of female teachers in the districts East and South?<\/p>\n
\nTotal number of employees = 9000
\n![](\"https:\/\/media-cdn.cracku.in\/uploads\/Screenshot_513_gtnGQ2W.png\")
\nIf the number of employees working in department A is x and the total number of employees working in departments C and E is y, then the value of y – 2x is:<\/p>\n
\n![](\"https:\/\/media-cdn.cracku.in\/uploads\/Screenshot_435_lgUmhXV.png\")
\nThe table given below shows the number of girls of class XII in six different sections A, B, C, D, E and F.
\n![](\"https:\/\/media-cdn.cracku.in\/uploads\/Screenshot_436_QrXzApm.png\")
\nThe total number of girls in sections B, C and D together is what percent more than the total number of boys in sections A, B and D together?<\/p>\n
\n![](\"https:\/\/media-cdn.cracku.in\/uploads\/Screenshot_433_pKD7jVa.png\")
\nWhat is the expenditure (in \u20b9) on education?<\/p>\n
\nStudy the pie-chart and answer the question.
\n![](\"https:\/\/cracku.in\/media\/uploads\/image_ZeMev2w.png\")
\nThe number of students in school R is what per cent of the total number of students in schools Q and T together?<\/p>\n
\nStudy the pie-chart and answer the question.
\n![](\"https:\/\/cracku.in\/media\/uploads\/image_mkkllaM.png\")
\nThe difference between the central angles corresponding to schools T and R is:<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q51%20%26%2064_ownQEpq.png\")
\nWhat is the average number of students enrolled in Hockey and Tennis together?<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q51%20%26%2064.png\")
\nIf 24 students playing cricket are shifted to Kabaddi, then find the new ratio of the number of students in Cricket to those in Kabaddi.<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q51%2C%2056%2C%2065%20%26%2073_1158XPi.png\")
<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q51%2C%2056%2C%2065%20%26%2073_G9mxoeI.png\")
<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q51%2C%2056%2C%2065%20%26%2073_H38NP3E.png\")
\nIf total marks are 720, then the marks obtained in Chemistry, Biology and Maths together is what percentage of the total marks ?<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q51%2C%2056%2C%2065%20%26%2073.png\")
\nIf the total marks are 720, then the marks obtained in English is what percentage of the marks obtained in Maths?<\/p>\n
\nThe pie-chart shows the Budget Expenditure of a company in the year 2018 (percentage distribution) on different heads A, B, C, D & E.
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q58_kQuy5Of.png\")
\nThe central angle of the sector representing expenditure on head D is:<\/p>\n
\nThe pie-chart shows Budget Expenditure of a company in the year 2018 (percentage distribution) on different heads A, B, C, D & E.
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q58_eCKXQKQ.png\")
\nIf \u20b9 165 crore were spent in year 2018 on A, what would have been the total expenditure for that year (in \u20b9 crores)?<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q71_dk4FgHg.png\")
\nBased on this information,if the total number of students is 9800, then the number of girls in the college B is:<\/p>\n
\n![](\"https:\/\/cracku.in\/media\/uploads\/Q68_L225fHX.png\")
Find the number of male lecturers in Physics.<\/p>\n